Coverage Report

Created: 2026-02-26 06:53

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
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Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
52
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
4.17M
#define word0(x) (x)->L[1]
181
2.88M
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
8.18M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
300k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
1.04M
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
3.36M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
437k
#define Exp_shift  20
235
92.0k
#define Exp_shift1 20
236
2.09M
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
2.14M
#define Exp_mask  0x7ff00000
239
1.44M
#define P 53
240
#define Nbits 53
241
802k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
831k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
431k
#define Exp_1  0x3ff00000
246
42.4k
#define Exp_11 0x3ff00000
247
1.25M
#define Ebits 11
248
413k
#define Frac_mask  0xfffff
249
44.6k
#define Frac_mask1 0xfffff
250
2.01M
#define Ten_pmax 22
251
83
#define Bletch 0x10
252
131k
#define Bndry_mask  0xfffff
253
7.45k
#define Bndry_mask1 0xfffff
254
76.8k
#define Sign_bit 0x80000000
255
6.86k
#define Log2P 1
256
#define Tiny0 0
257
308k
#define Tiny1 1
258
46.1k
#define Quick_max 14
259
30.6k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
1.07M
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
3.56k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
2.25k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
29.0M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
16.2M
#define freelist interp->dtoa.freelist
336
394
#define private_mem interp->dtoa.preallocated
337
1.07k
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
4.06M
{
344
4.06M
    int x;
345
4.06M
    Bigint *rv;
346
4.06M
    unsigned int len;
347
4.06M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
4.06M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
4.06M
        freelist[k] = rv->next;
351
394
    else {
352
394
        x = 1 << k;
353
394
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
394
            /sizeof(double);
355
394
        if (k <= Bigint_Kmax &&
356
394
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
394
        ) {
358
342
            rv = (Bigint*)pmem_next;
359
342
            pmem_next += len;
360
342
        }
361
52
        else {
362
52
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
52
            if (rv == NULL)
364
0
                return NULL;
365
52
        }
366
394
        rv->k = k;
367
394
        rv->maxwds = x;
368
394
    }
369
4.06M
    rv->sign = rv->wds = 0;
370
4.06M
    return rv;
371
4.06M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
8.17M
{
378
8.17M
    if (v) {
379
4.06M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
4.06M
        else {
382
4.06M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
4.06M
            v->next = freelist[v->k];
384
4.06M
            freelist[v->k] = v;
385
4.06M
        }
386
4.06M
    }
387
8.17M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
345k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
345k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
1.11M
{
445
1.11M
    int i, wds;
446
1.11M
    ULong *x;
447
1.11M
    ULLong carry, y;
448
1.11M
    Bigint *b1;
449
450
1.11M
    wds = b->wds;
451
1.11M
    x = b->x;
452
1.11M
    i = 0;
453
1.11M
    carry = a;
454
4.10M
    do {
455
4.10M
        y = *x * (ULLong)m + carry;
456
4.10M
        carry = y >> 32;
457
4.10M
        *x++ = (ULong)(y & FFFFFFFF);
458
4.10M
    }
459
4.10M
    while(++i < wds);
460
1.11M
    if (carry) {
461
63.3k
        if (wds >= b->maxwds) {
462
3.38k
            b1 = Balloc(b->k+1);
463
3.38k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
3.38k
            Bcopy(b1, b);
468
3.38k
            Bfree(b);
469
3.38k
            b = b1;
470
3.38k
        }
471
63.3k
        b->x[wds++] = (ULong)carry;
472
63.3k
        b->wds = wds;
473
63.3k
    }
474
1.11M
    return b;
475
1.11M
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
300k
{
486
300k
    Bigint *b;
487
300k
    int i, k;
488
300k
    Long x, y;
489
490
300k
    x = (nd + 8) / 9;
491
348k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
300k
    b = Balloc(k);
493
300k
    if (b == NULL)
494
0
        return NULL;
495
300k
    b->x[0] = y9;
496
300k
    b->wds = 1;
497
498
300k
    if (nd <= 9)
499
263k
      return b;
500
501
37.4k
    s += 9;
502
284k
    for (i = 9; i < nd0; i++) {
503
246k
        b = multadd(b, 10, *s++ - '0');
504
246k
        if (b == NULL)
505
0
            return NULL;
506
246k
    }
507
37.4k
    s++;
508
134k
    for(; i < nd; i++) {
509
97.1k
        b = multadd(b, 10, *s++ - '0');
510
97.1k
        if (b == NULL)
511
0
            return NULL;
512
97.1k
    }
513
37.4k
    return b;
514
37.4k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
473k
{
521
473k
    int k = 0;
522
523
473k
    if (!(x & 0xffff0000)) {
524
201k
        k = 16;
525
201k
        x <<= 16;
526
201k
    }
527
473k
    if (!(x & 0xff000000)) {
528
212k
        k += 8;
529
212k
        x <<= 8;
530
212k
    }
531
473k
    if (!(x & 0xf0000000)) {
532
305k
        k += 4;
533
305k
        x <<= 4;
534
305k
    }
535
473k
    if (!(x & 0xc0000000)) {
536
243k
        k += 2;
537
243k
        x <<= 2;
538
243k
    }
539
473k
    if (!(x & 0x80000000)) {
540
150k
        k++;
541
150k
        if (!(x & 0x40000000))
542
0
            return 32;
543
150k
    }
544
473k
    return k;
545
473k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
46.0k
{
553
46.0k
    int k;
554
46.0k
    ULong x = *y;
555
556
46.0k
    if (x & 7) {
557
27.9k
        if (x & 1)
558
12.6k
            return 0;
559
15.3k
        if (x & 2) {
560
6.05k
            *y = x >> 1;
561
6.05k
            return 1;
562
6.05k
        }
563
9.28k
        *y = x >> 2;
564
9.28k
        return 2;
565
15.3k
    }
566
18.0k
    k = 0;
567
18.0k
    if (!(x & 0xffff)) {
568
6.76k
        k = 16;
569
6.76k
        x >>= 16;
570
6.76k
    }
571
18.0k
    if (!(x & 0xff)) {
572
3.19k
        k += 8;
573
3.19k
        x >>= 8;
574
3.19k
    }
575
18.0k
    if (!(x & 0xf)) {
576
9.54k
        k += 4;
577
9.54k
        x >>= 4;
578
9.54k
    }
579
18.0k
    if (!(x & 0x3)) {
580
9.60k
        k += 2;
581
9.60k
        x >>= 2;
582
9.60k
    }
583
18.0k
    if (!(x & 1)) {
584
13.3k
        k++;
585
13.3k
        x >>= 1;
586
13.3k
        if (!x)
587
0
            return 32;
588
13.3k
    }
589
18.0k
    *y = x;
590
18.0k
    return k;
591
18.0k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
435k
{
598
435k
    Bigint *b;
599
600
435k
    b = Balloc(1);
601
435k
    if (b == NULL)
602
0
        return NULL;
603
435k
    b->x[0] = i;
604
435k
    b->wds = 1;
605
435k
    return b;
606
435k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
1.20M
{
614
1.20M
    Bigint *c;
615
1.20M
    int k, wa, wb, wc;
616
1.20M
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
1.20M
    ULong y;
618
1.20M
    ULLong carry, z;
619
620
1.20M
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
7.76k
        c = Balloc(0);
622
7.76k
        if (c == NULL)
623
0
            return NULL;
624
7.76k
        c->wds = 1;
625
7.76k
        c->x[0] = 0;
626
7.76k
        return c;
627
7.76k
    }
628
629
1.19M
    if (a->wds < b->wds) {
630
655k
        c = a;
631
655k
        a = b;
632
655k
        b = c;
633
655k
    }
634
1.19M
    k = a->k;
635
1.19M
    wa = a->wds;
636
1.19M
    wb = b->wds;
637
1.19M
    wc = wa + wb;
638
1.19M
    if (wc > a->maxwds)
639
753k
        k++;
640
1.19M
    c = Balloc(k);
641
1.19M
    if (c == NULL)
642
0
        return NULL;
643
8.60M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
7.40M
        *x = 0;
645
1.19M
    xa = a->x;
646
1.19M
    xae = xa + wa;
647
1.19M
    xb = b->x;
648
1.19M
    xbe = xb + wb;
649
1.19M
    xc0 = c->x;
650
3.67M
    for(; xb < xbe; xc0++) {
651
2.47M
        if ((y = *xb++)) {
652
2.46M
            x = xa;
653
2.46M
            xc = xc0;
654
2.46M
            carry = 0;
655
16.6M
            do {
656
16.6M
                z = *x++ * (ULLong)y + *xc + carry;
657
16.6M
                carry = z >> 32;
658
16.6M
                *xc++ = (ULong)(z & FFFFFFFF);
659
16.6M
            }
660
16.6M
            while(x < xae);
661
2.46M
            *xc = (ULong)carry;
662
2.46M
        }
663
2.47M
    }
664
2.01M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
1.19M
    c->wds = wc;
666
1.19M
    return c;
667
1.19M
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
389k
{
678
389k
    Bigint *b1, *p5, **p5s;
679
389k
    int i;
680
389k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
389k
    assert(0 <= k && k < 1024);
688
689
389k
    if ((i = k & 3)) {
690
177k
        b = multadd(b, p05[i-1], 0);
691
177k
        if (b == NULL)
692
0
            return NULL;
693
177k
    }
694
695
389k
    if (!(k >>= 2))
696
10.8k
        return b;
697
378k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
378k
    p5s = interp->dtoa.p5s;
699
1.79M
    for(;;) {
700
1.79M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
1.79M
        p5 = *p5s;
702
1.79M
        p5s++;
703
1.79M
        if (k & 1) {
704
1.13M
            b1 = mult(b, p5);
705
1.13M
            Bfree(b);
706
1.13M
            b = b1;
707
1.13M
            if (b == NULL)
708
0
                return NULL;
709
1.13M
        }
710
1.79M
        if (!(k >>= 1))
711
378k
            break;
712
1.79M
    }
713
378k
    return b;
714
378k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
863k
{
775
863k
    int i, k1, n, n1;
776
863k
    Bigint *b1;
777
863k
    ULong *x, *x1, *xe, z;
778
779
863k
    if (!k || (!b->x[0] && b->wds == 1))
780
8.29k
        return b;
781
782
855k
    n = k >> 5;
783
855k
    k1 = b->k;
784
855k
    n1 = n + b->wds + 1;
785
2.32M
    for(i = b->maxwds; n1 > i; i <<= 1)
786
1.47M
        k1++;
787
855k
    b1 = Balloc(k1);
788
855k
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
855k
    x1 = b1->x;
793
4.84M
    for(i = 0; i < n; i++)
794
3.99M
        *x1++ = 0;
795
855k
    x = b->x;
796
855k
    xe = x + b->wds;
797
855k
    if (k &= 0x1f) {
798
837k
        k1 = 32 - k;
799
837k
        z = 0;
800
2.55M
        do {
801
2.55M
            *x1++ = *x << k | z;
802
2.55M
            z = *x++ >> k1;
803
2.55M
        }
804
2.55M
        while(x < xe);
805
837k
        if ((*x1 = z))
806
196k
            ++n1;
807
837k
    }
808
17.6k
    else do
809
32.3k
             *x1++ = *x++;
810
32.3k
        while(x < xe);
811
855k
    b1->wds = n1 - 1;
812
855k
    Bfree(b);
813
855k
    return b1;
814
855k
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
1.60M
{
822
1.60M
    ULong *xa, *xa0, *xb, *xb0;
823
1.60M
    int i, j;
824
825
1.60M
    i = a->wds;
826
1.60M
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
1.60M
    if (i -= j)
834
179k
        return i;
835
1.42M
    xa0 = a->x;
836
1.42M
    xa = xa0 + j;
837
1.42M
    xb0 = b->x;
838
1.42M
    xb = xb0 + j;
839
1.99M
    for(;;) {
840
1.99M
        if (*--xa != *--xb)
841
1.40M
            return *xa < *xb ? -1 : 1;
842
588k
        if (xa <= xa0)
843
17.1k
            break;
844
588k
    }
845
17.1k
    return 0;
846
1.42M
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
453k
{
855
453k
    Bigint *c;
856
453k
    int i, wa, wb;
857
453k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
453k
    ULLong borrow, y;
859
860
453k
    i = cmp(a,b);
861
453k
    if (!i) {
862
2.96k
        c = Balloc(0);
863
2.96k
        if (c == NULL)
864
0
            return NULL;
865
2.96k
        c->wds = 1;
866
2.96k
        c->x[0] = 0;
867
2.96k
        return c;
868
2.96k
    }
869
450k
    if (i < 0) {
870
78.4k
        c = a;
871
78.4k
        a = b;
872
78.4k
        b = c;
873
78.4k
        i = 1;
874
78.4k
    }
875
371k
    else
876
371k
        i = 0;
877
450k
    c = Balloc(a->k);
878
450k
    if (c == NULL)
879
0
        return NULL;
880
450k
    c->sign = i;
881
450k
    wa = a->wds;
882
450k
    xa = a->x;
883
450k
    xae = xa + wa;
884
450k
    wb = b->wds;
885
450k
    xb = b->x;
886
450k
    xbe = xb + wb;
887
450k
    xc = c->x;
888
450k
    borrow = 0;
889
3.53M
    do {
890
3.53M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
3.53M
        borrow = y >> 32 & (ULong)1;
892
3.53M
        *xc++ = (ULong)(y & FFFFFFFF);
893
3.53M
    }
894
3.53M
    while(xb < xbe);
895
754k
    while(xa < xae) {
896
304k
        y = *xa++ - borrow;
897
304k
        borrow = y >> 32 & (ULong)1;
898
304k
        *xc++ = (ULong)(y & FFFFFFFF);
899
304k
    }
900
971k
    while(!*--xc)
901
521k
        wa--;
902
450k
    c->wds = wa;
903
450k
    return c;
904
450k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
209k
{
912
209k
    Long L;
913
209k
    U u;
914
915
209k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
209k
    word0(&u) = L;
917
209k
    word1(&u) = 0;
918
209k
    return dval(&u);
919
209k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
410k
{
926
410k
    ULong *xa, *xa0, w, y, z;
927
410k
    int k;
928
410k
    U d;
929
930
410k
    xa0 = a->x;
931
410k
    xa = xa0 + a->wds;
932
410k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
410k
    k = hi0bits(y);
937
410k
    *e = 32 - k;
938
410k
    if (k < Ebits) {
939
215k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
215k
        w = xa > xa0 ? *--xa : 0;
941
215k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
215k
        goto ret_d;
943
215k
    }
944
194k
    z = xa > xa0 ? *--xa : 0;
945
194k
    if (k -= Ebits) {
946
189k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
189k
        y = xa > xa0 ? *--xa : 0;
948
189k
        word1(&d) = z << k | y >> (32 - k);
949
189k
    }
950
5.09k
    else {
951
5.09k
        word0(&d) = Exp_1 | y;
952
5.09k
        word1(&d) = z;
953
5.09k
    }
954
410k
  ret_d:
955
410k
    return dval(&d);
956
194k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
366k
{
982
366k
    Bigint *b;
983
984
366k
    b = Balloc(1);
985
366k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
366k
    b->wds = 2;
990
366k
    b->x[0] = word1(d);
991
366k
    b->x[1] = word0(d) & Frac_mask;
992
366k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
366k
    if (*e < Etiny)
994
8.29k
        *e = Etiny;
995
358k
    else
996
358k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
366k
    if (scale && (b->x[0] || b->x[1])) {
1000
32.5k
        *e -= scale;
1001
32.5k
        if (*e < Etiny) {
1002
28.2k
            scale = Etiny - *e;
1003
28.2k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
28.2k
            assert(0 < scale && scale <= P - 1);
1006
28.2k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
17.0k
                assert(b->x[0] == 0);
1009
17.0k
                b->x[0] = b->x[1];
1010
17.0k
                b->x[1] = 0;
1011
17.0k
                scale -= 32;
1012
17.0k
            }
1013
28.2k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
26.0k
                assert(b->x[0] << (32 - scale) == 0);
1016
26.0k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
26.0k
                b->x[1] >>= scale;
1018
26.0k
            }
1019
28.2k
        }
1020
32.5k
    }
1021
    /* Ensure b is normalized. */
1022
366k
    if (!b->x[1])
1023
29.2k
        b->wds = 1;
1024
1025
366k
    return b;
1026
366k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
46.0k
{
1040
46.0k
    Bigint *b;
1041
46.0k
    int de, k;
1042
46.0k
    ULong *x, y, z;
1043
46.0k
    int i;
1044
1045
46.0k
    b = Balloc(1);
1046
46.0k
    if (b == NULL)
1047
0
        return NULL;
1048
46.0k
    x = b->x;
1049
1050
46.0k
    z = word0(d) & Frac_mask;
1051
46.0k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
46.0k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
42.4k
        z |= Exp_msk1;
1054
46.0k
    if ((y = word1(d))) {
1055
34.2k
        if ((k = lo0bits(&y))) {
1056
22.3k
            x[0] = y | z << (32 - k);
1057
22.3k
            z >>= k;
1058
22.3k
        }
1059
11.9k
        else
1060
11.9k
            x[0] = y;
1061
34.2k
        i =
1062
34.2k
            b->wds = (x[1] = z) ? 2 : 1;
1063
34.2k
    }
1064
11.7k
    else {
1065
11.7k
        k = lo0bits(&z);
1066
11.7k
        x[0] = z;
1067
11.7k
        i =
1068
11.7k
            b->wds = 1;
1069
11.7k
        k += 32;
1070
11.7k
    }
1071
46.0k
    if (de) {
1072
42.4k
        *e = de - Bias - (P-1) + k;
1073
42.4k
        *bits = P - k;
1074
42.4k
    }
1075
3.61k
    else {
1076
3.61k
        *e = de - Bias - (P-1) + 1 + k;
1077
3.61k
        *bits = 32*i - hi0bits(x[i-1]);
1078
3.61k
    }
1079
46.0k
    return b;
1080
46.0k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
205k
{
1088
205k
    U da, db;
1089
205k
    int k, ka, kb;
1090
1091
205k
    dval(&da) = b2d(a, &ka);
1092
205k
    dval(&db) = b2d(b, &kb);
1093
205k
    k = ka - kb + 32*(a->wds - b->wds);
1094
205k
    if (k > 0)
1095
41.8k
        word0(&da) += k*Exp_msk1;
1096
163k
    else {
1097
163k
        k = -k;
1098
163k
        word0(&db) += k*Exp_msk1;
1099
163k
    }
1100
205k
    return dval(&da) / dval(&db);
1101
205k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
32.6k
#define Scale_Bit 0x10
1119
36.5k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
59.8k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
59.8k
{
1129
59.8k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
59.8k
    if (p2 > 0)
1131
22.2k
        rv -= p2;
1132
59.8k
    return rv & kmask;
1133
59.8k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
542k
{
1142
542k
    int n;
1143
542k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
542k
    ULLong borrow, carry, y, ys;
1145
1146
542k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
542k
    if (b->wds < n)
1152
13.8k
        return 0;
1153
528k
    sx = S->x;
1154
528k
    sxe = sx + --n;
1155
528k
    bx = b->x;
1156
528k
    bxe = bx + n;
1157
528k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
528k
    if (q) {
1163
347k
        borrow = 0;
1164
347k
        carry = 0;
1165
2.03M
        do {
1166
2.03M
            ys = *sx++ * (ULLong)q + carry;
1167
2.03M
            carry = ys >> 32;
1168
2.03M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
2.03M
            borrow = y >> 32 & (ULong)1;
1170
2.03M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
2.03M
        }
1172
2.03M
        while(sx <= sxe);
1173
347k
        if (!*bxe) {
1174
2.53k
            bx = b->x;
1175
2.53k
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
2.53k
            b->wds = n;
1178
2.53k
        }
1179
347k
    }
1180
528k
    if (cmp(b, S) >= 0) {
1181
31.9k
        q++;
1182
31.9k
        borrow = 0;
1183
31.9k
        carry = 0;
1184
31.9k
        bx = b->x;
1185
31.9k
        sx = S->x;
1186
179k
        do {
1187
179k
            ys = *sx++ + carry;
1188
179k
            carry = ys >> 32;
1189
179k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
179k
            borrow = y >> 32 & (ULong)1;
1191
179k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
179k
        }
1193
179k
        while(sx <= sxe);
1194
31.9k
        bx = b->x;
1195
31.9k
        bxe = bx + n;
1196
31.9k
        if (!*bxe) {
1197
21.6k
            while(--bxe > bx && !*bxe)
1198
1.59k
                --n;
1199
20.0k
            b->wds = n;
1200
20.0k
        }
1201
31.9k
    }
1202
528k
    return q;
1203
542k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
4.38k
{
1214
4.38k
    U u;
1215
1216
4.38k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
325
        word0(&u) = (P+2)*Exp_msk1;
1219
325
        word1(&u) = 0;
1220
325
        return u.d;
1221
325
    }
1222
4.05k
    else {
1223
4.05k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
4.05k
        return ulp(x);
1225
4.05k
    }
1226
4.38k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
25.3k
{
1277
25.3k
    Bigint *b, *d;
1278
25.3k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
25.3k
    nd = bc->nd;
1281
25.3k
    nd0 = bc->nd0;
1282
25.3k
    p5 = nd + bc->e0;
1283
25.3k
    b = sd2b(rv, bc->scale, &p2);
1284
25.3k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
25.3k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
25.3k
    b = lshift(b, 1);
1294
25.3k
    if (b == NULL)
1295
0
        return -1;
1296
25.3k
    b->x[0] |= 1;
1297
25.3k
    p2--;
1298
1299
25.3k
    p2 -= p5;
1300
25.3k
    d = i2b(1);
1301
25.3k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
25.3k
    if (p5 > 0) {
1309
22.9k
        d = pow5mult(d, p5);
1310
22.9k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
22.9k
    }
1315
2.41k
    else if (p5 < 0) {
1316
1.48k
        b = pow5mult(b, -p5);
1317
1.48k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
1.48k
    }
1322
25.3k
    if (p2 > 0) {
1323
20.9k
        b2 = p2;
1324
20.9k
        d2 = 0;
1325
20.9k
    }
1326
4.46k
    else {
1327
4.46k
        b2 = 0;
1328
4.46k
        d2 = -p2;
1329
4.46k
    }
1330
25.3k
    i = dshift(d, d2);
1331
25.3k
    if ((b2 += i) > 0) {
1332
25.1k
        b = lshift(b, b2);
1333
25.1k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
25.1k
    }
1338
25.3k
    if ((d2 += i) > 0) {
1339
24.4k
        d = lshift(d, d2);
1340
24.4k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
24.4k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
25.3k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
734
        dd = -1;
1352
24.6k
    else {
1353
24.6k
        i = 0;
1354
431k
        for(;;) {
1355
431k
            b = multadd(b, 10, 0);
1356
431k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
431k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
431k
            i++;
1362
1363
431k
            if (dd)
1364
23.2k
                break;
1365
407k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
970
                dd = i < nd;
1368
970
                break;
1369
970
            }
1370
406k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
399
                dd = -1;
1373
399
                break;
1374
399
            }
1375
406k
        }
1376
24.6k
    }
1377
25.3k
    Bfree(b);
1378
25.3k
    Bfree(d);
1379
25.3k
    if (dd > 0 || (dd == 0 && odd))
1380
2.53k
        dval(rv) += sulp(rv, bc);
1381
25.3k
    return 0;
1382
25.3k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
1.12M
{
1388
1.12M
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
1.12M
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
1.12M
    const char *s, *s0, *s1;
1391
1.12M
    double aadj, aadj1;
1392
1.12M
    U aadj2, adj, rv, rv0;
1393
1.12M
    ULong y, z, abs_exp;
1394
1.12M
    Long L;
1395
1.12M
    BCinfo bc;
1396
1.12M
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
1.12M
    size_t ndigits, fraclen;
1398
1.12M
    double result;
1399
1400
1.12M
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
1.12M
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
1.12M
    sign = 0;
1407
1.12M
    switch (c) {
1408
733k
    case '-':
1409
733k
        sign = 1;
1410
733k
        _Py_FALLTHROUGH;
1411
733k
    case '+':
1412
733k
        c = *++s;
1413
1.12M
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
1.12M
    s1 = s;
1417
1.15M
    while (c == '0')
1418
31.8k
        c = *++s;
1419
1.12M
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
1.12M
    s0 = s1 = s;
1426
6.89M
    while ('0' <= c && c <= '9')
1427
5.77M
        c = *++s;
1428
1.12M
    ndigits = s - s1;
1429
1.12M
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
1.12M
    if (c == '.') {
1433
76.8k
        c = *++s;
1434
76.8k
        if (!ndigits) {
1435
28.9k
            s1 = s;
1436
2.11M
            while (c == '0')
1437
2.08M
                c = *++s;
1438
28.9k
            lz = lz || s != s1;
1439
28.9k
            fraclen += (s - s1);
1440
28.9k
            s0 = s;
1441
28.9k
        }
1442
76.8k
        s1 = s;
1443
27.7M
        while ('0' <= c && c <= '9')
1444
27.7M
            c = *++s;
1445
76.8k
        ndigits += s - s1;
1446
76.8k
        fraclen += s - s1;
1447
76.8k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
1.12M
    if (!ndigits && !lz) {
1453
46
        if (se)
1454
46
            *se = (char *)s00;
1455
46
        goto parse_error;
1456
46
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
1.12M
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
1.12M
    nd = (int)ndigits;
1466
1.12M
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
1.12M
    e = 0;
1470
1.12M
    if (c == 'e' || c == 'E') {
1471
1.04M
        s00 = s;
1472
1.04M
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
1.04M
        esign = 0;
1476
1.04M
        switch (c) {
1477
38.7k
        case '-':
1478
38.7k
            esign = 1;
1479
38.7k
            _Py_FALLTHROUGH;
1480
57.1k
        case '+':
1481
57.1k
            c = *++s;
1482
1.04M
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
1.04M
        s1 = s;
1486
1.29M
        while (c == '0')
1487
244k
            c = *++s;
1488
1.04M
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
1.04M
        s1 = s;
1492
1.04M
        abs_exp = 0;
1493
13.7M
        while ('0' <= c && c <= '9') {
1494
12.7M
            abs_exp = 10*abs_exp + (c - '0');
1495
12.7M
            c = *++s;
1496
12.7M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
1.04M
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
11.7k
            e = (int)MAX_ABS_EXP;
1503
1.03M
        else
1504
1.03M
            e = (int)abs_exp;
1505
1.04M
        if (esign)
1506
38.7k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
1.04M
        if (s == s1 && !lz)
1510
0
            s = s00;
1511
1.04M
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
1.12M
    e -= nd - nd0;
1515
1.12M
    if (nd0 <= 0)
1516
36.6k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
1.12M
    if (se)
1520
1.12M
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
1.12M
    if (!nd)
1525
18.8k
        goto ret;
1526
8.85M
    for (i = nd; i > 0; ) {
1527
8.85M
        --i;
1528
8.85M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
1.10M
            ++i;
1530
1.10M
            break;
1531
1.10M
        }
1532
8.85M
    }
1533
1.10M
    e += nd - i;
1534
1.10M
    nd = i;
1535
1.10M
    if (nd0 > nd)
1536
25.7k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
1.10M
    bc.e0 = e1 = e;
1575
1.10M
    y = z = 0;
1576
3.96M
    for (i = 0; i < nd; i++) {
1577
2.90M
        if (i < 9)
1578
2.43M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
477k
        else if (i < DBL_DIG+1)
1580
427k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
49.7k
        else
1582
49.7k
            break;
1583
2.90M
    }
1584
1585
1.10M
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
1.10M
    dval(&rv) = y;
1587
1.10M
    if (k > 9) {
1588
73.3k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
73.3k
    }
1590
1.10M
    if (nd <= DBL_DIG
1591
1.04M
        && Flt_Rounds == 1
1592
1.10M
        ) {
1593
1.04M
        if (!e)
1594
12.1k
            goto ret;
1595
1.03M
        if (e > 0) {
1596
978k
            if (e <= Ten_pmax) {
1597
31.9k
                dval(&rv) *= tens[e];
1598
31.9k
                goto ret;
1599
31.9k
            }
1600
946k
            i = DBL_DIG - nd;
1601
946k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
3.02k
                e -= i;
1606
3.02k
                dval(&rv) *= tens[i];
1607
3.02k
                dval(&rv) *= tens[e];
1608
3.02k
                goto ret;
1609
3.02k
            }
1610
946k
        }
1611
56.2k
        else if (e >= -Ten_pmax) {
1612
26.8k
            dval(&rv) /= tens[-e];
1613
26.8k
            goto ret;
1614
26.8k
        }
1615
1.03M
    }
1616
1.02M
    e1 += nd - k;
1617
1618
1.02M
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
1.02M
    if (e1 > 0) {
1623
980k
        if ((i = e1 & 15))
1624
898k
            dval(&rv) *= tens[i];
1625
980k
        if (e1 &= ~15) {
1626
970k
            if (e1 > DBL_MAX_10_EXP)
1627
723k
                goto ovfl;
1628
247k
            e1 >>= 4;
1629
661k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
413k
                if (e1 & 1)
1631
223k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
247k
            word0(&rv) -= P*Exp_msk1;
1634
247k
            dval(&rv) *= bigtens[j];
1635
247k
            if ((z = word0(&rv) & Exp_mask)
1636
247k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
1.43k
                goto ovfl;
1638
245k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
573
                word0(&rv) = Big0;
1642
573
                word1(&rv) = Big1;
1643
573
            }
1644
245k
            else
1645
245k
                word0(&rv) += P*Exp_msk1;
1646
245k
        }
1647
980k
    }
1648
49.0k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
45.6k
        e1 = -e1;
1660
45.6k
        if ((i = e1 & 15))
1661
36.8k
            dval(&rv) /= tens[i];
1662
45.6k
        if (e1 >>= 4) {
1663
36.5k
            if (e1 >= 1 << n_bigtens)
1664
3.87k
                goto undfl;
1665
32.6k
            if (e1 & Scale_Bit)
1666
21.8k
                bc.scale = 2*P;
1667
162k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
130k
                if (e1 & 1)
1669
77.8k
                    dval(&rv) *= tinytens[j];
1670
32.6k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
21.8k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
20.0k
                if (j >= 32) {
1674
13.8k
                    word1(&rv) = 0;
1675
13.8k
                    if (j >= 53)
1676
8.23k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
5.58k
                    else
1678
5.58k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
13.8k
                }
1680
6.19k
                else
1681
6.19k
                    word1(&rv) &= 0xffffffff << j;
1682
20.0k
            }
1683
32.6k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
32.6k
        }
1686
45.6k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
300k
    bc.nd = nd;
1693
300k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
300k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
285k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
285k
            --i;
1708
285k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
31.8k
                ++i;
1710
31.8k
                break;
1711
31.8k
            }
1712
285k
        }
1713
31.8k
        e += nd - i;
1714
31.8k
        nd = i;
1715
31.8k
        if (nd0 > nd)
1716
26.8k
            nd0 = nd;
1717
31.8k
        if (nd < 9) { /* must recompute y */
1718
22.8k
            y = 0;
1719
178k
            for(i = 0; i < nd0; ++i)
1720
156k
                y = 10*y + s0[i] - '0';
1721
31.0k
            for(; i < nd; ++i)
1722
8.28k
                y = 10*y + s0[i+1] - '0';
1723
22.8k
        }
1724
31.8k
    }
1725
300k
    bd0 = s2b(s0, nd0, nd, y);
1726
300k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
341k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
341k
        bd = Balloc(bd0->k);
1758
341k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
341k
        Bcopy(bd, bd0);
1762
341k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
341k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
341k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
341k
        bs = i2b(1);
1772
341k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
341k
        if (e >= 0) {
1777
277k
            bb2 = bb5 = 0;
1778
277k
            bd2 = bd5 = e;
1779
277k
        }
1780
63.7k
        else {
1781
63.7k
            bb2 = bb5 = -e;
1782
63.7k
            bd2 = bd5 = 0;
1783
63.7k
        }
1784
341k
        if (bbe >= 0)
1785
278k
            bb2 += bbe;
1786
62.6k
        else
1787
62.6k
            bd2 -= bbe;
1788
341k
        bs2 = bb2;
1789
341k
        bb2++;
1790
341k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
341k
        i = bb2 < bd2 ? bb2 : bd2;
1811
341k
        if (i > bs2)
1812
61.3k
            i = bs2;
1813
341k
        if (i > 0) {
1814
340k
            bb2 -= i;
1815
340k
            bd2 -= i;
1816
340k
            bs2 -= i;
1817
340k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
341k
        if (bb5 > 0) {
1821
63.7k
            bs = pow5mult(bs, bb5);
1822
63.7k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
63.7k
            Bigint *bb1 = mult(bs, bb);
1826
63.7k
            Bfree(bb);
1827
63.7k
            bb = bb1;
1828
63.7k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
63.7k
        }
1832
341k
        if (bb2 > 0) {
1833
341k
            bb = lshift(bb, bb2);
1834
341k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
341k
        }
1838
341k
        if (bd5 > 0) {
1839
268k
            bd = pow5mult(bd, bd5);
1840
268k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
268k
        }
1844
341k
        if (bd2 > 0) {
1845
61.3k
            bd = lshift(bd, bd2);
1846
61.3k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
61.3k
        }
1850
341k
        if (bs2 > 0) {
1851
275k
            bs = lshift(bs, bs2);
1852
275k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
275k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
341k
        delta = diff(bb, bd);
1862
341k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
341k
        dsign = delta->sign;
1866
341k
        delta->sign = 0;
1867
341k
        i = cmp(delta, bs);
1868
341k
        if (bc.nd > nd && i <= 0) {
1869
31.8k
            if (dsign)
1870
24.1k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
7.67k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
1.44k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
1.44k
                if (j - bc.scale >= 2) {
1890
1.20k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
1.20k
                    break; /* Use bigcomp. */
1892
1.20k
                }
1893
1.44k
            }
1894
1895
6.47k
            {
1896
6.47k
                bc.nd = nd;
1897
6.47k
                i = -1; /* Discarded digits make delta smaller. */
1898
6.47k
            }
1899
6.47k
        }
1900
1901
316k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
106k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
5.77k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
106k
                ) {
1908
101k
                break;
1909
101k
            }
1910
4.54k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
444
                break;
1913
444
            }
1914
4.10k
            delta = lshift(delta,Log2P);
1915
4.10k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
4.10k
            if (cmp(delta, bs) > 0)
1919
1.07k
                goto drop_down;
1920
3.03k
            break;
1921
4.10k
        }
1922
209k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
4.91k
            if (dsign) {
1925
2.12k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
770
                    &&  word1(&rv) == (
1927
770
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
770
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
479
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
479
                        + Exp_msk1
1934
479
                        ;
1935
479
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
479
                    break;
1938
479
                }
1939
2.12k
            }
1940
2.78k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
1.07k
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
1.07k
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
1.07k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
1.07k
                word0(&rv) = L | Bndry_mask1;
1958
1.07k
                word1(&rv) = 0xffffffff;
1959
1.07k
                break;
1960
1.07k
            }
1961
4.43k
            if (!odd)
1962
3.79k
                break;
1963
642
            if (dsign)
1964
394
                dval(&rv) += sulp(&rv, &bc);
1965
248
            else {
1966
248
                dval(&rv) -= sulp(&rv, &bc);
1967
248
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
248
            }
1973
            /* dsign = 1 - dsign; */
1974
642
            break;
1975
642
        }
1976
205k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
178k
            if (dsign)
1978
16.4k
                aadj = aadj1 = 1.;
1979
162k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
154k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
154k
                aadj = 1.;
1986
154k
                aadj1 = -1.;
1987
154k
            }
1988
7.76k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
7.76k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
7.76k
                else
1995
7.76k
                    aadj *= 0.5;
1996
7.76k
                aadj1 = -aadj;
1997
7.76k
            }
1998
178k
        }
1999
26.3k
        else {
2000
26.3k
            aadj *= 0.5;
2001
26.3k
            aadj1 = dsign ? aadj : -aadj;
2002
26.3k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
26.3k
        }
2005
205k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
205k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
3.00k
            dval(&rv0) = dval(&rv);
2011
3.00k
            word0(&rv) -= P*Exp_msk1;
2012
3.00k
            adj.d = aadj1 * ulp(&rv);
2013
3.00k
            dval(&rv) += adj.d;
2014
3.00k
            if ((word0(&rv) & Exp_mask) >=
2015
3.00k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
1.31k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
943
                    goto ovfl;
2018
943
                }
2019
370
                word0(&rv) = Big0;
2020
370
                word1(&rv) = Big1;
2021
370
                goto cont;
2022
1.31k
            }
2023
1.68k
            else
2024
1.68k
                word0(&rv) += P*Exp_msk1;
2025
3.00k
        }
2026
202k
        else {
2027
202k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
16.3k
                if (aadj <= 0x7fffffff) {
2029
16.3k
                    if ((z = (ULong)aadj) <= 0)
2030
1.94k
                        z = 1;
2031
16.3k
                    aadj = z;
2032
16.3k
                    aadj1 = dsign ? aadj : -aadj;
2033
16.3k
                }
2034
16.3k
                dval(&aadj2) = aadj1;
2035
16.3k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
16.3k
                aadj1 = dval(&aadj2);
2037
16.3k
            }
2038
202k
            adj.d = aadj1 * ulp(&rv);
2039
202k
            dval(&rv) += adj.d;
2040
202k
        }
2041
203k
        z = word0(&rv) & Exp_mask;
2042
203k
        if (bc.nd == nd) {
2043
183k
            if (!bc.scale)
2044
166k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
165k
                    L = (Long)aadj;
2047
165k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
165k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
165k
                        if (aadj < .4999999 || aadj > .5000001)
2051
162k
                            break;
2052
165k
                    }
2053
15
                    else if (aadj < .4999999/FLT_RADIX)
2054
15
                        break;
2055
165k
                }
2056
183k
        }
2057
41.1k
      cont:
2058
41.1k
        Bfree(bb); bb = NULL;
2059
41.1k
        Bfree(bd); bd = NULL;
2060
41.1k
        Bfree(bs); bs = NULL;
2061
41.1k
        Bfree(delta); delta = NULL;
2062
41.1k
    }
2063
299k
    if (bc.nd > nd) {
2064
25.3k
        error = bigcomp(&rv, s0, &bc);
2065
25.3k
        if (error)
2066
0
            goto failed_malloc;
2067
25.3k
    }
2068
2069
299k
    if (bc.scale) {
2070
21.8k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
21.8k
        word1(&rv0) = 0;
2072
21.8k
        dval(&rv) *= dval(&rv0);
2073
21.8k
    }
2074
2075
392k
  ret:
2076
392k
    result = sign ? -dval(&rv) : dval(&rv);
2077
392k
    goto done;
2078
2079
46
  parse_error:
2080
46
    result = 0.0;
2081
46
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
3.87k
  undfl:
2089
3.87k
    result = sign ? -0.0 : 0.0;
2090
3.87k
    goto done;
2091
2092
725k
  ovfl:
2093
725k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
725k
    word0(&rv) = Exp_mask;
2096
725k
    word1(&rv) = 0;
2097
725k
    result = sign ? -dval(&rv) : dval(&rv);
2098
725k
    goto done;
2099
2100
1.12M
  done:
2101
1.12M
    Bfree(bb);
2102
1.12M
    Bfree(bd);
2103
1.12M
    Bfree(bs);
2104
1.12M
    Bfree(bd0);
2105
1.12M
    Bfree(delta);
2106
1.12M
    return result;
2107
2108
299k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
53.9k
{
2113
53.9k
    int j, k, *r;
2114
2115
53.9k
    j = sizeof(ULong);
2116
53.9k
    for(k = 0;
2117
53.9k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
53.9k
        j <<= 1)
2119
0
        k++;
2120
53.9k
    r = (int*)Balloc(k);
2121
53.9k
    if (r == NULL)
2122
0
        return NULL;
2123
53.9k
    *r = k;
2124
53.9k
    return (char *)(r+1);
2125
53.9k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
7.95k
{
2130
7.95k
    char *rv, *t;
2131
2132
7.95k
    rv = rv_alloc(n);
2133
7.95k
    if (rv == NULL)
2134
0
        return NULL;
2135
7.95k
    t = rv;
2136
19.5k
    while((*t = *s++)) t++;
2137
7.95k
    if (rve)
2138
7.95k
        *rve = t;
2139
7.95k
    return rv;
2140
7.95k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
53.9k
{
2151
53.9k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
53.9k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
53.9k
    Bfree(b);
2154
53.9k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
53.9k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
53.9k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
53.9k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
53.9k
        spec_case, try_quick;
2235
53.9k
    Long L;
2236
53.9k
    int denorm;
2237
53.9k
    ULong x;
2238
53.9k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
53.9k
    U d2, eps, u;
2240
53.9k
    double ds;
2241
53.9k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
53.9k
    mlo = mhi = S = 0;
2246
53.9k
    s0 = 0;
2247
2248
53.9k
    u.d = dd;
2249
53.9k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
22.8k
        *sign = 1;
2252
22.8k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
22.8k
    }
2254
31.0k
    else
2255
31.0k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
53.9k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
517
    {
2260
        /* Infinity or NaN */
2261
517
        *decpt = 9999;
2262
517
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
517
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
517
    }
2266
53.4k
    if (!dval(&u)) {
2267
7.43k
        *decpt = 1;
2268
7.43k
        return nrv_alloc("0", rve, 1);
2269
7.43k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
46.0k
    b = d2b(&u, &be, &bbits);
2274
46.0k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
46.0k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
42.4k
        dval(&d2) = dval(&u);
2278
42.4k
        word0(&d2) &= Frac_mask1;
2279
42.4k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
42.4k
        i -= Bias;
2304
42.4k
        denorm = 0;
2305
42.4k
    }
2306
3.61k
    else {
2307
        /* d is denormalized */
2308
2309
3.61k
        i = bbits + be + (Bias + (P-1) - 1);
2310
3.61k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
3.61k
            : word1(&u) << (32 - i);
2312
3.61k
        dval(&d2) = x;
2313
3.61k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
3.61k
        i -= (Bias + (P-1) - 1) + 1;
2315
3.61k
        denorm = 1;
2316
3.61k
    }
2317
46.0k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
46.0k
        i*0.301029995663981;
2319
46.0k
    k = (int)ds;
2320
46.0k
    if (ds < 0. && ds != k)
2321
11.9k
        k--;    /* want k = floor(ds) */
2322
46.0k
    k_check = 1;
2323
46.0k
    if (k >= 0 && k <= Ten_pmax) {
2324
17.8k
        if (dval(&u) < tens[k])
2325
1.79k
            k--;
2326
17.8k
        k_check = 0;
2327
17.8k
    }
2328
46.0k
    j = bbits - i - 1;
2329
46.0k
    if (j >= 0) {
2330
17.0k
        b2 = 0;
2331
17.0k
        s2 = j;
2332
17.0k
    }
2333
29.0k
    else {
2334
29.0k
        b2 = -j;
2335
29.0k
        s2 = 0;
2336
29.0k
    }
2337
46.0k
    if (k >= 0) {
2338
33.5k
        b5 = 0;
2339
33.5k
        s5 = k;
2340
33.5k
        s2 += k;
2341
33.5k
    }
2342
12.5k
    else {
2343
12.5k
        b2 -= k;
2344
12.5k
        b5 = -k;
2345
12.5k
        s5 = 0;
2346
12.5k
    }
2347
46.0k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
46.0k
    try_quick = 1;
2351
2352
46.0k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
46.0k
    leftright = 1;
2357
46.0k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
46.0k
    switch(mode) {
2360
45.9k
    case 0:
2361
45.9k
    case 1:
2362
45.9k
        i = 18;
2363
45.9k
        ndigits = 0;
2364
45.9k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
106
    case 3:
2374
106
        leftright = 0;
2375
106
        _Py_FALLTHROUGH;
2376
106
    case 5:
2377
106
        i = ndigits + k + 1;
2378
106
        ilim = i;
2379
106
        ilim1 = i - 1;
2380
106
        if (i <= 0)
2381
0
            i = 1;
2382
46.0k
    }
2383
46.0k
    s0 = rv_alloc(i);
2384
46.0k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
46.0k
    s = s0;
2387
2388
2389
46.0k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
106
        i = 0;
2394
106
        dval(&d2) = dval(&u);
2395
106
        k0 = k;
2396
106
        ilim0 = ilim;
2397
106
        ieps = 2; /* conservative */
2398
106
        if (k > 0) {
2399
83
            ds = tens[k&0xf];
2400
83
            j = k >> 4;
2401
83
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
83
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
83
            dval(&u) /= ds;
2413
83
        }
2414
23
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
106
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
106
        dval(&eps) = ieps*dval(&u) + 7.;
2431
106
        word0(&eps) -= (P-1)*Exp_msk1;
2432
106
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
106
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
106
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
106
            dval(&eps) *= tens[ilim-1];
2463
290
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
290
                L = (Long)(dval(&u));
2465
290
                if (!(dval(&u) -= L))
2466
15
                    ilim = i;
2467
290
                *s++ = '0' + (int)L;
2468
290
                if (i == ilim) {
2469
106
                    if (dval(&u) > 0.5 + dval(&eps))
2470
54
                        goto bump_up;
2471
52
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
57
                        while(*--s == '0');
2473
52
                        s++;
2474
52
                        goto ret1;
2475
52
                    }
2476
0
                    break;
2477
106
                }
2478
290
            }
2479
106
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
45.9k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
11.5k
        ds = tens[k];
2492
11.5k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
16.2k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
16.2k
            L = (Long)(dval(&u) / ds);
2500
16.2k
            dval(&u) -= L*ds;
2501
16.2k
            *s++ = '0' + (int)L;
2502
16.2k
            if (!dval(&u)) {
2503
11.5k
                break;
2504
11.5k
            }
2505
4.70k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
54
                  bump_up:
2509
57
                    while(*--s == '9')
2510
3
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
54
                    ++*s++;
2516
54
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
54
                break;
2526
0
            }
2527
4.70k
        }
2528
11.5k
        goto ret1;
2529
11.5k
    }
2530
2531
34.4k
    m2 = b2;
2532
34.4k
    m5 = b5;
2533
34.4k
    if (leftright) {
2534
34.4k
        i =
2535
34.4k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
34.4k
            1 + P - bbits;
2537
34.4k
        b2 += i;
2538
34.4k
        s2 += i;
2539
34.4k
        mhi = i2b(1);
2540
34.4k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
34.4k
    }
2543
34.4k
    if (m2 > 0 && s2 > 0) {
2544
31.6k
        i = m2 < s2 ? m2 : s2;
2545
31.6k
        b2 -= i;
2546
31.6k
        m2 -= i;
2547
31.6k
        s2 -= i;
2548
31.6k
    }
2549
34.4k
    if (b5 > 0) {
2550
12.5k
        if (leftright) {
2551
12.5k
            if (m5 > 0) {
2552
12.5k
                mhi = pow5mult(mhi, m5);
2553
12.5k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
12.5k
                b1 = mult(mhi, b);
2556
12.5k
                Bfree(b);
2557
12.5k
                b = b1;
2558
12.5k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
12.5k
            }
2561
12.5k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
12.5k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
12.5k
    }
2573
34.4k
    S = i2b(1);
2574
34.4k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
34.4k
    if (s5 > 0) {
2577
20.3k
        S = pow5mult(S, s5);
2578
20.3k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
20.3k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
34.4k
    spec_case = 0;
2585
34.4k
    if ((mode < 2 || leftright)
2586
34.4k
        ) {
2587
34.4k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.27k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
34.4k
            ) {
2590
            /* The special case */
2591
921
            b2 += Log2P;
2592
921
            s2 += Log2P;
2593
921
            spec_case = 1;
2594
921
        }
2595
34.4k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
34.4k
#define iInc 28
2605
34.4k
    i = dshift(S, s2);
2606
34.4k
    b2 += i;
2607
34.4k
    m2 += i;
2608
34.4k
    s2 += i;
2609
34.4k
    if (b2 > 0) {
2610
34.4k
        b = lshift(b, b2);
2611
34.4k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
34.4k
    }
2614
34.4k
    if (s2 > 0) {
2615
33.9k
        S = lshift(S, s2);
2616
33.9k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
33.9k
    }
2619
34.4k
    if (k_check) {
2620
28.1k
        if (cmp(b,S) < 0) {
2621
4.73k
            k--;
2622
4.73k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
4.73k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
4.73k
            if (leftright) {
2626
4.73k
                mhi = multadd(mhi, 10, 0);
2627
4.73k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
4.73k
            }
2630
4.73k
            ilim = ilim1;
2631
4.73k
        }
2632
28.1k
    }
2633
34.4k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
34.4k
    if (leftright) {
2653
34.4k
        if (m2 > 0) {
2654
33.7k
            mhi = lshift(mhi, m2);
2655
33.7k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
33.7k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
34.4k
        mlo = mhi;
2664
34.4k
        if (spec_case) {
2665
921
            mhi = Balloc(mhi->k);
2666
921
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
921
            Bcopy(mhi, mlo);
2669
921
            mhi = lshift(mhi, Log2P);
2670
921
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
921
        }
2673
2674
111k
        for(i = 1;;i++) {
2675
111k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
111k
            j = cmp(b, mlo);
2680
111k
            delta = diff(S, mhi);
2681
111k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
111k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
111k
            Bfree(delta);
2685
111k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
111k
                ) {
2687
1.59k
                if (dig == '9')
2688
234
                    goto round_9_up;
2689
1.35k
                if (j > 0)
2690
703
                    dig++;
2691
1.35k
                *s++ = dig;
2692
1.35k
                goto ret;
2693
1.59k
            }
2694
109k
            if (j < 0 || (j == 0 && mode != 1
2695
2.07k
                          && !(word1(&u) & 1)
2696
94.1k
                    )) {
2697
16.6k
                if (!b->x[0] && b->wds <= 1) {
2698
2.05k
                    goto accept_dig;
2699
2.05k
                }
2700
14.5k
                if (j1 > 0) {
2701
2.78k
                    b = lshift(b, 1);
2702
2.78k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
2.78k
                    j1 = cmp(b, S);
2705
2.78k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.56k
                        && dig++ == '9')
2707
245
                        goto round_9_up;
2708
2.78k
                }
2709
16.3k
              accept_dig:
2710
16.3k
                *s++ = dig;
2711
16.3k
                goto ret;
2712
14.5k
            }
2713
93.2k
            if (j1 > 0) {
2714
16.2k
                if (dig == '9') { /* possible if i == 1 */
2715
4.68k
                  round_9_up:
2716
4.68k
                    *s++ = '9';
2717
4.68k
                    goto roundoff;
2718
4.20k
                }
2719
12.0k
                *s++ = dig + 1;
2720
12.0k
                goto ret;
2721
16.2k
            }
2722
76.9k
            *s++ = dig;
2723
76.9k
            if (i == ilim)
2724
0
                break;
2725
76.9k
            b = multadd(b, 10, 0);
2726
76.9k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
76.9k
            if (mlo == mhi) {
2729
73.9k
                mlo = mhi = multadd(mhi, 10, 0);
2730
73.9k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
73.9k
            }
2733
3.04k
            else {
2734
3.04k
                mlo = multadd(mlo, 10, 0);
2735
3.04k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
3.04k
                mhi = multadd(mhi, 10, 0);
2738
3.04k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
3.04k
            }
2741
76.9k
        }
2742
34.4k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
4.68k
      roundoff:
2764
4.68k
        while(*--s == '9')
2765
4.68k
            if (s == s0) {
2766
4.68k
                k++;
2767
4.68k
                *s++ = '1';
2768
4.68k
                goto ret;
2769
4.68k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
34.4k
  ret:
2777
34.4k
    Bfree(S);
2778
34.4k
    if (mhi) {
2779
34.4k
        if (mlo && mlo != mhi)
2780
921
            Bfree(mlo);
2781
34.4k
        Bfree(mhi);
2782
34.4k
    }
2783
46.0k
  ret1:
2784
46.0k
    Bfree(b);
2785
46.0k
    *s = 0;
2786
46.0k
    *decpt = k + 1;
2787
46.0k
    if (rve)
2788
46.0k
        *rve = s;
2789
46.0k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
34.4k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
32
{
2809
32
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
32
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
32
    Bigint *p5 = i2b(625);
2814
32
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
32
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
256
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
224
        p5 = mult(p5, p5);
2822
224
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
224
        p5s[i] = p5;
2826
224
    }
2827
2828
32
#endif
2829
32
    return PyStatus_Ok();
2830
32
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}