Refractive Index Real Depth Apparent Depth at Frances Bernard blog

Refractive Index Real Depth Apparent Depth. A ray coming from medium x is refracted as shown in the figure below while passing to the medium y. but with the formula of apparent depth we can find real depth as well if apparent depth is given i.e., d(apparent) = d(real) / μ 21. the real depth is the actual depth of the bottom of the tank, and the apparent depth is the virtual depth that is observed as a. as you can see refractive index of the water is equal to the ratio of real depth of fish to the apparent depth of it. the gradient of the graph of real depth d 1 against apparent depth d 2 is the refractive index of water. Which should be n = 4/3 = n2/n1 , but my book says, 4/3= real. the depth that you “see” is the image height \(h_i\) and is called the apparent depth. \[ \frac{\text{real depth}}{\text{apparent depth}}=\frac{h}{h'}=\frac{\tan \theta'}{\tan \theta} = n. we know that the refractive index of water to air is 4/3. The actual depth of the fish is the object.

Light Refraction Real depth & Apparent depth example and a problem
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\[ \frac{\text{real depth}}{\text{apparent depth}}=\frac{h}{h'}=\frac{\tan \theta'}{\tan \theta} = n. the gradient of the graph of real depth d 1 against apparent depth d 2 is the refractive index of water. Which should be n = 4/3 = n2/n1 , but my book says, 4/3= real. the real depth is the actual depth of the bottom of the tank, and the apparent depth is the virtual depth that is observed as a. The actual depth of the fish is the object. the depth that you “see” is the image height \(h_i\) and is called the apparent depth. A ray coming from medium x is refracted as shown in the figure below while passing to the medium y. we know that the refractive index of water to air is 4/3. as you can see refractive index of the water is equal to the ratio of real depth of fish to the apparent depth of it. but with the formula of apparent depth we can find real depth as well if apparent depth is given i.e., d(apparent) = d(real) / μ 21.

Light Refraction Real depth & Apparent depth example and a problem

Refractive Index Real Depth Apparent Depth \[ \frac{\text{real depth}}{\text{apparent depth}}=\frac{h}{h'}=\frac{\tan \theta'}{\tan \theta} = n. as you can see refractive index of the water is equal to the ratio of real depth of fish to the apparent depth of it. Which should be n = 4/3 = n2/n1 , but my book says, 4/3= real. The actual depth of the fish is the object. the real depth is the actual depth of the bottom of the tank, and the apparent depth is the virtual depth that is observed as a. A ray coming from medium x is refracted as shown in the figure below while passing to the medium y. \[ \frac{\text{real depth}}{\text{apparent depth}}=\frac{h}{h'}=\frac{\tan \theta'}{\tan \theta} = n. the depth that you “see” is the image height \(h_i\) and is called the apparent depth. the gradient of the graph of real depth d 1 against apparent depth d 2 is the refractive index of water. we know that the refractive index of water to air is 4/3. but with the formula of apparent depth we can find real depth as well if apparent depth is given i.e., d(apparent) = d(real) / μ 21.

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