Coverage Report

Created: 2026-01-17 06:16

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
Line
Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
55
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
3.26M
#define word0(x) (x)->L[1]
181
2.17M
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
6.49M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
221k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
799k
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
2.64M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
366k
#define Exp_shift  20
235
92.1k
#define Exp_shift1 20
236
1.55M
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
1.68M
#define Exp_mask  0x7ff00000
239
1.07M
#define P 53
240
#define Nbits 53
241
594k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
692k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
330k
#define Exp_1  0x3ff00000
246
42.1k
#define Exp_11 0x3ff00000
247
893k
#define Ebits 11
248
342k
#define Frac_mask  0xfffff
249
44.6k
#define Frac_mask1 0xfffff
250
1.52M
#define Ten_pmax 22
251
90
#define Bletch 0x10
252
99.8k
#define Bndry_mask  0xfffff
253
7.71k
#define Bndry_mask1 0xfffff
254
70.1k
#define Sign_bit 0x80000000
255
7.08k
#define Log2P 1
256
#define Tiny0 0
257
198k
#define Tiny1 1
258
46.1k
#define Quick_max 14
259
28.9k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
833k
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
4.07k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
2.56k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
28.8M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
13.2M
#define freelist interp->dtoa.freelist
336
365
#define private_mem interp->dtoa.preallocated
337
985
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
3.32M
{
344
3.32M
    int x;
345
3.32M
    Bigint *rv;
346
3.32M
    unsigned int len;
347
3.32M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
3.32M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
3.32M
        freelist[k] = rv->next;
351
365
    else {
352
365
        x = 1 << k;
353
365
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
365
            /sizeof(double);
355
365
        if (k <= Bigint_Kmax &&
356
365
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
365
        ) {
358
310
            rv = (Bigint*)pmem_next;
359
310
            pmem_next += len;
360
310
        }
361
55
        else {
362
55
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
55
            if (rv == NULL)
364
0
                return NULL;
365
55
        }
366
365
        rv->k = k;
367
365
        rv->maxwds = x;
368
365
    }
369
3.32M
    rv->sign = rv->wds = 0;
370
3.32M
    return rv;
371
3.32M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
6.61M
{
378
6.61M
    if (v) {
379
3.32M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
3.32M
        else {
382
3.32M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
3.32M
            v->next = freelist[v->k];
384
3.32M
            freelist[v->k] = v;
385
3.32M
        }
386
3.32M
    }
387
6.61M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
270k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
270k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
1.28M
{
445
1.28M
    int i, wds;
446
1.28M
    ULong *x;
447
1.28M
    ULLong carry, y;
448
1.28M
    Bigint *b1;
449
450
1.28M
    wds = b->wds;
451
1.28M
    x = b->x;
452
1.28M
    i = 0;
453
1.28M
    carry = a;
454
4.56M
    do {
455
4.56M
        y = *x * (ULLong)m + carry;
456
4.56M
        carry = y >> 32;
457
4.56M
        *x++ = (ULong)(y & FFFFFFFF);
458
4.56M
    }
459
4.56M
    while(++i < wds);
460
1.28M
    if (carry) {
461
75.5k
        if (wds >= b->maxwds) {
462
3.93k
            b1 = Balloc(b->k+1);
463
3.93k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
3.93k
            Bcopy(b1, b);
468
3.93k
            Bfree(b);
469
3.93k
            b = b1;
470
3.93k
        }
471
75.5k
        b->x[wds++] = (ULong)carry;
472
75.5k
        b->wds = wds;
473
75.5k
    }
474
1.28M
    return b;
475
1.28M
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
221k
{
486
221k
    Bigint *b;
487
221k
    int i, k;
488
221k
    Long x, y;
489
490
221k
    x = (nd + 8) / 9;
491
277k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
221k
    b = Balloc(k);
493
221k
    if (b == NULL)
494
0
        return NULL;
495
221k
    b->x[0] = y9;
496
221k
    b->wds = 1;
497
498
221k
    if (nd <= 9)
499
178k
      return b;
500
501
43.2k
    s += 9;
502
354k
    for (i = 9; i < nd0; i++) {
503
310k
        b = multadd(b, 10, *s++ - '0');
504
310k
        if (b == NULL)
505
0
            return NULL;
506
310k
    }
507
43.2k
    s++;
508
135k
    for(; i < nd; i++) {
509
92.0k
        b = multadd(b, 10, *s++ - '0');
510
92.0k
        if (b == NULL)
511
0
            return NULL;
512
92.0k
    }
513
43.2k
    return b;
514
43.2k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
377k
{
521
377k
    int k = 0;
522
523
377k
    if (!(x & 0xffff0000)) {
524
181k
        k = 16;
525
181k
        x <<= 16;
526
181k
    }
527
377k
    if (!(x & 0xff000000)) {
528
195k
        k += 8;
529
195k
        x <<= 8;
530
195k
    }
531
377k
    if (!(x & 0xf0000000)) {
532
203k
        k += 4;
533
203k
        x <<= 4;
534
203k
    }
535
377k
    if (!(x & 0xc0000000)) {
536
212k
        k += 2;
537
212k
        x <<= 2;
538
212k
    }
539
377k
    if (!(x & 0x80000000)) {
540
157k
        k++;
541
157k
        if (!(x & 0x40000000))
542
0
            return 32;
543
157k
    }
544
377k
    return k;
545
377k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
46.0k
{
553
46.0k
    int k;
554
46.0k
    ULong x = *y;
555
556
46.0k
    if (x & 7) {
557
28.3k
        if (x & 1)
558
13.4k
            return 0;
559
14.8k
        if (x & 2) {
560
7.01k
            *y = x >> 1;
561
7.01k
            return 1;
562
7.01k
        }
563
7.81k
        *y = x >> 2;
564
7.81k
        return 2;
565
14.8k
    }
566
17.7k
    k = 0;
567
17.7k
    if (!(x & 0xffff)) {
568
7.16k
        k = 16;
569
7.16k
        x >>= 16;
570
7.16k
    }
571
17.7k
    if (!(x & 0xff)) {
572
3.65k
        k += 8;
573
3.65k
        x >>= 8;
574
3.65k
    }
575
17.7k
    if (!(x & 0xf)) {
576
9.32k
        k += 4;
577
9.32k
        x >>= 4;
578
9.32k
    }
579
17.7k
    if (!(x & 0x3)) {
580
9.39k
        k += 2;
581
9.39k
        x >>= 2;
582
9.39k
    }
583
17.7k
    if (!(x & 1)) {
584
12.5k
        k++;
585
12.5k
        x >>= 1;
586
12.5k
        if (!x)
587
0
            return 32;
588
12.5k
    }
589
17.7k
    *y = x;
590
17.7k
    return k;
591
17.7k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
365k
{
598
365k
    Bigint *b;
599
600
365k
    b = Balloc(1);
601
365k
    if (b == NULL)
602
0
        return NULL;
603
365k
    b->x[0] = i;
604
365k
    b->wds = 1;
605
365k
    return b;
606
365k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
969k
{
614
969k
    Bigint *c;
615
969k
    int k, wa, wb, wc;
616
969k
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
969k
    ULong y;
618
969k
    ULLong carry, z;
619
620
969k
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
6.83k
        c = Balloc(0);
622
6.83k
        if (c == NULL)
623
0
            return NULL;
624
6.83k
        c->wds = 1;
625
6.83k
        c->x[0] = 0;
626
6.83k
        return c;
627
6.83k
    }
628
629
962k
    if (a->wds < b->wds) {
630
537k
        c = a;
631
537k
        a = b;
632
537k
        b = c;
633
537k
    }
634
962k
    k = a->k;
635
962k
    wa = a->wds;
636
962k
    wb = b->wds;
637
962k
    wc = wa + wb;
638
962k
    if (wc > a->maxwds)
639
591k
        k++;
640
962k
    c = Balloc(k);
641
962k
    if (c == NULL)
642
0
        return NULL;
643
7.61M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
6.65M
        *x = 0;
645
962k
    xa = a->x;
646
962k
    xae = xa + wa;
647
962k
    xb = b->x;
648
962k
    xbe = xb + wb;
649
962k
    xc0 = c->x;
650
3.10M
    for(; xb < xbe; xc0++) {
651
2.14M
        if ((y = *xb++)) {
652
2.13M
            x = xa;
653
2.13M
            xc = xc0;
654
2.13M
            carry = 0;
655
16.1M
            do {
656
16.1M
                z = *x++ * (ULLong)y + *xc + carry;
657
16.1M
                carry = z >> 32;
658
16.1M
                *xc++ = (ULong)(z & FFFFFFFF);
659
16.1M
            }
660
16.1M
            while(x < xae);
661
2.13M
            *xc = (ULong)carry;
662
2.13M
        }
663
2.14M
    }
664
1.61M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
962k
    c->wds = wc;
666
962k
    return c;
667
962k
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
317k
{
678
317k
    Bigint *b1, *p5, **p5s;
679
317k
    int i;
680
317k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
317k
    assert(0 <= k && k < 1024);
688
689
317k
    if ((i = k & 3)) {
690
182k
        b = multadd(b, p05[i-1], 0);
691
182k
        if (b == NULL)
692
0
            return NULL;
693
182k
    }
694
695
317k
    if (!(k >>= 2))
696
13.1k
        return b;
697
304k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
304k
    p5s = interp->dtoa.p5s;
699
1.48M
    for(;;) {
700
1.48M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
1.48M
        p5 = *p5s;
702
1.48M
        p5s++;
703
1.48M
        if (k & 1) {
704
893k
            b1 = mult(b, p5);
705
893k
            Bfree(b);
706
893k
            b = b1;
707
893k
            if (b == NULL)
708
0
                return NULL;
709
893k
        }
710
1.48M
        if (!(k >>= 1))
711
304k
            break;
712
1.48M
    }
713
304k
    return b;
714
304k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
727k
{
775
727k
    int i, k1, n, n1;
776
727k
    Bigint *b1;
777
727k
    ULong *x, *x1, *xe, z;
778
779
727k
    if (!k || (!b->x[0] && b->wds == 1))
780
7.43k
        return b;
781
782
720k
    n = k >> 5;
783
720k
    k1 = b->k;
784
720k
    n1 = n + b->wds + 1;
785
1.98M
    for(i = b->maxwds; n1 > i; i <<= 1)
786
1.26M
        k1++;
787
720k
    b1 = Balloc(k1);
788
720k
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
720k
    x1 = b1->x;
793
4.44M
    for(i = 0; i < n; i++)
794
3.72M
        *x1++ = 0;
795
720k
    x = b->x;
796
720k
    xe = x + b->wds;
797
720k
    if (k &= 0x1f) {
798
698k
        k1 = 32 - k;
799
698k
        z = 0;
800
2.34M
        do {
801
2.34M
            *x1++ = *x << k | z;
802
2.34M
            z = *x++ >> k1;
803
2.34M
        }
804
2.34M
        while(x < xe);
805
698k
        if ((*x1 = z))
806
132k
            ++n1;
807
698k
    }
808
21.9k
    else do
809
40.8k
             *x1++ = *x++;
810
40.8k
        while(x < xe);
811
720k
    b1->wds = n1 - 1;
812
720k
    Bfree(b);
813
720k
    return b1;
814
720k
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
1.56M
{
822
1.56M
    ULong *xa, *xa0, *xb, *xb0;
823
1.56M
    int i, j;
824
825
1.56M
    i = a->wds;
826
1.56M
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
1.56M
    if (i -= j)
834
185k
        return i;
835
1.38M
    xa0 = a->x;
836
1.38M
    xa = xa0 + j;
837
1.38M
    xb0 = b->x;
838
1.38M
    xb = xb0 + j;
839
1.80M
    for(;;) {
840
1.80M
        if (*--xa != *--xb)
841
1.36M
            return *xa < *xb ? -1 : 1;
842
436k
        if (xa <= xa0)
843
18.1k
            break;
844
436k
    }
845
18.1k
    return 0;
846
1.38M
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
383k
{
855
383k
    Bigint *c;
856
383k
    int i, wa, wb;
857
383k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
383k
    ULLong borrow, y;
859
860
383k
    i = cmp(a,b);
861
383k
    if (!i) {
862
3.54k
        c = Balloc(0);
863
3.54k
        if (c == NULL)
864
0
            return NULL;
865
3.54k
        c->wds = 1;
866
3.54k
        c->x[0] = 0;
867
3.54k
        return c;
868
3.54k
    }
869
379k
    if (i < 0) {
870
80.1k
        c = a;
871
80.1k
        a = b;
872
80.1k
        b = c;
873
80.1k
        i = 1;
874
80.1k
    }
875
299k
    else
876
299k
        i = 0;
877
379k
    c = Balloc(a->k);
878
379k
    if (c == NULL)
879
0
        return NULL;
880
379k
    c->sign = i;
881
379k
    wa = a->wds;
882
379k
    xa = a->x;
883
379k
    xae = xa + wa;
884
379k
    wb = b->wds;
885
379k
    xb = b->x;
886
379k
    xbe = xb + wb;
887
379k
    xc = c->x;
888
379k
    borrow = 0;
889
3.15M
    do {
890
3.15M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
3.15M
        borrow = y >> 32 & (ULong)1;
892
3.15M
        *xc++ = (ULong)(y & FFFFFFFF);
893
3.15M
    }
894
3.15M
    while(xb < xbe);
895
664k
    while(xa < xae) {
896
284k
        y = *xa++ - borrow;
897
284k
        borrow = y >> 32 & (ULong)1;
898
284k
        *xc++ = (ULong)(y & FFFFFFFF);
899
284k
    }
900
762k
    while(!*--xc)
901
382k
        wa--;
902
379k
    c->wds = wa;
903
379k
    return c;
904
379k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
158k
{
912
158k
    Long L;
913
158k
    U u;
914
915
158k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
158k
    word0(&u) = L;
917
158k
    word1(&u) = 0;
918
158k
    return dval(&u);
919
158k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
308k
{
926
308k
    ULong *xa, *xa0, w, y, z;
927
308k
    int k;
928
308k
    U d;
929
930
308k
    xa0 = a->x;
931
308k
    xa = xa0 + a->wds;
932
308k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
308k
    k = hi0bits(y);
937
308k
    *e = 32 - k;
938
308k
    if (k < Ebits) {
939
138k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
138k
        w = xa > xa0 ? *--xa : 0;
941
138k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
138k
        goto ret_d;
943
138k
    }
944
169k
    z = xa > xa0 ? *--xa : 0;
945
169k
    if (k -= Ebits) {
946
164k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
164k
        y = xa > xa0 ? *--xa : 0;
948
164k
        word1(&d) = z << k | y >> (32 - k);
949
164k
    }
950
5.48k
    else {
951
5.48k
        word0(&d) = Exp_1 | y;
952
5.48k
        word1(&d) = z;
953
5.48k
    }
954
308k
  ret_d:
955
308k
    return dval(&d);
956
169k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
296k
{
982
296k
    Bigint *b;
983
984
296k
    b = Balloc(1);
985
296k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
296k
    b->wds = 2;
990
296k
    b->x[0] = word1(d);
991
296k
    b->x[1] = word0(d) & Frac_mask;
992
296k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
296k
    if (*e < Etiny)
994
7.43k
        *e = Etiny;
995
288k
    else
996
288k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
296k
    if (scale && (b->x[0] || b->x[1])) {
1000
33.3k
        *e -= scale;
1001
33.3k
        if (*e < Etiny) {
1002
29.3k
            scale = Etiny - *e;
1003
29.3k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
29.3k
            assert(0 < scale && scale <= P - 1);
1006
29.3k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
17.1k
                assert(b->x[0] == 0);
1009
17.1k
                b->x[0] = b->x[1];
1010
17.1k
                b->x[1] = 0;
1011
17.1k
                scale -= 32;
1012
17.1k
            }
1013
29.3k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
27.0k
                assert(b->x[0] << (32 - scale) == 0);
1016
27.0k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
27.0k
                b->x[1] >>= scale;
1018
27.0k
            }
1019
29.3k
        }
1020
33.3k
    }
1021
    /* Ensure b is normalized. */
1022
296k
    if (!b->x[1])
1023
28.4k
        b->wds = 1;
1024
1025
296k
    return b;
1026
296k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
46.0k
{
1040
46.0k
    Bigint *b;
1041
46.0k
    int de, k;
1042
46.0k
    ULong *x, y, z;
1043
46.0k
    int i;
1044
1045
46.0k
    b = Balloc(1);
1046
46.0k
    if (b == NULL)
1047
0
        return NULL;
1048
46.0k
    x = b->x;
1049
1050
46.0k
    z = word0(d) & Frac_mask;
1051
46.0k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
46.0k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
42.1k
        z |= Exp_msk1;
1054
46.0k
    if ((y = word1(d))) {
1055
34.5k
        if ((k = lo0bits(&y))) {
1056
21.6k
            x[0] = y | z << (32 - k);
1057
21.6k
            z >>= k;
1058
21.6k
        }
1059
12.8k
        else
1060
12.8k
            x[0] = y;
1061
34.5k
        i =
1062
34.5k
            b->wds = (x[1] = z) ? 2 : 1;
1063
34.5k
    }
1064
11.5k
    else {
1065
11.5k
        k = lo0bits(&z);
1066
11.5k
        x[0] = z;
1067
11.5k
        i =
1068
11.5k
            b->wds = 1;
1069
11.5k
        k += 32;
1070
11.5k
    }
1071
46.0k
    if (de) {
1072
42.1k
        *e = de - Bias - (P-1) + k;
1073
42.1k
        *bits = P - k;
1074
42.1k
    }
1075
3.97k
    else {
1076
3.97k
        *e = de - Bias - (P-1) + 1 + k;
1077
3.97k
        *bits = 32*i - hi0bits(x[i-1]);
1078
3.97k
    }
1079
46.0k
    return b;
1080
46.0k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
154k
{
1088
154k
    U da, db;
1089
154k
    int k, ka, kb;
1090
1091
154k
    dval(&da) = b2d(a, &ka);
1092
154k
    dval(&db) = b2d(b, &kb);
1093
154k
    k = ka - kb + 32*(a->wds - b->wds);
1094
154k
    if (k > 0)
1095
47.1k
        word0(&da) += k*Exp_msk1;
1096
106k
    else {
1097
106k
        k = -k;
1098
106k
        word0(&db) += k*Exp_msk1;
1099
106k
    }
1100
154k
    return dval(&da) / dval(&db);
1101
154k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
30.8k
#define Scale_Bit 0x10
1119
33.8k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
65.6k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
65.6k
{
1129
65.6k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
65.6k
    if (p2 > 0)
1131
25.6k
        rv -= p2;
1132
65.6k
    return rv & kmask;
1133
65.6k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
642k
{
1142
642k
    int n;
1143
642k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
642k
    ULLong borrow, carry, y, ys;
1145
1146
642k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
642k
    if (b->wds < n)
1152
19.5k
        return 0;
1153
622k
    sx = S->x;
1154
622k
    sxe = sx + --n;
1155
622k
    bx = b->x;
1156
622k
    bxe = bx + n;
1157
622k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
622k
    if (q) {
1163
395k
        borrow = 0;
1164
395k
        carry = 0;
1165
2.16M
        do {
1166
2.16M
            ys = *sx++ * (ULLong)q + carry;
1167
2.16M
            carry = ys >> 32;
1168
2.16M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
2.16M
            borrow = y >> 32 & (ULong)1;
1170
2.16M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
2.16M
        }
1172
2.16M
        while(sx <= sxe);
1173
395k
        if (!*bxe) {
1174
2.96k
            bx = b->x;
1175
2.96k
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
2.96k
            b->wds = n;
1178
2.96k
        }
1179
395k
    }
1180
622k
    if (cmp(b, S) >= 0) {
1181
37.6k
        q++;
1182
37.6k
        borrow = 0;
1183
37.6k
        carry = 0;
1184
37.6k
        bx = b->x;
1185
37.6k
        sx = S->x;
1186
209k
        do {
1187
209k
            ys = *sx++ + carry;
1188
209k
            carry = ys >> 32;
1189
209k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
209k
            borrow = y >> 32 & (ULong)1;
1191
209k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
209k
        }
1193
209k
        while(sx <= sxe);
1194
37.6k
        bx = b->x;
1195
37.6k
        bxe = bx + n;
1196
37.6k
        if (!*bxe) {
1197
25.1k
            while(--bxe > bx && !*bxe)
1198
1.58k
                --n;
1199
23.5k
            b->wds = n;
1200
23.5k
        }
1201
37.6k
    }
1202
622k
    return q;
1203
642k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
4.33k
{
1214
4.33k
    U u;
1215
1216
4.33k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
397
        word0(&u) = (P+2)*Exp_msk1;
1219
397
        word1(&u) = 0;
1220
397
        return u.d;
1221
397
    }
1222
3.93k
    else {
1223
3.93k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
3.93k
        return ulp(x);
1225
3.93k
    }
1226
4.33k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
31.0k
{
1277
31.0k
    Bigint *b, *d;
1278
31.0k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
31.0k
    nd = bc->nd;
1281
31.0k
    nd0 = bc->nd0;
1282
31.0k
    p5 = nd + bc->e0;
1283
31.0k
    b = sd2b(rv, bc->scale, &p2);
1284
31.0k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
31.0k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
31.0k
    b = lshift(b, 1);
1294
31.0k
    if (b == NULL)
1295
0
        return -1;
1296
31.0k
    b->x[0] |= 1;
1297
31.0k
    p2--;
1298
1299
31.0k
    p2 -= p5;
1300
31.0k
    d = i2b(1);
1301
31.0k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
31.0k
    if (p5 > 0) {
1309
27.3k
        d = pow5mult(d, p5);
1310
27.3k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
27.3k
    }
1315
3.66k
    else if (p5 < 0) {
1316
1.82k
        b = pow5mult(b, -p5);
1317
1.82k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
1.82k
    }
1322
31.0k
    if (p2 > 0) {
1323
25.0k
        b2 = p2;
1324
25.0k
        d2 = 0;
1325
25.0k
    }
1326
6.03k
    else {
1327
6.03k
        b2 = 0;
1328
6.03k
        d2 = -p2;
1329
6.03k
    }
1330
31.0k
    i = dshift(d, d2);
1331
31.0k
    if ((b2 += i) > 0) {
1332
30.6k
        b = lshift(b, b2);
1333
30.6k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
30.6k
    }
1338
31.0k
    if ((d2 += i) > 0) {
1339
29.9k
        d = lshift(d, d2);
1340
29.9k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
29.9k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
31.0k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
1.01k
        dd = -1;
1352
30.0k
    else {
1353
30.0k
        i = 0;
1354
524k
        for(;;) {
1355
524k
            b = multadd(b, 10, 0);
1356
524k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
524k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
524k
            i++;
1362
1363
524k
            if (dd)
1364
28.7k
                break;
1365
495k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
726
                dd = i < nd;
1368
726
                break;
1369
726
            }
1370
495k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
552
                dd = -1;
1373
552
                break;
1374
552
            }
1375
495k
        }
1376
30.0k
    }
1377
31.0k
    Bfree(b);
1378
31.0k
    Bfree(d);
1379
31.0k
    if (dd > 0 || (dd == 0 && odd))
1380
2.06k
        dval(rv) += sulp(rv, bc);
1381
31.0k
    return 0;
1382
31.0k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
880k
{
1388
880k
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
880k
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
880k
    const char *s, *s0, *s1;
1391
880k
    double aadj, aadj1;
1392
880k
    U aadj2, adj, rv, rv0;
1393
880k
    ULong y, z, abs_exp;
1394
880k
    Long L;
1395
880k
    BCinfo bc;
1396
880k
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
880k
    size_t ndigits, fraclen;
1398
880k
    double result;
1399
1400
880k
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
880k
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
880k
    sign = 0;
1407
880k
    switch (c) {
1408
579k
    case '-':
1409
579k
        sign = 1;
1410
579k
        _Py_FALLTHROUGH;
1411
580k
    case '+':
1412
580k
        c = *++s;
1413
880k
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
880k
    s1 = s;
1417
907k
    while (c == '0')
1418
27.0k
        c = *++s;
1419
880k
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
880k
    s0 = s1 = s;
1426
7.44M
    while ('0' <= c && c <= '9')
1427
6.56M
        c = *++s;
1428
880k
    ndigits = s - s1;
1429
880k
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
880k
    if (c == '.') {
1433
84.9k
        c = *++s;
1434
84.9k
        if (!ndigits) {
1435
28.8k
            s1 = s;
1436
1.34M
            while (c == '0')
1437
1.32M
                c = *++s;
1438
28.8k
            lz = lz || s != s1;
1439
28.8k
            fraclen += (s - s1);
1440
28.8k
            s0 = s;
1441
28.8k
        }
1442
84.9k
        s1 = s;
1443
29.7M
        while ('0' <= c && c <= '9')
1444
29.6M
            c = *++s;
1445
84.9k
        ndigits += s - s1;
1446
84.9k
        fraclen += s - s1;
1447
84.9k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
880k
    if (!ndigits && !lz) {
1453
18
        if (se)
1454
18
            *se = (char *)s00;
1455
18
        goto parse_error;
1456
18
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
880k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
880k
    nd = (int)ndigits;
1466
880k
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
880k
    e = 0;
1470
880k
    if (c == 'e' || c == 'E') {
1471
799k
        s00 = s;
1472
799k
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
799k
        esign = 0;
1476
799k
        switch (c) {
1477
34.2k
        case '-':
1478
34.2k
            esign = 1;
1479
34.2k
            _Py_FALLTHROUGH;
1480
50.1k
        case '+':
1481
50.1k
            c = *++s;
1482
799k
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
799k
        s1 = s;
1486
917k
        while (c == '0')
1487
118k
            c = *++s;
1488
799k
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
799k
        s1 = s;
1492
799k
        abs_exp = 0;
1493
7.87M
        while ('0' <= c && c <= '9') {
1494
7.07M
            abs_exp = 10*abs_exp + (c - '0');
1495
7.07M
            c = *++s;
1496
7.07M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
799k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
9.60k
            e = (int)MAX_ABS_EXP;
1503
789k
        else
1504
789k
            e = (int)abs_exp;
1505
799k
        if (esign)
1506
34.2k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
799k
        if (s == s1 && !lz)
1510
0
            s = s00;
1511
799k
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
880k
    e -= nd - nd0;
1515
880k
    if (nd0 <= 0)
1516
34.1k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
880k
    if (se)
1520
880k
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
880k
    if (!nd)
1525
13.8k
        goto ret;
1526
9.46M
    for (i = nd; i > 0; ) {
1527
9.46M
        --i;
1528
9.46M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
866k
            ++i;
1530
866k
            break;
1531
866k
        }
1532
9.46M
    }
1533
866k
    e += nd - i;
1534
866k
    nd = i;
1535
866k
    if (nd0 > nd)
1536
26.1k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
866k
    bc.e0 = e1 = e;
1575
866k
    y = z = 0;
1576
3.35M
    for (i = 0; i < nd; i++) {
1577
2.54M
        if (i < 9)
1578
1.99M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
554k
        else if (i < DBL_DIG+1)
1580
496k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
58.0k
        else
1582
58.0k
            break;
1583
2.54M
    }
1584
1585
866k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
866k
    dval(&rv) = y;
1587
866k
    if (k > 9) {
1588
83.1k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
83.1k
    }
1590
866k
    if (nd <= DBL_DIG
1591
801k
        && Flt_Rounds == 1
1592
866k
        ) {
1593
801k
        if (!e)
1594
13.3k
            goto ret;
1595
788k
        if (e > 0) {
1596
731k
            if (e <= Ten_pmax) {
1597
29.8k
                dval(&rv) *= tens[e];
1598
29.8k
                goto ret;
1599
29.8k
            }
1600
701k
            i = DBL_DIG - nd;
1601
701k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
2.72k
                e -= i;
1606
2.72k
                dval(&rv) *= tens[i];
1607
2.72k
                dval(&rv) *= tens[e];
1608
2.72k
                goto ret;
1609
2.72k
            }
1610
701k
        }
1611
56.4k
        else if (e >= -Ten_pmax) {
1612
30.5k
            dval(&rv) /= tens[-e];
1613
30.5k
            goto ret;
1614
30.5k
        }
1615
788k
    }
1616
790k
    e1 += nd - k;
1617
1618
790k
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
790k
    if (e1 > 0) {
1623
742k
        if ((i = e1 & 15))
1624
686k
            dval(&rv) *= tens[i];
1625
742k
        if (e1 &= ~15) {
1626
732k
            if (e1 > DBL_MAX_10_EXP)
1627
564k
                goto ovfl;
1628
167k
            e1 >>= 4;
1629
486k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
319k
                if (e1 & 1)
1631
178k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
167k
            word0(&rv) -= P*Exp_msk1;
1634
167k
            dval(&rv) *= bigtens[j];
1635
167k
            if ((z = word0(&rv) & Exp_mask)
1636
167k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
832
                goto ovfl;
1638
166k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
600
                word0(&rv) = Big0;
1642
600
                word1(&rv) = Big1;
1643
600
            }
1644
166k
            else
1645
166k
                word0(&rv) += P*Exp_msk1;
1646
166k
        }
1647
742k
    }
1648
47.7k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
43.7k
        e1 = -e1;
1660
43.7k
        if ((i = e1 & 15))
1661
35.6k
            dval(&rv) /= tens[i];
1662
43.7k
        if (e1 >>= 4) {
1663
33.8k
            if (e1 >= 1 << n_bigtens)
1664
3.01k
                goto undfl;
1665
30.8k
            if (e1 & Scale_Bit)
1666
21.9k
                bc.scale = 2*P;
1667
153k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
122k
                if (e1 & 1)
1669
72.6k
                    dval(&rv) *= tinytens[j];
1670
30.8k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
21.9k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
20.1k
                if (j >= 32) {
1674
13.6k
                    word1(&rv) = 0;
1675
13.6k
                    if (j >= 53)
1676
7.36k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
6.25k
                    else
1678
6.25k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
13.6k
                }
1680
6.57k
                else
1681
6.57k
                    word1(&rv) &= 0xffffffff << j;
1682
20.1k
            }
1683
30.8k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
30.8k
        }
1686
43.7k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
221k
    bc.nd = nd;
1693
221k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
221k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
349k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
349k
            --i;
1708
349k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
38.5k
                ++i;
1710
38.5k
                break;
1711
38.5k
            }
1712
349k
        }
1713
38.5k
        e += nd - i;
1714
38.5k
        nd = i;
1715
38.5k
        if (nd0 > nd)
1716
34.0k
            nd0 = nd;
1717
38.5k
        if (nd < 9) { /* must recompute y */
1718
27.4k
            y = 0;
1719
213k
            for(i = 0; i < nd0; ++i)
1720
185k
                y = 10*y + s0[i] - '0';
1721
36.0k
            for(; i < nd; ++i)
1722
8.65k
                y = 10*y + s0[i+1] - '0';
1723
27.4k
        }
1724
38.5k
    }
1725
221k
    bd0 = s2b(s0, nd0, nd, y);
1726
221k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
265k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
265k
        bd = Balloc(bd0->k);
1758
265k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
265k
        Bcopy(bd, bd0);
1762
265k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
265k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
265k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
265k
        bs = i2b(1);
1772
265k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
265k
        if (e >= 0) {
1777
202k
            bb2 = bb5 = 0;
1778
202k
            bd2 = bd5 = e;
1779
202k
        }
1780
62.4k
        else {
1781
62.4k
            bb2 = bb5 = -e;
1782
62.4k
            bd2 = bd5 = 0;
1783
62.4k
        }
1784
265k
        if (bbe >= 0)
1785
204k
            bb2 += bbe;
1786
60.9k
        else
1787
60.9k
            bd2 -= bbe;
1788
265k
        bs2 = bb2;
1789
265k
        bb2++;
1790
265k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
265k
        i = bb2 < bd2 ? bb2 : bd2;
1811
265k
        if (i > bs2)
1812
59.9k
            i = bs2;
1813
265k
        if (i > 0) {
1814
264k
            bb2 -= i;
1815
264k
            bd2 -= i;
1816
264k
            bs2 -= i;
1817
264k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
265k
        if (bb5 > 0) {
1821
62.4k
            bs = pow5mult(bs, bb5);
1822
62.4k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
62.4k
            Bigint *bb1 = mult(bs, bb);
1826
62.4k
            Bfree(bb);
1827
62.4k
            bb = bb1;
1828
62.4k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
62.4k
        }
1832
265k
        if (bb2 > 0) {
1833
265k
            bb = lshift(bb, bb2);
1834
265k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
265k
        }
1838
265k
        if (bd5 > 0) {
1839
193k
            bd = pow5mult(bd, bd5);
1840
193k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
193k
        }
1844
265k
        if (bd2 > 0) {
1845
59.9k
            bd = lshift(bd, bd2);
1846
59.9k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
59.9k
        }
1850
265k
        if (bs2 > 0) {
1851
200k
            bs = lshift(bs, bs2);
1852
200k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
200k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
265k
        delta = diff(bb, bd);
1862
265k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
265k
        dsign = delta->sign;
1866
265k
        delta->sign = 0;
1867
265k
        i = cmp(delta, bs);
1868
265k
        if (bc.nd > nd && i <= 0) {
1869
38.5k
            if (dsign)
1870
29.6k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
8.84k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
1.63k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
1.63k
                if (j - bc.scale >= 2) {
1890
1.36k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
1.36k
                    break; /* Use bigcomp. */
1892
1.36k
                }
1893
1.63k
            }
1894
1895
7.47k
            {
1896
7.47k
                bc.nd = nd;
1897
7.47k
                i = -1; /* Discarded digits make delta smaller. */
1898
7.47k
            }
1899
7.47k
        }
1900
1901
234k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
75.4k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
5.69k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
75.4k
                ) {
1908
71.2k
                break;
1909
71.2k
            }
1910
4.22k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
566
                break;
1913
566
            }
1914
3.66k
            delta = lshift(delta,Log2P);
1915
3.66k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
3.66k
            if (cmp(delta, bs) > 0)
1919
1.26k
                goto drop_down;
1920
2.39k
            break;
1921
3.66k
        }
1922
158k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
4.71k
            if (dsign) {
1925
2.15k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
831
                    &&  word1(&rv) == (
1927
831
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
831
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
502
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
502
                        + Exp_msk1
1934
502
                        ;
1935
502
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
502
                    break;
1938
502
                }
1939
2.15k
            }
1940
2.56k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
1.26k
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
1.26k
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
1.26k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
1.26k
                word0(&rv) = L | Bndry_mask1;
1958
1.26k
                word1(&rv) = 0xffffffff;
1959
1.26k
                break;
1960
1.26k
            }
1961
4.20k
            if (!odd)
1962
3.30k
                break;
1963
901
            if (dsign)
1964
549
                dval(&rv) += sulp(&rv, &bc);
1965
352
            else {
1966
352
                dval(&rv) -= sulp(&rv, &bc);
1967
352
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
352
            }
1973
            /* dsign = 1 - dsign; */
1974
901
            break;
1975
901
        }
1976
154k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
121k
            if (dsign)
1978
15.4k
                aadj = aadj1 = 1.;
1979
106k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
99.3k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
99.3k
                aadj = 1.;
1986
99.3k
                aadj1 = -1.;
1987
99.3k
            }
1988
6.83k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
6.83k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
6.83k
                else
1995
6.83k
                    aadj *= 0.5;
1996
6.83k
                aadj1 = -aadj;
1997
6.83k
            }
1998
121k
        }
1999
32.3k
        else {
2000
32.3k
            aadj *= 0.5;
2001
32.3k
            aadj1 = dsign ? aadj : -aadj;
2002
32.3k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
32.3k
        }
2005
154k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
154k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
3.31k
            dval(&rv0) = dval(&rv);
2011
3.31k
            word0(&rv) -= P*Exp_msk1;
2012
3.31k
            adj.d = aadj1 * ulp(&rv);
2013
3.31k
            dval(&rv) += adj.d;
2014
3.31k
            if ((word0(&rv) & Exp_mask) >=
2015
3.31k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
1.50k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
1.05k
                    goto ovfl;
2018
1.05k
                }
2019
454
                word0(&rv) = Big0;
2020
454
                word1(&rv) = Big1;
2021
454
                goto cont;
2022
1.50k
            }
2023
1.81k
            else
2024
1.81k
                word0(&rv) += P*Exp_msk1;
2025
3.31k
        }
2026
150k
        else {
2027
150k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
16.1k
                if (aadj <= 0x7fffffff) {
2029
16.1k
                    if ((z = (ULong)aadj) <= 0)
2030
1.54k
                        z = 1;
2031
16.1k
                    aadj = z;
2032
16.1k
                    aadj1 = dsign ? aadj : -aadj;
2033
16.1k
                }
2034
16.1k
                dval(&aadj2) = aadj1;
2035
16.1k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
16.1k
                aadj1 = dval(&aadj2);
2037
16.1k
            }
2038
150k
            adj.d = aadj1 * ulp(&rv);
2039
150k
            dval(&rv) += adj.d;
2040
150k
        }
2041
152k
        z = word0(&rv) & Exp_mask;
2042
152k
        if (bc.nd == nd) {
2043
128k
            if (!bc.scale)
2044
112k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
110k
                    L = (Long)aadj;
2047
110k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
110k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
110k
                        if (aadj < .4999999 || aadj > .5000001)
2051
109k
                            break;
2052
110k
                    }
2053
15
                    else if (aadj < .4999999/FLT_RADIX)
2054
15
                        break;
2055
110k
                }
2056
128k
        }
2057
43.8k
      cont:
2058
43.8k
        Bfree(bb); bb = NULL;
2059
43.8k
        Bfree(bd); bd = NULL;
2060
43.8k
        Bfree(bs); bs = NULL;
2061
43.8k
        Bfree(delta); delta = NULL;
2062
43.8k
    }
2063
220k
    if (bc.nd > nd) {
2064
31.0k
        error = bigcomp(&rv, s0, &bc);
2065
31.0k
        if (error)
2066
0
            goto failed_malloc;
2067
31.0k
    }
2068
2069
220k
    if (bc.scale) {
2070
21.9k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
21.9k
        word1(&rv0) = 0;
2072
21.9k
        dval(&rv) *= dval(&rv0);
2073
21.9k
    }
2074
2075
310k
  ret:
2076
310k
    result = sign ? -dval(&rv) : dval(&rv);
2077
310k
    goto done;
2078
2079
18
  parse_error:
2080
18
    result = 0.0;
2081
18
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
3.01k
  undfl:
2089
3.01k
    result = sign ? -0.0 : 0.0;
2090
3.01k
    goto done;
2091
2092
566k
  ovfl:
2093
566k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
566k
    word0(&rv) = Exp_mask;
2096
566k
    word1(&rv) = 0;
2097
566k
    result = sign ? -dval(&rv) : dval(&rv);
2098
566k
    goto done;
2099
2100
880k
  done:
2101
880k
    Bfree(bb);
2102
880k
    Bfree(bd);
2103
880k
    Bfree(bs);
2104
880k
    Bfree(bd0);
2105
880k
    Bfree(delta);
2106
880k
    return result;
2107
2108
220k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
51.9k
{
2113
51.9k
    int j, k, *r;
2114
2115
51.9k
    j = sizeof(ULong);
2116
51.9k
    for(k = 0;
2117
51.9k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
51.9k
        j <<= 1)
2119
0
        k++;
2120
51.9k
    r = (int*)Balloc(k);
2121
51.9k
    if (r == NULL)
2122
0
        return NULL;
2123
51.9k
    *r = k;
2124
51.9k
    return (char *)(r+1);
2125
51.9k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
5.87k
{
2130
5.87k
    char *rv, *t;
2131
2132
5.87k
    rv = rv_alloc(n);
2133
5.87k
    if (rv == NULL)
2134
0
        return NULL;
2135
5.87k
    t = rv;
2136
15.2k
    while((*t = *s++)) t++;
2137
5.87k
    if (rve)
2138
5.87k
        *rve = t;
2139
5.87k
    return rv;
2140
5.87k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
51.9k
{
2151
51.9k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
51.9k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
51.9k
    Bfree(b);
2154
51.9k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
51.9k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
51.9k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
51.9k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
51.9k
        spec_case, try_quick;
2235
51.9k
    Long L;
2236
51.9k
    int denorm;
2237
51.9k
    ULong x;
2238
51.9k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
51.9k
    U d2, eps, u;
2240
51.9k
    double ds;
2241
51.9k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
51.9k
    mlo = mhi = S = 0;
2246
51.9k
    s0 = 0;
2247
2248
51.9k
    u.d = dd;
2249
51.9k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
18.1k
        *sign = 1;
2252
18.1k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
18.1k
    }
2254
33.7k
    else
2255
33.7k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
51.9k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
500
    {
2260
        /* Infinity or NaN */
2261
500
        *decpt = 9999;
2262
500
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
500
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
500
    }
2266
51.4k
    if (!dval(&u)) {
2267
5.37k
        *decpt = 1;
2268
5.37k
        return nrv_alloc("0", rve, 1);
2269
5.37k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
46.0k
    b = d2b(&u, &be, &bbits);
2274
46.0k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
46.0k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
42.1k
        dval(&d2) = dval(&u);
2278
42.1k
        word0(&d2) &= Frac_mask1;
2279
42.1k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
42.1k
        i -= Bias;
2304
42.1k
        denorm = 0;
2305
42.1k
    }
2306
3.97k
    else {
2307
        /* d is denormalized */
2308
2309
3.97k
        i = bbits + be + (Bias + (P-1) - 1);
2310
3.97k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
3.97k
            : word1(&u) << (32 - i);
2312
3.97k
        dval(&d2) = x;
2313
3.97k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
3.97k
        i -= (Bias + (P-1) - 1) + 1;
2315
3.97k
        denorm = 1;
2316
3.97k
    }
2317
46.0k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
46.0k
        i*0.301029995663981;
2319
46.0k
    k = (int)ds;
2320
46.0k
    if (ds < 0. && ds != k)
2321
12.6k
        k--;    /* want k = floor(ds) */
2322
46.0k
    k_check = 1;
2323
46.0k
    if (k >= 0 && k <= Ten_pmax) {
2324
19.0k
        if (dval(&u) < tens[k])
2325
2.28k
            k--;
2326
19.0k
        k_check = 0;
2327
19.0k
    }
2328
46.0k
    j = bbits - i - 1;
2329
46.0k
    if (j >= 0) {
2330
18.8k
        b2 = 0;
2331
18.8k
        s2 = j;
2332
18.8k
    }
2333
27.2k
    else {
2334
27.2k
        b2 = -j;
2335
27.2k
        s2 = 0;
2336
27.2k
    }
2337
46.0k
    if (k >= 0) {
2338
32.7k
        b5 = 0;
2339
32.7k
        s5 = k;
2340
32.7k
        s2 += k;
2341
32.7k
    }
2342
13.2k
    else {
2343
13.2k
        b2 -= k;
2344
13.2k
        b5 = -k;
2345
13.2k
        s5 = 0;
2346
13.2k
    }
2347
46.0k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
46.0k
    try_quick = 1;
2351
2352
46.0k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
46.0k
    leftright = 1;
2357
46.0k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
46.0k
    switch(mode) {
2360
45.9k
    case 0:
2361
45.9k
    case 1:
2362
45.9k
        i = 18;
2363
45.9k
        ndigits = 0;
2364
45.9k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
114
    case 3:
2374
114
        leftright = 0;
2375
114
        _Py_FALLTHROUGH;
2376
114
    case 5:
2377
114
        i = ndigits + k + 1;
2378
114
        ilim = i;
2379
114
        ilim1 = i - 1;
2380
114
        if (i <= 0)
2381
0
            i = 1;
2382
46.0k
    }
2383
46.0k
    s0 = rv_alloc(i);
2384
46.0k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
46.0k
    s = s0;
2387
2388
2389
46.0k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
114
        i = 0;
2394
114
        dval(&d2) = dval(&u);
2395
114
        k0 = k;
2396
114
        ilim0 = ilim;
2397
114
        ieps = 2; /* conservative */
2398
114
        if (k > 0) {
2399
90
            ds = tens[k&0xf];
2400
90
            j = k >> 4;
2401
90
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
90
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
90
            dval(&u) /= ds;
2413
90
        }
2414
24
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
114
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
114
        dval(&eps) = ieps*dval(&u) + 7.;
2431
114
        word0(&eps) -= (P-1)*Exp_msk1;
2432
114
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
114
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
114
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
114
            dval(&eps) *= tens[ilim-1];
2463
313
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
313
                L = (Long)(dval(&u));
2465
313
                if (!(dval(&u) -= L))
2466
15
                    ilim = i;
2467
313
                *s++ = '0' + (int)L;
2468
313
                if (i == ilim) {
2469
114
                    if (dval(&u) > 0.5 + dval(&eps))
2470
58
                        goto bump_up;
2471
56
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
61
                        while(*--s == '0');
2473
56
                        s++;
2474
56
                        goto ret1;
2475
56
                    }
2476
0
                    break;
2477
114
                }
2478
313
            }
2479
114
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
45.9k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
11.3k
        ds = tens[k];
2492
11.3k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
17.0k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
17.0k
            L = (Long)(dval(&u) / ds);
2500
17.0k
            dval(&u) -= L*ds;
2501
17.0k
            *s++ = '0' + (int)L;
2502
17.0k
            if (!dval(&u)) {
2503
11.3k
                break;
2504
11.3k
            }
2505
5.69k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
58
                  bump_up:
2509
59
                    while(*--s == '9')
2510
1
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
58
                    ++*s++;
2516
58
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
58
                break;
2526
0
            }
2527
5.69k
        }
2528
11.3k
        goto ret1;
2529
11.3k
    }
2530
2531
34.6k
    m2 = b2;
2532
34.6k
    m5 = b5;
2533
34.6k
    if (leftright) {
2534
34.6k
        i =
2535
34.6k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
34.6k
            1 + P - bbits;
2537
34.6k
        b2 += i;
2538
34.6k
        s2 += i;
2539
34.6k
        mhi = i2b(1);
2540
34.6k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
34.6k
    }
2543
34.6k
    if (m2 > 0 && s2 > 0) {
2544
30.9k
        i = m2 < s2 ? m2 : s2;
2545
30.9k
        b2 -= i;
2546
30.9k
        m2 -= i;
2547
30.9k
        s2 -= i;
2548
30.9k
    }
2549
34.6k
    if (b5 > 0) {
2550
13.2k
        if (leftright) {
2551
13.2k
            if (m5 > 0) {
2552
13.2k
                mhi = pow5mult(mhi, m5);
2553
13.2k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
13.2k
                b1 = mult(mhi, b);
2556
13.2k
                Bfree(b);
2557
13.2k
                b = b1;
2558
13.2k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
13.2k
            }
2561
13.2k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
13.2k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
13.2k
    }
2573
34.6k
    S = i2b(1);
2574
34.6k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
34.6k
    if (s5 > 0) {
2577
19.0k
        S = pow5mult(S, s5);
2578
19.0k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
19.0k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
34.6k
    spec_case = 0;
2585
34.6k
    if ((mode < 2 || leftright)
2586
34.6k
        ) {
2587
34.6k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.40k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
34.6k
            ) {
2590
            /* The special case */
2591
1.14k
            b2 += Log2P;
2592
1.14k
            s2 += Log2P;
2593
1.14k
            spec_case = 1;
2594
1.14k
        }
2595
34.6k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
34.6k
#define iInc 28
2605
34.6k
    i = dshift(S, s2);
2606
34.6k
    b2 += i;
2607
34.6k
    m2 += i;
2608
34.6k
    s2 += i;
2609
34.6k
    if (b2 > 0) {
2610
34.6k
        b = lshift(b, b2);
2611
34.6k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
34.6k
    }
2614
34.6k
    if (s2 > 0) {
2615
34.0k
        S = lshift(S, s2);
2616
34.0k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
34.0k
    }
2619
34.6k
    if (k_check) {
2620
27.0k
        if (cmp(b,S) < 0) {
2621
4.00k
            k--;
2622
4.00k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
4.00k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
4.00k
            if (leftright) {
2626
4.00k
                mhi = multadd(mhi, 10, 0);
2627
4.00k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
4.00k
            }
2630
4.00k
            ilim = ilim1;
2631
4.00k
        }
2632
27.0k
    }
2633
34.6k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
34.6k
    if (leftright) {
2653
34.6k
        if (m2 > 0) {
2654
33.7k
            mhi = lshift(mhi, m2);
2655
33.7k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
33.7k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
34.6k
        mlo = mhi;
2664
34.6k
        if (spec_case) {
2665
1.14k
            mhi = Balloc(mhi->k);
2666
1.14k
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
1.14k
            Bcopy(mhi, mlo);
2669
1.14k
            mhi = lshift(mhi, Log2P);
2670
1.14k
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
1.14k
        }
2673
2674
117k
        for(i = 1;;i++) {
2675
117k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
117k
            j = cmp(b, mlo);
2680
117k
            delta = diff(S, mhi);
2681
117k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
117k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
117k
            Bfree(delta);
2685
117k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
117k
                ) {
2687
1.78k
                if (dig == '9')
2688
235
                    goto round_9_up;
2689
1.55k
                if (j > 0)
2690
698
                    dig++;
2691
1.55k
                *s++ = dig;
2692
1.55k
                goto ret;
2693
1.78k
            }
2694
115k
            if (j < 0 || (j == 0 && mode != 1
2695
1.93k
                          && !(word1(&u) & 1)
2696
98.9k
                    )) {
2697
17.9k
                if (!b->x[0] && b->wds <= 1) {
2698
2.45k
                    goto accept_dig;
2699
2.45k
                }
2700
15.5k
                if (j1 > 0) {
2701
2.98k
                    b = lshift(b, 1);
2702
2.98k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
2.98k
                    j1 = cmp(b, S);
2705
2.98k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.77k
                        && dig++ == '9')
2707
280
                        goto round_9_up;
2708
2.98k
                }
2709
17.6k
              accept_dig:
2710
17.6k
                *s++ = dig;
2711
17.6k
                goto ret;
2712
15.5k
            }
2713
97.9k
            if (j1 > 0) {
2714
14.8k
                if (dig == '9') { /* possible if i == 1 */
2715
3.96k
                  round_9_up:
2716
3.96k
                    *s++ = '9';
2717
3.96k
                    goto roundoff;
2718
3.44k
                }
2719
11.4k
                *s++ = dig + 1;
2720
11.4k
                goto ret;
2721
14.8k
            }
2722
83.1k
            *s++ = dig;
2723
83.1k
            if (i == ilim)
2724
0
                break;
2725
83.1k
            b = multadd(b, 10, 0);
2726
83.1k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
83.1k
            if (mlo == mhi) {
2729
78.7k
                mlo = mhi = multadd(mhi, 10, 0);
2730
78.7k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
78.7k
            }
2733
4.38k
            else {
2734
4.38k
                mlo = multadd(mlo, 10, 0);
2735
4.38k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
4.38k
                mhi = multadd(mhi, 10, 0);
2738
4.38k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
4.38k
            }
2741
83.1k
        }
2742
34.6k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
3.96k
      roundoff:
2764
3.96k
        while(*--s == '9')
2765
3.96k
            if (s == s0) {
2766
3.96k
                k++;
2767
3.96k
                *s++ = '1';
2768
3.96k
                goto ret;
2769
3.96k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
34.6k
  ret:
2777
34.6k
    Bfree(S);
2778
34.6k
    if (mhi) {
2779
34.6k
        if (mlo && mlo != mhi)
2780
1.14k
            Bfree(mlo);
2781
34.6k
        Bfree(mhi);
2782
34.6k
    }
2783
46.0k
  ret1:
2784
46.0k
    Bfree(b);
2785
46.0k
    *s = 0;
2786
46.0k
    *decpt = k + 1;
2787
46.0k
    if (rve)
2788
46.0k
        *rve = s;
2789
46.0k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
34.6k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
28
{
2809
28
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
28
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
28
    Bigint *p5 = i2b(625);
2814
28
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
28
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
224
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
196
        p5 = mult(p5, p5);
2822
196
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
196
        p5s[i] = p5;
2826
196
    }
2827
2828
28
#endif
2829
28
    return PyStatus_Ok();
2830
28
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}