Coverage Report

Created: 2025-07-12 06:44

/src/elfutils/libelf/elf32_xlatetof.c
Line
Count
Source (jump to first uncovered line)
1
/* Convert from memory to file representation.
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   Copyright (C) 1998, 1999, 2000, 2002, 2015 Red Hat, Inc.
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   This file is part of elfutils.
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   Written by Ulrich Drepper <drepper@redhat.com>, 1998.
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   This file is free software; you can redistribute it and/or modify
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   it under the terms of either
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     * the GNU Lesser General Public License as published by the Free
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       Software Foundation; either version 3 of the License, or (at
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       your option) any later version
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   or
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     * the GNU General Public License as published by the Free
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       Software Foundation; either version 2 of the License, or (at
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       your option) any later version
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   or both in parallel, as here.
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   elfutils is distributed in the hope that it will be useful, but
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   WITHOUT ANY WARRANTY; without even the implied warranty of
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   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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   General Public License for more details.
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   You should have received copies of the GNU General Public License and
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   the GNU Lesser General Public License along with this program.  If
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   not, see <http://www.gnu.org/licenses/>.  */
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#ifdef HAVE_CONFIG_H
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# include <config.h>
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#endif
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#include <assert.h>
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#include <string.h>
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#include "libelfP.h"
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#ifndef LIBELFBITS
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# define LIBELFBITS 32
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#endif
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Elf_Data *
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elfw2(LIBELFBITS, xlatetof) (Elf_Data *dest, const Elf_Data *src,
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           unsigned int encode)
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13.7k
{
48
13.7k
  if (src == NULL || dest == NULL)
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0
    return NULL;
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51
13.7k
  if (src->d_type >= ELF_T_NUM)
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0
    {
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0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
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0
      return NULL;
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0
    }
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57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
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     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
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13.7k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
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63
  /* We shouldn't require integer number of records when processing
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     notes.  Payload bytes follow the header immediately, it's not an
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     array of records as is the case otherwise.  */
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13.7k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
13.7k
      && src->d_size % recsize != 0)
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6.91k
    {
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6.91k
      __libelf_seterrno (ELF_E_INVALID_DATA);
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6.91k
      return NULL;
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6.91k
    }
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  /* Next see whether the converted data fits in the output buffer.  */
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6.83k
  if (src->d_size > dest->d_size)
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0
    {
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0
      __libelf_seterrno (ELF_E_DEST_SIZE);
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0
      return NULL;
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0
    }
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  /* Test the encode parameter.  */
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6.83k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
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0
    {
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0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
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0
      return NULL;
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0
    }
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87
  /* Determine the translation function to use.
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89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
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  change the byte order.
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  */
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6.83k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
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6.83k
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
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0
    {
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      /* We simply have to copy since the byte order is the same.  */
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0
      if (src->d_buf != dest->d_buf)
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0
  memmove (dest->d_buf, src->d_buf, src->d_size);
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0
    }
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6.83k
  else
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6.83k
    {
107
6.83k
      xfct_t fctp;
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6.83k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
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      /* Do the real work.  */
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6.83k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
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6.83k
    }
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  /* Now set the real destination type and length since the operation was
115
     successful.  */
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6.83k
  dest->d_type = src->d_type;
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6.83k
  dest->d_size = src->d_size;
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119
6.83k
  return dest;
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6.83k
}
elf32_xlatetof
Line
Count
Source
47
12.8k
{
48
12.8k
  if (src == NULL || dest == NULL)
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0
    return NULL;
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51
12.8k
  if (src->d_type >= ELF_T_NUM)
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0
    {
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0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
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0
      return NULL;
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0
    }
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57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
12.8k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
12.8k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
12.8k
      && src->d_size % recsize != 0)
68
6.26k
    {
69
6.26k
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
6.26k
      return NULL;
71
6.26k
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
6.62k
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
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0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
6.62k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
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0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
6.62k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
6.62k
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
6.62k
  else
106
6.62k
    {
107
6.62k
      xfct_t fctp;
108
6.62k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
6.62k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
6.62k
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
6.62k
  dest->d_type = src->d_type;
117
6.62k
  dest->d_size = src->d_size;
118
119
6.62k
  return dest;
120
6.62k
}
elf64_xlatetof
Line
Count
Source
47
865
{
48
865
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
865
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
865
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
865
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
865
      && src->d_size % recsize != 0)
68
653
    {
69
653
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
653
      return NULL;
71
653
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
212
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
212
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
212
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
212
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
212
  else
106
212
    {
107
212
      xfct_t fctp;
108
212
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
212
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
212
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
212
  dest->d_type = src->d_type;
117
212
  dest->d_size = src->d_size;
118
119
212
  return dest;
120
212
}
121
INTDEF(elfw2(LIBELFBITS, xlatetof))