F(X) Dot G(X) at Richard Randolph blog

F(X) Dot G(X). Evaluate f (2x) f (2 x) by substituting in the value of g g into f f. The notation $f \cdot g$ means that for every $x$ the function is $$ (f \cdot g)(x) = f(x) \cdot g(x) $$ which is pointwise multiplication. A function basically relates an input to an output, there’s an input, a relationship and an output. This time, we plugged a. Previously, we'd plugged a number into g(x), found a new value, plugged that value into f (x), and simplified the result. In this example, both functions had domains of all. The composite of two functions f(x) and g(x) must abide by the domain restrictions of f(x) and g(x).

Example 17 Let f(x) = root x, g(x) = x. Find f + g, fg, f/g
from www.teachoo.com

In this example, both functions had domains of all. Evaluate f (2x) f (2 x) by substituting in the value of g g into f f. The composite of two functions f(x) and g(x) must abide by the domain restrictions of f(x) and g(x). This time, we plugged a. A function basically relates an input to an output, there’s an input, a relationship and an output. The notation $f \cdot g$ means that for every $x$ the function is $$ (f \cdot g)(x) = f(x) \cdot g(x) $$ which is pointwise multiplication. Previously, we'd plugged a number into g(x), found a new value, plugged that value into f (x), and simplified the result.

Example 17 Let f(x) = root x, g(x) = x. Find f + g, fg, f/g

F(X) Dot G(X) Evaluate f (2x) f (2 x) by substituting in the value of g g into f f. The notation $f \cdot g$ means that for every $x$ the function is $$ (f \cdot g)(x) = f(x) \cdot g(x) $$ which is pointwise multiplication. In this example, both functions had domains of all. The composite of two functions f(x) and g(x) must abide by the domain restrictions of f(x) and g(x). Evaluate f (2x) f (2 x) by substituting in the value of g g into f f. This time, we plugged a. A function basically relates an input to an output, there’s an input, a relationship and an output. Previously, we'd plugged a number into g(x), found a new value, plugged that value into f (x), and simplified the result.

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