Coverage Report

Created: 2025-11-09 06:26

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
Line
Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
33
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
1.45M
#define word0(x) (x)->L[1]
181
972k
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
3.84M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
66.1k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
554k
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
1.85M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
155k
#define Exp_shift  20
235
85.3k
#define Exp_shift1 20
236
412k
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
872k
#define Exp_mask  0x7ff00000
239
362k
#define P 53
240
#define Nbits 53
241
188k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
269k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
86.4k
#define Exp_1  0x3ff00000
246
38.4k
#define Exp_11 0x3ff00000
247
173k
#define Ebits 11
248
136k
#define Frac_mask  0xfffff
249
41.1k
#define Frac_mask1 0xfffff
250
1.10M
#define Ten_pmax 22
251
0
#define Bletch 0x10
252
59.1k
#define Bndry_mask  0xfffff
253
6.98k
#define Bndry_mask1 0xfffff
254
59.1k
#define Sign_bit 0x80000000
255
6.20k
#define Log2P 1
256
#define Tiny0 0
257
18.0k
#define Tiny1 1
258
42.6k
#define Quick_max 14
259
25.7k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
592k
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
4.30k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
2.68k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
14.0M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
5.39M
#define freelist interp->dtoa.freelist
336
206
#define private_mem interp->dtoa.preallocated
337
552
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
1.34M
{
344
1.34M
    int x;
345
1.34M
    Bigint *rv;
346
1.34M
    unsigned int len;
347
1.34M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
1.34M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
1.34M
        freelist[k] = rv->next;
351
206
    else {
352
206
        x = 1 << k;
353
206
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
206
            /sizeof(double);
355
206
        if (k <= Bigint_Kmax &&
356
206
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
206
        ) {
358
173
            rv = (Bigint*)pmem_next;
359
173
            pmem_next += len;
360
173
        }
361
33
        else {
362
33
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
33
            if (rv == NULL)
364
0
                return NULL;
365
33
        }
366
206
        rv->k = k;
367
206
        rv->maxwds = x;
368
206
    }
369
1.34M
    rv->sign = rv->wds = 0;
370
1.34M
    return rv;
371
1.34M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
4.11M
{
378
4.11M
    if (v) {
379
1.34M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
1.34M
        else {
382
1.34M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
1.34M
            v->next = freelist[v->k];
384
1.34M
            freelist[v->k] = v;
385
1.34M
        }
386
1.34M
    }
387
4.11M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
89.2k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
89.2k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
620k
{
445
620k
    int i, wds;
446
620k
    ULong *x;
447
620k
    ULLong carry, y;
448
620k
    Bigint *b1;
449
450
620k
    wds = b->wds;
451
620k
    x = b->x;
452
620k
    i = 0;
453
620k
    carry = a;
454
2.06M
    do {
455
2.06M
        y = *x * (ULLong)m + carry;
456
2.06M
        carry = y >> 32;
457
2.06M
        *x++ = (ULong)(y & FFFFFFFF);
458
2.06M
    }
459
2.06M
    while(++i < wds);
460
620k
    if (carry) {
461
40.4k
        if (wds >= b->maxwds) {
462
1.74k
            b1 = Balloc(b->k+1);
463
1.74k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
1.74k
            Bcopy(b1, b);
468
1.74k
            Bfree(b);
469
1.74k
            b = b1;
470
1.74k
        }
471
40.4k
        b->x[wds++] = (ULong)carry;
472
40.4k
        b->wds = wds;
473
40.4k
    }
474
620k
    return b;
475
620k
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
66.1k
{
486
66.1k
    Bigint *b;
487
66.1k
    int i, k;
488
66.1k
    Long x, y;
489
490
66.1k
    x = (nd + 8) / 9;
491
96.9k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
66.1k
    b = Balloc(k);
493
66.1k
    if (b == NULL)
494
0
        return NULL;
495
66.1k
    b->x[0] = y9;
496
66.1k
    b->wds = 1;
497
498
66.1k
    if (nd <= 9)
499
40.9k
      return b;
500
501
25.1k
    s += 9;
502
196k
    for (i = 9; i < nd0; i++) {
503
170k
        b = multadd(b, 10, *s++ - '0');
504
170k
        if (b == NULL)
505
0
            return NULL;
506
170k
    }
507
25.1k
    s++;
508
78.1k
    for(; i < nd; i++) {
509
52.9k
        b = multadd(b, 10, *s++ - '0');
510
52.9k
        if (b == NULL)
511
0
            return NULL;
512
52.9k
    }
513
25.1k
    return b;
514
25.1k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
111k
{
521
111k
    int k = 0;
522
523
111k
    if (!(x & 0xffff0000)) {
524
68.4k
        k = 16;
525
68.4k
        x <<= 16;
526
68.4k
    }
527
111k
    if (!(x & 0xff000000)) {
528
70.0k
        k += 8;
529
70.0k
        x <<= 8;
530
70.0k
    }
531
111k
    if (!(x & 0xf0000000)) {
532
68.1k
        k += 4;
533
68.1k
        x <<= 4;
534
68.1k
    }
535
111k
    if (!(x & 0xc0000000)) {
536
63.4k
        k += 2;
537
63.4k
        x <<= 2;
538
63.4k
    }
539
111k
    if (!(x & 0x80000000)) {
540
65.9k
        k++;
541
65.9k
        if (!(x & 0x40000000))
542
0
            return 32;
543
65.9k
    }
544
111k
    return k;
545
111k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
42.6k
{
553
42.6k
    int k;
554
42.6k
    ULong x = *y;
555
556
42.6k
    if (x & 7) {
557
24.5k
        if (x & 1)
558
13.0k
            return 0;
559
11.5k
        if (x & 2) {
560
7.25k
            *y = x >> 1;
561
7.25k
            return 1;
562
7.25k
        }
563
4.27k
        *y = x >> 2;
564
4.27k
        return 2;
565
11.5k
    }
566
18.1k
    k = 0;
567
18.1k
    if (!(x & 0xffff)) {
568
7.51k
        k = 16;
569
7.51k
        x >>= 16;
570
7.51k
    }
571
18.1k
    if (!(x & 0xff)) {
572
4.10k
        k += 8;
573
4.10k
        x >>= 8;
574
4.10k
    }
575
18.1k
    if (!(x & 0xf)) {
576
9.62k
        k += 4;
577
9.62k
        x >>= 4;
578
9.62k
    }
579
18.1k
    if (!(x & 0x3)) {
580
9.31k
        k += 2;
581
9.31k
        x >>= 2;
582
9.31k
    }
583
18.1k
    if (!(x & 1)) {
584
12.1k
        k++;
585
12.1k
        x >>= 1;
586
12.1k
        if (!x)
587
0
            return 32;
588
12.1k
    }
589
18.1k
    *y = x;
590
18.1k
    return k;
591
18.1k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
155k
{
598
155k
    Bigint *b;
599
600
155k
    b = Balloc(1);
601
155k
    if (b == NULL)
602
0
        return NULL;
603
155k
    b->x[0] = i;
604
155k
    b->wds = 1;
605
155k
    return b;
606
155k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
362k
{
614
362k
    Bigint *c;
615
362k
    int k, wa, wb, wc;
616
362k
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
362k
    ULong y;
618
362k
    ULLong carry, z;
619
620
362k
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
4.17k
        c = Balloc(0);
622
4.17k
        if (c == NULL)
623
0
            return NULL;
624
4.17k
        c->wds = 1;
625
4.17k
        c->x[0] = 0;
626
4.17k
        return c;
627
4.17k
    }
628
629
358k
    if (a->wds < b->wds) {
630
169k
        c = a;
631
169k
        a = b;
632
169k
        b = c;
633
169k
    }
634
358k
    k = a->k;
635
358k
    wa = a->wds;
636
358k
    wb = b->wds;
637
358k
    wc = wa + wb;
638
358k
    if (wc > a->maxwds)
639
153k
        k++;
640
358k
    c = Balloc(k);
641
358k
    if (c == NULL)
642
0
        return NULL;
643
3.41M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
3.05M
        *x = 0;
645
358k
    xa = a->x;
646
358k
    xae = xa + wa;
647
358k
    xb = b->x;
648
358k
    xbe = xb + wb;
649
358k
    xc0 = c->x;
650
1.13M
    for(; xb < xbe; xc0++) {
651
774k
        if ((y = *xb++)) {
652
769k
            x = xa;
653
769k
            xc = xc0;
654
769k
            carry = 0;
655
7.82M
            do {
656
7.82M
                z = *x++ * (ULLong)y + *xc + carry;
657
7.82M
                carry = z >> 32;
658
7.82M
                *xc++ = (ULong)(z & FFFFFFFF);
659
7.82M
            }
660
7.82M
            while(x < xae);
661
769k
            *xc = (ULong)carry;
662
769k
        }
663
774k
    }
664
614k
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
358k
    c->wds = wc;
666
358k
    return c;
667
358k
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
114k
{
678
114k
    Bigint *b1, *p5, **p5s;
679
114k
    int i;
680
114k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
114k
    assert(0 <= k && k < 1024);
688
689
114k
    if ((i = k & 3)) {
690
77.0k
        b = multadd(b, p05[i-1], 0);
691
77.0k
        if (b == NULL)
692
0
            return NULL;
693
77.0k
    }
694
695
114k
    if (!(k >>= 2))
696
10.3k
        return b;
697
104k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
104k
    p5s = interp->dtoa.p5s;
699
520k
    for(;;) {
700
520k
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
520k
        p5 = *p5s;
702
520k
        p5s++;
703
520k
        if (k & 1) {
704
303k
            b1 = mult(b, p5);
705
303k
            Bfree(b);
706
303k
            b = b1;
707
303k
            if (b == NULL)
708
0
                return NULL;
709
303k
        }
710
520k
        if (!(k >>= 1))
711
104k
            break;
712
520k
    }
713
104k
    return b;
714
104k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
288k
{
775
288k
    int i, k1, n, n1;
776
288k
    Bigint *b1;
777
288k
    ULong *x, *x1, *xe, z;
778
779
288k
    if (!k || (!b->x[0] && b->wds == 1))
780
4.57k
        return b;
781
782
283k
    n = k >> 5;
783
283k
    k1 = b->k;
784
283k
    n1 = n + b->wds + 1;
785
688k
    for(i = b->maxwds; n1 > i; i <<= 1)
786
405k
        k1++;
787
283k
    b1 = Balloc(k1);
788
283k
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
283k
    x1 = b1->x;
793
1.60M
    for(i = 0; i < n; i++)
794
1.32M
        *x1++ = 0;
795
283k
    x = b->x;
796
283k
    xe = x + b->wds;
797
283k
    if (k &= 0x1f) {
798
282k
        k1 = 32 - k;
799
282k
        z = 0;
800
1.41M
        do {
801
1.41M
            *x1++ = *x << k | z;
802
1.41M
            z = *x++ >> k1;
803
1.41M
        }
804
1.41M
        while(x < xe);
805
282k
        if ((*x1 = z))
806
42.4k
            ++n1;
807
282k
    }
808
1.70k
    else do
809
4.13k
             *x1++ = *x++;
810
4.13k
        while(x < xe);
811
283k
    b1->wds = n1 - 1;
812
283k
    Bfree(b);
813
283k
    return b1;
814
283k
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
816k
{
822
816k
    ULong *xa, *xa0, *xb, *xb0;
823
816k
    int i, j;
824
825
816k
    i = a->wds;
826
816k
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
816k
    if (i -= j)
834
174k
        return i;
835
642k
    xa0 = a->x;
836
642k
    xa = xa0 + j;
837
642k
    xb0 = b->x;
838
642k
    xb = xb0 + j;
839
778k
    for(;;) {
840
778k
        if (*--xa != *--xb)
841
623k
            return *xa < *xb ? -1 : 1;
842
155k
        if (xa <= xa0)
843
18.6k
            break;
844
155k
    }
845
18.6k
    return 0;
846
642k
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
207k
{
855
207k
    Bigint *c;
856
207k
    int i, wa, wb;
857
207k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
207k
    ULLong borrow, y;
859
860
207k
    i = cmp(a,b);
861
207k
    if (!i) {
862
3.79k
        c = Balloc(0);
863
3.79k
        if (c == NULL)
864
0
            return NULL;
865
3.79k
        c->wds = 1;
866
3.79k
        c->x[0] = 0;
867
3.79k
        return c;
868
3.79k
    }
869
203k
    if (i < 0) {
870
40.2k
        c = a;
871
40.2k
        a = b;
872
40.2k
        b = c;
873
40.2k
        i = 1;
874
40.2k
    }
875
163k
    else
876
163k
        i = 0;
877
203k
    c = Balloc(a->k);
878
203k
    if (c == NULL)
879
0
        return NULL;
880
203k
    c->sign = i;
881
203k
    wa = a->wds;
882
203k
    xa = a->x;
883
203k
    xae = xa + wa;
884
203k
    wb = b->wds;
885
203k
    xb = b->x;
886
203k
    xbe = xb + wb;
887
203k
    xc = c->x;
888
203k
    borrow = 0;
889
1.50M
    do {
890
1.50M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
1.50M
        borrow = y >> 32 & (ULong)1;
892
1.50M
        *xc++ = (ULong)(y & FFFFFFFF);
893
1.50M
    }
894
1.50M
    while(xb < xbe);
895
408k
    while(xa < xae) {
896
204k
        y = *xa++ - borrow;
897
204k
        borrow = y >> 32 & (ULong)1;
898
204k
        *xc++ = (ULong)(y & FFFFFFFF);
899
204k
    }
900
308k
    while(!*--xc)
901
104k
        wa--;
902
203k
    c->wds = wa;
903
203k
    return c;
904
203k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
37.2k
{
912
37.2k
    Long L;
913
37.2k
    U u;
914
915
37.2k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
37.2k
    word0(&u) = L;
917
37.2k
    word1(&u) = 0;
918
37.2k
    return dval(&u);
919
37.2k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
69.2k
{
926
69.2k
    ULong *xa, *xa0, w, y, z;
927
69.2k
    int k;
928
69.2k
    U d;
929
930
69.2k
    xa0 = a->x;
931
69.2k
    xa = xa0 + a->wds;
932
69.2k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
69.2k
    k = hi0bits(y);
937
69.2k
    *e = 32 - k;
938
69.2k
    if (k < Ebits) {
939
17.6k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
17.6k
        w = xa > xa0 ? *--xa : 0;
941
17.6k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
17.6k
        goto ret_d;
943
17.6k
    }
944
51.5k
    z = xa > xa0 ? *--xa : 0;
945
51.5k
    if (k -= Ebits) {
946
47.9k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
47.9k
        y = xa > xa0 ? *--xa : 0;
948
47.9k
        word1(&d) = z << k | y >> (32 - k);
949
47.9k
    }
950
3.62k
    else {
951
3.62k
        word0(&d) = Exp_1 | y;
952
3.62k
        word1(&d) = z;
953
3.62k
    }
954
69.2k
  ret_d:
955
69.2k
    return dval(&d);
956
51.5k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
93.8k
{
982
93.8k
    Bigint *b;
983
984
93.8k
    b = Balloc(1);
985
93.8k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
93.8k
    b->wds = 2;
990
93.8k
    b->x[0] = word1(d);
991
93.8k
    b->x[1] = word0(d) & Frac_mask;
992
93.8k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
93.8k
    if (*e < Etiny)
994
4.57k
        *e = Etiny;
995
89.2k
    else
996
89.2k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
93.8k
    if (scale && (b->x[0] || b->x[1])) {
1000
27.8k
        *e -= scale;
1001
27.8k
        if (*e < Etiny) {
1002
24.5k
            scale = Etiny - *e;
1003
24.5k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
24.5k
            assert(0 < scale && scale <= P - 1);
1006
24.5k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
11.9k
                assert(b->x[0] == 0);
1009
11.9k
                b->x[0] = b->x[1];
1010
11.9k
                b->x[1] = 0;
1011
11.9k
                scale -= 32;
1012
11.9k
            }
1013
24.5k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
23.0k
                assert(b->x[0] << (32 - scale) == 0);
1016
23.0k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
23.0k
                b->x[1] >>= scale;
1018
23.0k
            }
1019
24.5k
        }
1020
27.8k
    }
1021
    /* Ensure b is normalized. */
1022
93.8k
    if (!b->x[1])
1023
20.2k
        b->wds = 1;
1024
1025
93.8k
    return b;
1026
93.8k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
42.6k
{
1040
42.6k
    Bigint *b;
1041
42.6k
    int de, k;
1042
42.6k
    ULong *x, y, z;
1043
42.6k
    int i;
1044
1045
42.6k
    b = Balloc(1);
1046
42.6k
    if (b == NULL)
1047
0
        return NULL;
1048
42.6k
    x = b->x;
1049
1050
42.6k
    z = word0(d) & Frac_mask;
1051
42.6k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
42.6k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
38.4k
        z |= Exp_msk1;
1054
42.6k
    if ((y = word1(d))) {
1055
31.1k
        if ((k = lo0bits(&y))) {
1056
18.6k
            x[0] = y | z << (32 - k);
1057
18.6k
            z >>= k;
1058
18.6k
        }
1059
12.4k
        else
1060
12.4k
            x[0] = y;
1061
31.1k
        i =
1062
31.1k
            b->wds = (x[1] = z) ? 2 : 1;
1063
31.1k
    }
1064
11.5k
    else {
1065
11.5k
        k = lo0bits(&z);
1066
11.5k
        x[0] = z;
1067
11.5k
        i =
1068
11.5k
            b->wds = 1;
1069
11.5k
        k += 32;
1070
11.5k
    }
1071
42.6k
    if (de) {
1072
38.4k
        *e = de - Bias - (P-1) + k;
1073
38.4k
        *bits = P - k;
1074
38.4k
    }
1075
4.20k
    else {
1076
4.20k
        *e = de - Bias - (P-1) + 1 + k;
1077
4.20k
        *bits = 32*i - hi0bits(x[i-1]);
1078
4.20k
    }
1079
42.6k
    return b;
1080
42.6k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
34.6k
{
1088
34.6k
    U da, db;
1089
34.6k
    int k, ka, kb;
1090
1091
34.6k
    dval(&da) = b2d(a, &ka);
1092
34.6k
    dval(&db) = b2d(b, &kb);
1093
34.6k
    k = ka - kb + 32*(a->wds - b->wds);
1094
34.6k
    if (k > 0)
1095
21.9k
        word0(&da) += k*Exp_msk1;
1096
12.6k
    else {
1097
12.6k
        k = -k;
1098
12.6k
        word0(&db) += k*Exp_msk1;
1099
12.6k
    }
1100
34.6k
    return dval(&da) / dval(&db);
1101
34.6k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
22.0k
#define Scale_Bit 0x10
1119
22.9k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
38.3k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
38.3k
{
1129
38.3k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
38.3k
    if (p2 > 0)
1131
23.6k
        rv -= p2;
1132
38.3k
    return rv & kmask;
1133
38.3k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
253k
{
1142
253k
    int n;
1143
253k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
253k
    ULLong borrow, carry, y, ys;
1145
1146
253k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
253k
    if (b->wds < n)
1152
6.90k
        return 0;
1153
246k
    sx = S->x;
1154
246k
    sxe = sx + --n;
1155
246k
    bx = b->x;
1156
246k
    bxe = bx + n;
1157
246k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
246k
    if (q) {
1163
197k
        borrow = 0;
1164
197k
        carry = 0;
1165
1.11M
        do {
1166
1.11M
            ys = *sx++ * (ULLong)q + carry;
1167
1.11M
            carry = ys >> 32;
1168
1.11M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
1.11M
            borrow = y >> 32 & (ULong)1;
1170
1.11M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
1.11M
        }
1172
1.11M
        while(sx <= sxe);
1173
197k
        if (!*bxe) {
1174
892
            bx = b->x;
1175
892
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
892
            b->wds = n;
1178
892
        }
1179
197k
    }
1180
246k
    if (cmp(b, S) >= 0) {
1181
18.5k
        q++;
1182
18.5k
        borrow = 0;
1183
18.5k
        carry = 0;
1184
18.5k
        bx = b->x;
1185
18.5k
        sx = S->x;
1186
109k
        do {
1187
109k
            ys = *sx++ + carry;
1188
109k
            carry = ys >> 32;
1189
109k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
109k
            borrow = y >> 32 & (ULong)1;
1191
109k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
109k
        }
1193
109k
        while(sx <= sxe);
1194
18.5k
        bx = b->x;
1195
18.5k
        bxe = bx + n;
1196
18.5k
        if (!*bxe) {
1197
19.2k
            while(--bxe > bx && !*bxe)
1198
1.60k
                --n;
1199
17.6k
            b->wds = n;
1200
17.6k
        }
1201
18.5k
    }
1202
246k
    return q;
1203
253k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
3.07k
{
1214
3.07k
    U u;
1215
1216
3.07k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
401
        word0(&u) = (P+2)*Exp_msk1;
1219
401
        word1(&u) = 0;
1220
401
        return u.d;
1221
401
    }
1222
2.67k
    else {
1223
2.67k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
2.67k
        return ulp(x);
1225
2.67k
    }
1226
3.07k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
7.31k
{
1277
7.31k
    Bigint *b, *d;
1278
7.31k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
7.31k
    nd = bc->nd;
1281
7.31k
    nd0 = bc->nd0;
1282
7.31k
    p5 = nd + bc->e0;
1283
7.31k
    b = sd2b(rv, bc->scale, &p2);
1284
7.31k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
7.31k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
7.31k
    b = lshift(b, 1);
1294
7.31k
    if (b == NULL)
1295
0
        return -1;
1296
7.31k
    b->x[0] |= 1;
1297
7.31k
    p2--;
1298
1299
7.31k
    p2 -= p5;
1300
7.31k
    d = i2b(1);
1301
7.31k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
7.31k
    if (p5 > 0) {
1309
4.99k
        d = pow5mult(d, p5);
1310
4.99k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
4.99k
    }
1315
2.31k
    else if (p5 < 0) {
1316
1.49k
        b = pow5mult(b, -p5);
1317
1.49k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
1.49k
    }
1322
7.31k
    if (p2 > 0) {
1323
3.86k
        b2 = p2;
1324
3.86k
        d2 = 0;
1325
3.86k
    }
1326
3.44k
    else {
1327
3.44k
        b2 = 0;
1328
3.44k
        d2 = -p2;
1329
3.44k
    }
1330
7.31k
    i = dshift(d, d2);
1331
7.31k
    if ((b2 += i) > 0) {
1332
7.05k
        b = lshift(b, b2);
1333
7.05k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
7.05k
    }
1338
7.31k
    if ((d2 += i) > 0) {
1339
6.56k
        d = lshift(d, d2);
1340
6.56k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
6.56k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
7.31k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
832
        dd = -1;
1352
6.48k
    else {
1353
6.48k
        i = 0;
1354
132k
        for(;;) {
1355
132k
            b = multadd(b, 10, 0);
1356
132k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
132k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
132k
            i++;
1362
1363
132k
            if (dd)
1364
4.95k
                break;
1365
127k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
852
                dd = i < nd;
1368
852
                break;
1369
852
            }
1370
126k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
672
                dd = -1;
1373
672
                break;
1374
672
            }
1375
126k
        }
1376
6.48k
    }
1377
7.31k
    Bfree(b);
1378
7.31k
    Bfree(d);
1379
7.31k
    if (dd > 0 || (dd == 0 && odd))
1380
1.61k
        dval(rv) += sulp(rv, bc);
1381
7.31k
    return 0;
1382
7.31k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
619k
{
1388
619k
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
619k
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
619k
    const char *s, *s0, *s1;
1391
619k
    double aadj, aadj1;
1392
619k
    U aadj2, adj, rv, rv0;
1393
619k
    ULong y, z, abs_exp;
1394
619k
    Long L;
1395
619k
    BCinfo bc;
1396
619k
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
619k
    size_t ndigits, fraclen;
1398
619k
    double result;
1399
1400
619k
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
619k
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
619k
    sign = 0;
1407
619k
    switch (c) {
1408
492k
    case '-':
1409
492k
        sign = 1;
1410
492k
        _Py_FALLTHROUGH;
1411
492k
    case '+':
1412
492k
        c = *++s;
1413
619k
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
619k
    s1 = s;
1417
636k
    while (c == '0')
1418
17.3k
        c = *++s;
1419
619k
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
619k
    s0 = s1 = s;
1426
5.12M
    while ('0' <= c && c <= '9')
1427
4.50M
        c = *++s;
1428
619k
    ndigits = s - s1;
1429
619k
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
619k
    if (c == '.') {
1433
61.9k
        c = *++s;
1434
61.9k
        if (!ndigits) {
1435
21.1k
            s1 = s;
1436
1.59M
            while (c == '0')
1437
1.57M
                c = *++s;
1438
21.1k
            lz = lz || s != s1;
1439
21.1k
            fraclen += (s - s1);
1440
21.1k
            s0 = s;
1441
21.1k
        }
1442
61.9k
        s1 = s;
1443
17.0M
        while ('0' <= c && c <= '9')
1444
16.9M
            c = *++s;
1445
61.9k
        ndigits += s - s1;
1446
61.9k
        fraclen += s - s1;
1447
61.9k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
619k
    if (!ndigits && !lz) {
1453
19
        if (se)
1454
19
            *se = (char *)s00;
1455
19
        goto parse_error;
1456
19
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
618k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
618k
    nd = (int)ndigits;
1466
618k
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
618k
    e = 0;
1470
618k
    if (c == 'e' || c == 'E') {
1471
554k
        s00 = s;
1472
554k
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
554k
        esign = 0;
1476
554k
        switch (c) {
1477
25.4k
        case '-':
1478
25.4k
            esign = 1;
1479
25.4k
            _Py_FALLTHROUGH;
1480
36.8k
        case '+':
1481
36.8k
            c = *++s;
1482
554k
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
554k
        s1 = s;
1486
558k
        while (c == '0')
1487
4.44k
            c = *++s;
1488
554k
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
554k
        s1 = s;
1492
554k
        abs_exp = 0;
1493
2.33M
        while ('0' <= c && c <= '9') {
1494
1.78M
            abs_exp = 10*abs_exp + (c - '0');
1495
1.78M
            c = *++s;
1496
1.78M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
554k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
6.29k
            e = (int)MAX_ABS_EXP;
1503
548k
        else
1504
548k
            e = (int)abs_exp;
1505
554k
        if (esign)
1506
25.4k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
554k
        if (s == s1 && !lz)
1510
0
            s = s00;
1511
554k
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
618k
    e -= nd - nd0;
1515
618k
    if (nd0 <= 0)
1516
24.5k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
618k
    if (se)
1520
618k
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
618k
    if (!nd)
1525
9.20k
        goto ret;
1526
2.77M
    for (i = nd; i > 0; ) {
1527
2.77M
        --i;
1528
2.77M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
609k
            ++i;
1530
609k
            break;
1531
609k
        }
1532
2.77M
    }
1533
609k
    e += nd - i;
1534
609k
    nd = i;
1535
609k
    if (nd0 > nd)
1536
8.12k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
609k
    bc.e0 = e1 = e;
1575
609k
    y = z = 0;
1576
1.80M
    for (i = 0; i < nd; i++) {
1577
1.21M
        if (i < 9)
1578
980k
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
232k
        else if (i < DBL_DIG+1)
1580
211k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
21.4k
        else
1582
21.4k
            break;
1583
1.21M
    }
1584
1585
609k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
609k
    dval(&rv) = y;
1587
609k
    if (k > 9) {
1588
36.3k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
36.3k
    }
1590
609k
    if (nd <= DBL_DIG
1591
581k
        && Flt_Rounds == 1
1592
609k
        ) {
1593
581k
        if (!e)
1594
12.9k
            goto ret;
1595
568k
        if (e > 0) {
1596
525k
            if (e <= Ten_pmax) {
1597
22.6k
                dval(&rv) *= tens[e];
1598
22.6k
                goto ret;
1599
22.6k
            }
1600
503k
            i = DBL_DIG - nd;
1601
503k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
3.12k
                e -= i;
1606
3.12k
                dval(&rv) *= tens[i];
1607
3.12k
                dval(&rv) *= tens[e];
1608
3.12k
                goto ret;
1609
3.12k
            }
1610
503k
        }
1611
43.0k
        else if (e >= -Ten_pmax) {
1612
25.0k
            dval(&rv) /= tens[-e];
1613
25.0k
            goto ret;
1614
25.0k
        }
1615
568k
    }
1616
545k
    e1 += nd - k;
1617
1618
545k
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
545k
    if (e1 > 0) {
1623
512k
        if ((i = e1 & 15))
1624
499k
            dval(&rv) *= tens[i];
1625
512k
        if (e1 &= ~15) {
1626
506k
            if (e1 > DBL_MAX_10_EXP)
1627
478k
                goto ovfl;
1628
27.8k
            e1 >>= 4;
1629
76.3k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
48.5k
                if (e1 & 1)
1631
22.0k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
27.8k
            word0(&rv) -= P*Exp_msk1;
1634
27.8k
            dval(&rv) *= bigtens[j];
1635
27.8k
            if ((z = word0(&rv) & Exp_mask)
1636
27.8k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
541
                goto ovfl;
1638
27.3k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
505
                word0(&rv) = Big0;
1642
505
                word1(&rv) = Big1;
1643
505
            }
1644
26.8k
            else
1645
26.8k
                word0(&rv) += P*Exp_msk1;
1646
27.3k
        }
1647
512k
    }
1648
33.1k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
29.2k
        e1 = -e1;
1660
29.2k
        if ((i = e1 & 15))
1661
25.0k
            dval(&rv) /= tens[i];
1662
29.2k
        if (e1 >>= 4) {
1663
22.9k
            if (e1 >= 1 << n_bigtens)
1664
903
                goto undfl;
1665
22.0k
            if (e1 & Scale_Bit)
1666
17.1k
                bc.scale = 2*P;
1667
115k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
93.3k
                if (e1 & 1)
1669
54.3k
                    dval(&rv) *= tinytens[j];
1670
22.0k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
17.1k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
15.8k
                if (j >= 32) {
1674
9.17k
                    word1(&rv) = 0;
1675
9.17k
                    if (j >= 53)
1676
4.69k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
4.48k
                    else
1678
4.48k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
9.17k
                }
1680
6.63k
                else
1681
6.63k
                    word1(&rv) &= 0xffffffff << j;
1682
15.8k
            }
1683
22.0k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
22.0k
        }
1686
29.2k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
66.1k
    bc.nd = nd;
1693
66.1k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
66.1k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
62.5k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
62.5k
            --i;
1708
62.5k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
10.2k
                ++i;
1710
10.2k
                break;
1711
10.2k
            }
1712
62.5k
        }
1713
10.2k
        e += nd - i;
1714
10.2k
        nd = i;
1715
10.2k
        if (nd0 > nd)
1716
7.31k
            nd0 = nd;
1717
10.2k
        if (nd < 9) { /* must recompute y */
1718
4.02k
            y = 0;
1719
21.4k
            for(i = 0; i < nd0; ++i)
1720
17.3k
                y = 10*y + s0[i] - '0';
1721
11.6k
            for(; i < nd; ++i)
1722
7.63k
                y = 10*y + s0[i+1] - '0';
1723
4.02k
        }
1724
10.2k
    }
1725
66.1k
    bd0 = s2b(s0, nd0, nd, y);
1726
66.1k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
86.4k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
86.4k
        bd = Balloc(bd0->k);
1758
86.4k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
86.4k
        Bcopy(bd, bd0);
1762
86.4k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
86.4k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
86.4k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
86.4k
        bs = i2b(1);
1772
86.4k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
86.4k
        if (e >= 0) {
1777
40.0k
            bb2 = bb5 = 0;
1778
40.0k
            bd2 = bd5 = e;
1779
40.0k
        }
1780
46.4k
        else {
1781
46.4k
            bb2 = bb5 = -e;
1782
46.4k
            bd2 = bd5 = 0;
1783
46.4k
        }
1784
86.4k
        if (bbe >= 0)
1785
41.8k
            bb2 += bbe;
1786
44.6k
        else
1787
44.6k
            bd2 -= bbe;
1788
86.4k
        bs2 = bb2;
1789
86.4k
        bb2++;
1790
86.4k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
86.4k
        i = bb2 < bd2 ? bb2 : bd2;
1811
86.4k
        if (i > bs2)
1812
44.5k
            i = bs2;
1813
86.4k
        if (i > 0) {
1814
85.6k
            bb2 -= i;
1815
85.6k
            bd2 -= i;
1816
85.6k
            bs2 -= i;
1817
85.6k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
86.4k
        if (bb5 > 0) {
1821
46.4k
            bs = pow5mult(bs, bb5);
1822
46.4k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
46.4k
            Bigint *bb1 = mult(bs, bb);
1826
46.4k
            Bfree(bb);
1827
46.4k
            bb = bb1;
1828
46.4k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
46.4k
        }
1832
86.4k
        if (bb2 > 0) {
1833
86.4k
            bb = lshift(bb, bb2);
1834
86.4k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
86.4k
        }
1838
86.4k
        if (bd5 > 0) {
1839
33.2k
            bd = pow5mult(bd, bd5);
1840
33.2k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
33.2k
        }
1844
86.4k
        if (bd2 > 0) {
1845
44.5k
            bd = lshift(bd, bd2);
1846
44.5k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
44.5k
        }
1850
86.4k
        if (bs2 > 0) {
1851
37.6k
            bs = lshift(bs, bs2);
1852
37.6k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
37.6k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
86.4k
        delta = diff(bb, bd);
1862
86.4k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
86.4k
        dsign = delta->sign;
1866
86.4k
        delta->sign = 0;
1867
86.4k
        i = cmp(delta, bs);
1868
86.4k
        if (bc.nd > nd && i <= 0) {
1869
10.2k
            if (dsign)
1870
6.43k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
3.77k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
1.15k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
1.15k
                if (j - bc.scale >= 2) {
1890
879
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
879
                    break; /* Use bigcomp. */
1892
879
                }
1893
1.15k
            }
1894
1895
2.89k
            {
1896
2.89k
                bc.nd = nd;
1897
2.89k
                i = -1; /* Discarded digits make delta smaller. */
1898
2.89k
            }
1899
2.89k
        }
1900
1901
79.1k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
40.9k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
4.90k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
40.9k
                ) {
1908
37.5k
                break;
1909
37.5k
            }
1910
3.47k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
452
                break;
1913
452
            }
1914
3.02k
            delta = lshift(delta,Log2P);
1915
3.02k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
3.02k
            if (cmp(delta, bs) > 0)
1919
981
                goto drop_down;
1920
2.03k
            break;
1921
3.02k
        }
1922
38.1k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
3.55k
            if (dsign) {
1925
2.00k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
856
                    &&  word1(&rv) == (
1927
856
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
856
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
492
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
492
                        + Exp_msk1
1934
492
                        ;
1935
492
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
492
                    break;
1938
492
                }
1939
2.00k
            }
1940
1.55k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
981
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
981
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
981
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
981
                word0(&rv) = L | Bndry_mask1;
1958
981
                word1(&rv) = 0xffffffff;
1959
981
                break;
1960
981
            }
1961
3.06k
            if (!odd)
1962
2.49k
                break;
1963
575
            if (dsign)
1964
337
                dval(&rv) += sulp(&rv, &bc);
1965
238
            else {
1966
238
                dval(&rv) -= sulp(&rv, &bc);
1967
238
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
238
            }
1973
            /* dsign = 1 - dsign; */
1974
575
            break;
1975
575
        }
1976
34.6k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
24.1k
            if (dsign)
1978
10.9k
                aadj = aadj1 = 1.;
1979
13.2k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
9.03k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
9.03k
                aadj = 1.;
1986
9.03k
                aadj1 = -1.;
1987
9.03k
            }
1988
4.17k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
4.17k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
4.17k
                else
1995
4.17k
                    aadj *= 0.5;
1996
4.17k
                aadj1 = -aadj;
1997
4.17k
            }
1998
24.1k
        }
1999
10.4k
        else {
2000
10.4k
            aadj *= 0.5;
2001
10.4k
            aadj1 = dsign ? aadj : -aadj;
2002
10.4k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
10.4k
        }
2005
34.6k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
34.6k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
2.15k
            dval(&rv0) = dval(&rv);
2011
2.15k
            word0(&rv) -= P*Exp_msk1;
2012
2.15k
            adj.d = aadj1 * ulp(&rv);
2013
2.15k
            dval(&rv) += adj.d;
2014
2.15k
            if ((word0(&rv) & Exp_mask) >=
2015
2.15k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
1.61k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
1.06k
                    goto ovfl;
2018
1.06k
                }
2019
557
                word0(&rv) = Big0;
2020
557
                word1(&rv) = Big1;
2021
557
                goto cont;
2022
1.61k
            }
2023
533
            else
2024
533
                word0(&rv) += P*Exp_msk1;
2025
2.15k
        }
2026
32.4k
        else {
2027
32.4k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
12.9k
                if (aadj <= 0x7fffffff) {
2029
12.9k
                    if ((z = (ULong)aadj) <= 0)
2030
728
                        z = 1;
2031
12.9k
                    aadj = z;
2032
12.9k
                    aadj1 = dsign ? aadj : -aadj;
2033
12.9k
                }
2034
12.9k
                dval(&aadj2) = aadj1;
2035
12.9k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
12.9k
                aadj1 = dval(&aadj2);
2037
12.9k
            }
2038
32.4k
            adj.d = aadj1 * ulp(&rv);
2039
32.4k
            dval(&rv) += adj.d;
2040
32.4k
        }
2041
33.0k
        z = word0(&rv) & Exp_mask;
2042
33.0k
        if (bc.nd == nd) {
2043
28.8k
            if (!bc.scale)
2044
15.8k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
14.0k
                    L = (Long)aadj;
2047
14.0k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
14.0k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
14.0k
                        if (aadj < .4999999 || aadj > .5000001)
2051
13.1k
                            break;
2052
14.0k
                    }
2053
15
                    else if (aadj < .4999999/FLT_RADIX)
2054
15
                        break;
2055
14.0k
                }
2056
28.8k
        }
2057
20.3k
      cont:
2058
20.3k
        Bfree(bb); bb = NULL;
2059
20.3k
        Bfree(bd); bd = NULL;
2060
20.3k
        Bfree(bs); bs = NULL;
2061
20.3k
        Bfree(delta); delta = NULL;
2062
20.3k
    }
2063
65.0k
    if (bc.nd > nd) {
2064
7.31k
        error = bigcomp(&rv, s0, &bc);
2065
7.31k
        if (error)
2066
0
            goto failed_malloc;
2067
7.31k
    }
2068
2069
65.0k
    if (bc.scale) {
2070
17.1k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
17.1k
        word1(&rv0) = 0;
2072
17.1k
        dval(&rv) *= dval(&rv0);
2073
17.1k
    }
2074
2075
138k
  ret:
2076
138k
    result = sign ? -dval(&rv) : dval(&rv);
2077
138k
    goto done;
2078
2079
19
  parse_error:
2080
19
    result = 0.0;
2081
19
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
903
  undfl:
2089
903
    result = sign ? -0.0 : 0.0;
2090
903
    goto done;
2091
2092
480k
  ovfl:
2093
480k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
480k
    word0(&rv) = Exp_mask;
2096
480k
    word1(&rv) = 0;
2097
480k
    result = sign ? -dval(&rv) : dval(&rv);
2098
480k
    goto done;
2099
2100
619k
  done:
2101
619k
    Bfree(bb);
2102
619k
    Bfree(bd);
2103
619k
    Bfree(bs);
2104
619k
    Bfree(bd0);
2105
619k
    Bfree(delta);
2106
619k
    return result;
2107
2108
65.0k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
47.2k
{
2113
47.2k
    int j, k, *r;
2114
2115
47.2k
    j = sizeof(ULong);
2116
47.2k
    for(k = 0;
2117
47.2k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
47.2k
        j <<= 1)
2119
0
        k++;
2120
47.2k
    r = (int*)Balloc(k);
2121
47.2k
    if (r == NULL)
2122
0
        return NULL;
2123
47.2k
    *r = k;
2124
47.2k
    return (char *)(r+1);
2125
47.2k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
4.56k
{
2130
4.56k
    char *rv, *t;
2131
2132
4.56k
    rv = rv_alloc(n);
2133
4.56k
    if (rv == NULL)
2134
0
        return NULL;
2135
4.56k
    t = rv;
2136
12.5k
    while((*t = *s++)) t++;
2137
4.56k
    if (rve)
2138
4.56k
        *rve = t;
2139
4.56k
    return rv;
2140
4.56k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
47.2k
{
2151
47.2k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
47.2k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
47.2k
    Bfree(b);
2154
47.2k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
47.2k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
47.2k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
47.2k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
47.2k
        spec_case, try_quick;
2235
47.2k
    Long L;
2236
47.2k
    int denorm;
2237
47.2k
    ULong x;
2238
47.2k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
47.2k
    U d2, eps, u;
2240
47.2k
    double ds;
2241
47.2k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
47.2k
    mlo = mhi = S = 0;
2246
47.2k
    s0 = 0;
2247
2248
47.2k
    u.d = dd;
2249
47.2k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
11.9k
        *sign = 1;
2252
11.9k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
11.9k
    }
2254
35.3k
    else
2255
35.3k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
47.2k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
483
    {
2260
        /* Infinity or NaN */
2261
483
        *decpt = 9999;
2262
483
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
483
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
483
    }
2266
46.7k
    if (!dval(&u)) {
2267
4.08k
        *decpt = 1;
2268
4.08k
        return nrv_alloc("0", rve, 1);
2269
4.08k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
42.6k
    b = d2b(&u, &be, &bbits);
2274
42.6k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
42.6k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
38.4k
        dval(&d2) = dval(&u);
2278
38.4k
        word0(&d2) &= Frac_mask1;
2279
38.4k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
38.4k
        i -= Bias;
2304
38.4k
        denorm = 0;
2305
38.4k
    }
2306
4.20k
    else {
2307
        /* d is denormalized */
2308
2309
4.20k
        i = bbits + be + (Bias + (P-1) - 1);
2310
4.20k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
4.20k
            : word1(&u) << (32 - i);
2312
4.20k
        dval(&d2) = x;
2313
4.20k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
4.20k
        i -= (Bias + (P-1) - 1) + 1;
2315
4.20k
        denorm = 1;
2316
4.20k
    }
2317
42.6k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
42.6k
        i*0.301029995663981;
2319
42.6k
    k = (int)ds;
2320
42.6k
    if (ds < 0. && ds != k)
2321
12.3k
        k--;    /* want k = floor(ds) */
2322
42.6k
    k_check = 1;
2323
42.6k
    if (k >= 0 && k <= Ten_pmax) {
2324
20.0k
        if (dval(&u) < tens[k])
2325
2.67k
            k--;
2326
20.0k
        k_check = 0;
2327
20.0k
    }
2328
42.6k
    j = bbits - i - 1;
2329
42.6k
    if (j >= 0) {
2330
18.5k
        b2 = 0;
2331
18.5k
        s2 = j;
2332
18.5k
    }
2333
24.0k
    else {
2334
24.0k
        b2 = -j;
2335
24.0k
        s2 = 0;
2336
24.0k
    }
2337
42.6k
    if (k >= 0) {
2338
29.6k
        b5 = 0;
2339
29.6k
        s5 = k;
2340
29.6k
        s2 += k;
2341
29.6k
    }
2342
13.0k
    else {
2343
13.0k
        b2 -= k;
2344
13.0k
        b5 = -k;
2345
13.0k
        s5 = 0;
2346
13.0k
    }
2347
42.6k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
42.6k
    try_quick = 1;
2351
2352
42.6k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
42.6k
    leftright = 1;
2357
42.6k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
42.6k
    switch(mode) {
2360
42.6k
    case 0:
2361
42.6k
    case 1:
2362
42.6k
        i = 18;
2363
42.6k
        ndigits = 0;
2364
42.6k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
0
    case 3:
2374
0
        leftright = 0;
2375
0
        _Py_FALLTHROUGH;
2376
0
    case 5:
2377
0
        i = ndigits + k + 1;
2378
0
        ilim = i;
2379
0
        ilim1 = i - 1;
2380
0
        if (i <= 0)
2381
0
            i = 1;
2382
42.6k
    }
2383
42.6k
    s0 = rv_alloc(i);
2384
42.6k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
42.6k
    s = s0;
2387
2388
2389
42.6k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
0
        i = 0;
2394
0
        dval(&d2) = dval(&u);
2395
0
        k0 = k;
2396
0
        ilim0 = ilim;
2397
0
        ieps = 2; /* conservative */
2398
0
        if (k > 0) {
2399
0
            ds = tens[k&0xf];
2400
0
            j = k >> 4;
2401
0
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
0
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
0
            dval(&u) /= ds;
2413
0
        }
2414
0
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
0
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
0
        dval(&eps) = ieps*dval(&u) + 7.;
2431
0
        word0(&eps) -= (P-1)*Exp_msk1;
2432
0
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
0
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
0
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
0
            dval(&eps) *= tens[ilim-1];
2463
0
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
0
                L = (Long)(dval(&u));
2465
0
                if (!(dval(&u) -= L))
2466
0
                    ilim = i;
2467
0
                *s++ = '0' + (int)L;
2468
0
                if (i == ilim) {
2469
0
                    if (dval(&u) > 0.5 + dval(&eps))
2470
0
                        goto bump_up;
2471
0
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
0
                        while(*--s == '0');
2473
0
                        s++;
2474
0
                        goto ret1;
2475
0
                    }
2476
0
                    break;
2477
0
                }
2478
0
            }
2479
0
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
42.6k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
11.6k
        ds = tens[k];
2492
11.6k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
18.2k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
18.2k
            L = (Long)(dval(&u) / ds);
2500
18.2k
            dval(&u) -= L*ds;
2501
18.2k
            *s++ = '0' + (int)L;
2502
18.2k
            if (!dval(&u)) {
2503
11.6k
                break;
2504
11.6k
            }
2505
6.67k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
0
                  bump_up:
2509
0
                    while(*--s == '9')
2510
0
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
0
                    ++*s++;
2516
0
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
0
                break;
2526
0
            }
2527
6.67k
        }
2528
11.6k
        goto ret1;
2529
11.6k
    }
2530
2531
31.0k
    m2 = b2;
2532
31.0k
    m5 = b5;
2533
31.0k
    if (leftright) {
2534
31.0k
        i =
2535
31.0k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
31.0k
            1 + P - bbits;
2537
31.0k
        b2 += i;
2538
31.0k
        s2 += i;
2539
31.0k
        mhi = i2b(1);
2540
31.0k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
31.0k
    }
2543
31.0k
    if (m2 > 0 && s2 > 0) {
2544
27.1k
        i = m2 < s2 ? m2 : s2;
2545
27.1k
        b2 -= i;
2546
27.1k
        m2 -= i;
2547
27.1k
        s2 -= i;
2548
27.1k
    }
2549
31.0k
    if (b5 > 0) {
2550
13.0k
        if (leftright) {
2551
13.0k
            if (m5 > 0) {
2552
13.0k
                mhi = pow5mult(mhi, m5);
2553
13.0k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
13.0k
                b1 = mult(mhi, b);
2556
13.0k
                Bfree(b);
2557
13.0k
                b = b1;
2558
13.0k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
13.0k
            }
2561
13.0k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
13.0k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
13.0k
    }
2573
31.0k
    S = i2b(1);
2574
31.0k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
31.0k
    if (s5 > 0) {
2577
15.5k
        S = pow5mult(S, s5);
2578
15.5k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
15.5k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
31.0k
    spec_case = 0;
2585
31.0k
    if ((mode < 2 || leftright)
2586
31.0k
        ) {
2587
31.0k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.32k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
31.0k
            ) {
2590
            /* The special case */
2591
1.06k
            b2 += Log2P;
2592
1.06k
            s2 += Log2P;
2593
1.06k
            spec_case = 1;
2594
1.06k
        }
2595
31.0k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
31.0k
#define iInc 28
2605
31.0k
    i = dshift(S, s2);
2606
31.0k
    b2 += i;
2607
31.0k
    m2 += i;
2608
31.0k
    s2 += i;
2609
31.0k
    if (b2 > 0) {
2610
31.0k
        b = lshift(b, b2);
2611
31.0k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
31.0k
    }
2614
31.0k
    if (s2 > 0) {
2615
30.4k
        S = lshift(S, s2);
2616
30.4k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
30.4k
    }
2619
31.0k
    if (k_check) {
2620
22.6k
        if (cmp(b,S) < 0) {
2621
2.14k
            k--;
2622
2.14k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
2.14k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
2.14k
            if (leftright) {
2626
2.14k
                mhi = multadd(mhi, 10, 0);
2627
2.14k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
2.14k
            }
2630
2.14k
            ilim = ilim1;
2631
2.14k
        }
2632
22.6k
    }
2633
31.0k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
31.0k
    if (leftright) {
2653
31.0k
        if (m2 > 0) {
2654
30.1k
            mhi = lshift(mhi, m2);
2655
30.1k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
30.1k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
31.0k
        mlo = mhi;
2664
31.0k
        if (spec_case) {
2665
1.06k
            mhi = Balloc(mhi->k);
2666
1.06k
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
1.06k
            Bcopy(mhi, mlo);
2669
1.06k
            mhi = lshift(mhi, Log2P);
2670
1.06k
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
1.06k
        }
2673
2674
121k
        for(i = 1;;i++) {
2675
121k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
121k
            j = cmp(b, mlo);
2680
121k
            delta = diff(S, mhi);
2681
121k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
121k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
121k
            Bfree(delta);
2685
121k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
121k
                ) {
2687
2.47k
                if (dig == '9')
2688
395
                    goto round_9_up;
2689
2.07k
                if (j > 0)
2690
897
                    dig++;
2691
2.07k
                *s++ = dig;
2692
2.07k
                goto ret;
2693
2.47k
            }
2694
118k
            if (j < 0 || (j == 0 && mode != 1
2695
1.82k
                          && !(word1(&u) & 1)
2696
101k
                    )) {
2697
17.9k
                if (!b->x[0] && b->wds <= 1) {
2698
2.77k
                    goto accept_dig;
2699
2.77k
                }
2700
15.1k
                if (j1 > 0) {
2701
3.03k
                    b = lshift(b, 1);
2702
3.03k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
3.03k
                    j1 = cmp(b, S);
2705
3.03k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.81k
                        && dig++ == '9')
2707
299
                        goto round_9_up;
2708
3.03k
                }
2709
17.6k
              accept_dig:
2710
17.6k
                *s++ = dig;
2711
17.6k
                goto ret;
2712
15.1k
            }
2713
100k
            if (j1 > 0) {
2714
10.6k
                if (dig == '9') { /* possible if i == 1 */
2715
2.08k
                  round_9_up:
2716
2.08k
                    *s++ = '9';
2717
2.08k
                    goto roundoff;
2718
1.39k
                }
2719
9.24k
                *s++ = dig + 1;
2720
9.24k
                goto ret;
2721
10.6k
            }
2722
90.0k
            *s++ = dig;
2723
90.0k
            if (i == ilim)
2724
0
                break;
2725
90.0k
            b = multadd(b, 10, 0);
2726
90.0k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
90.0k
            if (mlo == mhi) {
2729
87.0k
                mlo = mhi = multadd(mhi, 10, 0);
2730
87.0k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
87.0k
            }
2733
3.00k
            else {
2734
3.00k
                mlo = multadd(mlo, 10, 0);
2735
3.00k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
3.00k
                mhi = multadd(mhi, 10, 0);
2738
3.00k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
3.00k
            }
2741
90.0k
        }
2742
31.0k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
2.08k
      roundoff:
2764
2.08k
        while(*--s == '9')
2765
2.08k
            if (s == s0) {
2766
2.08k
                k++;
2767
2.08k
                *s++ = '1';
2768
2.08k
                goto ret;
2769
2.08k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
31.0k
  ret:
2777
31.0k
    Bfree(S);
2778
31.0k
    if (mhi) {
2779
31.0k
        if (mlo && mlo != mhi)
2780
1.06k
            Bfree(mlo);
2781
31.0k
        Bfree(mhi);
2782
31.0k
    }
2783
42.6k
  ret1:
2784
42.6k
    Bfree(b);
2785
42.6k
    *s = 0;
2786
42.6k
    *decpt = k + 1;
2787
42.6k
    if (rve)
2788
42.6k
        *rve = s;
2789
42.6k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
31.0k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
16
{
2809
16
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
16
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
16
    Bigint *p5 = i2b(625);
2814
16
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
16
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
128
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
112
        p5 = mult(p5, p5);
2822
112
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
112
        p5s[i] = p5;
2826
112
    }
2827
2828
16
#endif
2829
16
    return PyStatus_Ok();
2830
16
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}