Column Buy Id In Field List Is Ambiguous at Alex Pierce blog

Column Buy Id In Field List Is Ambiguous. Sql supports qualifying a column by prefixing the reference with either the full table name: Select user_name,candidate_id from user as usr inner join candidate as can on usr.user_id = can.entered_by inner join. Column 'rest_id' in field list is ambiguous. When i run, $product =. Select tbl_names.id, tbl_section.id, name, section. You need to specify columns with table alias name also. 위 에러는 rest_id 라는 컬럼을 가진 테이블이 많다는 것을 의미한다. 따라서 어느 테이블의 rest_id 를 사용할 것인지 지정해주면 된다. Column user_id is in both table_reviews, table_users tables. Select tbl_names.id, tbl_section.id, name, section. In your query, the column worker_name and id columns exists in both tables, where worker_name retains the same. 1052 column 'id' in field list is ambiguous (sql: Sql supports qualifying a column by prefixing the reference with either the full table name: In the select query, you are not specifying table name to select data. So, mysql gets confused and generates the column '.

一文解决Column ‘xxx‘ in field list is ambiguous问题_column 'id' in field list
from blog.csdn.net

Column 'rest_id' in field list is ambiguous. You need to specify columns with table alias name also. Sql supports qualifying a column by prefixing the reference with either the full table name: 따라서 어느 테이블의 rest_id 를 사용할 것인지 지정해주면 된다. Column user_id is in both table_reviews, table_users tables. Select tbl_names.id, tbl_section.id, name, section. Select tbl_names.id, tbl_section.id, name, section. In the select query, you are not specifying table name to select data. Sql supports qualifying a column by prefixing the reference with either the full table name: In your query, the column worker_name and id columns exists in both tables, where worker_name retains the same.

一文解决Column ‘xxx‘ in field list is ambiguous问题_column 'id' in field list

Column Buy Id In Field List Is Ambiguous Select user_name,candidate_id from user as usr inner join candidate as can on usr.user_id = can.entered_by inner join. 따라서 어느 테이블의 rest_id 를 사용할 것인지 지정해주면 된다. Column 'rest_id' in field list is ambiguous. Column user_id is in both table_reviews, table_users tables. You need to specify columns with table alias name also. So, mysql gets confused and generates the column '. 1052 column 'id' in field list is ambiguous (sql: In the select query, you are not specifying table name to select data. In your query, the column worker_name and id columns exists in both tables, where worker_name retains the same. Select tbl_names.id, tbl_section.id, name, section. Sql supports qualifying a column by prefixing the reference with either the full table name: Sql supports qualifying a column by prefixing the reference with either the full table name: Select user_name,candidate_id from user as usr inner join candidate as can on usr.user_id = can.entered_by inner join. 위 에러는 rest_id 라는 컬럼을 가진 테이블이 많다는 것을 의미한다. When i run, $product =. Select tbl_names.id, tbl_section.id, name, section.

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