description

# lastIndexWhere method

int lastIndexWhere(

1. bool test(
   1. E element
   ), [
2. int? start

])
override

The last index in the list that satisfies the provided `test`.

Searches the list from index `start` to 0. The first time an object `o` is encountered so that `test(o)` is true, the index of `o` is returned. If `start` is omitted, it defaults to the length of the list.

    final notes = <String>['do', 're', 'mi', 're'];
    final first = notes.lastIndexWhere((note) => note.startsWith('r')); // 3
    final second = notes.lastIndexWhere((note) => note.startsWith('r'),
        2); // 1

Returns -1 if `element` is not found.

    final notes = <String>['do', 're', 'mi', 're'];
    final index = notes.lastIndexWhere((note) => note.startsWith('k'));
    print(index); // -1

## Implementation

    int lastIndexWhere(bool test(E element), [int? start]) {
      if (start == null || start >= this.length) start = this.length - 1;

      for (int i = start; i >= 0; i--) {
        if (test(this[i])) return i;
      }
      return -1;
    }