-->

Rectangular Piece Of Cardboard Creases X Maximize


-->

Rectangular Piece Of Cardboard Creases X Maximize. They're close to 3% of the distance between the creases. To find the value of x that maximizes the volume enclosed by the box, we need to find an expression for the volume in terms of x and then maximize it.

A rectangular piece of cardboard is 4 times as long as it is wide. If
A rectangular piece of cardboard is 4 times as long as it is wide. If from www.youtube.com

Letting x represent the distance (in inches) between the creases, use the aleks graphing calculator to find the value of x that maximizes the volume. A piece of cardboard has a perimeter of 14 inches. It's done folded about the crease to make a rectangular box with open ends that's fair.

-->

A rectangular piece of cardboard is 4 times as long as it is wide. If

It's done folded about the crease to make a rectangular box with open ends that's fair. Letting x represent the distance (in inches) between the creases, use the aleks graphing_calculator to find the value of x that maximizes the yolume. To find the value of x that maximizes the volume enclosed by the box, we need to find an expression for the volume in terms of x and then maximize it. To solve the problem of maximizing the volume of a box created from a rectangular piece of cardboard with a perimeter of 13 inches, we can follow these.

-->