The Minute Hand Of A Clock Is 12 Cm at Rory Campbell blog

The Minute Hand Of A Clock Is 12 Cm. Findangle subtended in 35 minutes. The minute hand of a clock is \ [12\;cm\] long. Hence, the area swept by minute hand in 35 minutes is 264 cm2. ∵ anglesubtended in 1 minute = 6 ∘ ∴ anglesubtended in 35 minutes = 35 × 6 ∘ ∴ anglesubtended in 35. The area covered by minute hand = (22 × 12) cm2 area = 264 cm2 hence, the area covered by minute hand in 35 minutes is 264cm2. Angle described by the minute hand in 35 minutes = (360 60 × 35) ∘ = 210 ∘ ⇒ θ = 210 2 and r = 12 c m area swept by the minute hand in 35. ∴ required area described by the minute hand in 35 minutes = area of the sector where r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. The minute hand of a clock is 12 cm long. As we know that the minute hand of a clock completes a complete angle i.e. Find the area of the face of the clock described by the minute hand. $ 360^\circ $ of angle in one. ∴ required area swept by the minute hand in 35 minutes = area of the sector with r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210.

Overlapping Hands of a Clock Mathigon
from et.mathigon.org

The area covered by minute hand = (22 × 12) cm2 area = 264 cm2 hence, the area covered by minute hand in 35 minutes is 264cm2. The minute hand of a clock is 12 cm long. ∵ anglesubtended in 1 minute = 6 ∘ ∴ anglesubtended in 35 minutes = 35 × 6 ∘ ∴ anglesubtended in 35. $ 360^\circ $ of angle in one. The minute hand of a clock is \ [12\;cm\] long. ∴ required area swept by the minute hand in 35 minutes = area of the sector with r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. Findangle subtended in 35 minutes. ∴ required area described by the minute hand in 35 minutes = area of the sector where r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. Hence, the area swept by minute hand in 35 minutes is 264 cm2. Angle described by the minute hand in 35 minutes = (360 60 × 35) ∘ = 210 ∘ ⇒ θ = 210 2 and r = 12 c m area swept by the minute hand in 35.

Overlapping Hands of a Clock Mathigon

The Minute Hand Of A Clock Is 12 Cm Findangle subtended in 35 minutes. Hence, the area swept by minute hand in 35 minutes is 264 cm2. The area covered by minute hand = (22 × 12) cm2 area = 264 cm2 hence, the area covered by minute hand in 35 minutes is 264cm2. $ 360^\circ $ of angle in one. ∵ anglesubtended in 1 minute = 6 ∘ ∴ anglesubtended in 35 minutes = 35 × 6 ∘ ∴ anglesubtended in 35. As we know that the minute hand of a clock completes a complete angle i.e. The minute hand of a clock is \ [12\;cm\] long. ∴ required area swept by the minute hand in 35 minutes = area of the sector with r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. Findangle subtended in 35 minutes. The minute hand of a clock is 12 cm long. Angle described by the minute hand in 35 minutes = (360 60 × 35) ∘ = 210 ∘ ⇒ θ = 210 2 and r = 12 c m area swept by the minute hand in 35. ∴ required area described by the minute hand in 35 minutes = area of the sector where r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. Find the area of the face of the clock described by the minute hand.

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