Hand Of A Clock Is 12 Cm Long at Lora Allan blog

Hand Of A Clock Is 12 Cm Long. $ 360^\circ $ of angle in one. As we know that the minute hand of a clock completes a complete angle i.e. Angle described by the minute hand in 35 minutes = (360 60 × 35) ∘ = 210° now, r = 12 cm and θ = 210° ∴ required area swept by the minute hand in 35. Length of minute hand = 12cm Area swept by the minute hand in 35 minutes = (π r 2 θ 360) = (22 7 × 12 × 12 × 210 360) c m 2 = 264 c m 2 Findangle subtended in 35 minutes. ∵ anglesubtended in 1 minute = 6 ∘ ∴ anglesubtended in 35 minutes = 35 × 6 ∘ ∴ anglesubtended in 35. The minute hand of a clock is 12cm long, find the area of the clock described by minute hand in 42min. The minute hand of a clock is \ [12\;cm\] long. ∴ required area described by the minute hand in 35 minutes = area of the sector where r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210.

What's A Clock With Hands Called at Jimmy True blog
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Length of minute hand = 12cm The minute hand of a clock is 12cm long, find the area of the clock described by minute hand in 42min. As we know that the minute hand of a clock completes a complete angle i.e. Angle described by the minute hand in 35 minutes = (360 60 × 35) ∘ = 210° now, r = 12 cm and θ = 210° ∴ required area swept by the minute hand in 35. ∴ required area described by the minute hand in 35 minutes = area of the sector where r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. ∵ anglesubtended in 1 minute = 6 ∘ ∴ anglesubtended in 35 minutes = 35 × 6 ∘ ∴ anglesubtended in 35. The minute hand of a clock is \ [12\;cm\] long. $ 360^\circ $ of angle in one. Findangle subtended in 35 minutes. Area swept by the minute hand in 35 minutes = (π r 2 θ 360) = (22 7 × 12 × 12 × 210 360) c m 2 = 264 c m 2

What's A Clock With Hands Called at Jimmy True blog

Hand Of A Clock Is 12 Cm Long The minute hand of a clock is 12cm long, find the area of the clock described by minute hand in 42min. As we know that the minute hand of a clock completes a complete angle i.e. The minute hand of a clock is 12cm long, find the area of the clock described by minute hand in 42min. Area swept by the minute hand in 35 minutes = (π r 2 θ 360) = (22 7 × 12 × 12 × 210 360) c m 2 = 264 c m 2 The minute hand of a clock is \ [12\;cm\] long. Angle described by the minute hand in 35 minutes = (360 60 × 35) ∘ = 210° now, r = 12 cm and θ = 210° ∴ required area swept by the minute hand in 35. $ 360^\circ $ of angle in one. ∵ anglesubtended in 1 minute = 6 ∘ ∴ anglesubtended in 35 minutes = 35 × 6 ∘ ∴ anglesubtended in 35. Findangle subtended in 35 minutes. ∴ required area described by the minute hand in 35 minutes = area of the sector where r = 12 cm and θ = 210° r = π r 2 θ 360 cm = (22 7 × 12 × 12 × 210. Length of minute hand = 12cm

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