What is the general shape of the graph of the equation $y = \frac{k}{x}$, where $k$ is a non-zero constant?
A straight line
An ellipse
A rectangular hyperbola
A circle
A parabola
If the equation of a hyperbola is $y = \frac{5}{x}$, in which quadrants does its graph lie?
Quadrants I and III
Quadrants I and IV
Quadrants II and IV
Quadrants II and III
Quadrants I and II
The graph of the equation $y = \frac{k}{x}$ lies in Quadrants II and IV. What can be concluded about the value of the constant $k$?
$k = 1$
$k < 0$
$k = 0$
$k$ can be any real number
$k > 0$
What are the equations of the asymptotes for the graph of $y = \frac{-2}{x}$?
The graph has no asymptotes
$x = -2$ and $y = 0$
$x = 0$ and $y = -2$
$x = 2$ and $y = -2$
$x = 0$ and $y = 0$
Which of the following points lies on the graph of the hyperbola $y = \frac{12}{x}$?
$(4, 8)$
$(6, 3)$
$(2, 8)$
$(3, 4)$
$(1, 11)$
What is the equation of the vertical asymptote for the rectangular hyperbola given by the equation $y = \frac{5}{x-3} + 2$?
$y = 3$
$x = 5$
$y = 2$
$x = 3$
$x = -3$
Identify the vertical asymptote for the function $f(x) = \frac{-2}{x+7}$.
$x = -2$
$y = -7$
$x = -7$
$y = 0$
$x = 7$
Find the equation of the vertical asymptote for the graph of $y = \frac{4}{2x-8} - 1$.
$x = 4$
$x = -4$
$x = 2$
$x = 8$
$y = -1$
What is the vertical asymptote of the hyperbola defined by the equation $y = \frac{1}{6-x}$?
$x = -6$
$y = 6$
$x = 1$
$x = 6$
For a rectangular hyperbola with the general equation $y = \frac{a}{x-h} + k$, where $a eq 0$, what is the equation of the vertical asymptote?
$x = -h$
$x = h$
$x = a$
$y = h$
$y = k$
What is the equation of the horizontal asymptote for the rectangular hyperbola with the equation $y = \frac{2}{x-3} + 5$?
$y = 5$
Identify the horizontal asymptote of the function $f(x) = \frac{-4}{x+1} - 7$.
$x = -1$
$y = 7$
Determine the equation of the horizontal asymptote for the graph of $y = \frac{5}{x-6}$.
No horizontal asymptote
What is the horizontal asymptote of the hyperbola defined by the equation $y = 9 + \frac{1}{x+2}$?
$y = 1$
$x = 9$
$y = -2$
$y = 9$
Find the equation of the horizontal asymptote for the function $y = -11 + \frac{8}{x}$.
$x = 0$
$y = -11$
$y = 8$
$x = -11$
What are the equations of the vertical and horizontal asymptotes for the rectangular hyperbola with the equation $y = \frac{3}{x-2} + 5$?
Vertical asymptote: $x = 2$, Horizontal asymptote: $y = -5$
Vertical asymptote: $x = -5$, Horizontal asymptote: $y = -2$
Vertical asymptote: $x = -2$, Horizontal asymptote: $y = -5$
Vertical asymptote: $x = 2$, Horizontal asymptote: $y = 5$
Vertical asymptote: $x = 5$, Horizontal asymptote: $y = 2$
A rectangular hyperbola has a vertical asymptote at $x = -4$ and a horizontal asymptote at $y = 1$. Which of the following could be the equation of this hyperbola?
$y = \frac{2}{x+4} + 1$
$y = \frac{2}{x-4} + 1$
$y = \frac{2}{x+1} + 4$
$y = \frac{2}{x-1} - 4$
$y = \frac{2}{x+4} - 1$
How is the graph of $y = \frac{1}{x+3} - 7$ translated from the parent graph of $y = \frac{1}{x}$?
7 units to the left and 3 units down
7 units to the right and 3 units up
3 units to the left and 7 units down
3 units to the left and 7 units up
3 units to the right and 7 units down
What are the coordinates of the center (the point of intersection of the asymptotes) of the hyperbola given by the equation $y = \frac{-5}{x-1} + 6$?
$(1, -6)$
$(6, 1)$
$(-1, -6)$
$(-1, 6)$
$(1, 6)$
The graph of the function $f(x) = \frac{2}{x}$ is translated to create the graph of $g(x) = \frac{2}{x-h} + k$. The new graph has a vertical asymptote at $x=5$ and a horizontal asymptote at $y=-3$. What is the equation for $g(x)$?
$g(x) = \frac{2}{x+3} - 5$
$g(x) = \frac{2}{x-5} - 3$
$g(x) = \frac{2}{x-5} + 3$
$g(x) = \frac{2}{x+5} - 3$
$g(x) = \frac{2}{x-3} + 5$
The graph of the function $y = \frac{5}{x}$ lies in which quadrants of the Cartesian plane?
Quadrants 2 and 3
Quadrants 1 and 2
Quadrants 1 and 3
Quadrants 3 and 4
Quadrants 2 and 4
The branches of the hyperbola with the equation $f(x) = \frac{-10}{x}$ are located in which quadrants?
Quadrants 1 and 4
Consider the function $g(x) = \frac{3}{x-2} + 1$. Relative to its asymptotes ($x=2$ and $y=1$), in which 'quadrants' do the branches of the graph lie?
The graph of the equation $y = -\frac{7}{x+4} - 5$ has its branches in which quadrants, relative to its asymptotes?
A rectangular hyperbola is described by the equation $y = \frac{k}{x}$. If the graph passes through the point $(-2, 3)$, in which quadrants do the branches of the hyperbola lie?
Quadrants 2 and 4, because $k$ must be negative.
It cannot be determined from the given information.
Quadrants 1 and 3, because $k$ must be positive.
Quadrants 3 and 4, because the y-coordinate is positive.
Quadrants 1 and 2, because the x-coordinate is negative.
Find the x-intercept of the rectangular hyperbola with the equation $y = \frac{2}{x-3} + 1$.
$x=5$
$x=1$
$x=3$
$x=\frac{1}{3}$
No x-intercept
What is the x-intercept of the function $f(x) = \frac{4}{x+2} - 2$?
$x=-4$
$x=4$
$x=-2$
$x=0$
Determine the coordinates of the x-intercept for the graph of $y = -\frac{6}{x-1} - 3$.
$(1, 0)$
$(3, 0)$
$(-3, 0)$
$(-1, 0)$
$(0, 3)$
Calculate the x-intercept for the hyperbola given by the equation $y = \frac{5}{2x+4} + 1$.
$x = -\frac{9}{2}$
$x = \frac{1}{2}$
$x = \frac{9}{2}$
$x = \frac{9}{4}$
Which of the following rectangular hyperbolas does not have an x-intercept?
$y = \frac{3}{x-2} + 1$
$y = \frac{1}{x+6} - 6$
$y = \frac{5}{x+1}$
$y = 3 + \frac{1}{x-3}$
$y = \frac{-2}{x} - 4$
Find the y-intercept of the rectangular hyperbola with the equation $y = \frac{4}{x-2} + 5$.
$(2, 5)$
$(0, 7)$
$(0, 5)$
$(0, -2)$
What are the coordinates of the y-intercept for the function $f(x) = \frac{-6}{x+3} - 1$?
$(0, -1)$
$(0, -3)$
$(-3, -1)$
$(0, 1)$
Determine the y-intercept of the graph of the equation $y = \frac{4}{x+2} - 2$.
$(-2, -2)$
$(0, 2)$
No y-intercept
$(0, 0)$
A rectangular hyperbola is defined by the equation $y = \frac{3x+1}{x-1}$. At which point does it cross the y-axis?
A rectangular hyperbola with the equation $y = \frac{a}{x-2} + k$ has a y-intercept at $(0, 1)$ and passes through the point $(4, 5)$. What is the value of $k$?
$k=2$
$k=5$
$k=3$
$k=4$
$k=1$
Find the domain of the function $f(x) = \frac{2}{x-3} + 5$.
$x \in \mathbb{R}, x eq 3$
$x \in \mathbb{R}, x eq 5$
$y \in \mathbb{R}, y eq 5$
$x \in \mathbb{R}, x eq -3$
$x > 3$
Find the range of the function $g(x) = \frac{-1}{x+4} - 2$.
$y \in \mathbb{R}, y eq 2$
$y < -2$
$x \in \mathbb{R}, x eq -4$
$y \in \mathbb{R}, y eq -2$
$y \in \mathbb{R}, y eq -4$
What is the domain of the rectangular hyperbola given by the equation $y = \frac{5}{x} + 1$?
$x > 0$
$x \in \mathbb{R}$
$x \in \mathbb{R}, x eq 1$
$y \in \mathbb{R}, y eq 1$
$x \in \mathbb{R}, x eq 0$
What is the range of the rectangular hyperbola given by the equation $y = \frac{7}{x - 6}$?
$y \in \mathbb{R}$
$y \in \mathbb{R}, y eq 0$
$x \in \mathbb{R}, x eq 6$
$y \in \mathbb{R}, y eq 6$
$y \in \mathbb{R}, y eq -6$
State the domain and range of the function $h(x) = \frac{1}{x+1} + 1$.
Domain: $x \in \mathbb{R}$; Range: $y \in \mathbb{R}, y eq 1$
Domain: $x \in \mathbb{R}, x eq -1$; Range: $y \in \mathbb{R}, y eq 1$
Domain: $x \in \mathbb{R}, x eq -1$; Range: $y \in \mathbb{R}$
Domain: $y \in \mathbb{R}, y eq 1$; Range: $x \in \mathbb{R}, x eq -1$
Domain: $x \in \mathbb{R}, x eq 1$; Range: $y \in \mathbb{R}, y eq -1$
A rectangular hyperbola has the equation $y = 8 - \frac{3}{x-2}$. What is its domain?
$x \in \mathbb{R}, x eq 8$
$x \in \mathbb{R}, x eq 2$
$x \in \mathbb{R}, x eq -2$
$y \in \mathbb{R}, y eq 8$
A rectangular hyperbola has the equation $y = \frac{10}{5-x} + 7$. What is its range?
$x \in \mathbb{R}, x eq -5$
$y \in \mathbb{R}, y eq 7$
$y \in \mathbb{R}, y eq -7$
The function $f(x) = \frac{k}{x-p} + q$ has a domain of $x \in \mathbb{R}, x eq -5$ and a range of $y \in \mathbb{R}, y eq 10$. What are the values of $p$ and $q$?
$p = 10, q = -5$
$p = -5, q = -10$
$p = -5, q = 10$
$p = 5, q = -10$
$p = 5, q = 10$
Find the domain and range for the function $y = \frac{2x+1}{x-1}$.
Domain: $x \in \mathbb{R}, x eq 1$; Range: $y \in \mathbb{R}, y eq 2$
Domain: $y \in \mathbb{R}, y eq 2$; Range: $x \in \mathbb{R}, x eq 1$
Domain: $x \in \mathbb{R}, x eq -1$; Range: $y \in \mathbb{R}, y eq -2$
Domain: $x \in \mathbb{R}, x eq 1$; Range: $y \in \mathbb{R}, y eq 1$
Domain: $x \in \mathbb{R}, x eq -1$; Range: $y \in \mathbb{R}, y eq 2$
Which of the following functions has a domain of $x \in \mathbb{R}, x eq 4$ and a range of $y \in \mathbb{R}, y eq -3$?
$y = \frac{1}{x+4} - 3$
$y = \frac{1}{x-4} + 3$
$y = \frac{1}{x+3} - 4$
$y = \frac{1}{x-3} + 4$
$y = \frac{1}{x-4} - 3$
A rectangular hyperbola has a vertical asymptote at $x=2$ and a horizontal asymptote at $y=-1$. The graph passes through the point $(3,1)$. Determine the equation of the hyperbola.
$y = \frac{2}{x-2} - 1$
$y = \frac{2}{x+2} + 1$
$y = \frac{-2}{x-2} - 1$
$y = \frac{1}{x-2} - 1$
$y = \frac{2}{x-3} - 1$
A rectangular hyperbola has a vertical asymptote at $x=-3$ and a horizontal asymptote at $y=4$. It passes through the origin $(0,0)$. What is its equation?
$y = \frac{12}{x+3} + 4$
$y = \frac{-3}{x+3} + 4$
$y = \frac{4}{x+3} + 4$
$y = \frac{-12}{x+3} + 4$
$y = \frac{-12}{x-3} + 4$
The graph of a hyperbola has asymptotes with equations $x=1$ and $y=-2$. The y-intercept of the graph is at $(0, -3)$. Determine the equation of the hyperbola.
$y = \frac{2}{x-1} - 2$
$y = \frac{1}{x+1} - 2$
$y = \frac{1}{x-1} - 2$
$y = \frac{-1}{x-1} - 2$
$y = \frac{1}{x-1} + 2$
A rectangular hyperbola has a horizontal asymptote at $y=5$ and an x-intercept at $(2, 0)$. The vertical asymptote is $x=3$. Find the equation of the hyperbola.
$y = \frac{-5}{x-3} + 5$
$y = \frac{5}{x-5} + 3$
$y = \frac{5}{x+3} + 5$
$y = \frac{3}{x-2} + 5$
$y = \frac{5}{x-3} + 5$
The asymptotes of a hyperbola are given by the lines $x=-4$ and $y=-1$. The graph passes through the point $(-5, -3)$. What is the equation of the hyperbola?
$y = \frac{4}{x+4} - 1$
$y = \frac{-2}{x+4} - 1$
$y = \frac{2}{x-4} - 1$
A hyperbola has a vertical asymptote at $x=0$ and a horizontal asymptote at $y=3$. It passes through the point $(1, 5)$. Find its equation.
$y = \frac{1}{x} + 3$
$y = \frac{3}{x} + 2$
$y = \frac{2}{x+1} + 3$
$y = \frac{2}{x} + 3$
$y = \frac{2}{x} - 3$
The graph of a hyperbola has a y-intercept at $(0, 2.5)$ and an x-intercept at $(-5, 0)$. The vertical asymptote is the line $x=-2$. What is the equation of the hyperbola?
$y = \frac{3}{x+2} + 1$
$y = \frac{6}{x+2} - 1$
$y = \frac{3}{x+2} - 2$
$y = \frac{-3}{x+2} + 1$
A hyperbola has asymptotes $y=1$ and $x=-1$. It passes through the point $(1, 2)$. What is the value of '$a$' in the standard equation $y = \frac{a}{x-p} + q$?
$a=-2$
$a=2$
$a=1$
$a=0.5$
$a=-1$
The horizontal asymptote of a hyperbola is $y=0$ and the vertical asymptote is $x=4$. It passes through the point $(2, -1)$. What is its equation?
$y = \frac{2}{x-4}$
$y = \frac{4}{x-2}$
$y = \frac{-2}{x-4}$
$y = \frac{1}{x-4}$
$y = \frac{2}{x+4}$
A rectangular hyperbola is defined by the equation $y=\frac{a}{x-p}+q$. Its asymptotes are $x=5$ and $y=-3$. The graph's x-intercept is $(4,0)$. Find the equation.
$y = \frac{5}{x-4} - 3$
$y = \frac{-3}{x-5} + 3$
$y = \frac{3}{x-5} - 3$
$y = \frac{-3}{x+5} - 3$
$y = \frac{-3}{x-5} - 3$
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