Coverage Report

Created: 2025-12-14 07:06

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
Line
Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
56
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
2.60M
#define word0(x) (x)->L[1]
181
1.71M
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
5.39M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
173k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
671k
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
2.28M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
324k
#define Exp_shift  20
235
82.9k
#define Exp_shift1 20
236
1.17M
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
1.37M
#define Exp_mask  0x7ff00000
239
809k
#define P 53
240
#define Nbits 53
241
444k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
610k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
234k
#define Exp_1  0x3ff00000
246
37.2k
#define Exp_11 0x3ff00000
247
636k
#define Ebits 11
248
303k
#define Frac_mask  0xfffff
249
39.1k
#define Frac_mask1 0xfffff
250
1.27M
#define Ten_pmax 22
251
92
#define Bletch 0x10
252
87.1k
#define Bndry_mask  0xfffff
253
6.62k
#define Bndry_mask1 0xfffff
254
58.1k
#define Sign_bit 0x80000000
255
6.13k
#define Log2P 1
256
#define Tiny0 0
257
136k
#define Tiny1 1
258
41.5k
#define Quick_max 14
259
24.5k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
692k
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
2.97k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
1.88k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
25.1M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
11.3M
#define freelist interp->dtoa.freelist
336
363
#define private_mem interp->dtoa.preallocated
337
977
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
2.84M
{
344
2.84M
    int x;
345
2.84M
    Bigint *rv;
346
2.84M
    unsigned int len;
347
2.84M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
2.84M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
2.84M
        freelist[k] = rv->next;
351
363
    else {
352
363
        x = 1 << k;
353
363
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
363
            /sizeof(double);
355
363
        if (k <= Bigint_Kmax &&
356
363
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
363
        ) {
358
307
            rv = (Bigint*)pmem_next;
359
307
            pmem_next += len;
360
307
        }
361
56
        else {
362
56
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
56
            if (rv == NULL)
364
0
                return NULL;
365
56
        }
366
363
        rv->k = k;
367
363
        rv->maxwds = x;
368
363
    }
369
2.84M
    rv->sign = rv->wds = 0;
370
2.84M
    return rv;
371
2.84M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
5.78M
{
378
5.78M
    if (v) {
379
2.84M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
2.84M
        else {
382
2.84M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
2.84M
            v->next = freelist[v->k];
384
2.84M
            freelist[v->k] = v;
385
2.84M
        }
386
2.84M
    }
387
5.78M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
228k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
228k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
1.61M
{
445
1.61M
    int i, wds;
446
1.61M
    ULong *x;
447
1.61M
    ULLong carry, y;
448
1.61M
    Bigint *b1;
449
450
1.61M
    wds = b->wds;
451
1.61M
    x = b->x;
452
1.61M
    i = 0;
453
1.61M
    carry = a;
454
5.70M
    do {
455
5.70M
        y = *x * (ULLong)m + carry;
456
5.70M
        carry = y >> 32;
457
5.70M
        *x++ = (ULong)(y & FFFFFFFF);
458
5.70M
    }
459
5.70M
    while(++i < wds);
460
1.61M
    if (carry) {
461
93.7k
        if (wds >= b->maxwds) {
462
6.36k
            b1 = Balloc(b->k+1);
463
6.36k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
6.36k
            Bcopy(b1, b);
468
6.36k
            Bfree(b);
469
6.36k
            b = b1;
470
6.36k
        }
471
93.7k
        b->x[wds++] = (ULong)carry;
472
93.7k
        b->wds = wds;
473
93.7k
    }
474
1.61M
    return b;
475
1.61M
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
173k
{
486
173k
    Bigint *b;
487
173k
    int i, k;
488
173k
    Long x, y;
489
490
173k
    x = (nd + 8) / 9;
491
235k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
173k
    b = Balloc(k);
493
173k
    if (b == NULL)
494
0
        return NULL;
495
173k
    b->x[0] = y9;
496
173k
    b->wds = 1;
497
498
173k
    if (nd <= 9)
499
126k
      return b;
500
501
47.1k
    s += 9;
502
465k
    for (i = 9; i < nd0; i++) {
503
418k
        b = multadd(b, 10, *s++ - '0');
504
418k
        if (b == NULL)
505
0
            return NULL;
506
418k
    }
507
47.1k
    s++;
508
177k
    for(; i < nd; i++) {
509
129k
        b = multadd(b, 10, *s++ - '0');
510
129k
        if (b == NULL)
511
0
            return NULL;
512
129k
    }
513
47.1k
    return b;
514
47.1k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
291k
{
521
291k
    int k = 0;
522
523
291k
    if (!(x & 0xffff0000)) {
524
134k
        k = 16;
525
134k
        x <<= 16;
526
134k
    }
527
291k
    if (!(x & 0xff000000)) {
528
155k
        k += 8;
529
155k
        x <<= 8;
530
155k
    }
531
291k
    if (!(x & 0xf0000000)) {
532
168k
        k += 4;
533
168k
        x <<= 4;
534
168k
    }
535
291k
    if (!(x & 0xc0000000)) {
536
173k
        k += 2;
537
173k
        x <<= 2;
538
173k
    }
539
291k
    if (!(x & 0x80000000)) {
540
128k
        k++;
541
128k
        if (!(x & 0x40000000))
542
0
            return 32;
543
128k
    }
544
291k
    return k;
545
291k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
41.4k
{
553
41.4k
    int k;
554
41.4k
    ULong x = *y;
555
556
41.4k
    if (x & 7) {
557
23.5k
        if (x & 1)
558
12.8k
            return 0;
559
10.6k
        if (x & 2) {
560
6.85k
            *y = x >> 1;
561
6.85k
            return 1;
562
6.85k
        }
563
3.81k
        *y = x >> 2;
564
3.81k
        return 2;
565
10.6k
    }
566
17.9k
    k = 0;
567
17.9k
    if (!(x & 0xffff)) {
568
7.92k
        k = 16;
569
7.92k
        x >>= 16;
570
7.92k
    }
571
17.9k
    if (!(x & 0xff)) {
572
3.98k
        k += 8;
573
3.98k
        x >>= 8;
574
3.98k
    }
575
17.9k
    if (!(x & 0xf)) {
576
9.68k
        k += 4;
577
9.68k
        x >>= 4;
578
9.68k
    }
579
17.9k
    if (!(x & 0x3)) {
580
9.16k
        k += 2;
581
9.16k
        x >>= 2;
582
9.16k
    }
583
17.9k
    if (!(x & 1)) {
584
11.8k
        k++;
585
11.8k
        x >>= 1;
586
11.8k
        if (!x)
587
0
            return 32;
588
11.8k
    }
589
17.9k
    *y = x;
590
17.9k
    return k;
591
17.9k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
322k
{
598
322k
    Bigint *b;
599
600
322k
    b = Balloc(1);
601
322k
    if (b == NULL)
602
0
        return NULL;
603
322k
    b->x[0] = i;
604
322k
    b->wds = 1;
605
322k
    return b;
606
322k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
781k
{
614
781k
    Bigint *c;
615
781k
    int k, wa, wb, wc;
616
781k
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
781k
    ULong y;
618
781k
    ULLong carry, z;
619
620
781k
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
4.68k
        c = Balloc(0);
622
4.68k
        if (c == NULL)
623
0
            return NULL;
624
4.68k
        c->wds = 1;
625
4.68k
        c->x[0] = 0;
626
4.68k
        return c;
627
4.68k
    }
628
629
777k
    if (a->wds < b->wds) {
630
406k
        c = a;
631
406k
        a = b;
632
406k
        b = c;
633
406k
    }
634
777k
    k = a->k;
635
777k
    wa = a->wds;
636
777k
    wb = b->wds;
637
777k
    wc = wa + wb;
638
777k
    if (wc > a->maxwds)
639
470k
        k++;
640
777k
    c = Balloc(k);
641
777k
    if (c == NULL)
642
0
        return NULL;
643
5.79M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
5.02M
        *x = 0;
645
777k
    xa = a->x;
646
777k
    xae = xa + wa;
647
777k
    xb = b->x;
648
777k
    xbe = xb + wb;
649
777k
    xc0 = c->x;
650
2.32M
    for(; xb < xbe; xc0++) {
651
1.54M
        if ((y = *xb++)) {
652
1.53M
            x = xa;
653
1.53M
            xc = xc0;
654
1.53M
            carry = 0;
655
11.1M
            do {
656
11.1M
                z = *x++ * (ULLong)y + *xc + carry;
657
11.1M
                carry = z >> 32;
658
11.1M
                *xc++ = (ULong)(z & FFFFFFFF);
659
11.1M
            }
660
11.1M
            while(x < xae);
661
1.53M
            *xc = (ULong)carry;
662
1.53M
        }
663
1.54M
    }
664
1.29M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
777k
    c->wds = wc;
666
777k
    return c;
667
777k
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
282k
{
678
282k
    Bigint *b1, *p5, **p5s;
679
282k
    int i;
680
282k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
282k
    assert(0 <= k && k < 1024);
688
689
282k
    if ((i = k & 3)) {
690
189k
        b = multadd(b, p05[i-1], 0);
691
189k
        if (b == NULL)
692
0
            return NULL;
693
189k
    }
694
695
282k
    if (!(k >>= 2))
696
11.4k
        return b;
697
271k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
271k
    p5s = interp->dtoa.p5s;
699
1.21M
    for(;;) {
700
1.21M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
1.21M
        p5 = *p5s;
702
1.21M
        p5s++;
703
1.21M
        if (k & 1) {
704
709k
            b1 = mult(b, p5);
705
709k
            Bfree(b);
706
709k
            b = b1;
707
709k
            if (b == NULL)
708
0
                return NULL;
709
709k
        }
710
1.21M
        if (!(k >>= 1))
711
271k
            break;
712
1.21M
    }
713
271k
    return b;
714
271k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
656k
{
775
656k
    int i, k1, n, n1;
776
656k
    Bigint *b1;
777
656k
    ULong *x, *x1, *xe, z;
778
779
656k
    if (!k || (!b->x[0] && b->wds == 1))
780
5.18k
        return b;
781
782
651k
    n = k >> 5;
783
651k
    k1 = b->k;
784
651k
    n1 = n + b->wds + 1;
785
1.59M
    for(i = b->maxwds; n1 > i; i <<= 1)
786
945k
        k1++;
787
651k
    b1 = Balloc(k1);
788
651k
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
651k
    x1 = b1->x;
793
3.09M
    for(i = 0; i < n; i++)
794
2.43M
        *x1++ = 0;
795
651k
    x = b->x;
796
651k
    xe = x + b->wds;
797
651k
    if (k &= 0x1f) {
798
643k
        k1 = 32 - k;
799
643k
        z = 0;
800
2.14M
        do {
801
2.14M
            *x1++ = *x << k | z;
802
2.14M
            z = *x++ >> k1;
803
2.14M
        }
804
2.14M
        while(x < xe);
805
643k
        if ((*x1 = z))
806
113k
            ++n1;
807
643k
    }
808
8.23k
    else do
809
16.0k
             *x1++ = *x++;
810
16.0k
        while(x < xe);
811
651k
    b1->wds = n1 - 1;
812
651k
    Bfree(b);
813
651k
    return b1;
814
651k
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
1.63M
{
822
1.63M
    ULong *xa, *xa0, *xb, *xb0;
823
1.63M
    int i, j;
824
825
1.63M
    i = a->wds;
826
1.63M
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
1.63M
    if (i -= j)
834
168k
        return i;
835
1.47M
    xa0 = a->x;
836
1.47M
    xa = xa0 + j;
837
1.47M
    xb0 = b->x;
838
1.47M
    xb = xb0 + j;
839
1.82M
    for(;;) {
840
1.82M
        if (*--xa != *--xb)
841
1.45M
            return *xa < *xb ? -1 : 1;
842
375k
        if (xa <= xa0)
843
17.6k
            break;
844
375k
    }
845
17.6k
    return 0;
846
1.47M
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
333k
{
855
333k
    Bigint *c;
856
333k
    int i, wa, wb;
857
333k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
333k
    ULLong borrow, y;
859
860
333k
    i = cmp(a,b);
861
333k
    if (!i) {
862
3.46k
        c = Balloc(0);
863
3.46k
        if (c == NULL)
864
0
            return NULL;
865
3.46k
        c->wds = 1;
866
3.46k
        c->x[0] = 0;
867
3.46k
        return c;
868
3.46k
    }
869
329k
    if (i < 0) {
870
89.8k
        c = a;
871
89.8k
        a = b;
872
89.8k
        b = c;
873
89.8k
        i = 1;
874
89.8k
    }
875
240k
    else
876
240k
        i = 0;
877
329k
    c = Balloc(a->k);
878
329k
    if (c == NULL)
879
0
        return NULL;
880
329k
    c->sign = i;
881
329k
    wa = a->wds;
882
329k
    xa = a->x;
883
329k
    xae = xa + wa;
884
329k
    wb = b->wds;
885
329k
    xb = b->x;
886
329k
    xbe = xb + wb;
887
329k
    xc = c->x;
888
329k
    borrow = 0;
889
2.35M
    do {
890
2.35M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
2.35M
        borrow = y >> 32 & (ULong)1;
892
2.35M
        *xc++ = (ULong)(y & FFFFFFFF);
893
2.35M
    }
894
2.35M
    while(xb < xbe);
895
546k
    while(xa < xae) {
896
216k
        y = *xa++ - borrow;
897
216k
        borrow = y >> 32 & (ULong)1;
898
216k
        *xc++ = (ULong)(y & FFFFFFFF);
899
216k
    }
900
650k
    while(!*--xc)
901
320k
        wa--;
902
329k
    c->wds = wa;
903
329k
    return c;
904
329k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
111k
{
912
111k
    Long L;
913
111k
    U u;
914
915
111k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
111k
    word0(&u) = L;
917
111k
    word1(&u) = 0;
918
111k
    return dval(&u);
919
111k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
216k
{
926
216k
    ULong *xa, *xa0, w, y, z;
927
216k
    int k;
928
216k
    U d;
929
930
216k
    xa0 = a->x;
931
216k
    xa = xa0 + a->wds;
932
216k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
216k
    k = hi0bits(y);
937
216k
    *e = 32 - k;
938
216k
    if (k < Ebits) {
939
101k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
101k
        w = xa > xa0 ? *--xa : 0;
941
101k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
101k
        goto ret_d;
943
101k
    }
944
114k
    z = xa > xa0 ? *--xa : 0;
945
114k
    if (k -= Ebits) {
946
109k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
109k
        y = xa > xa0 ? *--xa : 0;
948
109k
        word1(&d) = z << k | y >> (32 - k);
949
109k
    }
950
4.63k
    else {
951
4.63k
        word0(&d) = Exp_1 | y;
952
4.63k
        word1(&d) = z;
953
4.63k
    }
954
216k
  ret_d:
955
216k
    return dval(&d);
956
114k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
262k
{
982
262k
    Bigint *b;
983
984
262k
    b = Balloc(1);
985
262k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
262k
    b->wds = 2;
990
262k
    b->x[0] = word1(d);
991
262k
    b->x[1] = word0(d) & Frac_mask;
992
262k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
262k
    if (*e < Etiny)
994
5.18k
        *e = Etiny;
995
257k
    else
996
257k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
262k
    if (scale && (b->x[0] || b->x[1])) {
1000
28.9k
        *e -= scale;
1001
28.9k
        if (*e < Etiny) {
1002
25.5k
            scale = Etiny - *e;
1003
25.5k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
25.5k
            assert(0 < scale && scale <= P - 1);
1006
25.5k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
12.5k
                assert(b->x[0] == 0);
1009
12.5k
                b->x[0] = b->x[1];
1010
12.5k
                b->x[1] = 0;
1011
12.5k
                scale -= 32;
1012
12.5k
            }
1013
25.5k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
24.0k
                assert(b->x[0] << (32 - scale) == 0);
1016
24.0k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
24.0k
                b->x[1] >>= scale;
1018
24.0k
            }
1019
25.5k
        }
1020
28.9k
    }
1021
    /* Ensure b is normalized. */
1022
262k
    if (!b->x[1])
1023
21.3k
        b->wds = 1;
1024
1025
262k
    return b;
1026
262k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
41.4k
{
1040
41.4k
    Bigint *b;
1041
41.4k
    int de, k;
1042
41.4k
    ULong *x, y, z;
1043
41.4k
    int i;
1044
1045
41.4k
    b = Balloc(1);
1046
41.4k
    if (b == NULL)
1047
0
        return NULL;
1048
41.4k
    x = b->x;
1049
1050
41.4k
    z = word0(d) & Frac_mask;
1051
41.4k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
41.4k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
37.2k
        z |= Exp_msk1;
1054
41.4k
    if ((y = word1(d))) {
1055
30.3k
        if ((k = lo0bits(&y))) {
1056
18.0k
            x[0] = y | z << (32 - k);
1057
18.0k
            z >>= k;
1058
18.0k
        }
1059
12.2k
        else
1060
12.2k
            x[0] = y;
1061
30.3k
        i =
1062
30.3k
            b->wds = (x[1] = z) ? 2 : 1;
1063
30.3k
    }
1064
11.1k
    else {
1065
11.1k
        k = lo0bits(&z);
1066
11.1k
        x[0] = z;
1067
11.1k
        i =
1068
11.1k
            b->wds = 1;
1069
11.1k
        k += 32;
1070
11.1k
    }
1071
41.4k
    if (de) {
1072
37.2k
        *e = de - Bias - (P-1) + k;
1073
37.2k
        *bits = P - k;
1074
37.2k
    }
1075
4.22k
    else {
1076
4.22k
        *e = de - Bias - (P-1) + 1 + k;
1077
4.22k
        *bits = 32*i - hi0bits(x[i-1]);
1078
4.22k
    }
1079
41.4k
    return b;
1080
41.4k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
108k
{
1088
108k
    U da, db;
1089
108k
    int k, ka, kb;
1090
1091
108k
    dval(&da) = b2d(a, &ka);
1092
108k
    dval(&db) = b2d(b, &kb);
1093
108k
    k = ka - kb + 32*(a->wds - b->wds);
1094
108k
    if (k > 0)
1095
33.5k
        word0(&da) += k*Exp_msk1;
1096
74.6k
    else {
1097
74.6k
        k = -k;
1098
74.6k
        word0(&db) += k*Exp_msk1;
1099
74.6k
    }
1100
108k
    return dval(&da) / dval(&db);
1101
108k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
24.5k
#define Scale_Bit 0x10
1119
25.6k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
71.3k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
71.3k
{
1129
71.3k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
71.3k
    if (p2 > 0)
1131
24.4k
        rv -= p2;
1132
71.3k
    return rv & kmask;
1133
71.3k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
819k
{
1142
819k
    int n;
1143
819k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
819k
    ULLong borrow, carry, y, ys;
1145
1146
819k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
819k
    if (b->wds < n)
1152
26.5k
        return 0;
1153
792k
    sx = S->x;
1154
792k
    sxe = sx + --n;
1155
792k
    bx = b->x;
1156
792k
    bxe = bx + n;
1157
792k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
792k
    if (q) {
1163
505k
        borrow = 0;
1164
505k
        carry = 0;
1165
2.61M
        do {
1166
2.61M
            ys = *sx++ * (ULLong)q + carry;
1167
2.61M
            carry = ys >> 32;
1168
2.61M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
2.61M
            borrow = y >> 32 & (ULong)1;
1170
2.61M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
2.61M
        }
1172
2.61M
        while(sx <= sxe);
1173
505k
        if (!*bxe) {
1174
2.11k
            bx = b->x;
1175
2.11k
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
2.11k
            b->wds = n;
1178
2.11k
        }
1179
505k
    }
1180
792k
    if (cmp(b, S) >= 0) {
1181
42.7k
        q++;
1182
42.7k
        borrow = 0;
1183
42.7k
        carry = 0;
1184
42.7k
        bx = b->x;
1185
42.7k
        sx = S->x;
1186
243k
        do {
1187
243k
            ys = *sx++ + carry;
1188
243k
            carry = ys >> 32;
1189
243k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
243k
            borrow = y >> 32 & (ULong)1;
1191
243k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
243k
        }
1193
243k
        while(sx <= sxe);
1194
42.7k
        bx = b->x;
1195
42.7k
        bxe = bx + n;
1196
42.7k
        if (!*bxe) {
1197
28.0k
            while(--bxe > bx && !*bxe)
1198
1.59k
                --n;
1199
26.4k
            b->wds = n;
1200
26.4k
        }
1201
42.7k
    }
1202
792k
    return q;
1203
819k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
3.57k
{
1214
3.57k
    U u;
1215
1216
3.57k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
399
        word0(&u) = (P+2)*Exp_msk1;
1219
399
        word1(&u) = 0;
1220
399
        return u.d;
1221
399
    }
1222
3.18k
    else {
1223
3.18k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
3.18k
        return ulp(x);
1225
3.18k
    }
1226
3.57k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
41.2k
{
1277
41.2k
    Bigint *b, *d;
1278
41.2k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
41.2k
    nd = bc->nd;
1281
41.2k
    nd0 = bc->nd0;
1282
41.2k
    p5 = nd + bc->e0;
1283
41.2k
    b = sd2b(rv, bc->scale, &p2);
1284
41.2k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
41.2k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
41.2k
    b = lshift(b, 1);
1294
41.2k
    if (b == NULL)
1295
0
        return -1;
1296
41.2k
    b->x[0] |= 1;
1297
41.2k
    p2--;
1298
1299
41.2k
    p2 -= p5;
1300
41.2k
    d = i2b(1);
1301
41.2k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
41.2k
    if (p5 > 0) {
1309
38.8k
        d = pow5mult(d, p5);
1310
38.8k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
38.8k
    }
1315
2.36k
    else if (p5 < 0) {
1316
1.68k
        b = pow5mult(b, -p5);
1317
1.68k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
1.68k
    }
1322
41.2k
    if (p2 > 0) {
1323
36.6k
        b2 = p2;
1324
36.6k
        d2 = 0;
1325
36.6k
    }
1326
4.56k
    else {
1327
4.56k
        b2 = 0;
1328
4.56k
        d2 = -p2;
1329
4.56k
    }
1330
41.2k
    i = dshift(d, d2);
1331
41.2k
    if ((b2 += i) > 0) {
1332
40.9k
        b = lshift(b, b2);
1333
40.9k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
40.9k
    }
1338
41.2k
    if ((d2 += i) > 0) {
1339
40.4k
        d = lshift(d, d2);
1340
40.4k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
40.4k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
41.2k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
939
        dd = -1;
1352
40.3k
    else {
1353
40.3k
        i = 0;
1354
707k
        for(;;) {
1355
707k
            b = multadd(b, 10, 0);
1356
707k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
707k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
707k
            i++;
1362
1363
707k
            if (dd)
1364
38.8k
                break;
1365
668k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
836
                dd = i < nd;
1368
836
                break;
1369
836
            }
1370
667k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
665
                dd = -1;
1373
665
                break;
1374
665
            }
1375
667k
        }
1376
40.3k
    }
1377
41.2k
    Bfree(b);
1378
41.2k
    Bfree(d);
1379
41.2k
    if (dd > 0 || (dd == 0 && odd))
1380
1.93k
        dval(rv) += sulp(rv, bc);
1381
41.2k
    return 0;
1382
41.2k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
762k
{
1388
762k
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
762k
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
762k
    const char *s, *s0, *s1;
1391
762k
    double aadj, aadj1;
1392
762k
    U aadj2, adj, rv, rv0;
1393
762k
    ULong y, z, abs_exp;
1394
762k
    Long L;
1395
762k
    BCinfo bc;
1396
762k
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
762k
    size_t ndigits, fraclen;
1398
762k
    double result;
1399
1400
762k
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
762k
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
762k
    sign = 0;
1407
762k
    switch (c) {
1408
508k
    case '-':
1409
508k
        sign = 1;
1410
508k
        _Py_FALLTHROUGH;
1411
508k
    case '+':
1412
508k
        c = *++s;
1413
762k
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
762k
    s1 = s;
1417
784k
    while (c == '0')
1418
21.8k
        c = *++s;
1419
762k
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
762k
    s0 = s1 = s;
1426
7.74M
    while ('0' <= c && c <= '9')
1427
6.98M
        c = *++s;
1428
762k
    ndigits = s - s1;
1429
762k
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
762k
    if (c == '.') {
1433
88.4k
        c = *++s;
1434
88.4k
        if (!ndigits) {
1435
23.8k
            s1 = s;
1436
1.67M
            while (c == '0')
1437
1.65M
                c = *++s;
1438
23.8k
            lz = lz || s != s1;
1439
23.8k
            fraclen += (s - s1);
1440
23.8k
            s0 = s;
1441
23.8k
        }
1442
88.4k
        s1 = s;
1443
26.7M
        while ('0' <= c && c <= '9')
1444
26.6M
            c = *++s;
1445
88.4k
        ndigits += s - s1;
1446
88.4k
        fraclen += s - s1;
1447
88.4k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
762k
    if (!ndigits && !lz) {
1453
21
        if (se)
1454
21
            *se = (char *)s00;
1455
21
        goto parse_error;
1456
21
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
762k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
762k
    nd = (int)ndigits;
1466
762k
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
762k
    e = 0;
1470
762k
    if (c == 'e' || c == 'E') {
1471
671k
        s00 = s;
1472
671k
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
671k
        esign = 0;
1476
671k
        switch (c) {
1477
28.3k
        case '-':
1478
28.3k
            esign = 1;
1479
28.3k
            _Py_FALLTHROUGH;
1480
39.0k
        case '+':
1481
39.0k
            c = *++s;
1482
671k
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
671k
        s1 = s;
1486
846k
        while (c == '0')
1487
174k
            c = *++s;
1488
671k
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
671k
        s1 = s;
1492
671k
        abs_exp = 0;
1493
6.10M
        while ('0' <= c && c <= '9') {
1494
5.43M
            abs_exp = 10*abs_exp + (c - '0');
1495
5.43M
            c = *++s;
1496
5.43M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
671k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
6.35k
            e = (int)MAX_ABS_EXP;
1503
664k
        else
1504
664k
            e = (int)abs_exp;
1505
671k
        if (esign)
1506
28.3k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
671k
        if (s == s1 && !lz)
1510
0
            s = s00;
1511
671k
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
762k
    e -= nd - nd0;
1515
762k
    if (nd0 <= 0)
1516
28.4k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
762k
    if (se)
1520
762k
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
762k
    if (!nd)
1525
10.7k
        goto ret;
1526
6.73M
    for (i = nd; i > 0; ) {
1527
6.73M
        --i;
1528
6.73M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
751k
            ++i;
1530
751k
            break;
1531
751k
        }
1532
6.73M
    }
1533
751k
    e += nd - i;
1534
751k
    nd = i;
1535
751k
    if (nd0 > nd)
1536
25.8k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
751k
    bc.e0 = e1 = e;
1575
751k
    y = z = 0;
1576
3.13M
    for (i = 0; i < nd; i++) {
1577
2.45M
        if (i < 9)
1578
1.79M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
658k
        else if (i < DBL_DIG+1)
1580
586k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
72.4k
        else
1582
72.4k
            break;
1583
2.45M
    }
1584
1585
751k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
751k
    dval(&rv) = y;
1587
751k
    if (k > 9) {
1588
91.3k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
91.3k
    }
1590
751k
    if (nd <= DBL_DIG
1591
672k
        && Flt_Rounds == 1
1592
751k
        ) {
1593
672k
        if (!e)
1594
13.4k
            goto ret;
1595
658k
        if (e > 0) {
1596
609k
            if (e <= Ten_pmax) {
1597
27.0k
                dval(&rv) *= tens[e];
1598
27.0k
                goto ret;
1599
27.0k
            }
1600
582k
            i = DBL_DIG - nd;
1601
582k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
2.91k
                e -= i;
1606
2.91k
                dval(&rv) *= tens[i];
1607
2.91k
                dval(&rv) *= tens[e];
1608
2.91k
                goto ret;
1609
2.91k
            }
1610
582k
        }
1611
49.3k
        else if (e >= -Ten_pmax) {
1612
28.8k
            dval(&rv) /= tens[-e];
1613
28.8k
            goto ret;
1614
28.8k
        }
1615
658k
    }
1616
679k
    e1 += nd - k;
1617
1618
679k
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
679k
    if (e1 > 0) {
1623
640k
        if ((i = e1 & 15))
1624
605k
            dval(&rv) *= tens[i];
1625
640k
        if (e1 &= ~15) {
1626
625k
            if (e1 > DBL_MAX_10_EXP)
1627
504k
                goto ovfl;
1628
121k
            e1 >>= 4;
1629
307k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
185k
                if (e1 & 1)
1631
83.4k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
121k
            word0(&rv) -= P*Exp_msk1;
1634
121k
            dval(&rv) *= bigtens[j];
1635
121k
            if ((z = word0(&rv) & Exp_mask)
1636
121k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
729
                goto ovfl;
1638
120k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
502
                word0(&rv) = Big0;
1642
502
                word1(&rv) = Big1;
1643
502
            }
1644
119k
            else
1645
119k
                word0(&rv) += P*Exp_msk1;
1646
120k
        }
1647
640k
    }
1648
39.1k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
35.5k
        e1 = -e1;
1660
35.5k
        if ((i = e1 & 15))
1661
31.5k
            dval(&rv) /= tens[i];
1662
35.5k
        if (e1 >>= 4) {
1663
25.6k
            if (e1 >= 1 << n_bigtens)
1664
1.09k
                goto undfl;
1665
24.5k
            if (e1 & Scale_Bit)
1666
18.0k
                bc.scale = 2*P;
1667
125k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
101k
                if (e1 & 1)
1669
59.2k
                    dval(&rv) *= tinytens[j];
1670
24.5k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
18.0k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
16.6k
                if (j >= 32) {
1674
9.73k
                    word1(&rv) = 0;
1675
9.73k
                    if (j >= 53)
1676
5.20k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
4.53k
                    else
1678
4.53k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
9.73k
                }
1680
6.91k
                else
1681
6.91k
                    word1(&rv) &= 0xffffffff << j;
1682
16.6k
            }
1683
24.5k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
24.5k
        }
1686
35.5k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
173k
    bc.nd = nd;
1693
173k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
173k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
417k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
417k
            --i;
1708
417k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
50.7k
                ++i;
1710
50.7k
                break;
1711
50.7k
            }
1712
417k
        }
1713
50.7k
        e += nd - i;
1714
50.7k
        nd = i;
1715
50.7k
        if (nd0 > nd)
1716
47.4k
            nd0 = nd;
1717
50.7k
        if (nd < 9) { /* must recompute y */
1718
33.0k
            y = 0;
1719
263k
            for(i = 0; i < nd0; ++i)
1720
230k
                y = 10*y + s0[i] - '0';
1721
40.9k
            for(; i < nd; ++i)
1722
7.93k
                y = 10*y + s0[i+1] - '0';
1723
33.0k
        }
1724
50.7k
    }
1725
173k
    bd0 = s2b(s0, nd0, nd, y);
1726
173k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
221k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
221k
        bd = Balloc(bd0->k);
1758
221k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
221k
        Bcopy(bd, bd0);
1762
221k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
221k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
221k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
221k
        bs = i2b(1);
1772
221k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
221k
        if (e >= 0) {
1777
161k
            bb2 = bb5 = 0;
1778
161k
            bd2 = bd5 = e;
1779
161k
        }
1780
59.5k
        else {
1781
59.5k
            bb2 = bb5 = -e;
1782
59.5k
            bd2 = bd5 = 0;
1783
59.5k
        }
1784
221k
        if (bbe >= 0)
1785
169k
            bb2 += bbe;
1786
51.4k
        else
1787
51.4k
            bd2 -= bbe;
1788
221k
        bs2 = bb2;
1789
221k
        bb2++;
1790
221k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
221k
        i = bb2 < bd2 ? bb2 : bd2;
1811
221k
        if (i > bs2)
1812
50.4k
            i = bs2;
1813
221k
        if (i > 0) {
1814
220k
            bb2 -= i;
1815
220k
            bd2 -= i;
1816
220k
            bs2 -= i;
1817
220k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
221k
        if (bb5 > 0) {
1821
59.5k
            bs = pow5mult(bs, bb5);
1822
59.5k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
59.5k
            Bigint *bb1 = mult(bs, bb);
1826
59.5k
            Bfree(bb);
1827
59.5k
            bb = bb1;
1828
59.5k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
59.5k
        }
1832
221k
        if (bb2 > 0) {
1833
221k
            bb = lshift(bb, bb2);
1834
221k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
221k
        }
1838
221k
        if (bd5 > 0) {
1839
154k
            bd = pow5mult(bd, bd5);
1840
154k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
154k
        }
1844
221k
        if (bd2 > 0) {
1845
50.4k
            bd = lshift(bd, bd2);
1846
50.4k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
50.4k
        }
1850
221k
        if (bs2 > 0) {
1851
166k
            bs = lshift(bs, bs2);
1852
166k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
166k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
221k
        delta = diff(bb, bd);
1862
221k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
221k
        dsign = delta->sign;
1866
221k
        delta->sign = 0;
1867
221k
        i = cmp(delta, bs);
1868
221k
        if (bc.nd > nd && i <= 0) {
1869
50.7k
            if (dsign)
1870
40.2k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
10.5k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
1.24k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
1.24k
                if (j - bc.scale >= 2) {
1890
980
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
980
                    break; /* Use bigcomp. */
1892
980
                }
1893
1.24k
            }
1894
1895
9.54k
            {
1896
9.54k
                bc.nd = nd;
1897
9.54k
                i = -1; /* Discarded digits make delta smaller. */
1898
9.54k
            }
1899
9.54k
        }
1900
1901
179k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
68.2k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
4.77k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
68.2k
                ) {
1908
64.9k
                break;
1909
64.9k
            }
1910
3.34k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
480
                break;
1913
480
            }
1914
2.86k
            delta = lshift(delta,Log2P);
1915
2.86k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
2.86k
            if (cmp(delta, bs) > 0)
1919
1.01k
                goto drop_down;
1920
1.85k
            break;
1921
2.86k
        }
1922
111k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
3.44k
            if (dsign) {
1925
1.87k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
832
                    &&  word1(&rv) == (
1927
832
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
832
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
462
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
462
                        + Exp_msk1
1934
462
                        ;
1935
462
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
462
                    break;
1938
462
                }
1939
1.87k
            }
1940
1.57k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
1.01k
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
1.01k
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
1.01k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
1.01k
                word0(&rv) = L | Bndry_mask1;
1958
1.01k
                word1(&rv) = 0xffffffff;
1959
1.01k
                break;
1960
1.01k
            }
1961
2.98k
            if (!odd)
1962
2.32k
                break;
1963
662
            if (dsign)
1964
344
                dval(&rv) += sulp(&rv, &bc);
1965
318
            else {
1966
318
                dval(&rv) -= sulp(&rv, &bc);
1967
318
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
318
            }
1973
            /* dsign = 1 - dsign; */
1974
662
            break;
1975
662
        }
1976
108k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
88.4k
            if (dsign)
1978
15.6k
                aadj = aadj1 = 1.;
1979
72.8k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
68.1k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
68.1k
                aadj = 1.;
1986
68.1k
                aadj1 = -1.;
1987
68.1k
            }
1988
4.68k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
4.68k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
4.68k
                else
1995
4.68k
                    aadj *= 0.5;
1996
4.68k
                aadj1 = -aadj;
1997
4.68k
            }
1998
88.4k
        }
1999
19.7k
        else {
2000
19.7k
            aadj *= 0.5;
2001
19.7k
            aadj1 = dsign ? aadj : -aadj;
2002
19.7k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
19.7k
        }
2005
108k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
108k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
1.70k
            dval(&rv0) = dval(&rv);
2011
1.70k
            word0(&rv) -= P*Exp_msk1;
2012
1.70k
            adj.d = aadj1 * ulp(&rv);
2013
1.70k
            dval(&rv) += adj.d;
2014
1.70k
            if ((word0(&rv) & Exp_mask) >=
2015
1.70k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
1.09k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
796
                    goto ovfl;
2018
796
                }
2019
294
                word0(&rv) = Big0;
2020
294
                word1(&rv) = Big1;
2021
294
                goto cont;
2022
1.09k
            }
2023
615
            else
2024
615
                word0(&rv) += P*Exp_msk1;
2025
1.70k
        }
2026
106k
        else {
2027
106k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
13.7k
                if (aadj <= 0x7fffffff) {
2029
13.7k
                    if ((z = (ULong)aadj) <= 0)
2030
749
                        z = 1;
2031
13.7k
                    aadj = z;
2032
13.7k
                    aadj1 = dsign ? aadj : -aadj;
2033
13.7k
                }
2034
13.7k
                dval(&aadj2) = aadj1;
2035
13.7k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
13.7k
                aadj1 = dval(&aadj2);
2037
13.7k
            }
2038
106k
            adj.d = aadj1 * ulp(&rv);
2039
106k
            dval(&rv) += adj.d;
2040
106k
        }
2041
107k
        z = word0(&rv) & Exp_mask;
2042
107k
        if (bc.nd == nd) {
2043
75.7k
            if (!bc.scale)
2044
62.0k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
60.4k
                    L = (Long)aadj;
2047
60.4k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
60.4k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
60.4k
                        if (aadj < .4999999 || aadj > .5000001)
2051
59.5k
                            break;
2052
60.4k
                    }
2053
15
                    else if (aadj < .4999999/FLT_RADIX)
2054
15
                        break;
2055
60.4k
                }
2056
75.7k
        }
2057
47.7k
      cont:
2058
47.7k
        Bfree(bb); bb = NULL;
2059
47.7k
        Bfree(bd); bd = NULL;
2060
47.7k
        Bfree(bs); bs = NULL;
2061
47.7k
        Bfree(delta); delta = NULL;
2062
47.7k
    }
2063
172k
    if (bc.nd > nd) {
2064
41.2k
        error = bigcomp(&rv, s0, &bc);
2065
41.2k
        if (error)
2066
0
            goto failed_malloc;
2067
41.2k
    }
2068
2069
172k
    if (bc.scale) {
2070
18.0k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
18.0k
        word1(&rv0) = 0;
2072
18.0k
        dval(&rv) *= dval(&rv0);
2073
18.0k
    }
2074
2075
255k
  ret:
2076
255k
    result = sign ? -dval(&rv) : dval(&rv);
2077
255k
    goto done;
2078
2079
21
  parse_error:
2080
21
    result = 0.0;
2081
21
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
1.09k
  undfl:
2089
1.09k
    result = sign ? -0.0 : 0.0;
2090
1.09k
    goto done;
2091
2092
505k
  ovfl:
2093
505k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
505k
    word0(&rv) = Exp_mask;
2096
505k
    word1(&rv) = 0;
2097
505k
    result = sign ? -dval(&rv) : dval(&rv);
2098
505k
    goto done;
2099
2100
762k
  done:
2101
762k
    Bfree(bb);
2102
762k
    Bfree(bd);
2103
762k
    Bfree(bs);
2104
762k
    Bfree(bd0);
2105
762k
    Bfree(delta);
2106
762k
    return result;
2107
2108
172k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
46.4k
{
2113
46.4k
    int j, k, *r;
2114
2115
46.4k
    j = sizeof(ULong);
2116
46.4k
    for(k = 0;
2117
46.4k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
46.4k
        j <<= 1)
2119
0
        k++;
2120
46.4k
    r = (int*)Balloc(k);
2121
46.4k
    if (r == NULL)
2122
0
        return NULL;
2123
46.4k
    *r = k;
2124
46.4k
    return (char *)(r+1);
2125
46.4k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
4.93k
{
2130
4.93k
    char *rv, *t;
2131
2132
4.93k
    rv = rv_alloc(n);
2133
4.93k
    if (rv == NULL)
2134
0
        return NULL;
2135
4.93k
    t = rv;
2136
13.1k
    while((*t = *s++)) t++;
2137
4.93k
    if (rve)
2138
4.93k
        *rve = t;
2139
4.93k
    return rv;
2140
4.93k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
46.4k
{
2151
46.4k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
46.4k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
46.4k
    Bfree(b);
2154
46.4k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
46.4k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
46.4k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
46.4k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
46.4k
        spec_case, try_quick;
2235
46.4k
    Long L;
2236
46.4k
    int denorm;
2237
46.4k
    ULong x;
2238
46.4k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
46.4k
    U d2, eps, u;
2240
46.4k
    double ds;
2241
46.4k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
46.4k
    mlo = mhi = S = 0;
2246
46.4k
    s0 = 0;
2247
2248
46.4k
    u.d = dd;
2249
46.4k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
11.7k
        *sign = 1;
2252
11.7k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
11.7k
    }
2254
34.6k
    else
2255
34.6k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
46.4k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
474
    {
2260
        /* Infinity or NaN */
2261
474
        *decpt = 9999;
2262
474
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
474
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
474
    }
2266
45.9k
    if (!dval(&u)) {
2267
4.45k
        *decpt = 1;
2268
4.45k
        return nrv_alloc("0", rve, 1);
2269
4.45k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
41.4k
    b = d2b(&u, &be, &bbits);
2274
41.4k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
41.4k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
37.2k
        dval(&d2) = dval(&u);
2278
37.2k
        word0(&d2) &= Frac_mask1;
2279
37.2k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
37.2k
        i -= Bias;
2304
37.2k
        denorm = 0;
2305
37.2k
    }
2306
4.22k
    else {
2307
        /* d is denormalized */
2308
2309
4.22k
        i = bbits + be + (Bias + (P-1) - 1);
2310
4.22k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
4.22k
            : word1(&u) << (32 - i);
2312
4.22k
        dval(&d2) = x;
2313
4.22k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
4.22k
        i -= (Bias + (P-1) - 1) + 1;
2315
4.22k
        denorm = 1;
2316
4.22k
    }
2317
41.4k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
41.4k
        i*0.301029995663981;
2319
41.4k
    k = (int)ds;
2320
41.4k
    if (ds < 0. && ds != k)
2321
12.2k
        k--;    /* want k = floor(ds) */
2322
41.4k
    k_check = 1;
2323
41.4k
    if (k >= 0 && k <= Ten_pmax) {
2324
19.5k
        if (dval(&u) < tens[k])
2325
2.32k
            k--;
2326
19.5k
        k_check = 0;
2327
19.5k
    }
2328
41.4k
    j = bbits - i - 1;
2329
41.4k
    if (j >= 0) {
2330
18.7k
        b2 = 0;
2331
18.7k
        s2 = j;
2332
18.7k
    }
2333
22.6k
    else {
2334
22.6k
        b2 = -j;
2335
22.6k
        s2 = 0;
2336
22.6k
    }
2337
41.4k
    if (k >= 0) {
2338
28.5k
        b5 = 0;
2339
28.5k
        s5 = k;
2340
28.5k
        s2 += k;
2341
28.5k
    }
2342
12.9k
    else {
2343
12.9k
        b2 -= k;
2344
12.9k
        b5 = -k;
2345
12.9k
        s5 = 0;
2346
12.9k
    }
2347
41.4k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
41.4k
    try_quick = 1;
2351
2352
41.4k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
41.4k
    leftright = 1;
2357
41.4k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
41.4k
    switch(mode) {
2360
41.3k
    case 0:
2361
41.3k
    case 1:
2362
41.3k
        i = 18;
2363
41.3k
        ndigits = 0;
2364
41.3k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
115
    case 3:
2374
115
        leftright = 0;
2375
115
        _Py_FALLTHROUGH;
2376
115
    case 5:
2377
115
        i = ndigits + k + 1;
2378
115
        ilim = i;
2379
115
        ilim1 = i - 1;
2380
115
        if (i <= 0)
2381
0
            i = 1;
2382
41.4k
    }
2383
41.4k
    s0 = rv_alloc(i);
2384
41.4k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
41.4k
    s = s0;
2387
2388
2389
41.4k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
115
        i = 0;
2394
115
        dval(&d2) = dval(&u);
2395
115
        k0 = k;
2396
115
        ilim0 = ilim;
2397
115
        ieps = 2; /* conservative */
2398
115
        if (k > 0) {
2399
92
            ds = tens[k&0xf];
2400
92
            j = k >> 4;
2401
92
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
92
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
92
            dval(&u) /= ds;
2413
92
        }
2414
23
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
115
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
115
        dval(&eps) = ieps*dval(&u) + 7.;
2431
115
        word0(&eps) -= (P-1)*Exp_msk1;
2432
115
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
115
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
115
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
115
            dval(&eps) *= tens[ilim-1];
2463
311
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
311
                L = (Long)(dval(&u));
2465
311
                if (!(dval(&u) -= L))
2466
14
                    ilim = i;
2467
311
                *s++ = '0' + (int)L;
2468
311
                if (i == ilim) {
2469
115
                    if (dval(&u) > 0.5 + dval(&eps))
2470
63
                        goto bump_up;
2471
52
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
58
                        while(*--s == '0');
2473
52
                        s++;
2474
52
                        goto ret1;
2475
52
                    }
2476
0
                    break;
2477
115
                }
2478
311
            }
2479
115
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
41.3k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
11.2k
        ds = tens[k];
2492
11.2k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
17.2k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
17.2k
            L = (Long)(dval(&u) / ds);
2500
17.2k
            dval(&u) -= L*ds;
2501
17.2k
            *s++ = '0' + (int)L;
2502
17.2k
            if (!dval(&u)) {
2503
11.2k
                break;
2504
11.2k
            }
2505
6.00k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
63
                  bump_up:
2509
65
                    while(*--s == '9')
2510
2
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
63
                    ++*s++;
2516
63
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
63
                break;
2526
0
            }
2527
6.00k
        }
2528
11.3k
        goto ret1;
2529
11.2k
    }
2530
2531
30.0k
    m2 = b2;
2532
30.0k
    m5 = b5;
2533
30.0k
    if (leftright) {
2534
30.0k
        i =
2535
30.0k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
30.0k
            1 + P - bbits;
2537
30.0k
        b2 += i;
2538
30.0k
        s2 += i;
2539
30.0k
        mhi = i2b(1);
2540
30.0k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
30.0k
    }
2543
30.0k
    if (m2 > 0 && s2 > 0) {
2544
26.1k
        i = m2 < s2 ? m2 : s2;
2545
26.1k
        b2 -= i;
2546
26.1k
        m2 -= i;
2547
26.1k
        s2 -= i;
2548
26.1k
    }
2549
30.0k
    if (b5 > 0) {
2550
12.9k
        if (leftright) {
2551
12.9k
            if (m5 > 0) {
2552
12.9k
                mhi = pow5mult(mhi, m5);
2553
12.9k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
12.9k
                b1 = mult(mhi, b);
2556
12.9k
                Bfree(b);
2557
12.9k
                b = b1;
2558
12.9k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
12.9k
            }
2561
12.9k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
12.9k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
12.9k
    }
2573
30.0k
    S = i2b(1);
2574
30.0k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
30.0k
    if (s5 > 0) {
2577
14.6k
        S = pow5mult(S, s5);
2578
14.6k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
14.6k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
30.0k
    spec_case = 0;
2585
30.0k
    if ((mode < 2 || leftright)
2586
30.0k
        ) {
2587
30.0k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.35k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
30.0k
            ) {
2590
            /* The special case */
2591
1.09k
            b2 += Log2P;
2592
1.09k
            s2 += Log2P;
2593
1.09k
            spec_case = 1;
2594
1.09k
        }
2595
30.0k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
30.0k
#define iInc 28
2605
30.0k
    i = dshift(S, s2);
2606
30.0k
    b2 += i;
2607
30.0k
    m2 += i;
2608
30.0k
    s2 += i;
2609
30.0k
    if (b2 > 0) {
2610
30.0k
        b = lshift(b, b2);
2611
30.0k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
30.0k
    }
2614
30.0k
    if (s2 > 0) {
2615
29.4k
        S = lshift(S, s2);
2616
29.4k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
29.4k
    }
2619
30.0k
    if (k_check) {
2620
21.9k
        if (cmp(b,S) < 0) {
2621
2.01k
            k--;
2622
2.01k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
2.01k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
2.01k
            if (leftright) {
2626
2.01k
                mhi = multadd(mhi, 10, 0);
2627
2.01k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
2.01k
            }
2630
2.01k
            ilim = ilim1;
2631
2.01k
        }
2632
21.9k
    }
2633
30.0k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
30.0k
    if (leftright) {
2653
30.0k
        if (m2 > 0) {
2654
29.1k
            mhi = lshift(mhi, m2);
2655
29.1k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
29.1k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
30.0k
        mlo = mhi;
2664
30.0k
        if (spec_case) {
2665
1.09k
            mhi = Balloc(mhi->k);
2666
1.09k
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
1.09k
            Bcopy(mhi, mlo);
2669
1.09k
            mhi = lshift(mhi, Log2P);
2670
1.09k
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
1.09k
        }
2673
2674
112k
        for(i = 1;;i++) {
2675
112k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
112k
            j = cmp(b, mlo);
2680
112k
            delta = diff(S, mhi);
2681
112k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
112k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
112k
            Bfree(delta);
2685
112k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
112k
                ) {
2687
2.06k
                if (dig == '9')
2688
397
                    goto round_9_up;
2689
1.66k
                if (j > 0)
2690
698
                    dig++;
2691
1.66k
                *s++ = dig;
2692
1.66k
                goto ret;
2693
2.06k
            }
2694
110k
            if (j < 0 || (j == 0 && mode != 1
2695
1.79k
                          && !(word1(&u) & 1)
2696
93.0k
                    )) {
2697
17.9k
                if (!b->x[0] && b->wds <= 1) {
2698
2.89k
                    goto accept_dig;
2699
2.89k
                }
2700
15.0k
                if (j1 > 0) {
2701
2.97k
                    b = lshift(b, 1);
2702
2.97k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
2.97k
                    j1 = cmp(b, S);
2705
2.97k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.77k
                        && dig++ == '9')
2707
299
                        goto round_9_up;
2708
2.97k
                }
2709
17.6k
              accept_dig:
2710
17.6k
                *s++ = dig;
2711
17.6k
                goto ret;
2712
15.0k
            }
2713
92.2k
            if (j1 > 0) {
2714
10.0k
                if (dig == '9') { /* possible if i == 1 */
2715
1.95k
                  round_9_up:
2716
1.95k
                    *s++ = '9';
2717
1.95k
                    goto roundoff;
2718
1.26k
                }
2719
8.80k
                *s++ = dig + 1;
2720
8.80k
                goto ret;
2721
10.0k
            }
2722
82.1k
            *s++ = dig;
2723
82.1k
            if (i == ilim)
2724
0
                break;
2725
82.1k
            b = multadd(b, 10, 0);
2726
82.1k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
82.1k
            if (mlo == mhi) {
2729
79.2k
                mlo = mhi = multadd(mhi, 10, 0);
2730
79.2k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
79.2k
            }
2733
2.88k
            else {
2734
2.88k
                mlo = multadd(mlo, 10, 0);
2735
2.88k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
2.88k
                mhi = multadd(mhi, 10, 0);
2738
2.88k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
2.88k
            }
2741
82.1k
        }
2742
30.0k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
1.95k
      roundoff:
2764
1.95k
        while(*--s == '9')
2765
1.95k
            if (s == s0) {
2766
1.95k
                k++;
2767
1.95k
                *s++ = '1';
2768
1.95k
                goto ret;
2769
1.95k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
30.0k
  ret:
2777
30.0k
    Bfree(S);
2778
30.0k
    if (mhi) {
2779
30.0k
        if (mlo && mlo != mhi)
2780
1.09k
            Bfree(mlo);
2781
30.0k
        Bfree(mhi);
2782
30.0k
    }
2783
41.4k
  ret1:
2784
41.4k
    Bfree(b);
2785
41.4k
    *s = 0;
2786
41.4k
    *decpt = k + 1;
2787
41.4k
    if (rve)
2788
41.4k
        *rve = s;
2789
41.4k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
30.0k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
28
{
2809
28
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
28
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
28
    Bigint *p5 = i2b(625);
2814
28
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
28
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
224
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
196
        p5 = mult(p5, p5);
2822
196
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
196
        p5s[i] = p5;
2826
196
    }
2827
2828
28
#endif
2829
28
    return PyStatus_Ok();
2830
28
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}