description

# tryParse static method

double? tryParse(

1. String source

)
override

Parse `source` as a double literal and return its value.

Like parse, except that this function returns `null` for invalid inputs instead of throwing.

Example:

    var value = double.tryParse('3.14'); // 3.14
    value = double.tryParse('  3.14 \xA0'); // 3.14
    value = double.tryParse('0.'); // 0.0
    value = double.tryParse('.0'); // 0.0
    value = double.tryParse('-1.e3'); // -1000.0
    value = double.tryParse('1234E+7'); // 12340000000.0
    value = double.tryParse('+.12e-9'); // 1.2e-10
    value = double.tryParse('-NaN'); // NaN
    value = double.tryParse('0xFF'); // null
    value = double.tryParse(double.infinity.toString()); // Infinity

## Implementation

    external static double? tryParse(String source);