Coverage Report

Created: 2023-08-28 06:31

/src/binutils-gdb/libiberty/objalloc.c
Line
Count
Source (jump to first uncovered line)
1
/* objalloc.c -- routines to allocate memory for objects
2
   Copyright (C) 1997-2023 Free Software Foundation, Inc.
3
   Written by Ian Lance Taylor, Cygnus Solutions.
4
5
This program is free software; you can redistribute it and/or modify it
6
under the terms of the GNU General Public License as published by the
7
Free Software Foundation; either version 2, or (at your option) any
8
later version.
9
10
This program is distributed in the hope that it will be useful,
11
but WITHOUT ANY WARRANTY; without even the implied warranty of
12
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
13
GNU General Public License for more details.
14
15
You should have received a copy of the GNU General Public License
16
along with this program; if not, write to the Free Software
17
Foundation, 51 Franklin Street - Fifth Floor,
18
Boston, MA 02110-1301, USA.  */
19
20
#include "config.h"
21
#include "ansidecl.h"
22
23
#include "objalloc.h"
24
25
/* Get a definition for NULL.  */
26
#include <stdio.h>
27
28
#if VMS
29
#include <stdlib.h>
30
#include <unixlib.h>
31
#else
32
33
/* Get a definition for size_t.  */
34
#include <stddef.h>
35
36
#ifdef HAVE_STDLIB_H
37
#include <stdlib.h>
38
#else
39
/* For systems with larger pointers than ints, this must be declared.  */
40
extern void *malloc (size_t);
41
extern void free (void *);
42
#endif
43
44
#endif
45
46
/* These routines allocate space for an object.  Freeing allocated
47
   space may or may not free all more recently allocated space.
48
49
   We handle large and small allocation requests differently.  If we
50
   don't have enough space in the current block, and the allocation
51
   request is for more than 512 bytes, we simply pass it through to
52
   malloc.  */
53
54
/* The objalloc structure is defined in objalloc.h.  */
55
56
/* This structure appears at the start of each chunk.  */
57
58
struct objalloc_chunk
59
{
60
  /* Next chunk.  */
61
  struct objalloc_chunk *next;
62
  /* If this chunk contains large objects, this is the value of
63
     current_ptr when this chunk was allocated.  If this chunk
64
     contains small objects, this is NULL.  */
65
  char *current_ptr;
66
};
67
68
/* The aligned size of objalloc_chunk.  */
69
70
#define CHUNK_HEADER_SIZE         \
71
205M
  ((sizeof (struct objalloc_chunk) + OBJALLOC_ALIGN - 1) \
72
205M
   &~ (OBJALLOC_ALIGN - 1))
73
74
/* We ask for this much memory each time we create a chunk which is to
75
   hold small objects.  */
76
77
1.12G
#define CHUNK_SIZE (4096 - 32)
78
79
/* A request for this amount or more is just passed through to malloc.  */
80
81
53.5M
#define BIG_REQUEST (512)
82
83
/* Create an objalloc structure.  */
84
85
struct objalloc *
86
objalloc_create (void)
87
6.59M
{
88
6.59M
  struct objalloc *ret;
89
6.59M
  struct objalloc_chunk *chunk;
90
91
6.59M
  ret = (struct objalloc *) malloc (sizeof *ret);
92
6.59M
  if (ret == NULL)
93
0
    return NULL;
94
95
6.59M
  ret->chunks = (void *) malloc (CHUNK_SIZE);
96
6.59M
  if (ret->chunks == NULL)
97
0
    {
98
0
      free (ret);
99
0
      return NULL;
100
0
    }
101
102
6.59M
  chunk = (struct objalloc_chunk *) ret->chunks;
103
6.59M
  chunk->next = NULL;
104
6.59M
  chunk->current_ptr = NULL;
105
106
6.59M
  ret->current_ptr = (char *) chunk + CHUNK_HEADER_SIZE;
107
6.59M
  ret->current_space = CHUNK_SIZE - CHUNK_HEADER_SIZE;
108
109
6.59M
  return ret;
110
6.59M
}
111
112
/* Allocate space from an objalloc structure.  */
113
114
void *
115
_objalloc_alloc (struct objalloc *o, unsigned long original_len)
116
53.5M
{
117
53.5M
  unsigned long len = original_len;
118
119
  /* We avoid confusion from zero sized objects by always allocating
120
     at least 1 byte.  */
121
53.5M
  if (len == 0)
122
0
    len = 1;
123
124
53.5M
  len = (len + OBJALLOC_ALIGN - 1) &~ (OBJALLOC_ALIGN - 1);
125
126
  /* Check for overflow in the alignment operation above and the
127
     malloc argument below. */
128
53.5M
  if (len + CHUNK_HEADER_SIZE < original_len)
129
0
    return NULL;
130
131
53.5M
  if (len <= o->current_space)
132
0
    {
133
0
      o->current_ptr += len;
134
0
      o->current_space -= len;
135
0
      return (void *) (o->current_ptr - len);
136
0
    }
137
138
53.5M
  if (len >= BIG_REQUEST)
139
31.1M
    {
140
31.1M
      char *ret;
141
31.1M
      struct objalloc_chunk *chunk;
142
143
31.1M
      ret = (char *) malloc (CHUNK_HEADER_SIZE + len);
144
31.1M
      if (ret == NULL)
145
0
  return NULL;
146
147
31.1M
      chunk = (struct objalloc_chunk *) ret;
148
31.1M
      chunk->next = (struct objalloc_chunk *) o->chunks;
149
31.1M
      chunk->current_ptr = o->current_ptr;
150
151
31.1M
      o->chunks = (void *) chunk;
152
153
31.1M
      return (void *) (ret + CHUNK_HEADER_SIZE);
154
31.1M
    }
155
22.3M
  else
156
22.3M
    {
157
22.3M
      struct objalloc_chunk *chunk;
158
159
22.3M
      chunk = (struct objalloc_chunk *) malloc (CHUNK_SIZE);
160
22.3M
      if (chunk == NULL)
161
0
  return NULL;
162
22.3M
      chunk->next = (struct objalloc_chunk *) o->chunks;
163
22.3M
      chunk->current_ptr = NULL;
164
165
22.3M
      o->current_ptr = (char *) chunk + CHUNK_HEADER_SIZE;
166
22.3M
      o->current_space = CHUNK_SIZE - CHUNK_HEADER_SIZE;
167
168
22.3M
      o->chunks = (void *) chunk;
169
170
22.3M
      return objalloc_alloc (o, len);
171
22.3M
    }
172
53.5M
}
173
174
/* Free an entire objalloc structure.  */
175
176
void
177
objalloc_free (struct objalloc *o)
178
6.59M
{
179
6.59M
  struct objalloc_chunk *l;
180
181
6.59M
  l = (struct objalloc_chunk *) o->chunks;
182
47.8M
  while (l != NULL)
183
41.2M
    {
184
41.2M
      struct objalloc_chunk *next;
185
186
41.2M
      next = l->next;
187
41.2M
      free (l);
188
41.2M
      l = next;
189
41.2M
    }
190
191
6.59M
  free (o);
192
6.59M
}
193
194
/* Free a block from an objalloc structure.  This also frees all more
195
   recently allocated blocks.  */
196
197
void
198
objalloc_free_block (struct objalloc *o, void *block)
199
530M
{
200
530M
  struct objalloc_chunk *p, *small;
201
530M
  char *b = (char *) block;
202
203
  /* First set P to the chunk which contains the block we are freeing,
204
     and set Q to the last small object chunk we see before P.  */
205
530M
  small = NULL;
206
567M
  for (p = (struct objalloc_chunk *) o->chunks; p != NULL; p = p->next)
207
567M
    {
208
567M
      if (p->current_ptr == NULL)
209
535M
  {
210
535M
    if (b > (char *) p && b < (char *) p + CHUNK_SIZE)
211
530M
      break;
212
4.64M
    small = p;
213
4.64M
  }
214
32.1M
      else
215
32.1M
  {
216
32.1M
    if (b == (char *) p + CHUNK_HEADER_SIZE)
217
29.2k
      break;
218
32.1M
  }
219
567M
    }
220
221
  /* If we can't find the chunk, the caller has made a mistake.  */
222
530M
  if (p == NULL)
223
0
    abort ();
224
225
530M
  if (p->current_ptr == NULL)
226
530M
    {
227
530M
      struct objalloc_chunk *q;
228
530M
      struct objalloc_chunk *first;
229
230
      /* The block is in a chunk containing small objects.  We can
231
   free every chunk through SMALL, because they have certainly
232
   been allocated more recently.  After SMALL, we will not see
233
   any chunks containing small objects; we can free any big
234
   chunk if the current_ptr is greater than or equal to B.  We
235
   can then reset the new current_ptr to B.  */
236
237
530M
      first = NULL;
238
530M
      q = (struct objalloc_chunk *) o->chunks;
239
567M
      while (q != p)
240
36.7M
  {
241
36.7M
    struct objalloc_chunk *next;
242
243
36.7M
    next = q->next;
244
36.7M
    if (small != NULL)
245
10.3M
      {
246
10.3M
        if (small == q)
247
564k
    small = NULL;
248
10.3M
        free (q);
249
10.3M
      }
250
26.4M
    else if (q->current_ptr > b)
251
8.41M
      free (q);
252
18.0M
    else if (first == NULL)
253
14.5M
      first = q;
254
255
36.7M
    q = next;
256
36.7M
  }
257
258
530M
      if (first == NULL)
259
515M
  first = p;
260
530M
      o->chunks = (void *) first;
261
262
      /* Now start allocating from this small block again.  */
263
530M
      o->current_ptr = b;
264
530M
      o->current_space = ((char *) p + CHUNK_SIZE) - b;
265
530M
    }
266
29.2k
  else
267
29.2k
    {
268
29.2k
      struct objalloc_chunk *q;
269
29.2k
      char *current_ptr;
270
271
      /* This block is in a large chunk by itself.  We can free
272
         everything on the list up to and including this block.  We
273
         then start allocating from the next chunk containing small
274
         objects, setting current_ptr from the value stored with the
275
         large chunk we are freeing.  */
276
277
29.2k
      current_ptr = p->current_ptr;
278
29.2k
      p = p->next;
279
280
29.2k
      q = (struct objalloc_chunk *) o->chunks;
281
111k
      while (q != p)
282
82.5k
  {
283
82.5k
    struct objalloc_chunk *next;
284
285
82.5k
    next = q->next;
286
82.5k
    free (q);
287
82.5k
    q = next;
288
82.5k
  }
289
290
29.2k
      o->chunks = (void *) p;
291
292
51.4k
      while (p->current_ptr != NULL)
293
22.1k
  p = p->next;
294
295
29.2k
      o->current_ptr = current_ptr;
296
29.2k
      o->current_space = ((char *) p + CHUNK_SIZE) - current_ptr;
297
29.2k
    }
298
530M
}