Coverage Report

Created: 2025-11-13 06:36

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/elfutils/libelf/elf32_xlatetof.c
Line
Count
Source
1
/* Convert from memory to file representation.
2
   Copyright (C) 1998, 1999, 2000, 2002, 2015 Red Hat, Inc.
3
   This file is part of elfutils.
4
   Written by Ulrich Drepper <drepper@redhat.com>, 1998.
5
6
   This file is free software; you can redistribute it and/or modify
7
   it under the terms of either
8
9
     * the GNU Lesser General Public License as published by the Free
10
       Software Foundation; either version 3 of the License, or (at
11
       your option) any later version
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13
   or
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15
     * the GNU General Public License as published by the Free
16
       Software Foundation; either version 2 of the License, or (at
17
       your option) any later version
18
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   or both in parallel, as here.
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21
   elfutils is distributed in the hope that it will be useful, but
22
   WITHOUT ANY WARRANTY; without even the implied warranty of
23
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
24
   General Public License for more details.
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26
   You should have received copies of the GNU General Public License and
27
   the GNU Lesser General Public License along with this program.  If
28
   not, see <http://www.gnu.org/licenses/>.  */
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30
#ifdef HAVE_CONFIG_H
31
# include <config.h>
32
#endif
33
34
#include <assert.h>
35
#include <string.h>
36
37
#include "libelfP.h"
38
39
#ifndef LIBELFBITS
40
# define LIBELFBITS 32
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#endif
42
43
44
Elf_Data *
45
elfw2(LIBELFBITS, xlatetof) (Elf_Data *dest, const Elf_Data *src,
46
           unsigned int encode)
47
13.7k
{
48
13.7k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
13.7k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
13.7k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
13.7k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
13.7k
      && src->d_size % recsize != 0)
68
6.49k
    {
69
6.49k
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
6.49k
      return NULL;
71
6.49k
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
7.21k
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
7.21k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
7.21k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
7.21k
  else
106
7.21k
    {
107
7.21k
      xfct_t fctp;
108
7.21k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
7.21k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
7.21k
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
7.21k
  dest->d_type = src->d_type;
117
7.21k
  dest->d_size = src->d_size;
118
119
7.21k
  return dest;
120
7.21k
}
elf32_xlatetof
Line
Count
Source
47
12.7k
{
48
12.7k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
12.7k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
12.7k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
12.7k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
12.7k
      && src->d_size % recsize != 0)
68
5.76k
    {
69
5.76k
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
5.76k
      return NULL;
71
5.76k
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
7.02k
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
7.02k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
7.02k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
7.02k
  else
106
7.02k
    {
107
7.02k
      xfct_t fctp;
108
7.02k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
7.02k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
7.02k
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
7.02k
  dest->d_type = src->d_type;
117
7.02k
  dest->d_size = src->d_size;
118
119
7.02k
  return dest;
120
7.02k
}
elf64_xlatetof
Line
Count
Source
47
919
{
48
919
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
919
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
919
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
919
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
919
      && src->d_size % recsize != 0)
68
729
    {
69
729
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
729
      return NULL;
71
729
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
190
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
190
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
190
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
190
  else
106
190
    {
107
190
      xfct_t fctp;
108
190
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
190
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
190
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
190
  dest->d_type = src->d_type;
117
190
  dest->d_size = src->d_size;
118
119
190
  return dest;
120
190
}
121
INTDEF(elfw2(LIBELFBITS, xlatetof))