description

# tryParse static method

int? tryParse(

1. String source, {
2. int? radix,

})
override

Parse `source` as a, possibly signed, integer literal.

Like parse except that this function returns `null` where a similar call to parse would throw a FormatException.

Example:

    print(int.tryParse('2021')); // 2021
    print(int.tryParse('1f')); // null
    // From binary (base 2) value.
    print(int.tryParse('1100', radix: 2)); // 12
    print(int.tryParse('00011111', radix: 2)); // 31
    print(int.tryParse('011111100101', radix: 2)); // 2021
    // From octal (base 8) value.
    print(int.tryParse('14', radix: 8)); // 12
    print(int.tryParse('37', radix: 8)); // 31
    print(int.tryParse('3745', radix: 8)); // 2021
    // From hexadecimal (base 16) value.
    print(int.tryParse('c', radix: 16)); // 12
    print(int.tryParse('1f', radix: 16)); // 31
    print(int.tryParse('7e5', radix: 16)); // 2021
    // From base 35 value.
    print(int.tryParse('y1', radix: 35)); // 1191 == 34 * 35 + 1
    print(int.tryParse('z1', radix: 35)); // null
    // From base 36 value.
    print(int.tryParse('y1', radix: 36)); // 1225 == 34 * 36 + 1
    print(int.tryParse('z1', radix: 36)); // 1261 == 35 * 36 + 1

## Implementation

    external static int? tryParse(String source, {int? radix});