Coverage Report

Created: 2025-07-12 06:44

/src/elfutils/libelf/elf32_xlatetom.c
Line
Count
Source (jump to first uncovered line)
1
/* Convert from file to memory representation.
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   Copyright (C) 1998, 1999, 2000, 2002, 2012, 2015 Red Hat, Inc.
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   This file is part of elfutils.
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   Written by Ulrich Drepper <drepper@redhat.com>, 1998.
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6
   This file is free software; you can redistribute it and/or modify
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   it under the terms of either
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9
     * the GNU Lesser General Public License as published by the Free
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       Software Foundation; either version 3 of the License, or (at
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       your option) any later version
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   or
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     * the GNU General Public License as published by the Free
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       Software Foundation; either version 2 of the License, or (at
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       your option) any later version
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   or both in parallel, as here.
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   elfutils is distributed in the hope that it will be useful, but
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   WITHOUT ANY WARRANTY; without even the implied warranty of
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   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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   General Public License for more details.
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   You should have received copies of the GNU General Public License and
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   the GNU Lesser General Public License along with this program.  If
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   not, see <http://www.gnu.org/licenses/>.  */
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#ifdef HAVE_CONFIG_H
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# include <config.h>
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#endif
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34
#include <assert.h>
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#include <string.h>
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37
#include "libelfP.h"
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39
#ifndef LIBELFBITS
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# define LIBELFBITS 32
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#endif
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43
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Elf_Data *
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elfw2(LIBELFBITS, xlatetom) (Elf_Data *dest, const Elf_Data *src,
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           unsigned int encode)
47
298k
{
48
298k
  if (src == NULL || dest == NULL)
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0
    return NULL;
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51
298k
  if (src->d_type >= ELF_T_NUM)
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0
    {
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0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
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0
      return NULL;
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0
    }
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57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
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298k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
64
  /* We shouldn't require integer number of records when processing
65
     notes.  Payload bytes follow the header immediately, it's not an
66
     array of records as is the case otherwise.  */
67
298k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
68
298k
      && src->d_size % recsize != 0)
69
31
    {
70
31
      __libelf_seterrno (ELF_E_INVALID_DATA);
71
31
      return NULL;
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31
    }
73
74
  /* Next see whether the converted data fits in the output buffer.  */
75
298k
  if (src->d_size > dest->d_size)
76
0
    {
77
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
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0
      return NULL;
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0
    }
80
81
  /* Test the encode parameter.  */
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298k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
83
413
    {
84
413
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
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413
      return NULL;
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413
    }
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88
  /* Determine the translation function to use.
89
90
     At this point we make an assumption which is valid for all
91
     existing implementations so far: the memory and file sizes are
92
     the same.  This has very important consequences:
93
     a) The requirement that the source and destination buffer can
94
  overlap can easily be fulfilled.
95
     b) We need only one function to convert from and memory to file
96
  and vice versa since the function only has to copy and/or
97
  change the byte order.
98
  */
99
297k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
100
297k
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
101
70.3k
    {
102
      /* We simply have to copy since the byte order is the same.  */
103
70.3k
      if (src->d_buf != dest->d_buf)
104
37.1k
  memmove (dest->d_buf, src->d_buf, src->d_size);
105
70.3k
    }
106
227k
  else
107
227k
    {
108
227k
      xfct_t fctp;
109
227k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
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111
      /* Do the real work.  */
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227k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 0);
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227k
    }
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115
  /* Now set the real destination type and length since the operation was
116
     successful.  */
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297k
  dest->d_type = src->d_type;
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297k
  dest->d_size = src->d_size;
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120
297k
  return dest;
121
298k
}
elf32_xlatetom
Line
Count
Source
47
276k
{
48
276k
  if (src == NULL || dest == NULL)
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0
    return NULL;
50
51
276k
  if (src->d_type >= ELF_T_NUM)
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0
    {
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0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
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0
      return NULL;
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0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
276k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
64
  /* We shouldn't require integer number of records when processing
65
     notes.  Payload bytes follow the header immediately, it's not an
66
     array of records as is the case otherwise.  */
67
276k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
68
276k
      && src->d_size % recsize != 0)
69
14
    {
70
14
      __libelf_seterrno (ELF_E_INVALID_DATA);
71
14
      return NULL;
72
14
    }
73
74
  /* Next see whether the converted data fits in the output buffer.  */
75
276k
  if (src->d_size > dest->d_size)
76
0
    {
77
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
78
0
      return NULL;
79
0
    }
80
81
  /* Test the encode parameter.  */
82
276k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
83
205
    {
84
205
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
85
205
      return NULL;
86
205
    }
87
88
  /* Determine the translation function to use.
89
90
     At this point we make an assumption which is valid for all
91
     existing implementations so far: the memory and file sizes are
92
     the same.  This has very important consequences:
93
     a) The requirement that the source and destination buffer can
94
  overlap can easily be fulfilled.
95
     b) We need only one function to convert from and memory to file
96
  and vice versa since the function only has to copy and/or
97
  change the byte order.
98
  */
99
276k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
100
276k
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
101
51.9k
    {
102
      /* We simply have to copy since the byte order is the same.  */
103
51.9k
      if (src->d_buf != dest->d_buf)
104
25.8k
  memmove (dest->d_buf, src->d_buf, src->d_size);
105
51.9k
    }
106
224k
  else
107
224k
    {
108
224k
      xfct_t fctp;
109
224k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
110
111
      /* Do the real work.  */
112
224k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 0);
113
224k
    }
114
115
  /* Now set the real destination type and length since the operation was
116
     successful.  */
117
276k
  dest->d_type = src->d_type;
118
276k
  dest->d_size = src->d_size;
119
120
276k
  return dest;
121
276k
}
elf64_xlatetom
Line
Count
Source
47
21.8k
{
48
21.8k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
21.8k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
21.8k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
64
  /* We shouldn't require integer number of records when processing
65
     notes.  Payload bytes follow the header immediately, it's not an
66
     array of records as is the case otherwise.  */
67
21.8k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
68
21.8k
      && src->d_size % recsize != 0)
69
17
    {
70
17
      __libelf_seterrno (ELF_E_INVALID_DATA);
71
17
      return NULL;
72
17
    }
73
74
  /* Next see whether the converted data fits in the output buffer.  */
75
21.8k
  if (src->d_size > dest->d_size)
76
0
    {
77
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
78
0
      return NULL;
79
0
    }
80
81
  /* Test the encode parameter.  */
82
21.8k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
83
208
    {
84
208
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
85
208
      return NULL;
86
208
    }
87
88
  /* Determine the translation function to use.
89
90
     At this point we make an assumption which is valid for all
91
     existing implementations so far: the memory and file sizes are
92
     the same.  This has very important consequences:
93
     a) The requirement that the source and destination buffer can
94
  overlap can easily be fulfilled.
95
     b) We need only one function to convert from and memory to file
96
  and vice versa since the function only has to copy and/or
97
  change the byte order.
98
  */
99
21.6k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
100
21.6k
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
101
18.4k
    {
102
      /* We simply have to copy since the byte order is the same.  */
103
18.4k
      if (src->d_buf != dest->d_buf)
104
11.3k
  memmove (dest->d_buf, src->d_buf, src->d_size);
105
18.4k
    }
106
3.20k
  else
107
3.20k
    {
108
3.20k
      xfct_t fctp;
109
3.20k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
110
111
      /* Do the real work.  */
112
3.20k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 0);
113
3.20k
    }
114
115
  /* Now set the real destination type and length since the operation was
116
     successful.  */
117
21.6k
  dest->d_type = src->d_type;
118
21.6k
  dest->d_size = src->d_size;
119
120
21.6k
  return dest;
121
21.8k
}
122
INTDEF(elfw2(LIBELFBITS, xlatetom))