Qualified Case Label Must Be Replaced With Unqualified at Lucy Greenfield blog

Qualified Case Label Must Be Replaced With Unqualified. An enum switch case label must be the unqualified name of an enumeration constant. An enum switch case label must be the unqualified name of an enumeration constant case. In a switch statement on an enum you need the unqualified name, always. The compiler will simply look at the type of the enum parameter to the switch() statement and. Java infers automatically the type of the elements in case, so the labels must be unqualified. An enum switch case label must. You do not need to qualify, just use the enumeration's label: 这个错误是因为您在枚举类型的 switch 语句中使用了无效的.如果您使用了其他表达式作为 case 标签,编译器就会报错并提示“an enum switch case label must be the unqualified name of an. I'll add a test case. But this does not work. They put it on the ocjp to fool people who are more used to other languages,. Only unqualified enum value must be used for case labels. The compiler throws these errors for the syntax for each case statement:

20180628 185347 Case Labels USA
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But this does not work. 这个错误是因为您在枚举类型的 switch 语句中使用了无效的.如果您使用了其他表达式作为 case 标签,编译器就会报错并提示“an enum switch case label must be the unqualified name of an. Java infers automatically the type of the elements in case, so the labels must be unqualified. An enum switch case label must be the unqualified name of an enumeration constant case. In a switch statement on an enum you need the unqualified name, always. Only unqualified enum value must be used for case labels. You do not need to qualify, just use the enumeration's label: An enum switch case label must be the unqualified name of an enumeration constant. They put it on the ocjp to fool people who are more used to other languages,. The compiler throws these errors for the syntax for each case statement:

20180628 185347 Case Labels USA

Qualified Case Label Must Be Replaced With Unqualified They put it on the ocjp to fool people who are more used to other languages,. 这个错误是因为您在枚举类型的 switch 语句中使用了无效的.如果您使用了其他表达式作为 case 标签,编译器就会报错并提示“an enum switch case label must be the unqualified name of an. They put it on the ocjp to fool people who are more used to other languages,. The compiler throws these errors for the syntax for each case statement: But this does not work. An enum switch case label must be the unqualified name of an enumeration constant case. In a switch statement on an enum you need the unqualified name, always. An enum switch case label must. An enum switch case label must be the unqualified name of an enumeration constant. I'll add a test case. You do not need to qualify, just use the enumeration's label: Java infers automatically the type of the elements in case, so the labels must be unqualified. Only unqualified enum value must be used for case labels. The compiler will simply look at the type of the enum parameter to the switch() statement and.

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