Coverage Report

Created: 2025-07-08 11:15

/src/binutils-gdb/libiberty/objalloc.c
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/* objalloc.c -- routines to allocate memory for objects
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   Copyright (C) 1997-2025 Free Software Foundation, Inc.
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   Written by Ian Lance Taylor, Cygnus Solutions.
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This program is free software; you can redistribute it and/or modify it
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under the terms of the GNU General Public License as published by the
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Free Software Foundation; either version 2, or (at your option) any
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later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program; if not, write to the Free Software
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Foundation, 51 Franklin Street - Fifth Floor,
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Boston, MA 02110-1301, USA.  */
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#include "config.h"
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#include "ansidecl.h"
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#include "objalloc.h"
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/* Get a definition for NULL.  */
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#include <stdio.h>
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#if VMS
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#include <stdlib.h>
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#include <unixlib.h>
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#else
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/* Get a definition for size_t.  */
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#include <stddef.h>
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#ifdef HAVE_STDLIB_H
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#include <stdlib.h>
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#else
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/* For systems with larger pointers than ints, this must be declared.  */
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extern void *malloc (size_t);
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extern void free (void *);
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#endif
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#endif
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/* These routines allocate space for an object.  Freeing allocated
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   space may or may not free all more recently allocated space.
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   We handle large and small allocation requests differently.  If we
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   don't have enough space in the current block, and the allocation
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   request is for more than 512 bytes, we simply pass it through to
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   malloc.  */
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/* The objalloc structure is defined in objalloc.h.  */
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/* This structure appears at the start of each chunk.  */
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struct objalloc_chunk
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{
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  /* Next chunk.  */
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  struct objalloc_chunk *next;
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  /* If this chunk contains large objects, this is the value of
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     current_ptr when this chunk was allocated.  If this chunk
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     contains small objects, this is NULL.  */
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  char *current_ptr;
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};
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/* The aligned size of objalloc_chunk.  */
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#define CHUNK_HEADER_SIZE         \
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227M
  ((sizeof (struct objalloc_chunk) + OBJALLOC_ALIGN - 1) \
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227M
   &~ (OBJALLOC_ALIGN - 1))
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/* We ask for this much memory each time we create a chunk which is to
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   hold small objects.  */
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1.78G
#define CHUNK_SIZE (4096 - 32)
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/* A request for this amount or more is just passed through to malloc.  */
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56.2M
#define BIG_REQUEST (512)
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/* Create an objalloc structure.  */
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struct objalloc *
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objalloc_create (void)
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10.9M
{
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10.9M
  struct objalloc *ret;
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10.9M
  struct objalloc_chunk *chunk;
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10.9M
  ret = (struct objalloc *) malloc (sizeof *ret);
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10.9M
  if (ret == NULL)
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0
    return NULL;
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10.9M
  ret->chunks = (void *) malloc (CHUNK_SIZE);
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10.9M
  if (ret->chunks == NULL)
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0
    {
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0
      free (ret);
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0
      return NULL;
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0
    }
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10.9M
  chunk = (struct objalloc_chunk *) ret->chunks;
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10.9M
  chunk->next = NULL;
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10.9M
  chunk->current_ptr = NULL;
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10.9M
  ret->current_ptr = (char *) chunk + CHUNK_HEADER_SIZE;
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10.9M
  ret->current_space = CHUNK_SIZE - CHUNK_HEADER_SIZE;
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10.9M
  return ret;
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10.9M
}
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/* Allocate space from an objalloc structure.  */
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void *
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_objalloc_alloc (struct objalloc *o, unsigned long original_len)
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56.2M
{
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56.2M
  unsigned long len = original_len;
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  /* We avoid confusion from zero sized objects by always allocating
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     at least 1 byte.  */
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56.2M
  if (len == 0)
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0
    len = 1;
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56.2M
  len = (len + OBJALLOC_ALIGN - 1) &~ (OBJALLOC_ALIGN - 1);
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  /* Check for overflow in the alignment operation above and the
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     malloc argument below. */
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56.2M
  if (len + CHUNK_HEADER_SIZE < original_len)
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0
    return NULL;
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56.2M
  if (len <= o->current_space)
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0
    {
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0
      o->current_ptr += len;
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0
      o->current_space -= len;
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0
      return (void *) (o->current_ptr - len);
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0
    }
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56.2M
  if (len >= BIG_REQUEST)
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36.1M
    {
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36.1M
      char *ret;
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36.1M
      struct objalloc_chunk *chunk;
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36.1M
      ret = (char *) malloc (CHUNK_HEADER_SIZE + len);
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36.1M
      if (ret == NULL)
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0
  return NULL;
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36.1M
      chunk = (struct objalloc_chunk *) ret;
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36.1M
      chunk->next = (struct objalloc_chunk *) o->chunks;
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36.1M
      chunk->current_ptr = o->current_ptr;
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36.1M
      o->chunks = (void *) chunk;
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36.1M
      return (void *) (ret + CHUNK_HEADER_SIZE);
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36.1M
    }
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20.0M
  else
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20.0M
    {
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20.0M
      struct objalloc_chunk *chunk;
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20.0M
      chunk = (struct objalloc_chunk *) malloc (CHUNK_SIZE);
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20.0M
      if (chunk == NULL)
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0
  return NULL;
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20.0M
      chunk->next = (struct objalloc_chunk *) o->chunks;
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20.0M
      chunk->current_ptr = NULL;
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20.0M
      o->current_ptr = (char *) chunk + CHUNK_HEADER_SIZE;
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20.0M
      o->current_space = CHUNK_SIZE - CHUNK_HEADER_SIZE;
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20.0M
      o->chunks = (void *) chunk;
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20.0M
      return objalloc_alloc (o, len);
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20.0M
    }
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56.2M
}
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/* Free an entire objalloc structure.  */
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void
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objalloc_free (struct objalloc *o)
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10.9M
{
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10.9M
  struct objalloc_chunk *l;
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10.9M
  l = (struct objalloc_chunk *) o->chunks;
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56.9M
  while (l != NULL)
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45.9M
    {
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45.9M
      struct objalloc_chunk *next;
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45.9M
      next = l->next;
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45.9M
      free (l);
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45.9M
      l = next;
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45.9M
    }
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10.9M
  free (o);
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10.9M
}
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/* Free a block from an objalloc structure.  This also frees all more
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   recently allocated blocks.  */
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void
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objalloc_free_block (struct objalloc *o, void *block)
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862M
{
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862M
  struct objalloc_chunk *p, *small;
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862M
  char *b = (char *) block;
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  /* First set P to the chunk which contains the block we are freeing,
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     and set Q to the last small object chunk we see before P.  */
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862M
  small = NULL;
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902M
  for (p = (struct objalloc_chunk *) o->chunks; p != NULL; p = p->next)
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902M
    {
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902M
      if (p->current_ptr == NULL)
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865M
  {
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865M
    if (b > (char *) p && b < (char *) p + CHUNK_SIZE)
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862M
      break;
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3.72M
    small = p;
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3.72M
  }
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37.1M
      else
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37.1M
  {
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37.1M
    if (b == (char *) p + CHUNK_HEADER_SIZE)
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34.3k
      break;
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37.1M
  }
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902M
    }
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  /* If we can't find the chunk, the caller has made a mistake.  */
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862M
  if (p == NULL)
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0
    abort ();
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862M
  if (p->current_ptr == NULL)
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862M
    {
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862M
      struct objalloc_chunk *q;
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862M
      struct objalloc_chunk *first;
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      /* The block is in a chunk containing small objects.  We can
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   free every chunk through SMALL, because they have certainly
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   been allocated more recently.  After SMALL, we will not see
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   any chunks containing small objects; we can free any big
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   chunk if the current_ptr is greater than or equal to B.  We
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   can then reset the new current_ptr to B.  */
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862M
      first = NULL;
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862M
      q = (struct objalloc_chunk *) o->chunks;
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902M
      while (q != p)
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40.7M
  {
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40.7M
    struct objalloc_chunk *next;
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40.7M
    next = q->next;
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40.7M
    if (small != NULL)
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7.22M
      {
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7.22M
        if (small == q)
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861k
    small = NULL;
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7.22M
        free (q);
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7.22M
      }
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33.5M
    else if (q->current_ptr > b)
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13.9M
      free (q);
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19.5M
    else if (first == NULL)
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14.7M
      first = q;
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40.7M
    q = next;
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40.7M
  }
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862M
      if (first == NULL)
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847M
  first = p;
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862M
      o->chunks = (void *) first;
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      /* Now start allocating from this small block again.  */
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862M
      o->current_ptr = b;
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862M
      o->current_space = ((char *) p + CHUNK_SIZE) - b;
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862M
    }
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34.3k
  else
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34.3k
    {
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34.3k
      struct objalloc_chunk *q;
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34.3k
      char *current_ptr;
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      /* This block is in a large chunk by itself.  We can free
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         everything on the list up to and including this block.  We
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         then start allocating from the next chunk containing small
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         objects, setting current_ptr from the value stored with the
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         large chunk we are freeing.  */
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34.3k
      current_ptr = p->current_ptr;
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34.3k
      p = p->next;
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34.3k
      q = (struct objalloc_chunk *) o->chunks;
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134k
      while (q != p)
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100k
  {
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100k
    struct objalloc_chunk *next;
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100k
    next = q->next;
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100k
    free (q);
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100k
    q = next;
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100k
  }
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34.3k
      o->chunks = (void *) p;
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60.3k
      while (p->current_ptr != NULL)
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26.0k
  p = p->next;
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34.3k
      o->current_ptr = current_ptr;
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34.3k
      o->current_space = ((char *) p + CHUNK_SIZE) - current_ptr;
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34.3k
    }
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862M
}