Coverage Report

Created: 2026-03-07 06:56

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython3/Python/dtoa.c
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Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
60
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
2.20M
#define word0(x) (x)->L[1]
181
1.20M
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
3.83M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
158k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
189k
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
1.12M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
384k
#define Exp_shift  20
235
57.7k
#define Exp_shift1 20
236
1.05M
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
899k
#define Exp_mask  0x7ff00000
239
729k
#define P 53
240
#define Nbits 53
241
268k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
955k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
319k
#define Exp_1  0x3ff00000
246
24.0k
#define Exp_11 0x3ff00000
247
540k
#define Ebits 11
248
301k
#define Frac_mask  0xfffff
249
33.1k
#define Frac_mask1 0xfffff
250
258k
#define Ten_pmax 22
251
0
#define Bletch 0x10
252
188k
#define Bndry_mask  0xfffff
253
17.0k
#define Bndry_mask1 0xfffff
254
32.3k
#define Sign_bit 0x80000000
255
7.15k
#define Log2P 1
256
#define Tiny0 0
257
20.3k
#define Tiny1 1
258
28.8k
#define Quick_max 14
259
13.5k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
312k
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
14.9k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
9.08k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
34.9M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
12.1M
#define freelist interp->dtoa.freelist
336
296
#define private_mem interp->dtoa.preallocated
337
768
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
3.04M
{
344
3.04M
    int x;
345
3.04M
    Bigint *rv;
346
3.04M
    unsigned int len;
347
3.04M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
3.04M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
3.04M
        freelist[k] = rv->next;
351
296
    else {
352
296
        x = 1 << k;
353
296
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
296
            /sizeof(double);
355
296
        if (k <= Bigint_Kmax &&
356
296
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
296
        ) {
358
236
            rv = (Bigint*)pmem_next;
359
236
            pmem_next += len;
360
236
        }
361
60
        else {
362
60
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
60
            if (rv == NULL)
364
0
                return NULL;
365
60
        }
366
296
        rv->k = k;
367
296
        rv->maxwds = x;
368
296
    }
369
3.04M
    rv->sign = rv->wds = 0;
370
3.04M
    return rv;
371
3.04M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
4.14M
{
378
4.14M
    if (v) {
379
3.04M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
3.04M
        else {
382
3.04M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
3.04M
            v->next = freelist[v->k];
384
3.04M
            freelist[v->k] = v;
385
3.04M
        }
386
3.04M
    }
387
4.14M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
257k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
257k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
1.38M
{
445
1.38M
    int i, wds;
446
1.38M
    ULong *x;
447
1.38M
    ULLong carry, y;
448
1.38M
    Bigint *b1;
449
450
1.38M
    wds = b->wds;
451
1.38M
    x = b->x;
452
1.38M
    i = 0;
453
1.38M
    carry = a;
454
4.09M
    do {
455
4.09M
        y = *x * (ULLong)m + carry;
456
4.09M
        carry = y >> 32;
457
4.09M
        *x++ = (ULong)(y & FFFFFFFF);
458
4.09M
    }
459
4.09M
    while(++i < wds);
460
1.38M
    if (carry) {
461
103k
        if (wds >= b->maxwds) {
462
1.81k
            b1 = Balloc(b->k+1);
463
1.81k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
1.81k
            Bcopy(b1, b);
468
1.81k
            Bfree(b);
469
1.81k
            b = b1;
470
1.81k
        }
471
103k
        b->x[wds++] = (ULong)carry;
472
103k
        b->wds = wds;
473
103k
    }
474
1.38M
    return b;
475
1.38M
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
158k
{
486
158k
    Bigint *b;
487
158k
    int i, k;
488
158k
    Long x, y;
489
490
158k
    x = (nd + 8) / 9;
491
252k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
158k
    b = Balloc(k);
493
158k
    if (b == NULL)
494
0
        return NULL;
495
158k
    b->x[0] = y9;
496
158k
    b->wds = 1;
497
498
158k
    if (nd <= 9)
499
89.3k
      return b;
500
501
68.9k
    s += 9;
502
616k
    for (i = 9; i < nd0; i++) {
503
547k
        b = multadd(b, 10, *s++ - '0');
504
547k
        if (b == NULL)
505
0
            return NULL;
506
547k
    }
507
68.9k
    s++;
508
234k
    for(; i < nd; i++) {
509
165k
        b = multadd(b, 10, *s++ - '0');
510
165k
        if (b == NULL)
511
0
            return NULL;
512
165k
    }
513
68.9k
    return b;
514
68.9k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
287k
{
521
287k
    int k = 0;
522
523
287k
    if (!(x & 0xffff0000)) {
524
223k
        k = 16;
525
223k
        x <<= 16;
526
223k
    }
527
287k
    if (!(x & 0xff000000)) {
528
217k
        k += 8;
529
217k
        x <<= 8;
530
217k
    }
531
287k
    if (!(x & 0xf0000000)) {
532
215k
        k += 4;
533
215k
        x <<= 4;
534
215k
    }
535
287k
    if (!(x & 0xc0000000)) {
536
126k
        k += 2;
537
126k
        x <<= 2;
538
126k
    }
539
287k
    if (!(x & 0x80000000)) {
540
223k
        k++;
541
223k
        if (!(x & 0x40000000))
542
0
            return 32;
543
223k
    }
544
287k
    return k;
545
287k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
28.8k
{
553
28.8k
    int k;
554
28.8k
    ULong x = *y;
555
556
28.8k
    if (x & 7) {
557
16.2k
        if (x & 1)
558
6.85k
            return 0;
559
9.42k
        if (x & 2) {
560
7.28k
            *y = x >> 1;
561
7.28k
            return 1;
562
7.28k
        }
563
2.14k
        *y = x >> 2;
564
2.14k
        return 2;
565
9.42k
    }
566
12.5k
    k = 0;
567
12.5k
    if (!(x & 0xffff)) {
568
6.83k
        k = 16;
569
6.83k
        x >>= 16;
570
6.83k
    }
571
12.5k
    if (!(x & 0xff)) {
572
2.57k
        k += 8;
573
2.57k
        x >>= 8;
574
2.57k
    }
575
12.5k
    if (!(x & 0xf)) {
576
4.94k
        k += 4;
577
4.94k
        x >>= 4;
578
4.94k
    }
579
12.5k
    if (!(x & 0x3)) {
580
6.22k
        k += 2;
581
6.22k
        x >>= 2;
582
6.22k
    }
583
12.5k
    if (!(x & 1)) {
584
7.01k
        k++;
585
7.01k
        x >>= 1;
586
7.01k
        if (!x)
587
0
            return 32;
588
7.01k
    }
589
12.5k
    *y = x;
590
12.5k
    return k;
591
12.5k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
313k
{
598
313k
    Bigint *b;
599
600
313k
    b = Balloc(1);
601
313k
    if (b == NULL)
602
0
        return NULL;
603
313k
    b->x[0] = i;
604
313k
    b->wds = 1;
605
313k
    return b;
606
313k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
1.03M
{
614
1.03M
    Bigint *c;
615
1.03M
    int k, wa, wb, wc;
616
1.03M
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
1.03M
    ULong y;
618
1.03M
    ULLong carry, z;
619
620
1.03M
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
3.96k
        c = Balloc(0);
622
3.96k
        if (c == NULL)
623
0
            return NULL;
624
3.96k
        c->wds = 1;
625
3.96k
        c->x[0] = 0;
626
3.96k
        return c;
627
3.96k
    }
628
629
1.02M
    if (a->wds < b->wds) {
630
326k
        c = a;
631
326k
        a = b;
632
326k
        b = c;
633
326k
    }
634
1.02M
    k = a->k;
635
1.02M
    wa = a->wds;
636
1.02M
    wb = b->wds;
637
1.02M
    wc = wa + wb;
638
1.02M
    if (wc > a->maxwds)
639
374k
        k++;
640
1.02M
    c = Balloc(k);
641
1.02M
    if (c == NULL)
642
0
        return NULL;
643
11.1M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
10.1M
        *x = 0;
645
1.02M
    xa = a->x;
646
1.02M
    xae = xa + wa;
647
1.02M
    xb = b->x;
648
1.02M
    xbe = xb + wb;
649
1.02M
    xc0 = c->x;
650
3.20M
    for(; xb < xbe; xc0++) {
651
2.17M
        if ((y = *xb++)) {
652
2.16M
            x = xa;
653
2.16M
            xc = xc0;
654
2.16M
            carry = 0;
655
22.7M
            do {
656
22.7M
                z = *x++ * (ULLong)y + *xc + carry;
657
22.7M
                carry = z >> 32;
658
22.7M
                *xc++ = (ULong)(z & FFFFFFFF);
659
22.7M
            }
660
22.7M
            while(x < xae);
661
2.16M
            *xc = (ULong)carry;
662
2.16M
        }
663
2.17M
    }
664
1.72M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
1.02M
    c->wds = wc;
666
1.02M
    return c;
667
1.02M
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
246k
{
678
246k
    Bigint *b1, *p5, **p5s;
679
246k
    int i;
680
246k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
246k
    assert(0 <= k && k < 1024);
688
689
246k
    if ((i = k & 3)) {
690
215k
        b = multadd(b, p05[i-1], 0);
691
215k
        if (b == NULL)
692
0
            return NULL;
693
215k
    }
694
695
246k
    if (!(k >>= 2))
696
11.4k
        return b;
697
235k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
235k
    p5s = interp->dtoa.p5s;
699
1.37M
    for(;;) {
700
1.37M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
1.37M
        p5 = *p5s;
702
1.37M
        p5s++;
703
1.37M
        if (k & 1) {
704
853k
            b1 = mult(b, p5);
705
853k
            Bfree(b);
706
853k
            b = b1;
707
853k
            if (b == NULL)
708
0
                return NULL;
709
853k
        }
710
1.37M
        if (!(k >>= 1))
711
235k
            break;
712
1.37M
    }
713
235k
    return b;
714
235k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
602k
{
775
602k
    int i, k1, n, n1;
776
602k
    Bigint *b1;
777
602k
    ULong *x, *x1, *xe, z;
778
779
602k
    if (!k || (!b->x[0] && b->wds == 1))
780
4.67k
        return b;
781
782
598k
    n = k >> 5;
783
598k
    k1 = b->k;
784
598k
    n1 = n + b->wds + 1;
785
1.65M
    for(i = b->maxwds; n1 > i; i <<= 1)
786
1.05M
        k1++;
787
598k
    b1 = Balloc(k1);
788
598k
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
598k
    x1 = b1->x;
793
4.73M
    for(i = 0; i < n; i++)
794
4.13M
        *x1++ = 0;
795
598k
    x = b->x;
796
598k
    xe = x + b->wds;
797
598k
    if (k &= 0x1f) {
798
594k
        k1 = 32 - k;
799
594k
        z = 0;
800
4.37M
        do {
801
4.37M
            *x1++ = *x << k | z;
802
4.37M
            z = *x++ >> k1;
803
4.37M
        }
804
4.37M
        while(x < xe);
805
594k
        if ((*x1 = z))
806
65.0k
            ++n1;
807
594k
    }
808
3.55k
    else do
809
10.1k
             *x1++ = *x++;
810
10.1k
        while(x < xe);
811
598k
    b1->wds = n1 - 1;
812
598k
    Bfree(b);
813
598k
    return b1;
814
598k
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
1.20M
{
822
1.20M
    ULong *xa, *xa0, *xb, *xb0;
823
1.20M
    int i, j;
824
825
1.20M
    i = a->wds;
826
1.20M
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
1.20M
    if (i -= j)
834
148k
        return i;
835
1.05M
    xa0 = a->x;
836
1.05M
    xa = xa0 + j;
837
1.05M
    xb0 = b->x;
838
1.05M
    xb = xb0 + j;
839
1.31M
    for(;;) {
840
1.31M
        if (*--xa != *--xb)
841
1.02M
            return *xa < *xb ? -1 : 1;
842
289k
        if (xa <= xa0)
843
32.8k
            break;
844
289k
    }
845
32.8k
    return 0;
846
1.05M
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
348k
{
855
348k
    Bigint *c;
856
348k
    int i, wa, wb;
857
348k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
348k
    ULLong borrow, y;
859
860
348k
    i = cmp(a,b);
861
348k
    if (!i) {
862
4.21k
        c = Balloc(0);
863
4.21k
        if (c == NULL)
864
0
            return NULL;
865
4.21k
        c->wds = 1;
866
4.21k
        c->x[0] = 0;
867
4.21k
        return c;
868
4.21k
    }
869
344k
    if (i < 0) {
870
141k
        c = a;
871
141k
        a = b;
872
141k
        b = c;
873
141k
        i = 1;
874
141k
    }
875
202k
    else
876
202k
        i = 0;
877
344k
    c = Balloc(a->k);
878
344k
    if (c == NULL)
879
0
        return NULL;
880
344k
    c->sign = i;
881
344k
    wa = a->wds;
882
344k
    xa = a->x;
883
344k
    xae = xa + wa;
884
344k
    wb = b->wds;
885
344k
    xb = b->x;
886
344k
    xbe = xb + wb;
887
344k
    xc = c->x;
888
344k
    borrow = 0;
889
4.41M
    do {
890
4.41M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
4.41M
        borrow = y >> 32 & (ULong)1;
892
4.41M
        *xc++ = (ULong)(y & FFFFFFFF);
893
4.41M
    }
894
4.41M
    while(xb < xbe);
895
510k
    while(xa < xae) {
896
166k
        y = *xa++ - borrow;
897
166k
        borrow = y >> 32 & (ULong)1;
898
166k
        *xc++ = (ULong)(y & FFFFFFFF);
899
166k
    }
900
546k
    while(!*--xc)
901
202k
        wa--;
902
344k
    c->wds = wa;
903
344k
    return c;
904
344k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
138k
{
912
138k
    Long L;
913
138k
    U u;
914
915
138k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
138k
    word0(&u) = L;
917
138k
    word1(&u) = 0;
918
138k
    return dval(&u);
919
138k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
244k
{
926
244k
    ULong *xa, *xa0, w, y, z;
927
244k
    int k;
928
244k
    U d;
929
930
244k
    xa0 = a->x;
931
244k
    xa = xa0 + a->wds;
932
244k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
244k
    k = hi0bits(y);
937
244k
    *e = 32 - k;
938
244k
    if (k < Ebits) {
939
25.7k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
25.7k
        w = xa > xa0 ? *--xa : 0;
941
25.7k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
25.7k
        goto ret_d;
943
25.7k
    }
944
218k
    z = xa > xa0 ? *--xa : 0;
945
218k
    if (k -= Ebits) {
946
204k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
204k
        y = xa > xa0 ? *--xa : 0;
948
204k
        word1(&d) = z << k | y >> (32 - k);
949
204k
    }
950
13.9k
    else {
951
13.9k
        word0(&d) = Exp_1 | y;
952
13.9k
        word1(&d) = z;
953
13.9k
    }
954
244k
  ret_d:
955
244k
    return dval(&d);
956
218k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
272k
{
982
272k
    Bigint *b;
983
984
272k
    b = Balloc(1);
985
272k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
272k
    b->wds = 2;
990
272k
    b->x[0] = word1(d);
991
272k
    b->x[1] = word0(d) & Frac_mask;
992
272k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
272k
    if (*e < Etiny)
994
4.67k
        *e = Etiny;
995
267k
    else
996
267k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
272k
    if (scale && (b->x[0] || b->x[1])) {
1000
139k
        *e -= scale;
1001
139k
        if (*e < Etiny) {
1002
133k
            scale = Etiny - *e;
1003
133k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
133k
            assert(0 < scale && scale <= P - 1);
1006
133k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
124k
                assert(b->x[0] == 0);
1009
124k
                b->x[0] = b->x[1];
1010
124k
                b->x[1] = 0;
1011
124k
                scale -= 32;
1012
124k
            }
1013
133k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
39.4k
                assert(b->x[0] << (32 - scale) == 0);
1016
39.4k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
39.4k
                b->x[1] >>= scale;
1018
39.4k
            }
1019
133k
        }
1020
139k
    }
1021
    /* Ensure b is normalized. */
1022
272k
    if (!b->x[1])
1023
129k
        b->wds = 1;
1024
1025
272k
    return b;
1026
272k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
28.8k
{
1040
28.8k
    Bigint *b;
1041
28.8k
    int de, k;
1042
28.8k
    ULong *x, y, z;
1043
28.8k
    int i;
1044
1045
28.8k
    b = Balloc(1);
1046
28.8k
    if (b == NULL)
1047
0
        return NULL;
1048
28.8k
    x = b->x;
1049
1050
28.8k
    z = word0(d) & Frac_mask;
1051
28.8k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
28.8k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
24.0k
        z |= Exp_msk1;
1054
28.8k
    if ((y = word1(d))) {
1055
20.6k
        if ((k = lo0bits(&y))) {
1056
14.1k
            x[0] = y | z << (32 - k);
1057
14.1k
            z >>= k;
1058
14.1k
        }
1059
6.54k
        else
1060
6.54k
            x[0] = y;
1061
20.6k
        i =
1062
20.6k
            b->wds = (x[1] = z) ? 2 : 1;
1063
20.6k
    }
1064
8.18k
    else {
1065
8.18k
        k = lo0bits(&z);
1066
8.18k
        x[0] = z;
1067
8.18k
        i =
1068
8.18k
            b->wds = 1;
1069
8.18k
        k += 32;
1070
8.18k
    }
1071
28.8k
    if (de) {
1072
24.0k
        *e = de - Bias - (P-1) + k;
1073
24.0k
        *bits = P - k;
1074
24.0k
    }
1075
4.76k
    else {
1076
4.76k
        *e = de - Bias - (P-1) + 1 + k;
1077
4.76k
        *bits = 32*i - hi0bits(x[i-1]);
1078
4.76k
    }
1079
28.8k
    return b;
1080
28.8k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
122k
{
1088
122k
    U da, db;
1089
122k
    int k, ka, kb;
1090
1091
122k
    dval(&da) = b2d(a, &ka);
1092
122k
    dval(&db) = b2d(b, &kb);
1093
122k
    k = ka - kb + 32*(a->wds - b->wds);
1094
122k
    if (k > 0)
1095
43.9k
        word0(&da) += k*Exp_msk1;
1096
78.3k
    else {
1097
78.3k
        k = -k;
1098
78.3k
        word0(&db) += k*Exp_msk1;
1099
78.3k
    }
1100
122k
    return dval(&da) / dval(&db);
1101
122k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
82.0k
#define Scale_Bit 0x10
1119
93.2k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
38.4k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
38.4k
{
1129
38.4k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
38.4k
    if (p2 > 0)
1131
24.3k
        rv -= p2;
1132
38.4k
    return rv & kmask;
1133
38.4k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
392k
{
1142
392k
    int n;
1143
392k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
392k
    ULLong borrow, carry, y, ys;
1145
1146
392k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
392k
    if (b->wds < n)
1152
11.5k
        return 0;
1153
381k
    sx = S->x;
1154
381k
    sxe = sx + --n;
1155
381k
    bx = b->x;
1156
381k
    bxe = bx + n;
1157
381k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
381k
    if (q) {
1163
292k
        borrow = 0;
1164
292k
        carry = 0;
1165
1.67M
        do {
1166
1.67M
            ys = *sx++ * (ULLong)q + carry;
1167
1.67M
            carry = ys >> 32;
1168
1.67M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
1.67M
            borrow = y >> 32 & (ULong)1;
1170
1.67M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
1.67M
        }
1172
1.67M
        while(sx <= sxe);
1173
292k
        if (!*bxe) {
1174
1.09k
            bx = b->x;
1175
1.09k
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
1.09k
            b->wds = n;
1178
1.09k
        }
1179
292k
    }
1180
381k
    if (cmp(b, S) >= 0) {
1181
14.4k
        q++;
1182
14.4k
        borrow = 0;
1183
14.4k
        carry = 0;
1184
14.4k
        bx = b->x;
1185
14.4k
        sx = S->x;
1186
63.1k
        do {
1187
63.1k
            ys = *sx++ + carry;
1188
63.1k
            carry = ys >> 32;
1189
63.1k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
63.1k
            borrow = y >> 32 & (ULong)1;
1191
63.1k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
63.1k
        }
1193
63.1k
        while(sx <= sxe);
1194
14.4k
        bx = b->x;
1195
14.4k
        bxe = bx + n;
1196
14.4k
        if (!*bxe) {
1197
14.2k
            while(--bxe > bx && !*bxe)
1198
1.07k
                --n;
1199
13.1k
            b->wds = n;
1200
13.1k
        }
1201
14.4k
    }
1202
381k
    return q;
1203
392k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
17.0k
{
1214
17.0k
    U u;
1215
1216
17.0k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
574
        word0(&u) = (P+2)*Exp_msk1;
1219
574
        word1(&u) = 0;
1220
574
        return u.d;
1221
574
    }
1222
16.4k
    else {
1223
16.4k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
16.4k
        return ulp(x);
1225
16.4k
    }
1226
17.0k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
17.7k
{
1277
17.7k
    Bigint *b, *d;
1278
17.7k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
17.7k
    nd = bc->nd;
1281
17.7k
    nd0 = bc->nd0;
1282
17.7k
    p5 = nd + bc->e0;
1283
17.7k
    b = sd2b(rv, bc->scale, &p2);
1284
17.7k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
17.7k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
17.7k
    b = lshift(b, 1);
1294
17.7k
    if (b == NULL)
1295
0
        return -1;
1296
17.7k
    b->x[0] |= 1;
1297
17.7k
    p2--;
1298
1299
17.7k
    p2 -= p5;
1300
17.7k
    d = i2b(1);
1301
17.7k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
17.7k
    if (p5 > 0) {
1309
14.5k
        d = pow5mult(d, p5);
1310
14.5k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
14.5k
    }
1315
3.23k
    else if (p5 < 0) {
1316
2.52k
        b = pow5mult(b, -p5);
1317
2.52k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
2.52k
    }
1322
17.7k
    if (p2 > 0) {
1323
10.8k
        b2 = p2;
1324
10.8k
        d2 = 0;
1325
10.8k
    }
1326
6.95k
    else {
1327
6.95k
        b2 = 0;
1328
6.95k
        d2 = -p2;
1329
6.95k
    }
1330
17.7k
    i = dshift(d, d2);
1331
17.7k
    if ((b2 += i) > 0) {
1332
17.4k
        b = lshift(b, b2);
1333
17.4k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
17.4k
    }
1338
17.7k
    if ((d2 += i) > 0) {
1339
15.9k
        d = lshift(d, d2);
1340
15.9k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
15.9k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
17.7k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
1.28k
        dd = -1;
1352
16.4k
    else {
1353
16.4k
        i = 0;
1354
299k
        for(;;) {
1355
299k
            b = multadd(b, 10, 0);
1356
299k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
299k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
299k
            i++;
1362
1363
299k
            if (dd)
1364
14.6k
                break;
1365
284k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
1.65k
                dd = i < nd;
1368
1.65k
                break;
1369
1.65k
            }
1370
283k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
204
                dd = -1;
1373
204
                break;
1374
204
            }
1375
283k
        }
1376
16.4k
    }
1377
17.7k
    Bfree(b);
1378
17.7k
    Bfree(d);
1379
17.7k
    if (dd > 0 || (dd == 0 && odd))
1380
8.27k
        dval(rv) += sulp(rv, bc);
1381
17.7k
    return 0;
1382
17.7k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
378k
{
1388
378k
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
378k
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
378k
    const char *s, *s0, *s1;
1391
378k
    double aadj, aadj1;
1392
378k
    U aadj2, adj, rv, rv0;
1393
378k
    ULong y, z, abs_exp;
1394
378k
    Long L;
1395
378k
    BCinfo bc;
1396
378k
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
378k
    size_t ndigits, fraclen;
1398
378k
    double result;
1399
1400
378k
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
378k
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
378k
    sign = 0;
1407
378k
    switch (c) {
1408
8.81k
    case '-':
1409
8.81k
        sign = 1;
1410
8.81k
        _Py_FALLTHROUGH;
1411
8.82k
    case '+':
1412
8.82k
        c = *++s;
1413
378k
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
378k
    s1 = s;
1417
420k
    while (c == '0')
1418
42.4k
        c = *++s;
1419
378k
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
378k
    s0 = s1 = s;
1426
16.5M
    while ('0' <= c && c <= '9')
1427
16.1M
        c = *++s;
1428
378k
    ndigits = s - s1;
1429
378k
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
378k
    if (c == '.') {
1433
129k
        c = *++s;
1434
129k
        if (!ndigits) {
1435
34.6k
            s1 = s;
1436
1.23M
            while (c == '0')
1437
1.20M
                c = *++s;
1438
34.6k
            lz = lz || s != s1;
1439
34.6k
            fraclen += (s - s1);
1440
34.6k
            s0 = s;
1441
34.6k
        }
1442
129k
        s1 = s;
1443
24.8M
        while ('0' <= c && c <= '9')
1444
24.6M
            c = *++s;
1445
129k
        ndigits += s - s1;
1446
129k
        fraclen += s - s1;
1447
129k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
378k
    if (!ndigits && !lz) {
1453
1.68k
        if (se)
1454
1.68k
            *se = (char *)s00;
1455
1.68k
        goto parse_error;
1456
1.68k
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
376k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
376k
    nd = (int)ndigits;
1466
376k
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
376k
    e = 0;
1470
376k
    if (c == 'e' || c == 'E') {
1471
189k
        s00 = s;
1472
189k
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
189k
        esign = 0;
1476
189k
        switch (c) {
1477
100k
        case '-':
1478
100k
            esign = 1;
1479
100k
            _Py_FALLTHROUGH;
1480
102k
        case '+':
1481
102k
            c = *++s;
1482
189k
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
189k
        s1 = s;
1486
255k
        while (c == '0')
1487
65.8k
            c = *++s;
1488
189k
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
189k
        s1 = s;
1492
189k
        abs_exp = 0;
1493
4.15M
        while ('0' <= c && c <= '9') {
1494
3.96M
            abs_exp = 10*abs_exp + (c - '0');
1495
3.96M
            c = *++s;
1496
3.96M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
189k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
4.50k
            e = (int)MAX_ABS_EXP;
1503
185k
        else
1504
185k
            e = (int)abs_exp;
1505
189k
        if (esign)
1506
100k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
189k
        if (s == s1 && !lz)
1510
20
            s = s00;
1511
189k
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
376k
    e -= nd - nd0;
1515
376k
    if (nd0 <= 0)
1516
48.5k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
376k
    if (se)
1520
376k
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
376k
    if (!nd)
1525
23.1k
        goto ret;
1526
6.02M
    for (i = nd; i > 0; ) {
1527
6.02M
        --i;
1528
6.02M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
353k
            ++i;
1530
353k
            break;
1531
353k
        }
1532
6.02M
    }
1533
353k
    e += nd - i;
1534
353k
    nd = i;
1535
353k
    if (nd0 > nd)
1536
13.0k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
353k
    bc.e0 = e1 = e;
1575
353k
    y = z = 0;
1576
2.30M
    for (i = 0; i < nd; i++) {
1577
2.02M
        if (i < 9)
1578
1.35M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
667k
        else if (i < DBL_DIG+1)
1580
602k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
65.3k
        else
1582
65.3k
            break;
1583
2.02M
    }
1584
1585
353k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
353k
    dval(&rv) = y;
1587
353k
    if (k > 9) {
1588
97.8k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
97.8k
    }
1590
353k
    if (nd <= DBL_DIG
1591
280k
        && Flt_Rounds == 1
1592
353k
        ) {
1593
280k
        if (!e)
1594
75.8k
            goto ret;
1595
204k
        if (e > 0) {
1596
54.8k
            if (e <= Ten_pmax) {
1597
19.2k
                dval(&rv) *= tens[e];
1598
19.2k
                goto ret;
1599
19.2k
            }
1600
35.5k
            i = DBL_DIG - nd;
1601
35.5k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
3.36k
                e -= i;
1606
3.36k
                dval(&rv) *= tens[i];
1607
3.36k
                dval(&rv) *= tens[e];
1608
3.36k
                goto ret;
1609
3.36k
            }
1610
35.5k
        }
1611
150k
        else if (e >= -Ten_pmax) {
1612
64.8k
            dval(&rv) /= tens[-e];
1613
64.8k
            goto ret;
1614
64.8k
        }
1615
204k
    }
1616
190k
    e1 += nd - k;
1617
1618
190k
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
190k
    if (e1 > 0) {
1623
80.7k
        if ((i = e1 & 15))
1624
77.1k
            dval(&rv) *= tens[i];
1625
80.7k
        if (e1 &= ~15) {
1626
51.5k
            if (e1 > DBL_MAX_10_EXP)
1627
19.4k
                goto ovfl;
1628
32.1k
            e1 >>= 4;
1629
90.2k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
58.0k
                if (e1 & 1)
1631
23.7k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
32.1k
            word0(&rv) -= P*Exp_msk1;
1634
32.1k
            dval(&rv) *= bigtens[j];
1635
32.1k
            if ((z = word0(&rv) & Exp_mask)
1636
32.1k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
1.34k
                goto ovfl;
1638
30.7k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
460
                word0(&rv) = Big0;
1642
460
                word1(&rv) = Big1;
1643
460
            }
1644
30.3k
            else
1645
30.3k
                word0(&rv) += P*Exp_msk1;
1646
30.7k
        }
1647
80.7k
    }
1648
109k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
104k
        e1 = -e1;
1660
104k
        if ((i = e1 & 15))
1661
96.9k
            dval(&rv) /= tens[i];
1662
104k
        if (e1 >>= 4) {
1663
93.2k
            if (e1 >= 1 << n_bigtens)
1664
11.1k
                goto undfl;
1665
82.0k
            if (e1 & Scale_Bit)
1666
74.8k
                bc.scale = 2*P;
1667
468k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
386k
                if (e1 & 1)
1669
220k
                    dval(&rv) *= tinytens[j];
1670
82.0k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
74.8k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
71.5k
                if (j >= 32) {
1674
66.4k
                    word1(&rv) = 0;
1675
66.4k
                    if (j >= 53)
1676
4.37k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
62.0k
                    else
1678
62.0k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
66.4k
                }
1680
5.09k
                else
1681
5.09k
                    word1(&rv) &= 0xffffffff << j;
1682
71.5k
            }
1683
82.0k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
82.0k
        }
1686
104k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
158k
    bc.nd = nd;
1693
158k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
158k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
92.5k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
92.5k
            --i;
1708
92.5k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
21.4k
                ++i;
1710
21.4k
                break;
1711
21.4k
            }
1712
92.5k
        }
1713
21.4k
        e += nd - i;
1714
21.4k
        nd = i;
1715
21.4k
        if (nd0 > nd)
1716
13.7k
            nd0 = nd;
1717
21.4k
        if (nd < 9) { /* must recompute y */
1718
4.19k
            y = 0;
1719
18.3k
            for(i = 0; i < nd0; ++i)
1720
14.1k
                y = 10*y + s0[i] - '0';
1721
13.1k
            for(; i < nd; ++i)
1722
8.96k
                y = 10*y + s0[i+1] - '0';
1723
4.19k
        }
1724
21.4k
    }
1725
158k
    bd0 = s2b(s0, nd0, nd, y);
1726
158k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
254k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
254k
        bd = Balloc(bd0->k);
1758
254k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
254k
        Bcopy(bd, bd0);
1762
254k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
254k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
254k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
254k
        bs = i2b(1);
1772
254k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
254k
        if (e >= 0) {
1777
88.5k
            bb2 = bb5 = 0;
1778
88.5k
            bd2 = bd5 = e;
1779
88.5k
        }
1780
166k
        else {
1781
166k
            bb2 = bb5 = -e;
1782
166k
            bd2 = bd5 = 0;
1783
166k
        }
1784
254k
        if (bbe >= 0)
1785
90.6k
            bb2 += bbe;
1786
164k
        else
1787
164k
            bd2 -= bbe;
1788
254k
        bs2 = bb2;
1789
254k
        bb2++;
1790
254k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
254k
        i = bb2 < bd2 ? bb2 : bd2;
1811
254k
        if (i > bs2)
1812
163k
            i = bs2;
1813
254k
        if (i > 0) {
1814
253k
            bb2 -= i;
1815
253k
            bd2 -= i;
1816
253k
            bs2 -= i;
1817
253k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
254k
        if (bb5 > 0) {
1821
166k
            bs = pow5mult(bs, bb5);
1822
166k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
166k
            Bigint *bb1 = mult(bs, bb);
1826
166k
            Bfree(bb);
1827
166k
            bb = bb1;
1828
166k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
166k
        }
1832
254k
        if (bb2 > 0) {
1833
254k
            bb = lshift(bb, bb2);
1834
254k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
254k
        }
1838
254k
        if (bd5 > 0) {
1839
45.5k
            bd = pow5mult(bd, bd5);
1840
45.5k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
45.5k
        }
1844
254k
        if (bd2 > 0) {
1845
163k
            bd = lshift(bd, bd2);
1846
163k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
163k
        }
1850
254k
        if (bs2 > 0) {
1851
65.6k
            bs = lshift(bs, bs2);
1852
65.6k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
65.6k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
254k
        delta = diff(bb, bd);
1862
254k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
254k
        dsign = delta->sign;
1866
254k
        delta->sign = 0;
1867
254k
        i = cmp(delta, bs);
1868
254k
        if (bc.nd > nd && i <= 0) {
1869
21.4k
            if (dsign)
1870
11.1k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
10.3k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
6.98k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
6.98k
                if (j - bc.scale >= 2) {
1890
6.63k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
6.63k
                    break; /* Use bigcomp. */
1892
6.63k
                }
1893
6.98k
            }
1894
1895
3.71k
            {
1896
3.71k
                bc.nd = nd;
1897
3.71k
                i = -1; /* Discarded digits make delta smaller. */
1898
3.71k
            }
1899
3.71k
        }
1900
1901
236k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
97.0k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
4.89k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
97.0k
                ) {
1908
92.7k
                break;
1909
92.7k
            }
1910
4.24k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
613
                break;
1913
613
            }
1914
3.62k
            delta = lshift(delta,Log2P);
1915
3.62k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
3.62k
            if (cmp(delta, bs) > 0)
1919
1.12k
                goto drop_down;
1920
2.50k
            break;
1921
3.62k
        }
1922
139k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
17.6k
            if (dsign) {
1925
5.29k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
3.46k
                    &&  word1(&rv) == (
1927
3.46k
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
3.46k
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
2.58k
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
2.58k
                        + Exp_msk1
1934
2.58k
                        ;
1935
2.58k
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
2.58k
                    break;
1938
2.58k
                }
1939
5.29k
            }
1940
12.3k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
1.12k
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
1.12k
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
1.12k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
1.12k
                word0(&rv) = L | Bndry_mask1;
1958
1.12k
                word1(&rv) = 0xffffffff;
1959
1.12k
                break;
1960
1.12k
            }
1961
15.0k
            if (!odd)
1962
12.8k
                break;
1963
2.15k
            if (dsign)
1964
1.71k
                dval(&rv) += sulp(&rv, &bc);
1965
439
            else {
1966
439
                dval(&rv) -= sulp(&rv, &bc);
1967
439
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
439
            }
1973
            /* dsign = 1 - dsign; */
1974
2.15k
            break;
1975
2.15k
        }
1976
122k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
90.1k
            if (dsign)
1978
76.0k
                aadj = aadj1 = 1.;
1979
14.1k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
10.1k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
10.1k
                aadj = 1.;
1986
10.1k
                aadj1 = -1.;
1987
10.1k
            }
1988
3.96k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
3.96k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
3.96k
                else
1995
3.96k
                    aadj *= 0.5;
1996
3.96k
                aadj1 = -aadj;
1997
3.96k
            }
1998
90.1k
        }
1999
32.1k
        else {
2000
32.1k
            aadj *= 0.5;
2001
32.1k
            aadj1 = dsign ? aadj : -aadj;
2002
32.1k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
32.1k
        }
2005
122k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
122k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
6.86k
            dval(&rv0) = dval(&rv);
2011
6.86k
            word0(&rv) -= P*Exp_msk1;
2012
6.86k
            adj.d = aadj1 * ulp(&rv);
2013
6.86k
            dval(&rv) += adj.d;
2014
6.86k
            if ((word0(&rv) & Exp_mask) >=
2015
6.86k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
5.90k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
3.18k
                    goto ovfl;
2018
3.18k
                }
2019
2.72k
                word0(&rv) = Big0;
2020
2.72k
                word1(&rv) = Big1;
2021
2.72k
                goto cont;
2022
5.90k
            }
2023
969
            else
2024
969
                word0(&rv) += P*Exp_msk1;
2025
6.86k
        }
2026
115k
        else {
2027
115k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
64.9k
                if (aadj <= 0x7fffffff) {
2029
64.9k
                    if ((z = (ULong)aadj) <= 0)
2030
1.34k
                        z = 1;
2031
64.9k
                    aadj = z;
2032
64.9k
                    aadj1 = dsign ? aadj : -aadj;
2033
64.9k
                }
2034
64.9k
                dval(&aadj2) = aadj1;
2035
64.9k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
64.9k
                aadj1 = dval(&aadj2);
2037
64.9k
            }
2038
115k
            adj.d = aadj1 * ulp(&rv);
2039
115k
            dval(&rv) += adj.d;
2040
115k
        }
2041
116k
        z = word0(&rv) & Exp_mask;
2042
116k
        if (bc.nd == nd) {
2043
102k
            if (!bc.scale)
2044
37.4k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
33.4k
                    L = (Long)aadj;
2047
33.4k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
33.4k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
33.1k
                        if (aadj < .4999999 || aadj > .5000001)
2051
22.3k
                            break;
2052
33.1k
                    }
2053
301
                    else if (aadj < .4999999/FLT_RADIX)
2054
301
                        break;
2055
33.4k
                }
2056
102k
        }
2057
96.4k
      cont:
2058
96.4k
        Bfree(bb); bb = NULL;
2059
96.4k
        Bfree(bd); bd = NULL;
2060
96.4k
        Bfree(bs); bs = NULL;
2061
96.4k
        Bfree(delta); delta = NULL;
2062
96.4k
    }
2063
155k
    if (bc.nd > nd) {
2064
17.7k
        error = bigcomp(&rv, s0, &bc);
2065
17.7k
        if (error)
2066
0
            goto failed_malloc;
2067
17.7k
    }
2068
2069
155k
    if (bc.scale) {
2070
74.8k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
74.8k
        word1(&rv0) = 0;
2072
74.8k
        dval(&rv) *= dval(&rv0);
2073
74.8k
    }
2074
2075
341k
  ret:
2076
341k
    result = sign ? -dval(&rv) : dval(&rv);
2077
341k
    goto done;
2078
2079
1.68k
  parse_error:
2080
1.68k
    result = 0.0;
2081
1.68k
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
11.1k
  undfl:
2089
11.1k
    result = sign ? -0.0 : 0.0;
2090
11.1k
    goto done;
2091
2092
23.9k
  ovfl:
2093
23.9k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
23.9k
    word0(&rv) = Exp_mask;
2096
23.9k
    word1(&rv) = 0;
2097
23.9k
    result = sign ? -dval(&rv) : dval(&rv);
2098
23.9k
    goto done;
2099
2100
378k
  done:
2101
378k
    Bfree(bb);
2102
378k
    Bfree(bd);
2103
378k
    Bfree(bs);
2104
378k
    Bfree(bd0);
2105
378k
    Bfree(delta);
2106
378k
    return result;
2107
2108
155k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
32.3k
{
2113
32.3k
    int j, k, *r;
2114
2115
32.3k
    j = sizeof(ULong);
2116
32.3k
    for(k = 0;
2117
32.3k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
32.3k
        j <<= 1)
2119
0
        k++;
2120
32.3k
    r = (int*)Balloc(k);
2121
32.3k
    if (r == NULL)
2122
0
        return NULL;
2123
32.3k
    *r = k;
2124
32.3k
    return (char *)(r+1);
2125
32.3k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
3.45k
{
2130
3.45k
    char *rv, *t;
2131
2132
3.45k
    rv = rv_alloc(n);
2133
3.45k
    if (rv == NULL)
2134
0
        return NULL;
2135
3.45k
    t = rv;
2136
15.3k
    while((*t = *s++)) t++;
2137
3.45k
    if (rve)
2138
3.45k
        *rve = t;
2139
3.45k
    return rv;
2140
3.45k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
32.3k
{
2151
32.3k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
32.3k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
32.3k
    Bfree(b);
2154
32.3k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
32.3k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
32.3k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
32.3k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
32.3k
        spec_case, try_quick;
2235
32.3k
    Long L;
2236
32.3k
    int denorm;
2237
32.3k
    ULong x;
2238
32.3k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
32.3k
    U d2, eps, u;
2240
32.3k
    double ds;
2241
32.3k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
32.3k
    mlo = mhi = S = 0;
2246
32.3k
    s0 = 0;
2247
2248
32.3k
    u.d = dd;
2249
32.3k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
0
        *sign = 1;
2252
0
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
0
    }
2254
32.3k
    else
2255
32.3k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
32.3k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
1.20k
    {
2260
        /* Infinity or NaN */
2261
1.20k
        *decpt = 9999;
2262
1.20k
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
1.20k
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
1.20k
    }
2266
31.1k
    if (!dval(&u)) {
2267
2.25k
        *decpt = 1;
2268
2.25k
        return nrv_alloc("0", rve, 1);
2269
2.25k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
28.8k
    b = d2b(&u, &be, &bbits);
2274
28.8k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
28.8k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
24.0k
        dval(&d2) = dval(&u);
2278
24.0k
        word0(&d2) &= Frac_mask1;
2279
24.0k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
24.0k
        i -= Bias;
2304
24.0k
        denorm = 0;
2305
24.0k
    }
2306
4.76k
    else {
2307
        /* d is denormalized */
2308
2309
4.76k
        i = bbits + be + (Bias + (P-1) - 1);
2310
4.76k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
4.76k
            : word1(&u) << (32 - i);
2312
4.76k
        dval(&d2) = x;
2313
4.76k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
4.76k
        i -= (Bias + (P-1) - 1) + 1;
2315
4.76k
        denorm = 1;
2316
4.76k
    }
2317
28.8k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
28.8k
        i*0.301029995663981;
2319
28.8k
    k = (int)ds;
2320
28.8k
    if (ds < 0. && ds != k)
2321
11.0k
        k--;    /* want k = floor(ds) */
2322
28.8k
    k_check = 1;
2323
28.8k
    if (k >= 0 && k <= Ten_pmax) {
2324
14.9k
        if (dval(&u) < tens[k])
2325
1.04k
            k--;
2326
14.9k
        k_check = 0;
2327
14.9k
    }
2328
28.8k
    j = bbits - i - 1;
2329
28.8k
    if (j >= 0) {
2330
16.9k
        b2 = 0;
2331
16.9k
        s2 = j;
2332
16.9k
    }
2333
11.8k
    else {
2334
11.8k
        b2 = -j;
2335
11.8k
        s2 = 0;
2336
11.8k
    }
2337
28.8k
    if (k >= 0) {
2338
17.7k
        b5 = 0;
2339
17.7k
        s5 = k;
2340
17.7k
        s2 += k;
2341
17.7k
    }
2342
11.1k
    else {
2343
11.1k
        b2 -= k;
2344
11.1k
        b5 = -k;
2345
11.1k
        s5 = 0;
2346
11.1k
    }
2347
28.8k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
28.8k
    try_quick = 1;
2351
2352
28.8k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
28.8k
    leftright = 1;
2357
28.8k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
28.8k
    switch(mode) {
2360
28.8k
    case 0:
2361
28.8k
    case 1:
2362
28.8k
        i = 18;
2363
28.8k
        ndigits = 0;
2364
28.8k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
0
    case 3:
2374
0
        leftright = 0;
2375
0
        _Py_FALLTHROUGH;
2376
0
    case 5:
2377
0
        i = ndigits + k + 1;
2378
0
        ilim = i;
2379
0
        ilim1 = i - 1;
2380
0
        if (i <= 0)
2381
0
            i = 1;
2382
28.8k
    }
2383
28.8k
    s0 = rv_alloc(i);
2384
28.8k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
28.8k
    s = s0;
2387
2388
2389
28.8k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
0
        i = 0;
2394
0
        dval(&d2) = dval(&u);
2395
0
        k0 = k;
2396
0
        ilim0 = ilim;
2397
0
        ieps = 2; /* conservative */
2398
0
        if (k > 0) {
2399
0
            ds = tens[k&0xf];
2400
0
            j = k >> 4;
2401
0
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
0
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
0
            dval(&u) /= ds;
2413
0
        }
2414
0
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
0
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
0
        dval(&eps) = ieps*dval(&u) + 7.;
2431
0
        word0(&eps) -= (P-1)*Exp_msk1;
2432
0
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
0
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
0
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
0
            dval(&eps) *= tens[ilim-1];
2463
0
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
0
                L = (Long)(dval(&u));
2465
0
                if (!(dval(&u) -= L))
2466
0
                    ilim = i;
2467
0
                *s++ = '0' + (int)L;
2468
0
                if (i == ilim) {
2469
0
                    if (dval(&u) > 0.5 + dval(&eps))
2470
0
                        goto bump_up;
2471
0
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
0
                        while(*--s == '0');
2473
0
                        s++;
2474
0
                        goto ret1;
2475
0
                    }
2476
0
                    break;
2477
0
                }
2478
0
            }
2479
0
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
28.8k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
8.19k
        ds = tens[k];
2492
8.19k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
32.5k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
32.5k
            L = (Long)(dval(&u) / ds);
2500
32.5k
            dval(&u) -= L*ds;
2501
32.5k
            *s++ = '0' + (int)L;
2502
32.5k
            if (!dval(&u)) {
2503
8.19k
                break;
2504
8.19k
            }
2505
24.3k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
0
                  bump_up:
2509
0
                    while(*--s == '9')
2510
0
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
0
                    ++*s++;
2516
0
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
0
                break;
2526
0
            }
2527
24.3k
        }
2528
8.19k
        goto ret1;
2529
8.19k
    }
2530
2531
20.6k
    m2 = b2;
2532
20.6k
    m5 = b5;
2533
20.6k
    if (leftright) {
2534
20.6k
        i =
2535
20.6k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
20.6k
            1 + P - bbits;
2537
20.6k
        b2 += i;
2538
20.6k
        s2 += i;
2539
20.6k
        mhi = i2b(1);
2540
20.6k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
20.6k
    }
2543
20.6k
    if (m2 > 0 && s2 > 0) {
2544
16.3k
        i = m2 < s2 ? m2 : s2;
2545
16.3k
        b2 -= i;
2546
16.3k
        m2 -= i;
2547
16.3k
        s2 -= i;
2548
16.3k
    }
2549
20.6k
    if (b5 > 0) {
2550
11.1k
        if (leftright) {
2551
11.1k
            if (m5 > 0) {
2552
11.1k
                mhi = pow5mult(mhi, m5);
2553
11.1k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
11.1k
                b1 = mult(mhi, b);
2556
11.1k
                Bfree(b);
2557
11.1k
                b = b1;
2558
11.1k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
11.1k
            }
2561
11.1k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
11.1k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
11.1k
    }
2573
20.6k
    S = i2b(1);
2574
20.6k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
20.6k
    if (s5 > 0) {
2577
6.92k
        S = pow5mult(S, s5);
2578
6.92k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
6.92k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
20.6k
    spec_case = 0;
2585
20.6k
    if ((mode < 2 || leftright)
2586
20.6k
        ) {
2587
20.6k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.17k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
20.6k
            ) {
2590
            /* The special case */
2591
1.17k
            b2 += Log2P;
2592
1.17k
            s2 += Log2P;
2593
1.17k
            spec_case = 1;
2594
1.17k
        }
2595
20.6k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
20.6k
#define iInc 28
2605
20.6k
    i = dshift(S, s2);
2606
20.6k
    b2 += i;
2607
20.6k
    m2 += i;
2608
20.6k
    s2 += i;
2609
20.6k
    if (b2 > 0) {
2610
20.6k
        b = lshift(b, b2);
2611
20.6k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
20.6k
    }
2614
20.6k
    if (s2 > 0) {
2615
20.3k
        S = lshift(S, s2);
2616
20.3k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
20.3k
    }
2619
20.6k
    if (k_check) {
2620
13.9k
        if (cmp(b,S) < 0) {
2621
3.31k
            k--;
2622
3.31k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
3.31k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
3.31k
            if (leftright) {
2626
3.31k
                mhi = multadd(mhi, 10, 0);
2627
3.31k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
3.31k
            }
2630
3.31k
            ilim = ilim1;
2631
3.31k
        }
2632
13.9k
    }
2633
20.6k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
20.6k
    if (leftright) {
2653
20.6k
        if (m2 > 0) {
2654
20.0k
            mhi = lshift(mhi, m2);
2655
20.0k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
20.0k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
20.6k
        mlo = mhi;
2664
20.6k
        if (spec_case) {
2665
1.17k
            mhi = Balloc(mhi->k);
2666
1.17k
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
1.17k
            Bcopy(mhi, mlo);
2669
1.17k
            mhi = lshift(mhi, Log2P);
2670
1.17k
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
1.17k
        }
2673
2674
93.5k
        for(i = 1;;i++) {
2675
93.5k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
93.5k
            j = cmp(b, mlo);
2680
93.5k
            delta = diff(S, mhi);
2681
93.5k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
93.5k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
93.5k
            Bfree(delta);
2685
93.5k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
93.5k
                ) {
2687
1.17k
                if (dig == '9')
2688
477
                    goto round_9_up;
2689
694
                if (j > 0)
2690
375
                    dig++;
2691
694
                *s++ = dig;
2692
694
                goto ret;
2693
1.17k
            }
2694
92.3k
            if (j < 0 || (j == 0 && mode != 1
2695
1.61k
                          && !(word1(&u) & 1)
2696
80.3k
                    )) {
2697
12.0k
                if (!b->x[0] && b->wds <= 1) {
2698
2.85k
                    goto accept_dig;
2699
2.85k
                }
2700
9.20k
                if (j1 > 0) {
2701
2.18k
                    b = lshift(b, 1);
2702
2.18k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
2.18k
                    j1 = cmp(b, S);
2705
2.18k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.20k
                        && dig++ == '9')
2707
589
                        goto round_9_up;
2708
2.18k
                }
2709
11.4k
              accept_dig:
2710
11.4k
                *s++ = dig;
2711
11.4k
                goto ret;
2712
9.20k
            }
2713
80.2k
            if (j1 > 0) {
2714
7.43k
                if (dig == '9') { /* possible if i == 1 */
2715
3.53k
                  round_9_up:
2716
3.53k
                    *s++ = '9';
2717
3.53k
                    goto roundoff;
2718
2.47k
                }
2719
4.96k
                *s++ = dig + 1;
2720
4.96k
                goto ret;
2721
7.43k
            }
2722
72.8k
            *s++ = dig;
2723
72.8k
            if (i == ilim)
2724
0
                break;
2725
72.8k
            b = multadd(b, 10, 0);
2726
72.8k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
72.8k
            if (mlo == mhi) {
2729
71.1k
                mlo = mhi = multadd(mhi, 10, 0);
2730
71.1k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
71.1k
            }
2733
1.70k
            else {
2734
1.70k
                mlo = multadd(mlo, 10, 0);
2735
1.70k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
1.70k
                mhi = multadd(mhi, 10, 0);
2738
1.70k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
1.70k
            }
2741
72.8k
        }
2742
20.6k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
3.53k
      roundoff:
2764
3.53k
        while(*--s == '9')
2765
3.53k
            if (s == s0) {
2766
3.53k
                k++;
2767
3.53k
                *s++ = '1';
2768
3.53k
                goto ret;
2769
3.53k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
20.6k
  ret:
2777
20.6k
    Bfree(S);
2778
20.6k
    if (mhi) {
2779
20.6k
        if (mlo && mlo != mhi)
2780
1.17k
            Bfree(mlo);
2781
20.6k
        Bfree(mhi);
2782
20.6k
    }
2783
28.8k
  ret1:
2784
28.8k
    Bfree(b);
2785
28.8k
    *s = 0;
2786
28.8k
    *decpt = k + 1;
2787
28.8k
    if (rve)
2788
28.8k
        *rve = s;
2789
28.8k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
20.6k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
22
{
2809
22
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
22
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
22
    Bigint *p5 = i2b(625);
2814
22
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
22
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
176
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
154
        p5 = mult(p5, p5);
2822
154
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
154
        p5s[i] = p5;
2826
154
    }
2827
2828
22
#endif
2829
22
    return PyStatus_Ok();
2830
22
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}