Coverage Report

Created: 2026-02-09 07:07

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
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Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
52
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
3.04M
#define word0(x) (x)->L[1]
181
2.03M
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
6.39M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
193k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
821k
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
2.70M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
329k
#define Exp_shift  20
235
90.0k
#define Exp_shift1 20
236
1.35M
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
1.61M
#define Exp_mask  0x7ff00000
239
951k
#define P 53
240
#define Nbits 53
241
521k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
619k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
294k
#define Exp_1  0x3ff00000
246
41.2k
#define Exp_11 0x3ff00000
247
765k
#define Ebits 11
248
306k
#define Frac_mask  0xfffff
249
44.0k
#define Frac_mask1 0xfffff
250
1.57M
#define Ten_pmax 22
251
76
#define Bletch 0x10
252
91.5k
#define Bndry_mask  0xfffff
253
7.57k
#define Bndry_mask1 0xfffff
254
72.2k
#define Sign_bit 0x80000000
255
7.78k
#define Log2P 1
256
#define Tiny0 0
257
161k
#define Tiny1 1
258
45.1k
#define Quick_max 14
259
29.2k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
857k
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
4.32k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
2.75k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
27.9M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
12.0M
#define freelist interp->dtoa.freelist
336
394
#define private_mem interp->dtoa.preallocated
337
1.07k
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
3.00M
{
344
3.00M
    int x;
345
3.00M
    Bigint *rv;
346
3.00M
    unsigned int len;
347
3.00M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
3.00M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
3.00M
        freelist[k] = rv->next;
351
394
    else {
352
394
        x = 1 << k;
353
394
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
394
            /sizeof(double);
355
394
        if (k <= Bigint_Kmax &&
356
394
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
394
        ) {
358
342
            rv = (Bigint*)pmem_next;
359
342
            pmem_next += len;
360
342
        }
361
52
        else {
362
52
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
52
            if (rv == NULL)
364
0
                return NULL;
365
52
        }
366
394
        rv->k = k;
367
394
        rv->maxwds = x;
368
394
    }
369
3.00M
    rv->sign = rv->wds = 0;
370
3.00M
    return rv;
371
3.00M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
6.53M
{
378
6.53M
    if (v) {
379
3.00M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
3.00M
        else {
382
3.00M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
3.00M
            v->next = freelist[v->k];
384
3.00M
            freelist[v->k] = v;
385
3.00M
        }
386
3.00M
    }
387
6.53M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
239k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
239k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
1.20M
{
445
1.20M
    int i, wds;
446
1.20M
    ULong *x;
447
1.20M
    ULLong carry, y;
448
1.20M
    Bigint *b1;
449
450
1.20M
    wds = b->wds;
451
1.20M
    x = b->x;
452
1.20M
    i = 0;
453
1.20M
    carry = a;
454
4.24M
    do {
455
4.24M
        y = *x * (ULLong)m + carry;
456
4.24M
        carry = y >> 32;
457
4.24M
        *x++ = (ULong)(y & FFFFFFFF);
458
4.24M
    }
459
4.24M
    while(++i < wds);
460
1.20M
    if (carry) {
461
73.0k
        if (wds >= b->maxwds) {
462
4.18k
            b1 = Balloc(b->k+1);
463
4.18k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
4.18k
            Bcopy(b1, b);
468
4.18k
            Bfree(b);
469
4.18k
            b = b1;
470
4.18k
        }
471
73.0k
        b->x[wds++] = (ULong)carry;
472
73.0k
        b->wds = wds;
473
73.0k
    }
474
1.20M
    return b;
475
1.20M
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
193k
{
486
193k
    Bigint *b;
487
193k
    int i, k;
488
193k
    Long x, y;
489
490
193k
    x = (nd + 8) / 9;
491
248k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
193k
    b = Balloc(k);
493
193k
    if (b == NULL)
494
0
        return NULL;
495
193k
    b->x[0] = y9;
496
193k
    b->wds = 1;
497
498
193k
    if (nd <= 9)
499
149k
      return b;
500
501
43.6k
    s += 9;
502
337k
    for (i = 9; i < nd0; i++) {
503
293k
        b = multadd(b, 10, *s++ - '0');
504
293k
        if (b == NULL)
505
0
            return NULL;
506
293k
    }
507
43.6k
    s++;
508
142k
    for(; i < nd; i++) {
509
98.8k
        b = multadd(b, 10, *s++ - '0');
510
98.8k
        if (b == NULL)
511
0
            return NULL;
512
98.8k
    }
513
43.6k
    return b;
514
43.6k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
337k
{
521
337k
    int k = 0;
522
523
337k
    if (!(x & 0xffff0000)) {
524
173k
        k = 16;
525
173k
        x <<= 16;
526
173k
    }
527
337k
    if (!(x & 0xff000000)) {
528
182k
        k += 8;
529
182k
        x <<= 8;
530
182k
    }
531
337k
    if (!(x & 0xf0000000)) {
532
160k
        k += 4;
533
160k
        x <<= 4;
534
160k
    }
535
337k
    if (!(x & 0xc0000000)) {
536
194k
        k += 2;
537
194k
        x <<= 2;
538
194k
    }
539
337k
    if (!(x & 0x80000000)) {
540
153k
        k++;
541
153k
        if (!(x & 0x40000000))
542
0
            return 32;
543
153k
    }
544
337k
    return k;
545
337k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
45.0k
{
553
45.0k
    int k;
554
45.0k
    ULong x = *y;
555
556
45.0k
    if (x & 7) {
557
27.6k
        if (x & 1)
558
13.0k
            return 0;
559
14.6k
        if (x & 2) {
560
6.30k
            *y = x >> 1;
561
6.30k
            return 1;
562
6.30k
        }
563
8.36k
        *y = x >> 2;
564
8.36k
        return 2;
565
14.6k
    }
566
17.3k
    k = 0;
567
17.3k
    if (!(x & 0xffff)) {
568
6.59k
        k = 16;
569
6.59k
        x >>= 16;
570
6.59k
    }
571
17.3k
    if (!(x & 0xff)) {
572
3.03k
        k += 8;
573
3.03k
        x >>= 8;
574
3.03k
    }
575
17.3k
    if (!(x & 0xf)) {
576
9.08k
        k += 4;
577
9.08k
        x >>= 4;
578
9.08k
    }
579
17.3k
    if (!(x & 0x3)) {
580
9.11k
        k += 2;
581
9.11k
        x >>= 2;
582
9.11k
    }
583
17.3k
    if (!(x & 1)) {
584
12.4k
        k++;
585
12.4k
        x >>= 1;
586
12.4k
        if (!x)
587
0
            return 32;
588
12.4k
    }
589
17.3k
    *y = x;
590
17.3k
    return k;
591
17.3k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
329k
{
598
329k
    Bigint *b;
599
600
329k
    b = Balloc(1);
601
329k
    if (b == NULL)
602
0
        return NULL;
603
329k
    b->x[0] = i;
604
329k
    b->wds = 1;
605
329k
    return b;
606
329k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
886k
{
614
886k
    Bigint *c;
615
886k
    int k, wa, wb, wc;
616
886k
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
886k
    ULong y;
618
886k
    ULLong carry, z;
619
620
886k
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
7.02k
        c = Balloc(0);
622
7.02k
        if (c == NULL)
623
0
            return NULL;
624
7.02k
        c->wds = 1;
625
7.02k
        c->x[0] = 0;
626
7.02k
        return c;
627
7.02k
    }
628
629
879k
    if (a->wds < b->wds) {
630
487k
        c = a;
631
487k
        a = b;
632
487k
        b = c;
633
487k
    }
634
879k
    k = a->k;
635
879k
    wa = a->wds;
636
879k
    wb = b->wds;
637
879k
    wc = wa + wb;
638
879k
    if (wc > a->maxwds)
639
531k
        k++;
640
879k
    c = Balloc(k);
641
879k
    if (c == NULL)
642
0
        return NULL;
643
7.22M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
6.34M
        *x = 0;
645
879k
    xa = a->x;
646
879k
    xae = xa + wa;
647
879k
    xb = b->x;
648
879k
    xbe = xb + wb;
649
879k
    xc0 = c->x;
650
2.92M
    for(; xb < xbe; xc0++) {
651
2.04M
        if ((y = *xb++)) {
652
2.03M
            x = xa;
653
2.03M
            xc = xc0;
654
2.03M
            carry = 0;
655
15.9M
            do {
656
15.9M
                z = *x++ * (ULLong)y + *xc + carry;
657
15.9M
                carry = z >> 32;
658
15.9M
                *xc++ = (ULong)(z & FFFFFFFF);
659
15.9M
            }
660
15.9M
            while(x < xae);
661
2.03M
            *xc = (ULong)carry;
662
2.03M
        }
663
2.04M
    }
664
1.48M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
879k
    c->wds = wc;
666
879k
    return c;
667
879k
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
283k
{
678
283k
    Bigint *b1, *p5, **p5s;
679
283k
    int i;
680
283k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
283k
    assert(0 <= k && k < 1024);
688
689
283k
    if ((i = k & 3)) {
690
173k
        b = multadd(b, p05[i-1], 0);
691
173k
        if (b == NULL)
692
0
            return NULL;
693
173k
    }
694
695
283k
    if (!(k >>= 2))
696
11.3k
        return b;
697
272k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
272k
    p5s = interp->dtoa.p5s;
699
1.34M
    for(;;) {
700
1.34M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
1.34M
        p5 = *p5s;
702
1.34M
        p5s++;
703
1.34M
        if (k & 1) {
704
812k
            b1 = mult(b, p5);
705
812k
            Bfree(b);
706
812k
            b = b1;
707
812k
            if (b == NULL)
708
0
                return NULL;
709
812k
        }
710
1.34M
        if (!(k >>= 1))
711
272k
            break;
712
1.34M
    }
713
272k
    return b;
714
272k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
652k
{
775
652k
    int i, k1, n, n1;
776
652k
    Bigint *b1;
777
652k
    ULong *x, *x1, *xe, z;
778
779
652k
    if (!k || (!b->x[0] && b->wds == 1))
780
7.61k
        return b;
781
782
645k
    n = k >> 5;
783
645k
    k1 = b->k;
784
645k
    n1 = n + b->wds + 1;
785
1.81M
    for(i = b->maxwds; n1 > i; i <<= 1)
786
1.17M
        k1++;
787
645k
    b1 = Balloc(k1);
788
645k
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
645k
    x1 = b1->x;
793
4.29M
    for(i = 0; i < n; i++)
794
3.64M
        *x1++ = 0;
795
645k
    x = b->x;
796
645k
    xe = x + b->wds;
797
645k
    if (k &= 0x1f) {
798
621k
        k1 = 32 - k;
799
621k
        z = 0;
800
2.18M
        do {
801
2.18M
            *x1++ = *x << k | z;
802
2.18M
            z = *x++ >> k1;
803
2.18M
        }
804
2.18M
        while(x < xe);
805
621k
        if ((*x1 = z))
806
109k
            ++n1;
807
621k
    }
808
23.4k
    else do
809
43.0k
             *x1++ = *x++;
810
43.0k
        while(x < xe);
811
645k
    b1->wds = n1 - 1;
812
645k
    Bfree(b);
813
645k
    return b1;
814
645k
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
1.43M
{
822
1.43M
    ULong *xa, *xa0, *xb, *xb0;
823
1.43M
    int i, j;
824
825
1.43M
    i = a->wds;
826
1.43M
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
1.43M
    if (i -= j)
834
184k
        return i;
835
1.25M
    xa0 = a->x;
836
1.25M
    xa = xa0 + j;
837
1.25M
    xb0 = b->x;
838
1.25M
    xb = xb0 + j;
839
1.61M
    for(;;) {
840
1.61M
        if (*--xa != *--xb)
841
1.23M
            return *xa < *xb ? -1 : 1;
842
378k
        if (xa <= xa0)
843
17.3k
            break;
844
378k
    }
845
17.3k
    return 0;
846
1.25M
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
352k
{
855
352k
    Bigint *c;
856
352k
    int i, wa, wb;
857
352k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
352k
    ULLong borrow, y;
859
860
352k
    i = cmp(a,b);
861
352k
    if (!i) {
862
3.36k
        c = Balloc(0);
863
3.36k
        if (c == NULL)
864
0
            return NULL;
865
3.36k
        c->wds = 1;
866
3.36k
        c->x[0] = 0;
867
3.36k
        return c;
868
3.36k
    }
869
349k
    if (i < 0) {
870
73.3k
        c = a;
871
73.3k
        a = b;
872
73.3k
        b = c;
873
73.3k
        i = 1;
874
73.3k
    }
875
276k
    else
876
276k
        i = 0;
877
349k
    c = Balloc(a->k);
878
349k
    if (c == NULL)
879
0
        return NULL;
880
349k
    c->sign = i;
881
349k
    wa = a->wds;
882
349k
    xa = a->x;
883
349k
    xae = xa + wa;
884
349k
    wb = b->wds;
885
349k
    xb = b->x;
886
349k
    xbe = xb + wb;
887
349k
    xc = c->x;
888
349k
    borrow = 0;
889
3.02M
    do {
890
3.02M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
3.02M
        borrow = y >> 32 & (ULong)1;
892
3.02M
        *xc++ = (ULong)(y & FFFFFFFF);
893
3.02M
    }
894
3.02M
    while(xb < xbe);
895
635k
    while(xa < xae) {
896
286k
        y = *xa++ - borrow;
897
286k
        borrow = y >> 32 & (ULong)1;
898
286k
        *xc++ = (ULong)(y & FFFFFFFF);
899
286k
    }
900
680k
    while(!*--xc)
901
330k
        wa--;
902
349k
    c->wds = wa;
903
349k
    return c;
904
349k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
140k
{
912
140k
    Long L;
913
140k
    U u;
914
915
140k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
140k
    word0(&u) = L;
917
140k
    word1(&u) = 0;
918
140k
    return dval(&u);
919
140k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
273k
{
926
273k
    ULong *xa, *xa0, w, y, z;
927
273k
    int k;
928
273k
    U d;
929
930
273k
    xa0 = a->x;
931
273k
    xa = xa0 + a->wds;
932
273k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
273k
    k = hi0bits(y);
937
273k
    *e = 32 - k;
938
273k
    if (k < Ebits) {
939
109k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
109k
        w = xa > xa0 ? *--xa : 0;
941
109k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
109k
        goto ret_d;
943
109k
    }
944
163k
    z = xa > xa0 ? *--xa : 0;
945
163k
    if (k -= Ebits) {
946
157k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
157k
        y = xa > xa0 ? *--xa : 0;
948
157k
        word1(&d) = z << k | y >> (32 - k);
949
157k
    }
950
6.13k
    else {
951
6.13k
        word0(&d) = Exp_1 | y;
952
6.13k
        word1(&d) = z;
953
6.13k
    }
954
273k
  ret_d:
955
273k
    return dval(&d);
956
163k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
261k
{
982
261k
    Bigint *b;
983
984
261k
    b = Balloc(1);
985
261k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
261k
    b->wds = 2;
990
261k
    b->x[0] = word1(d);
991
261k
    b->x[1] = word0(d) & Frac_mask;
992
261k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
261k
    if (*e < Etiny)
994
7.61k
        *e = Etiny;
995
253k
    else
996
253k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
261k
    if (scale && (b->x[0] || b->x[1])) {
1000
32.0k
        *e -= scale;
1001
32.0k
        if (*e < Etiny) {
1002
28.4k
            scale = Etiny - *e;
1003
28.4k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
28.4k
            assert(0 < scale && scale <= P - 1);
1006
28.4k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
15.4k
                assert(b->x[0] == 0);
1009
15.4k
                b->x[0] = b->x[1];
1010
15.4k
                b->x[1] = 0;
1011
15.4k
                scale -= 32;
1012
15.4k
            }
1013
28.4k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
26.2k
                assert(b->x[0] << (32 - scale) == 0);
1016
26.2k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
26.2k
                b->x[1] >>= scale;
1018
26.2k
            }
1019
28.4k
        }
1020
32.0k
    }
1021
    /* Ensure b is normalized. */
1022
261k
    if (!b->x[1])
1023
27.5k
        b->wds = 1;
1024
1025
261k
    return b;
1026
261k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
45.0k
{
1040
45.0k
    Bigint *b;
1041
45.0k
    int de, k;
1042
45.0k
    ULong *x, y, z;
1043
45.0k
    int i;
1044
1045
45.0k
    b = Balloc(1);
1046
45.0k
    if (b == NULL)
1047
0
        return NULL;
1048
45.0k
    x = b->x;
1049
1050
45.0k
    z = word0(d) & Frac_mask;
1051
45.0k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
45.0k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
41.2k
        z |= Exp_msk1;
1054
45.0k
    if ((y = word1(d))) {
1055
33.5k
        if ((k = lo0bits(&y))) {
1056
21.2k
            x[0] = y | z << (32 - k);
1057
21.2k
            z >>= k;
1058
21.2k
        }
1059
12.3k
        else
1060
12.3k
            x[0] = y;
1061
33.5k
        i =
1062
33.5k
            b->wds = (x[1] = z) ? 2 : 1;
1063
33.5k
    }
1064
11.4k
    else {
1065
11.4k
        k = lo0bits(&z);
1066
11.4k
        x[0] = z;
1067
11.4k
        i =
1068
11.4k
            b->wds = 1;
1069
11.4k
        k += 32;
1070
11.4k
    }
1071
45.0k
    if (de) {
1072
41.2k
        *e = de - Bias - (P-1) + k;
1073
41.2k
        *bits = P - k;
1074
41.2k
    }
1075
3.76k
    else {
1076
3.76k
        *e = de - Bias - (P-1) + 1 + k;
1077
3.76k
        *bits = 32*i - hi0bits(x[i-1]);
1078
3.76k
    }
1079
45.0k
    return b;
1080
45.0k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
136k
{
1088
136k
    U da, db;
1089
136k
    int k, ka, kb;
1090
1091
136k
    dval(&da) = b2d(a, &ka);
1092
136k
    dval(&db) = b2d(b, &kb);
1093
136k
    k = ka - kb + 32*(a->wds - b->wds);
1094
136k
    if (k > 0)
1095
49.9k
        word0(&da) += k*Exp_msk1;
1096
86.5k
    else {
1097
86.5k
        k = -k;
1098
86.5k
        word0(&db) += k*Exp_msk1;
1099
86.5k
    }
1100
136k
    return dval(&da) / dval(&db);
1101
136k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
29.6k
#define Scale_Bit 0x10
1119
31.8k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
60.8k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
60.8k
{
1129
60.8k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
60.8k
    if (p2 > 0)
1131
23.2k
        rv -= p2;
1132
60.8k
    return rv & kmask;
1133
60.8k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
571k
{
1142
571k
    int n;
1143
571k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
571k
    ULLong borrow, carry, y, ys;
1145
1146
571k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
571k
    if (b->wds < n)
1152
18.6k
        return 0;
1153
553k
    sx = S->x;
1154
553k
    sxe = sx + --n;
1155
553k
    bx = b->x;
1156
553k
    bxe = bx + n;
1157
553k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
553k
    if (q) {
1163
365k
        borrow = 0;
1164
365k
        carry = 0;
1165
2.04M
        do {
1166
2.04M
            ys = *sx++ * (ULLong)q + carry;
1167
2.04M
            carry = ys >> 32;
1168
2.04M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
2.04M
            borrow = y >> 32 & (ULong)1;
1170
2.04M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
2.04M
        }
1172
2.04M
        while(sx <= sxe);
1173
365k
        if (!*bxe) {
1174
2.45k
            bx = b->x;
1175
2.45k
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
2.45k
            b->wds = n;
1178
2.45k
        }
1179
365k
    }
1180
553k
    if (cmp(b, S) >= 0) {
1181
32.9k
        q++;
1182
32.9k
        borrow = 0;
1183
32.9k
        carry = 0;
1184
32.9k
        bx = b->x;
1185
32.9k
        sx = S->x;
1186
190k
        do {
1187
190k
            ys = *sx++ + carry;
1188
190k
            carry = ys >> 32;
1189
190k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
190k
            borrow = y >> 32 & (ULong)1;
1191
190k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
190k
        }
1193
190k
        while(sx <= sxe);
1194
32.9k
        bx = b->x;
1195
32.9k
        bxe = bx + n;
1196
32.9k
        if (!*bxe) {
1197
22.6k
            while(--bxe > bx && !*bxe)
1198
1.59k
                --n;
1199
21.0k
            b->wds = n;
1200
21.0k
        }
1201
32.9k
    }
1202
553k
    return q;
1203
571k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
3.97k
{
1214
3.97k
    U u;
1215
1216
3.97k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
399
        word0(&u) = (P+2)*Exp_msk1;
1219
399
        word1(&u) = 0;
1220
399
        return u.d;
1221
399
    }
1222
3.57k
    else {
1223
3.57k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
3.57k
        return ulp(x);
1225
3.57k
    }
1226
3.97k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
26.8k
{
1277
26.8k
    Bigint *b, *d;
1278
26.8k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
26.8k
    nd = bc->nd;
1281
26.8k
    nd0 = bc->nd0;
1282
26.8k
    p5 = nd + bc->e0;
1283
26.8k
    b = sd2b(rv, bc->scale, &p2);
1284
26.8k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
26.8k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
26.8k
    b = lshift(b, 1);
1294
26.8k
    if (b == NULL)
1295
0
        return -1;
1296
26.8k
    b->x[0] |= 1;
1297
26.8k
    p2--;
1298
1299
26.8k
    p2 -= p5;
1300
26.8k
    d = i2b(1);
1301
26.8k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
26.8k
    if (p5 > 0) {
1309
24.1k
        d = pow5mult(d, p5);
1310
24.1k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
24.1k
    }
1315
2.74k
    else if (p5 < 0) {
1316
1.66k
        b = pow5mult(b, -p5);
1317
1.66k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
1.66k
    }
1322
26.8k
    if (p2 > 0) {
1323
21.9k
        b2 = p2;
1324
21.9k
        d2 = 0;
1325
21.9k
    }
1326
4.89k
    else {
1327
4.89k
        b2 = 0;
1328
4.89k
        d2 = -p2;
1329
4.89k
    }
1330
26.8k
    i = dshift(d, d2);
1331
26.8k
    if ((b2 += i) > 0) {
1332
26.6k
        b = lshift(b, b2);
1333
26.6k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
26.6k
    }
1338
26.8k
    if ((d2 += i) > 0) {
1339
25.7k
        d = lshift(d, d2);
1340
25.7k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
25.7k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
26.8k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
990
        dd = -1;
1352
25.8k
    else {
1353
25.8k
        i = 0;
1354
453k
        for(;;) {
1355
453k
            b = multadd(b, 10, 0);
1356
453k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
453k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
453k
            i++;
1362
1363
453k
            if (dd)
1364
24.5k
                break;
1365
429k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
793
                dd = i < nd;
1368
793
                break;
1369
793
            }
1370
428k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
567
                dd = -1;
1373
567
                break;
1374
567
            }
1375
428k
        }
1376
25.8k
    }
1377
26.8k
    Bfree(b);
1378
26.8k
    Bfree(d);
1379
26.8k
    if (dd > 0 || (dd == 0 && odd))
1380
2.07k
        dval(rv) += sulp(rv, bc);
1381
26.8k
    return 0;
1382
26.8k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
900k
{
1388
900k
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
900k
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
900k
    const char *s, *s0, *s1;
1391
900k
    double aadj, aadj1;
1392
900k
    U aadj2, adj, rv, rv0;
1393
900k
    ULong y, z, abs_exp;
1394
900k
    Long L;
1395
900k
    BCinfo bc;
1396
900k
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
900k
    size_t ndigits, fraclen;
1398
900k
    double result;
1399
1400
900k
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
900k
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
900k
    sign = 0;
1407
900k
    switch (c) {
1408
644k
    case '-':
1409
644k
        sign = 1;
1410
644k
        _Py_FALLTHROUGH;
1411
644k
    case '+':
1412
644k
        c = *++s;
1413
900k
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
900k
    s1 = s;
1417
928k
    while (c == '0')
1418
28.8k
        c = *++s;
1419
900k
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
900k
    s0 = s1 = s;
1426
8.25M
    while ('0' <= c && c <= '9')
1427
7.34M
        c = *++s;
1428
900k
    ndigits = s - s1;
1429
900k
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
900k
    if (c == '.') {
1433
83.7k
        c = *++s;
1434
83.7k
        if (!ndigits) {
1435
29.1k
            s1 = s;
1436
1.62M
            while (c == '0')
1437
1.59M
                c = *++s;
1438
29.1k
            lz = lz || s != s1;
1439
29.1k
            fraclen += (s - s1);
1440
29.1k
            s0 = s;
1441
29.1k
        }
1442
83.7k
        s1 = s;
1443
29.5M
        while ('0' <= c && c <= '9')
1444
29.4M
            c = *++s;
1445
83.7k
        ndigits += s - s1;
1446
83.7k
        fraclen += s - s1;
1447
83.7k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
900k
    if (!ndigits && !lz) {
1453
28
        if (se)
1454
28
            *se = (char *)s00;
1455
28
        goto parse_error;
1456
28
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
900k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
900k
    nd = (int)ndigits;
1466
900k
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
900k
    e = 0;
1470
900k
    if (c == 'e' || c == 'E') {
1471
821k
        s00 = s;
1472
821k
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
821k
        esign = 0;
1476
821k
        switch (c) {
1477
32.9k
        case '-':
1478
32.9k
            esign = 1;
1479
32.9k
            _Py_FALLTHROUGH;
1480
50.6k
        case '+':
1481
50.6k
            c = *++s;
1482
821k
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
821k
        s1 = s;
1486
975k
        while (c == '0')
1487
154k
            c = *++s;
1488
821k
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
821k
        s1 = s;
1492
821k
        abs_exp = 0;
1493
7.51M
        while ('0' <= c && c <= '9') {
1494
6.68M
            abs_exp = 10*abs_exp + (c - '0');
1495
6.68M
            c = *++s;
1496
6.68M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
821k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
8.29k
            e = (int)MAX_ABS_EXP;
1503
812k
        else
1504
812k
            e = (int)abs_exp;
1505
821k
        if (esign)
1506
32.9k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
821k
        if (s == s1 && !lz)
1510
0
            s = s00;
1511
821k
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
900k
    e -= nd - nd0;
1515
900k
    if (nd0 <= 0)
1516
35.8k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
900k
    if (se)
1520
900k
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
900k
    if (!nd)
1525
16.7k
        goto ret;
1526
9.45M
    for (i = nd; i > 0; ) {
1527
9.45M
        --i;
1528
9.45M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
883k
            ++i;
1530
883k
            break;
1531
883k
        }
1532
9.45M
    }
1533
883k
    e += nd - i;
1534
883k
    nd = i;
1535
883k
    if (nd0 > nd)
1536
24.3k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
883k
    bc.e0 = e1 = e;
1575
883k
    y = z = 0;
1576
3.21M
    for (i = 0; i < nd; i++) {
1577
2.38M
        if (i < 9)
1578
1.87M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
516k
        else if (i < DBL_DIG+1)
1580
462k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
53.2k
        else
1582
53.2k
            break;
1583
2.38M
    }
1584
1585
883k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
883k
    dval(&rv) = y;
1587
883k
    if (k > 9) {
1588
78.3k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
78.3k
    }
1590
883k
    if (nd <= DBL_DIG
1591
822k
        && Flt_Rounds == 1
1592
883k
        ) {
1593
822k
        if (!e)
1594
12.0k
            goto ret;
1595
810k
        if (e > 0) {
1596
757k
            if (e <= Ten_pmax) {
1597
26.5k
                dval(&rv) *= tens[e];
1598
26.5k
                goto ret;
1599
26.5k
            }
1600
731k
            i = DBL_DIG - nd;
1601
731k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
2.78k
                e -= i;
1606
2.78k
                dval(&rv) *= tens[i];
1607
2.78k
                dval(&rv) *= tens[e];
1608
2.78k
                goto ret;
1609
2.78k
            }
1610
731k
        }
1611
52.5k
        else if (e >= -Ten_pmax) {
1612
28.5k
            dval(&rv) /= tens[-e];
1613
28.5k
            goto ret;
1614
28.5k
        }
1615
810k
    }
1616
813k
    e1 += nd - k;
1617
1618
813k
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
813k
    if (e1 > 0) {
1623
767k
        if ((i = e1 & 15))
1624
720k
            dval(&rv) *= tens[i];
1625
767k
        if (e1 &= ~15) {
1626
757k
            if (e1 > DBL_MAX_10_EXP)
1627
616k
                goto ovfl;
1628
140k
            e1 >>= 4;
1629
433k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
292k
                if (e1 & 1)
1631
172k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
140k
            word0(&rv) -= P*Exp_msk1;
1634
140k
            dval(&rv) *= bigtens[j];
1635
140k
            if ((z = word0(&rv) & Exp_mask)
1636
140k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
855
                goto ovfl;
1638
140k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
797
                word0(&rv) = Big0;
1642
797
                word1(&rv) = Big1;
1643
797
            }
1644
139k
            else
1645
139k
                word0(&rv) += P*Exp_msk1;
1646
140k
        }
1647
767k
    }
1648
45.4k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
41.4k
        e1 = -e1;
1660
41.4k
        if ((i = e1 & 15))
1661
33.8k
            dval(&rv) /= tens[i];
1662
41.4k
        if (e1 >>= 4) {
1663
31.8k
            if (e1 >= 1 << n_bigtens)
1664
2.19k
                goto undfl;
1665
29.6k
            if (e1 & Scale_Bit)
1666
21.0k
                bc.scale = 2*P;
1667
147k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
117k
                if (e1 & 1)
1669
70.8k
                    dval(&rv) *= tinytens[j];
1670
29.6k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
21.0k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
19.5k
                if (j >= 32) {
1674
12.4k
                    word1(&rv) = 0;
1675
12.4k
                    if (j >= 53)
1676
7.51k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
4.96k
                    else
1678
4.96k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
12.4k
                }
1680
7.02k
                else
1681
7.02k
                    word1(&rv) &= 0xffffffff << j;
1682
19.5k
            }
1683
29.6k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
29.6k
        }
1686
41.4k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
193k
    bc.nd = nd;
1693
193k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
193k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
300k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
300k
            --i;
1708
300k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
34.2k
                ++i;
1710
34.2k
                break;
1711
34.2k
            }
1712
300k
        }
1713
34.2k
        e += nd - i;
1714
34.2k
        nd = i;
1715
34.2k
        if (nd0 > nd)
1716
29.8k
            nd0 = nd;
1717
34.2k
        if (nd < 9) { /* must recompute y */
1718
23.4k
            y = 0;
1719
179k
            for(i = 0; i < nd0; ++i)
1720
155k
                y = 10*y + s0[i] - '0';
1721
31.6k
            for(; i < nd; ++i)
1722
8.21k
                y = 10*y + s0[i+1] - '0';
1723
23.4k
        }
1724
34.2k
    }
1725
193k
    bd0 = s2b(s0, nd0, nd, y);
1726
193k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
234k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
234k
        bd = Balloc(bd0->k);
1758
234k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
234k
        Bcopy(bd, bd0);
1762
234k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
234k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
234k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
234k
        bs = i2b(1);
1772
234k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
234k
        if (e >= 0) {
1777
173k
            bb2 = bb5 = 0;
1778
173k
            bd2 = bd5 = e;
1779
173k
        }
1780
61.4k
        else {
1781
61.4k
            bb2 = bb5 = -e;
1782
61.4k
            bd2 = bd5 = 0;
1783
61.4k
        }
1784
234k
        if (bbe >= 0)
1785
175k
            bb2 += bbe;
1786
59.6k
        else
1787
59.6k
            bd2 -= bbe;
1788
234k
        bs2 = bb2;
1789
234k
        bb2++;
1790
234k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
234k
        i = bb2 < bd2 ? bb2 : bd2;
1811
234k
        if (i > bs2)
1812
58.5k
            i = bs2;
1813
234k
        if (i > 0) {
1814
233k
            bb2 -= i;
1815
233k
            bd2 -= i;
1816
233k
            bs2 -= i;
1817
233k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
234k
        if (bb5 > 0) {
1821
61.4k
            bs = pow5mult(bs, bb5);
1822
61.4k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
61.4k
            Bigint *bb1 = mult(bs, bb);
1826
61.4k
            Bfree(bb);
1827
61.4k
            bb = bb1;
1828
61.4k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
61.4k
        }
1832
234k
        if (bb2 > 0) {
1833
234k
            bb = lshift(bb, bb2);
1834
234k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
234k
        }
1838
234k
        if (bd5 > 0) {
1839
164k
            bd = pow5mult(bd, bd5);
1840
164k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
164k
        }
1844
234k
        if (bd2 > 0) {
1845
58.5k
            bd = lshift(bd, bd2);
1846
58.5k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
58.5k
        }
1850
234k
        if (bs2 > 0) {
1851
171k
            bs = lshift(bs, bs2);
1852
171k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
171k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
234k
        delta = diff(bb, bd);
1862
234k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
234k
        dsign = delta->sign;
1866
234k
        delta->sign = 0;
1867
234k
        i = cmp(delta, bs);
1868
234k
        if (bc.nd > nd && i <= 0) {
1869
34.2k
            if (dsign)
1870
25.6k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
8.64k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
1.46k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
1.46k
                if (j - bc.scale >= 2) {
1890
1.21k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
1.21k
                    break; /* Use bigcomp. */
1892
1.21k
                }
1893
1.46k
            }
1894
1895
7.42k
            {
1896
7.42k
                bc.nd = nd;
1897
7.42k
                i = -1; /* Discarded digits make delta smaller. */
1898
7.42k
            }
1899
7.42k
        }
1900
1901
207k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
66.2k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
6.60k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
66.2k
                ) {
1908
60.9k
                break;
1909
60.9k
            }
1910
5.36k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
652
                break;
1913
652
            }
1914
4.71k
            delta = lshift(delta,Log2P);
1915
4.71k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
4.71k
            if (cmp(delta, bs) > 0)
1919
1.39k
                goto drop_down;
1920
3.31k
            break;
1921
4.71k
        }
1922
141k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
5.05k
            if (dsign) {
1925
2.05k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
759
                    &&  word1(&rv) == (
1927
759
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
759
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
412
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
412
                        + Exp_msk1
1934
412
                        ;
1935
412
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
412
                    break;
1938
412
                }
1939
2.05k
            }
1940
2.99k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
1.39k
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
1.39k
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
1.39k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
1.39k
                word0(&rv) = L | Bndry_mask1;
1958
1.39k
                word1(&rv) = 0xffffffff;
1959
1.39k
                break;
1960
1.39k
            }
1961
4.64k
            if (!odd)
1962
3.96k
                break;
1963
677
            if (dsign)
1964
439
                dval(&rv) += sulp(&rv, &bc);
1965
238
            else {
1966
238
                dval(&rv) -= sulp(&rv, &bc);
1967
238
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
238
            }
1973
            /* dsign = 1 - dsign; */
1974
677
            break;
1975
677
        }
1976
136k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
101k
            if (dsign)
1978
14.0k
                aadj = aadj1 = 1.;
1979
87.6k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
80.5k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
80.5k
                aadj = 1.;
1986
80.5k
                aadj1 = -1.;
1987
80.5k
            }
1988
7.02k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
7.02k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
7.02k
                else
1995
7.02k
                    aadj *= 0.5;
1996
7.02k
                aadj1 = -aadj;
1997
7.02k
            }
1998
101k
        }
1999
34.9k
        else {
2000
34.9k
            aadj *= 0.5;
2001
34.9k
            aadj1 = dsign ? aadj : -aadj;
2002
34.9k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
34.9k
        }
2005
136k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
136k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
4.03k
            dval(&rv0) = dval(&rv);
2011
4.03k
            word0(&rv) -= P*Exp_msk1;
2012
4.03k
            adj.d = aadj1 * ulp(&rv);
2013
4.03k
            dval(&rv) += adj.d;
2014
4.03k
            if ((word0(&rv) & Exp_mask) >=
2015
4.03k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
1.57k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
1.18k
                    goto ovfl;
2018
1.18k
                }
2019
387
                word0(&rv) = Big0;
2020
387
                word1(&rv) = Big1;
2021
387
                goto cont;
2022
1.57k
            }
2023
2.46k
            else
2024
2.46k
                word0(&rv) += P*Exp_msk1;
2025
4.03k
        }
2026
132k
        else {
2027
132k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
16.0k
                if (aadj <= 0x7fffffff) {
2029
16.0k
                    if ((z = (ULong)aadj) <= 0)
2030
1.82k
                        z = 1;
2031
16.0k
                    aadj = z;
2032
16.0k
                    aadj1 = dsign ? aadj : -aadj;
2033
16.0k
                }
2034
16.0k
                dval(&aadj2) = aadj1;
2035
16.0k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
16.0k
                aadj1 = dval(&aadj2);
2037
16.0k
            }
2038
132k
            adj.d = aadj1 * ulp(&rv);
2039
132k
            dval(&rv) += adj.d;
2040
132k
        }
2041
134k
        z = word0(&rv) & Exp_mask;
2042
134k
        if (bc.nd == nd) {
2043
113k
            if (!bc.scale)
2044
97.3k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
95.9k
                    L = (Long)aadj;
2047
95.9k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
95.9k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
95.9k
                        if (aadj < .4999999 || aadj > .5000001)
2051
94.2k
                            break;
2052
95.9k
                    }
2053
11
                    else if (aadj < .4999999/FLT_RADIX)
2054
11
                        break;
2055
95.9k
                }
2056
113k
        }
2057
41.1k
      cont:
2058
41.1k
        Bfree(bb); bb = NULL;
2059
41.1k
        Bfree(bd); bd = NULL;
2060
41.1k
        Bfree(bs); bs = NULL;
2061
41.1k
        Bfree(delta); delta = NULL;
2062
41.1k
    }
2063
192k
    if (bc.nd > nd) {
2064
26.8k
        error = bigcomp(&rv, s0, &bc);
2065
26.8k
        if (error)
2066
0
            goto failed_malloc;
2067
26.8k
    }
2068
2069
192k
    if (bc.scale) {
2070
21.0k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
21.0k
        word1(&rv0) = 0;
2072
21.0k
        dval(&rv) *= dval(&rv0);
2073
21.0k
    }
2074
2075
279k
  ret:
2076
279k
    result = sign ? -dval(&rv) : dval(&rv);
2077
279k
    goto done;
2078
2079
28
  parse_error:
2080
28
    result = 0.0;
2081
28
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
2.19k
  undfl:
2089
2.19k
    result = sign ? -0.0 : 0.0;
2090
2.19k
    goto done;
2091
2092
618k
  ovfl:
2093
618k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
618k
    word0(&rv) = Exp_mask;
2096
618k
    word1(&rv) = 0;
2097
618k
    result = sign ? -dval(&rv) : dval(&rv);
2098
618k
    goto done;
2099
2100
900k
  done:
2101
900k
    Bfree(bb);
2102
900k
    Bfree(bd);
2103
900k
    Bfree(bs);
2104
900k
    Bfree(bd0);
2105
900k
    Bfree(delta);
2106
900k
    return result;
2107
2108
192k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
51.8k
{
2113
51.8k
    int j, k, *r;
2114
2115
51.8k
    j = sizeof(ULong);
2116
51.8k
    for(k = 0;
2117
51.8k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
51.8k
        j <<= 1)
2119
0
        k++;
2120
51.8k
    r = (int*)Balloc(k);
2121
51.8k
    if (r == NULL)
2122
0
        return NULL;
2123
51.8k
    *r = k;
2124
51.8k
    return (char *)(r+1);
2125
51.8k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
6.82k
{
2130
6.82k
    char *rv, *t;
2131
2132
6.82k
    rv = rv_alloc(n);
2133
6.82k
    if (rv == NULL)
2134
0
        return NULL;
2135
6.82k
    t = rv;
2136
16.8k
    while((*t = *s++)) t++;
2137
6.82k
    if (rve)
2138
6.82k
        *rve = t;
2139
6.82k
    return rv;
2140
6.82k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
51.8k
{
2151
51.8k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
51.8k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
51.8k
    Bfree(b);
2154
51.8k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
51.8k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
51.8k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
51.8k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
51.8k
        spec_case, try_quick;
2235
51.8k
    Long L;
2236
51.8k
    int denorm;
2237
51.8k
    ULong x;
2238
51.8k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
51.8k
    U d2, eps, u;
2240
51.8k
    double ds;
2241
51.8k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
51.8k
    mlo = mhi = S = 0;
2246
51.8k
    s0 = 0;
2247
2248
51.8k
    u.d = dd;
2249
51.8k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
20.3k
        *sign = 1;
2252
20.3k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
20.3k
    }
2254
31.4k
    else
2255
31.4k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
51.8k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
451
    {
2260
        /* Infinity or NaN */
2261
451
        *decpt = 9999;
2262
451
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
451
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
451
    }
2266
51.3k
    if (!dval(&u)) {
2267
6.37k
        *decpt = 1;
2268
6.37k
        return nrv_alloc("0", rve, 1);
2269
6.37k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
45.0k
    b = d2b(&u, &be, &bbits);
2274
45.0k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
45.0k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
41.2k
        dval(&d2) = dval(&u);
2278
41.2k
        word0(&d2) &= Frac_mask1;
2279
41.2k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
41.2k
        i -= Bias;
2304
41.2k
        denorm = 0;
2305
41.2k
    }
2306
3.76k
    else {
2307
        /* d is denormalized */
2308
2309
3.76k
        i = bbits + be + (Bias + (P-1) - 1);
2310
3.76k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
3.76k
            : word1(&u) << (32 - i);
2312
3.76k
        dval(&d2) = x;
2313
3.76k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
3.76k
        i -= (Bias + (P-1) - 1) + 1;
2315
3.76k
        denorm = 1;
2316
3.76k
    }
2317
45.0k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
45.0k
        i*0.301029995663981;
2319
45.0k
    k = (int)ds;
2320
45.0k
    if (ds < 0. && ds != k)
2321
11.9k
        k--;    /* want k = floor(ds) */
2322
45.0k
    k_check = 1;
2323
45.0k
    if (k >= 0 && k <= Ten_pmax) {
2324
17.9k
        if (dval(&u) < tens[k])
2325
2.02k
            k--;
2326
17.9k
        k_check = 0;
2327
17.9k
    }
2328
45.0k
    j = bbits - i - 1;
2329
45.0k
    if (j >= 0) {
2330
17.3k
        b2 = 0;
2331
17.3k
        s2 = j;
2332
17.3k
    }
2333
27.6k
    else {
2334
27.6k
        b2 = -j;
2335
27.6k
        s2 = 0;
2336
27.6k
    }
2337
45.0k
    if (k >= 0) {
2338
32.4k
        b5 = 0;
2339
32.4k
        s5 = k;
2340
32.4k
        s2 += k;
2341
32.4k
    }
2342
12.5k
    else {
2343
12.5k
        b2 -= k;
2344
12.5k
        b5 = -k;
2345
12.5k
        s5 = 0;
2346
12.5k
    }
2347
45.0k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
45.0k
    try_quick = 1;
2351
2352
45.0k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
45.0k
    leftright = 1;
2357
45.0k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
45.0k
    switch(mode) {
2360
44.9k
    case 0:
2361
44.9k
    case 1:
2362
44.9k
        i = 18;
2363
44.9k
        ndigits = 0;
2364
44.9k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
96
    case 3:
2374
96
        leftright = 0;
2375
96
        _Py_FALLTHROUGH;
2376
96
    case 5:
2377
96
        i = ndigits + k + 1;
2378
96
        ilim = i;
2379
96
        ilim1 = i - 1;
2380
96
        if (i <= 0)
2381
0
            i = 1;
2382
45.0k
    }
2383
45.0k
    s0 = rv_alloc(i);
2384
45.0k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
45.0k
    s = s0;
2387
2388
2389
45.0k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
96
        i = 0;
2394
96
        dval(&d2) = dval(&u);
2395
96
        k0 = k;
2396
96
        ilim0 = ilim;
2397
96
        ieps = 2; /* conservative */
2398
96
        if (k > 0) {
2399
76
            ds = tens[k&0xf];
2400
76
            j = k >> 4;
2401
76
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
76
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
76
            dval(&u) /= ds;
2413
76
        }
2414
20
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
96
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
96
        dval(&eps) = ieps*dval(&u) + 7.;
2431
96
        word0(&eps) -= (P-1)*Exp_msk1;
2432
96
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
96
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
96
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
96
            dval(&eps) *= tens[ilim-1];
2463
261
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
261
                L = (Long)(dval(&u));
2465
261
                if (!(dval(&u) -= L))
2466
18
                    ilim = i;
2467
261
                *s++ = '0' + (int)L;
2468
261
                if (i == ilim) {
2469
96
                    if (dval(&u) > 0.5 + dval(&eps))
2470
44
                        goto bump_up;
2471
52
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
57
                        while(*--s == '0');
2473
52
                        s++;
2474
52
                        goto ret1;
2475
52
                    }
2476
0
                    break;
2477
96
                }
2478
261
            }
2479
96
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
44.9k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
10.9k
        ds = tens[k];
2492
10.9k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
14.8k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
14.8k
            L = (Long)(dval(&u) / ds);
2500
14.8k
            dval(&u) -= L*ds;
2501
14.8k
            *s++ = '0' + (int)L;
2502
14.8k
            if (!dval(&u)) {
2503
10.9k
                break;
2504
10.9k
            }
2505
3.89k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
44
                  bump_up:
2509
45
                    while(*--s == '9')
2510
1
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
44
                    ++*s++;
2516
44
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
44
                break;
2526
0
            }
2527
3.89k
        }
2528
10.9k
        goto ret1;
2529
10.9k
    }
2530
2531
33.9k
    m2 = b2;
2532
33.9k
    m5 = b5;
2533
33.9k
    if (leftright) {
2534
33.9k
        i =
2535
33.9k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
33.9k
            1 + P - bbits;
2537
33.9k
        b2 += i;
2538
33.9k
        s2 += i;
2539
33.9k
        mhi = i2b(1);
2540
33.9k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
33.9k
    }
2543
33.9k
    if (m2 > 0 && s2 > 0) {
2544
30.7k
        i = m2 < s2 ? m2 : s2;
2545
30.7k
        b2 -= i;
2546
30.7k
        m2 -= i;
2547
30.7k
        s2 -= i;
2548
30.7k
    }
2549
33.9k
    if (b5 > 0) {
2550
12.5k
        if (leftright) {
2551
12.5k
            if (m5 > 0) {
2552
12.5k
                mhi = pow5mult(mhi, m5);
2553
12.5k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
12.5k
                b1 = mult(mhi, b);
2556
12.5k
                Bfree(b);
2557
12.5k
                b = b1;
2558
12.5k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
12.5k
            }
2561
12.5k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
12.5k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
12.5k
    }
2573
33.9k
    S = i2b(1);
2574
33.9k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
33.9k
    if (s5 > 0) {
2577
19.5k
        S = pow5mult(S, s5);
2578
19.5k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
19.5k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
33.9k
    spec_case = 0;
2585
33.9k
    if ((mode < 2 || leftright)
2586
33.9k
        ) {
2587
33.9k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.30k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
33.9k
            ) {
2590
            /* The special case */
2591
1.02k
            b2 += Log2P;
2592
1.02k
            s2 += Log2P;
2593
1.02k
            spec_case = 1;
2594
1.02k
        }
2595
33.9k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
33.9k
#define iInc 28
2605
33.9k
    i = dshift(S, s2);
2606
33.9k
    b2 += i;
2607
33.9k
    m2 += i;
2608
33.9k
    s2 += i;
2609
33.9k
    if (b2 > 0) {
2610
33.9k
        b = lshift(b, b2);
2611
33.9k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
33.9k
    }
2614
33.9k
    if (s2 > 0) {
2615
33.3k
        S = lshift(S, s2);
2616
33.3k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
33.3k
    }
2619
33.9k
    if (k_check) {
2620
27.0k
        if (cmp(b,S) < 0) {
2621
4.45k
            k--;
2622
4.45k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
4.45k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
4.45k
            if (leftright) {
2626
4.45k
                mhi = multadd(mhi, 10, 0);
2627
4.45k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
4.45k
            }
2630
4.45k
            ilim = ilim1;
2631
4.45k
        }
2632
27.0k
    }
2633
33.9k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
33.9k
    if (leftright) {
2653
33.9k
        if (m2 > 0) {
2654
33.1k
            mhi = lshift(mhi, m2);
2655
33.1k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
33.1k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
33.9k
        mlo = mhi;
2664
33.9k
        if (spec_case) {
2665
1.02k
            mhi = Balloc(mhi->k);
2666
1.02k
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
1.02k
            Bcopy(mhi, mlo);
2669
1.02k
            mhi = lshift(mhi, Log2P);
2670
1.02k
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
1.02k
        }
2673
2674
118k
        for(i = 1;;i++) {
2675
118k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
118k
            j = cmp(b, mlo);
2680
118k
            delta = diff(S, mhi);
2681
118k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
118k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
118k
            Bfree(delta);
2685
118k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
118k
                ) {
2687
1.71k
                if (dig == '9')
2688
232
                    goto round_9_up;
2689
1.48k
                if (j > 0)
2690
748
                    dig++;
2691
1.48k
                *s++ = dig;
2692
1.48k
                goto ret;
2693
1.71k
            }
2694
116k
            if (j < 0 || (j == 0 && mode != 1
2695
1.78k
                          && !(word1(&u) & 1)
2696
100k
                    )) {
2697
16.8k
                if (!b->x[0] && b->wds <= 1) {
2698
1.98k
                    goto accept_dig;
2699
1.98k
                }
2700
14.8k
                if (j1 > 0) {
2701
2.69k
                    b = lshift(b, 1);
2702
2.69k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
2.69k
                    j1 = cmp(b, S);
2705
2.69k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.60k
                        && dig++ == '9')
2707
268
                        goto round_9_up;
2708
2.69k
                }
2709
16.6k
              accept_dig:
2710
16.6k
                *s++ = dig;
2711
16.6k
                goto ret;
2712
14.8k
            }
2713
99.6k
            if (j1 > 0) {
2714
15.3k
                if (dig == '9') { /* possible if i == 1 */
2715
4.42k
                  round_9_up:
2716
4.42k
                    *s++ = '9';
2717
4.42k
                    goto roundoff;
2718
3.92k
                }
2719
11.4k
                *s++ = dig + 1;
2720
11.4k
                goto ret;
2721
15.3k
            }
2722
84.2k
            *s++ = dig;
2723
84.2k
            if (i == ilim)
2724
0
                break;
2725
84.2k
            b = multadd(b, 10, 0);
2726
84.2k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
84.2k
            if (mlo == mhi) {
2729
79.2k
                mlo = mhi = multadd(mhi, 10, 0);
2730
79.2k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
79.2k
            }
2733
5.00k
            else {
2734
5.00k
                mlo = multadd(mlo, 10, 0);
2735
5.00k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
5.00k
                mhi = multadd(mhi, 10, 0);
2738
5.00k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
5.00k
            }
2741
84.2k
        }
2742
33.9k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
4.42k
      roundoff:
2764
4.42k
        while(*--s == '9')
2765
4.42k
            if (s == s0) {
2766
4.42k
                k++;
2767
4.42k
                *s++ = '1';
2768
4.42k
                goto ret;
2769
4.42k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
33.9k
  ret:
2777
33.9k
    Bfree(S);
2778
33.9k
    if (mhi) {
2779
33.9k
        if (mlo && mlo != mhi)
2780
1.02k
            Bfree(mlo);
2781
33.9k
        Bfree(mhi);
2782
33.9k
    }
2783
45.0k
  ret1:
2784
45.0k
    Bfree(b);
2785
45.0k
    *s = 0;
2786
45.0k
    *decpt = k + 1;
2787
45.0k
    if (rve)
2788
45.0k
        *rve = s;
2789
45.0k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
33.9k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
32
{
2809
32
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
32
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
32
    Bigint *p5 = i2b(625);
2814
32
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
32
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
256
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
224
        p5 = mult(p5, p5);
2822
224
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
224
        p5s[i] = p5;
2826
224
    }
2827
2828
32
#endif
2829
32
    return PyStatus_Ok();
2830
32
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}