Cannot Borrow Immutable Static Item As Mutable at Mary Huntsberry blog

Cannot Borrow Immutable Static Item As Mutable. When you borrow separate struct fields within one function, the borrow checker understands they don't overlap. Lazy_static doesn't allow you to get direct mutable access to the static value. This pattern often yields cannot borrow *self as mutable more than once at a time or similarly for borrowing immutable when self is mutable. You'll need to use some form of interior mutability, for example by wrapping your runtime in a. Let mut mutable_string = string::from(hello); Let mut foo = foo { some_str: A very simple solution to this issue is to make the problematic method into a free function that only takes a mutable reference to the field or fields. I use a large stack for my program, so i tried to use lazy_static.

Mutable and immutable classes
from www.slideshare.net

When you borrow separate struct fields within one function, the borrow checker understands they don't overlap. Let mut foo = foo { some_str: I use a large stack for my program, so i tried to use lazy_static. This pattern often yields cannot borrow *self as mutable more than once at a time or similarly for borrowing immutable when self is mutable. Let mut mutable_string = string::from(hello); Lazy_static doesn't allow you to get direct mutable access to the static value. A very simple solution to this issue is to make the problematic method into a free function that only takes a mutable reference to the field or fields. You'll need to use some form of interior mutability, for example by wrapping your runtime in a.

Mutable and immutable classes

Cannot Borrow Immutable Static Item As Mutable This pattern often yields cannot borrow *self as mutable more than once at a time or similarly for borrowing immutable when self is mutable. When you borrow separate struct fields within one function, the borrow checker understands they don't overlap. Let mut mutable_string = string::from(hello); A very simple solution to this issue is to make the problematic method into a free function that only takes a mutable reference to the field or fields. This pattern often yields cannot borrow *self as mutable more than once at a time or similarly for borrowing immutable when self is mutable. Let mut foo = foo { some_str: You'll need to use some form of interior mutability, for example by wrapping your runtime in a. Lazy_static doesn't allow you to get direct mutable access to the static value. I use a large stack for my program, so i tried to use lazy_static.

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