Coverage Report

Created: 2026-07-24 06:20

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/elfutils/libelf/elf32_xlatetof.c
Line
Count
Source
1
/* Convert from memory to file representation.
2
   Copyright (C) 1998, 1999, 2000, 2002, 2015 Red Hat, Inc.
3
   This file is part of elfutils.
4
   Written by Ulrich Drepper <drepper@redhat.com>, 1998.
5
6
   This file is free software; you can redistribute it and/or modify
7
   it under the terms of either
8
9
     * the GNU Lesser General Public License as published by the Free
10
       Software Foundation; either version 3 of the License, or (at
11
       your option) any later version
12
13
   or
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15
     * the GNU General Public License as published by the Free
16
       Software Foundation; either version 2 of the License, or (at
17
       your option) any later version
18
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   or both in parallel, as here.
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21
   elfutils is distributed in the hope that it will be useful, but
22
   WITHOUT ANY WARRANTY; without even the implied warranty of
23
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
24
   General Public License for more details.
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26
   You should have received copies of the GNU General Public License and
27
   the GNU Lesser General Public License along with this program.  If
28
   not, see <http://www.gnu.org/licenses/>.  */
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30
#ifdef HAVE_CONFIG_H
31
# include <config.h>
32
#endif
33
34
#include <assert.h>
35
#include <string.h>
36
37
#include "libelfP.h"
38
39
#ifndef LIBELFBITS
40
# define LIBELFBITS 32
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#endif
42
43
44
Elf_Data *
45
elfw2(LIBELFBITS, xlatetof) (Elf_Data *dest, const Elf_Data *src,
46
           unsigned int encode)
47
12.4k
{
48
12.4k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
12.4k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
12.4k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
12.4k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
12.4k
      && src->d_size % recsize != 0)
68
5.11k
    {
69
5.11k
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
5.11k
      return NULL;
71
5.11k
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
7.32k
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
7.32k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
7.32k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
7.32k
  else
106
7.32k
    {
107
7.32k
      xfct_t fctp;
108
7.32k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
7.32k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
7.32k
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
7.32k
  dest->d_type = src->d_type;
117
7.32k
  dest->d_size = src->d_size;
118
119
7.32k
  return dest;
120
7.32k
}
elf32_xlatetof
Line
Count
Source
47
11.5k
{
48
11.5k
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
11.5k
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
11.5k
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
11.5k
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
11.5k
      && src->d_size % recsize != 0)
68
4.47k
    {
69
4.47k
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
4.47k
      return NULL;
71
4.47k
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
7.11k
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
7.11k
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
7.11k
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
7.11k
  else
106
7.11k
    {
107
7.11k
      xfct_t fctp;
108
7.11k
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
7.11k
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
7.11k
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
7.11k
  dest->d_type = src->d_type;
117
7.11k
  dest->d_size = src->d_size;
118
119
7.11k
  return dest;
120
7.11k
}
elf64_xlatetof
Line
Count
Source
47
848
{
48
848
  if (src == NULL || dest == NULL)
49
0
    return NULL;
50
51
848
  if (src->d_type >= ELF_T_NUM)
52
0
    {
53
0
      __libelf_seterrno (ELF_E_UNKNOWN_TYPE);
54
0
      return NULL;
55
0
    }
56
57
  /* First test whether the input data is really suitable for this
58
     type.  This means, whether there is an integer number of records.
59
     Note that for this implementation the memory and file size of the
60
     data types are identical.  */
61
848
  size_t recsize = __libelf_type_sizes[ELFW(ELFCLASS,LIBELFBITS) - 1][src->d_type];
62
63
  /* We shouldn't require integer number of records when processing
64
     notes.  Payload bytes follow the header immediately, it's not an
65
     array of records as is the case otherwise.  */
66
848
  if (src->d_type != ELF_T_NHDR && src->d_type != ELF_T_NHDR8
67
848
      && src->d_size % recsize != 0)
68
639
    {
69
639
      __libelf_seterrno (ELF_E_INVALID_DATA);
70
639
      return NULL;
71
639
    }
72
73
  /* Next see whether the converted data fits in the output buffer.  */
74
209
  if (src->d_size > dest->d_size)
75
0
    {
76
0
      __libelf_seterrno (ELF_E_DEST_SIZE);
77
0
      return NULL;
78
0
    }
79
80
  /* Test the encode parameter.  */
81
209
  if (encode != ELFDATA2LSB && encode != ELFDATA2MSB)
82
0
    {
83
0
      __libelf_seterrno (ELF_E_INVALID_ENCODING);
84
0
      return NULL;
85
0
    }
86
87
  /* Determine the translation function to use.
88
89
     At this point we make an assumption which is valid for all
90
     existing implementations so far: the memory and file sizes are
91
     the same.  This has very important consequences:
92
     a) The requirement that the source and destination buffer can
93
  overlap can easily be fulfilled.
94
     b) We need only one function to convert from and memory to file
95
  and vice versa since the function only has to copy and/or
96
  change the byte order.
97
  */
98
209
  if ((BYTE_ORDER == LITTLE_ENDIAN && encode == ELFDATA2LSB)
99
0
      || (BYTE_ORDER == BIG_ENDIAN && encode == ELFDATA2MSB))
100
0
    {
101
      /* We simply have to copy since the byte order is the same.  */
102
0
      if (src->d_buf != dest->d_buf)
103
0
  memmove (dest->d_buf, src->d_buf, src->d_size);
104
0
    }
105
209
  else
106
209
    {
107
209
      xfct_t fctp;
108
209
      fctp = __elf_xfctstom[ELFW(ELFCLASS, LIBELFBITS) - 1][src->d_type];
109
110
      /* Do the real work.  */
111
209
      (*fctp) (dest->d_buf, src->d_buf, src->d_size, 1);
112
209
    }
113
114
  /* Now set the real destination type and length since the operation was
115
     successful.  */
116
209
  dest->d_type = src->d_type;
117
209
  dest->d_size = src->d_size;
118
119
209
  return dest;
120
209
}
121
INTDEF(elfw2(LIBELFBITS, xlatetof))