Coverage Report

Created: 2026-07-16 08:15

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/ninja/src/edit_distance.cc
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// Copyright 2011 Google Inc. All Rights Reserved.
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//
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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//     http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS,
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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#include "edit_distance.h"
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#include <algorithm>
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#include <vector>
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int EditDistance(const StringPiece& s1,
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                 const StringPiece& s2,
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                 bool allow_replacements,
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                 int max_edit_distance) {
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  // The algorithm implemented below is the "classic"
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  // dynamic-programming algorithm for computing the Levenshtein
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  // distance, which is described here:
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  //
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  //   http://en.wikipedia.org/wiki/Levenshtein_distance
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  //
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  // Although the algorithm is typically described using an m x n
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  // array, only one row plus one element are used at a time, so this
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  // implementation just keeps one vector for the row.  To update one entry,
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  // only the entries to the left, top, and top-left are needed.  The left
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  // entry is in row[x-1], the top entry is what's in row[x] from the last
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  // iteration, and the top-left entry is stored in previous.
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  int m = static_cast<int>(s1.len_);
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  int n = static_cast<int>(s2.len_);
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  std::vector<int> row(n + 1);
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  for (int i = 1; i <= n; ++i)
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    row[i] = i;
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  for (int y = 1; y <= m; ++y) {
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    row[0] = y;
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    int best_this_row = row[0];
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    int previous = y - 1;
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    for (int x = 1; x <= n; ++x) {
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      int old_row = row[x];
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      if (allow_replacements) {
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        row[x] = std::min(previous + (s1.str_[y - 1] == s2.str_[x - 1] ? 0 : 1),
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                          std::min(row[x - 1], row[x]) + 1);
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      }
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      else {
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        if (s1.str_[y - 1] == s2.str_[x - 1])
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          row[x] = previous;
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        else
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          row[x] = std::min(row[x - 1], row[x]) + 1;
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      }
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      previous = old_row;
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      best_this_row = std::min(best_this_row, row[x]);
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    }
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    if (max_edit_distance && best_this_row > max_edit_distance)
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      return max_edit_distance + 1;
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  }
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  return row[n];
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0
}