/src/openssl32/crypto/bn/bn_recp.c
Line  | Count  | Source (jump to first uncovered line)  | 
1  |  | /*  | 
2  |  |  * Copyright 1995-2023 The OpenSSL Project Authors. All Rights Reserved.  | 
3  |  |  *  | 
4  |  |  * Licensed under the Apache License 2.0 (the "License").  You may not use  | 
5  |  |  * this file except in compliance with the License.  You can obtain a copy  | 
6  |  |  * in the file LICENSE in the source distribution or at  | 
7  |  |  * https://www.openssl.org/source/license.html  | 
8  |  |  */  | 
9  |  |  | 
10  |  | #include "internal/cryptlib.h"  | 
11  |  | #include "bn_local.h"  | 
12  |  |  | 
13  |  | void BN_RECP_CTX_init(BN_RECP_CTX *recp)  | 
14  | 8.06k  | { | 
15  | 8.06k  |     memset(recp, 0, sizeof(*recp));  | 
16  | 8.06k  |     bn_init(&(recp->N));  | 
17  | 8.06k  |     bn_init(&(recp->Nr));  | 
18  | 8.06k  | }  | 
19  |  |  | 
20  |  | BN_RECP_CTX *BN_RECP_CTX_new(void)  | 
21  | 0  | { | 
22  | 0  |     BN_RECP_CTX *ret;  | 
23  |  | 
  | 
24  | 0  |     if ((ret = OPENSSL_zalloc(sizeof(*ret))) == NULL)  | 
25  | 0  |         return NULL;  | 
26  |  |  | 
27  | 0  |     bn_init(&(ret->N));  | 
28  | 0  |     bn_init(&(ret->Nr));  | 
29  | 0  |     ret->flags = BN_FLG_MALLOCED;  | 
30  | 0  |     return ret;  | 
31  | 0  | }  | 
32  |  |  | 
33  |  | void BN_RECP_CTX_free(BN_RECP_CTX *recp)  | 
34  | 8.06k  | { | 
35  | 8.06k  |     if (recp == NULL)  | 
36  | 0  |         return;  | 
37  | 8.06k  |     BN_free(&recp->N);  | 
38  | 8.06k  |     BN_free(&recp->Nr);  | 
39  | 8.06k  |     if (recp->flags & BN_FLG_MALLOCED)  | 
40  | 0  |         OPENSSL_free(recp);  | 
41  | 8.06k  | }  | 
42  |  |  | 
43  |  | int BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)  | 
44  | 8.06k  | { | 
45  | 8.06k  |     if (BN_is_zero(d) || !BN_copy(&(recp->N), d))  | 
46  | 0  |         return 0;  | 
47  | 8.06k  |     BN_zero(&(recp->Nr));  | 
48  | 8.06k  |     recp->num_bits = BN_num_bits(d);  | 
49  | 8.06k  |     recp->shift = 0;  | 
50  | 8.06k  |     return 1;  | 
51  | 8.06k  | }  | 
52  |  |  | 
53  |  | int BN_mod_mul_reciprocal(BIGNUM *r, const BIGNUM *x, const BIGNUM *y,  | 
54  |  |                           BN_RECP_CTX *recp, BN_CTX *ctx)  | 
55  | 427k  | { | 
56  | 427k  |     int ret = 0;  | 
57  | 427k  |     BIGNUM *a;  | 
58  | 427k  |     const BIGNUM *ca;  | 
59  |  |  | 
60  | 427k  |     BN_CTX_start(ctx);  | 
61  | 427k  |     if ((a = BN_CTX_get(ctx)) == NULL)  | 
62  | 0  |         goto err;  | 
63  | 427k  |     if (y != NULL) { | 
64  | 427k  |         if (x == y) { | 
65  | 335k  |             if (!BN_sqr(a, x, ctx))  | 
66  | 0  |                 goto err;  | 
67  | 335k  |         } else { | 
68  | 91.6k  |             if (!BN_mul(a, x, y, ctx))  | 
69  | 0  |                 goto err;  | 
70  | 91.6k  |         }  | 
71  | 427k  |         ca = a;  | 
72  | 427k  |     } else  | 
73  | 0  |         ca = x;                 /* Just do the mod */  | 
74  |  |  | 
75  | 427k  |     ret = BN_div_recp(NULL, r, ca, recp, ctx);  | 
76  | 427k  |  err:  | 
77  | 427k  |     BN_CTX_end(ctx);  | 
78  | 427k  |     bn_check_top(r);  | 
79  | 427k  |     return ret;  | 
80  | 427k  | }  | 
81  |  |  | 
82  |  | int BN_div_recp(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m,  | 
83  |  |                 BN_RECP_CTX *recp, BN_CTX *ctx)  | 
84  | 427k  | { | 
85  | 427k  |     int i, j, ret = 0;  | 
86  | 427k  |     BIGNUM *a, *b, *d, *r;  | 
87  |  |  | 
88  | 427k  |     BN_CTX_start(ctx);  | 
89  | 427k  |     d = (dv != NULL) ? dv : BN_CTX_get(ctx);  | 
90  | 427k  |     r = (rem != NULL) ? rem : BN_CTX_get(ctx);  | 
91  | 427k  |     a = BN_CTX_get(ctx);  | 
92  | 427k  |     b = BN_CTX_get(ctx);  | 
93  | 427k  |     if (b == NULL)  | 
94  | 0  |         goto err;  | 
95  |  |  | 
96  | 427k  |     if (BN_ucmp(m, &(recp->N)) < 0) { | 
97  | 110k  |         BN_zero(d);  | 
98  | 110k  |         if (!BN_copy(r, m)) { | 
99  | 0  |             BN_CTX_end(ctx);  | 
100  | 0  |             return 0;  | 
101  | 0  |         }  | 
102  | 110k  |         BN_CTX_end(ctx);  | 
103  | 110k  |         return 1;  | 
104  | 110k  |     }  | 
105  |  |  | 
106  |  |     /*  | 
107  |  |      * We want the remainder Given input of ABCDEF / ab we need multiply  | 
108  |  |      * ABCDEF by 3 digests of the reciprocal of ab  | 
109  |  |      */  | 
110  |  |  | 
111  |  |     /* i := max(BN_num_bits(m), 2*BN_num_bits(N)) */  | 
112  | 316k  |     i = BN_num_bits(m);  | 
113  | 316k  |     j = recp->num_bits << 1;  | 
114  | 316k  |     if (j > i)  | 
115  | 268k  |         i = j;  | 
116  |  |  | 
117  |  |     /* Nr := round(2^i / N) */  | 
118  | 316k  |     if (i != recp->shift)  | 
119  | 7.84k  |         recp->shift = BN_reciprocal(&(recp->Nr), &(recp->N), i, ctx);  | 
120  |  |     /* BN_reciprocal could have returned -1 for an error */  | 
121  | 316k  |     if (recp->shift == -1)  | 
122  | 0  |         goto err;  | 
123  |  |  | 
124  |  |     /*-  | 
125  |  |      * d := |round(round(m / 2^BN_num_bits(N)) * recp->Nr / 2^(i - BN_num_bits(N)))|  | 
126  |  |      *    = |round(round(m / 2^BN_num_bits(N)) * round(2^i / N) / 2^(i - BN_num_bits(N)))|  | 
127  |  |      *   <= |(m / 2^BN_num_bits(N)) * (2^i / N) * (2^BN_num_bits(N) / 2^i)|  | 
128  |  |      *    = |m/N|  | 
129  |  |      */  | 
130  | 316k  |     if (!BN_rshift(a, m, recp->num_bits))  | 
131  | 0  |         goto err;  | 
132  | 316k  |     if (!BN_mul(b, a, &(recp->Nr), ctx))  | 
133  | 0  |         goto err;  | 
134  | 316k  |     if (!BN_rshift(d, b, i - recp->num_bits))  | 
135  | 0  |         goto err;  | 
136  | 316k  |     d->neg = 0;  | 
137  |  |  | 
138  | 316k  |     if (!BN_mul(b, &(recp->N), d, ctx))  | 
139  | 0  |         goto err;  | 
140  | 316k  |     if (!BN_usub(r, m, b))  | 
141  | 0  |         goto err;  | 
142  | 316k  |     r->neg = 0;  | 
143  |  |  | 
144  | 316k  |     j = 0;  | 
145  | 536k  |     while (BN_ucmp(r, &(recp->N)) >= 0) { | 
146  | 220k  |         if (j++ > 2) { | 
147  | 0  |             ERR_raise(ERR_LIB_BN, BN_R_BAD_RECIPROCAL);  | 
148  | 0  |             goto err;  | 
149  | 0  |         }  | 
150  | 220k  |         if (!BN_usub(r, r, &(recp->N)))  | 
151  | 0  |             goto err;  | 
152  | 220k  |         if (!BN_add_word(d, 1))  | 
153  | 0  |             goto err;  | 
154  | 220k  |     }  | 
155  |  |  | 
156  | 316k  |     r->neg = BN_is_zero(r) ? 0 : m->neg;  | 
157  | 316k  |     d->neg = m->neg ^ recp->N.neg;  | 
158  | 316k  |     ret = 1;  | 
159  | 316k  |  err:  | 
160  | 316k  |     BN_CTX_end(ctx);  | 
161  | 316k  |     bn_check_top(dv);  | 
162  | 316k  |     bn_check_top(rem);  | 
163  | 316k  |     return ret;  | 
164  | 316k  | }  | 
165  |  |  | 
166  |  | /*  | 
167  |  |  * len is the expected size of the result We actually calculate with an extra  | 
168  |  |  * word of precision, so we can do faster division if the remainder is not  | 
169  |  |  * required.  | 
170  |  |  */  | 
171  |  | /* r := 2^len / m */  | 
172  |  | int BN_reciprocal(BIGNUM *r, const BIGNUM *m, int len, BN_CTX *ctx)  | 
173  | 7.84k  | { | 
174  | 7.84k  |     int ret = -1;  | 
175  | 7.84k  |     BIGNUM *t;  | 
176  |  |  | 
177  | 7.84k  |     BN_CTX_start(ctx);  | 
178  | 7.84k  |     if ((t = BN_CTX_get(ctx)) == NULL)  | 
179  | 0  |         goto err;  | 
180  |  |  | 
181  | 7.84k  |     if (!BN_set_bit(t, len))  | 
182  | 0  |         goto err;  | 
183  |  |  | 
184  | 7.84k  |     if (!BN_div(r, NULL, t, m, ctx))  | 
185  | 0  |         goto err;  | 
186  |  |  | 
187  | 7.84k  |     ret = len;  | 
188  | 7.84k  |  err:  | 
189  | 7.84k  |     bn_check_top(r);  | 
190  | 7.84k  |     BN_CTX_end(ctx);  | 
191  | 7.84k  |     return ret;  | 
192  | 7.84k  | }  |