An Electric Kettle Is Rated 3Kw 250V at Mark Morris blog

An Electric Kettle Is Rated 3Kw 250V. Given that the voltage is 250 v and the power is. Yes, this kettle can be used in a circuit which contains a 13 a fuse because safe limit of current for kettle is, i = 3000w/250v = 12 a An electric kettle is rated 3 kw, 250 v. The power is given by the product of applied voltage and the electric current. That is, p = v i. An electric kettle is rated 3 kw, 250 v. Give reason whether this kettle can be used in a circuit which contains a fuse of current rating. The maximum current capacity of kettle, i = `p/v = 3000/250 = 12a` thus, the fuse should be of current capacity slightly less than 12a. Give reason whether this kettle can be used in a circuit which contains a 13 a fuse. The power of the kettle is given by the formula, \[p = vi\] where \[i\] is the current associated with the kettle and \[v\] is the voltage associated with. The power is given by the product of applied voltage and the electric current. That is, p = v i. Given that the voltage is 250 v and the power is. Answered feb 16, 2019 by akul (72.8k points) selected feb 16, 2019 by vikash kumar.

Answered feb 16, 2019 by akul (72.8k points) selected feb 16, 2019 by vikash kumar. An electric kettle is rated 3 kw, 250 v. Given that the voltage is 250 v and the power is. An electric kettle is rated 3 kw, 250 v. Give reason whether this kettle can be used in a circuit which contains a fuse of current rating. The power of the kettle is given by the formula, \[p = vi\] where \[i\] is the current associated with the kettle and \[v\] is the voltage associated with. The power is given by the product of applied voltage and the electric current. That is, p = v i. Give reason whether this kettle can be used in a circuit which contains a 13 a fuse. That is, p = v i.

The 9 Best Electric Kettles of 2023 by Real Simple

An Electric Kettle Is Rated 3Kw 250V Give reason whether this kettle can be used in a circuit which contains a 13 a fuse. The power of the kettle is given by the formula, \[p = vi\] where \[i\] is the current associated with the kettle and \[v\] is the voltage associated with. Answered feb 16, 2019 by akul (72.8k points) selected feb 16, 2019 by vikash kumar. That is, p = v i. The maximum current capacity of kettle, i = `p/v = 3000/250 = 12a` thus, the fuse should be of current capacity slightly less than 12a. The power is given by the product of applied voltage and the electric current. That is, p = v i. Give reason whether this kettle can be used in a circuit which contains a fuse of current rating. An electric kettle is rated 3 kw, 250 v. Give reason whether this kettle can be used in a circuit which contains a 13 a fuse. An electric kettle is rated 3 kw, 250 v. Given that the voltage is 250 v and the power is. The power is given by the product of applied voltage and the electric current. Given that the voltage is 250 v and the power is. Yes, this kettle can be used in a circuit which contains a 13 a fuse because safe limit of current for kettle is, i = 3000w/250v = 12 a