Coverage Report

Created: 2025-11-24 06:43

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/elfutils/libelf/elf32_xlatetom.c
Line
Count
Source
1
/* Convert from file to memory representation.
2
   Copyright (C) 1998, 1999, 2000, 2002, 2012, 2015 Red Hat, Inc.
3
   This file is part of elfutils.
4
   Written by Ulrich Drepper <drepper@redhat.com>, 1998.
5
6
   This file is free software; you can redistribute it and/or modify
7
   it under the terms of either
8
9
     * the GNU Lesser General Public License as published by the Free
10
       Software Foundation; either version 3 of the License, or (at
11
       your option) any later version
12
13
   or
14
15
     * the GNU General Public License as published by the Free
16
       Software Foundation; either version 2 of the License, or (at
17
       your option) any later version
18
19
   or both in parallel, as here.
20
21
   elfutils is distributed in the hope that it will be useful, but
22
   WITHOUT ANY WARRANTY; without even the implied warranty of
23
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
24
   General Public License for more details.
25
26
   You should have received copies of the GNU General Public License and
27
   the GNU Lesser General Public License along with this program.  If
28
   not, see <http://www.gnu.org/licenses/>.  */
29
30
#ifdef HAVE_CONFIG_H
31
# include <config.h>
32
#endif
33
34
#include <assert.h>
35
#include <string.h>
36
37
#include "libelfP.h"
38
39
#ifndef LIBELFBITS
40
# define LIBELFBITS 32
41
#endif
42
43
44
Elf_Data *
45
elfw2(LIBELFBITS, xlatetom) (Elf_Data *dest, const Elf_Data *src,
46
           unsigned int encode)
47
221k
{
48
221k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
221k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
221k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
64
  /* We shouldn't require integer number of records when processing
65
     notes.  Payload bytes follow the header immediately, it's not an
66
     array of records as is the case otherwise.  */
67
221k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
68
116k
      && src->d_size % recsize != 0)
69
14
    {
70
14
      __libelf_seterrno (ELF_E_INVALID_DATA);
71
14
      return NULL;
72
14
    }
73
74
  /* Next see whether the converted data fits in the output buffer.  */
75
221k
  if (src->d_size > dest->d_size)
76
0
    {
77
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
78
0
      return NULL;
79
0
    }
80
81
  /* Test the encode parameter.  */
82
221k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
83
418
    {
84
418
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
85
418
      return NULL;
86
418
    }
87
88
  /* Determine the translation function to use.
89
90
     At this point we make an assumption which is valid for all
91
     existing implementations so far: the memory and file sizes are
92
     the same.  This has very important consequences:
93
     a) The requirement that the source and destination buffer can
94
  overlap can easily be fulfilled.
95
     b) We need only one function to convert from and memory to file
96
  and vice versa since the function only has to copy and/or
97
  change the byte order.
98
  */
99
221k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
100
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
101
104k
    {
102
      /* We simply have to copy since the byte order is the same.  */
103
104k
      if (src->d_buf != dest->d_buf)
104
40.0k
  memmove (dest->d_buf, src->d_buf, src->d_size);
105
104k
    }
106
117k
  else
107
117k
    {
108
117k
      xfct_t fctp;
109
117k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
110
111
      /* Do the real work.  */
112
117k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 0);
113
117k
    }
114
115
  /* Now set the real destination type and length since the operation was
116
     successful.  */
117
221k
  dest->d_type = src->d_type;
118
221k
  dest->d_size = src->d_size;
119
120
221k
  return dest;
121
221k
}
elf32_xlatetom
Line
Count
Source
47
189k
{
48
189k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
189k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
189k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
64
  /* We shouldn't require integer number of records when processing
65
     notes.  Payload bytes follow the header immediately, it's not an
66
     array of records as is the case otherwise.  */
67
189k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
68
84.5k
      && src->d_size % recsize != 0)
69
4
    {
70
4
      __libelf_seterrno (ELF_E_INVALID_DATA);
71
4
      return NULL;
72
4
    }
73
74
  /* Next see whether the converted data fits in the output buffer.  */
75
189k
  if (src->d_size > dest->d_size)
76
0
    {
77
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
78
0
      return NULL;
79
0
    }
80
81
  /* Test the encode parameter.  */
82
189k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
83
208
    {
84
208
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
85
208
      return NULL;
86
208
    }
87
88
  /* Determine the translation function to use.
89
90
     At this point we make an assumption which is valid for all
91
     existing implementations so far: the memory and file sizes are
92
     the same.  This has very important consequences:
93
     a) The requirement that the source and destination buffer can
94
  overlap can easily be fulfilled.
95
     b) We need only one function to convert from and memory to file
96
  and vice versa since the function only has to copy and/or
97
  change the byte order.
98
  */
99
189k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
100
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
101
76.6k
    {
102
      /* We simply have to copy since the byte order is the same.  */
103
76.6k
      if (src->d_buf != dest->d_buf)
104
24.6k
  memmove (dest->d_buf, src->d_buf, src->d_size);
105
76.6k
    }
106
112k
  else
107
112k
    {
108
112k
      xfct_t fctp;
109
112k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
110
111
      /* Do the real work.  */
112
112k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 0);
113
112k
    }
114
115
  /* Now set the real destination type and length since the operation was
116
     successful.  */
117
189k
  dest->d_type = src->d_type;
118
189k
  dest->d_size = src->d_size;
119
120
189k
  return dest;
121
189k
}
elf64_xlatetom
Line
Count
Source
47
32.1k
{
48
32.1k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
32.1k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
32.1k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
64
  /* We shouldn't require integer number of records when processing
65
     notes.  Payload bytes follow the header immediately, it's not an
66
     array of records as is the case otherwise.  */
67
32.1k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
68
32.1k
      && src->d_size % recsize != 0)
69
10
    {
70
10
      __libelf_seterrno (ELF_E_INVALID_DATA);
71
10
      return NULL;
72
10
    }
73
74
  /* Next see whether the converted data fits in the output buffer.  */
75
32.0k
  if (src->d_size > dest->d_size)
76
0
    {
77
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
78
0
      return NULL;
79
0
    }
80
81
  /* Test the encode parameter.  */
82
32.0k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
83
210
    {
84
210
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
85
210
      return NULL;
86
210
    }
87
88
  /* Determine the translation function to use.
89
90
     At this point we make an assumption which is valid for all
91
     existing implementations so far: the memory and file sizes are
92
     the same.  This has very important consequences:
93
     a) The requirement that the source and destination buffer can
94
  overlap can easily be fulfilled.
95
     b) We need only one function to convert from and memory to file
96
  and vice versa since the function only has to copy and/or
97
  change the byte order.
98
  */
99
31.8k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
100
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
101
27.7k
    {
102
      /* We simply have to copy since the byte order is the same.  */
103
27.7k
      if (src->d_buf != dest->d_buf)
104
15.4k
  memmove (dest->d_buf, src->d_buf, src->d_size);
105
27.7k
    }
106
4.10k
  else
107
4.10k
    {
108
4.10k
      xfct_t fctp;
109
4.10k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
110
111
      /* Do the real work.  */
112
4.10k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 0);
113
4.10k
    }
114
115
  /* Now set the real destination type and length since the operation was
116
     successful.  */
117
31.8k
  dest->d_type = src->d_type;
118
31.8k
  dest->d_size = src->d_size;
119
120
31.8k
  return dest;
121
32.0k
}
122
INTDEF(elfw2(LIBELFBITS, xlatetom))