Capillary Tube Of Radius R Is Immersed In A Liquid at Linda France blog

Capillary Tube Of Radius R Is Immersed In A Liquid. If the radius of tube is doubled, mass of water that will rise in. Mass of water in capillary tube is m. A capillary tube of radius r is immersed in water and water rises in it to a height h. Let h be the height through which the liquid rise in the capillary tube of radius r. The correct answer is mass of liquid which rises in the capillary,m = (πr2)hρ = πr2×2σcosθrρg×ρ or m∝rclearly, if the radius is doubled, the mass. ∴ h= 2t cosθ rρg. When on end of the capillary tube of radius \[r\] is immersed in water (liquid) of density \[\rho \]. Then water rises to some height \[h\] in the. If is then very simple to calculate how far the. A capillary tube of radius `r` is immersed in a liquid. When the lower end of a narrow capillary tube is immersed in a liquid, the liquid inside the tube rises a little above the level of the liquid outside. (∴ r1 = r2 = r +50% of r = 23r) new mas m2 = πr22h2ρ. The correct option is c 10 g. ⇒ h1h2 = h1r1 = 32. The liquid rises to a height `h`.

Then water rises to some height \[h\] in the. If is then very simple to calculate how far the. When the lower end of a narrow capillary tube is immersed in a liquid, the liquid inside the tube rises a little above the level of the liquid outside. Mass of water in capillary tube is m. (∴ r1 = r2 = r +50% of r = 23r) new mas m2 = πr22h2ρ. Let h be the height through which the liquid rise in the capillary tube of radius r. The correct option is c 10 g. The correct answer is mass of liquid which rises in the capillary,m = (πr2)hρ = πr2×2σcosθrρg×ρ or m∝rclearly, if the radius is doubled, the mass. A capillary tube of radius r is immersed in water and water rises in it to a height h. The liquid rises to a height `h`.

A capillary tube of radius r is immersed in water and water rises in to

Capillary Tube Of Radius R Is Immersed In A Liquid (∴ r1 = r2 = r +50% of r = 23r) new mas m2 = πr22h2ρ. Mass of water in capillary tube is m. The correct option is c 10 g. If is then very simple to calculate how far the. The liquid rises to a height `h`. ∴ h= 2t cosθ rρg. If the radius of tube is doubled, mass of water that will rise in. A capillary tube of radius r is immersed in water and water rises in it to a height h. Let h be the height through which the liquid rise in the capillary tube of radius r. When on end of the capillary tube of radius \[r\] is immersed in water (liquid) of density \[\rho \]. A capillary tube of radius `r` is immersed in a liquid. (∴ r1 = r2 = r +50% of r = 23r) new mas m2 = πr22h2ρ. Then water rises to some height \[h\] in the. The correct answer is mass of liquid which rises in the capillary,m = (πr2)hρ = πr2×2σcosθrρg×ρ or m∝rclearly, if the radius is doubled, the mass. When the lower end of a narrow capillary tube is immersed in a liquid, the liquid inside the tube rises a little above the level of the liquid outside. ⇒ h1h2 = h1r1 = 32.