
Thus, in
, to find the circumcentre, we can draw
the perpendicular bisectors of sides AB, BC, and CA of
the triangle.
Hence, O is the point where these bisectors are
meeting together.
Therefore, O is the point which is equidistant from all
the vertices of
.
Question: 2
In a triangle locate a point in its interior which is
equidistant from all the sides of the triangle.
Solution:
We know that the point which is equidistant from all
the sides of a triangle is called the in centre of the
triangle.
So, in centre of a triangle is the intersection point of
the angle bisectors of the interior angles of the
triangle.