Coverage Report

Created: 2026-03-08 06:40

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
Line
Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
57
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754) ||  \
143
  defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754)
144
#  define IEEE_MC68k
145
#endif
146
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
147
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
148
#endif
149
150
/* The code below assumes that the endianness of integers matches the
151
   endianness of the two 32-bit words of a double.  Check this. */
152
#if defined(WORDS_BIGENDIAN) && (defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754) || \
153
                                 defined(DOUBLE_IS_ARM_MIXED_ENDIAN_IEEE754))
154
#error "doubles and ints have incompatible endianness"
155
#endif
156
157
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
158
#error "doubles and ints have incompatible endianness"
159
#endif
160
161
162
typedef uint32_t ULong;
163
typedef int32_t Long;
164
typedef uint64_t ULLong;
165
166
#undef DEBUG
167
#ifdef Py_DEBUG
168
#define DEBUG
169
#endif
170
171
/* End Python #define linking */
172
173
#ifdef DEBUG
174
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
175
#endif
176
177
typedef union { double d; ULong L[2]; } U;
178
179
#ifdef IEEE_8087
180
4.64M
#define word0(x) (x)->L[1]
181
3.17M
#define word1(x) (x)->L[0]
182
#else
183
#define word0(x) (x)->L[0]
184
#define word1(x) (x)->L[1]
185
#endif
186
7.98M
#define dval(x) (x)->d
187
188
#ifndef STRTOD_DIGLIM
189
377k
#define STRTOD_DIGLIM 40
190
#endif
191
192
/* maximum permitted exponent value for strtod; exponents larger than
193
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
194
   should fit into an int. */
195
#ifndef MAX_ABS_EXP
196
897k
#define MAX_ABS_EXP 1100000000U
197
#endif
198
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
199
   this is used to bound the total number of digits ignoring leading zeros and
200
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
201
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
202
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
203
#ifndef MAX_DIGITS
204
2.91M
#define MAX_DIGITS 1000000000U
205
#endif
206
207
/* Guard against trying to use the above values on unusual platforms with ints
208
 * of width less than 32 bits. */
209
#if MAX_ABS_EXP > INT_MAX
210
#error "MAX_ABS_EXP should fit in an int"
211
#endif
212
#if MAX_DIGITS > INT_MAX
213
#error "MAX_DIGITS should fit in an int"
214
#endif
215
216
/* The following definition of Storeinc is appropriate for MIPS processors.
217
 * An alternative that might be better on some machines is
218
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
219
 */
220
#if defined(IEEE_8087)
221
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
222
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
223
#else
224
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
225
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
226
#endif
227
228
/* #define P DBL_MANT_DIG */
229
/* Ten_pmax = floor(P*log(2)/log(5)) */
230
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
231
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
232
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
233
234
510k
#define Exp_shift  20
235
87.0k
#define Exp_shift1 20
236
2.61M
#define Exp_msk1    0x100000
237
#define Exp_msk11   0x100000
238
2.21M
#define Exp_mask  0x7ff00000
239
1.78M
#define P 53
240
#define Nbits 53
241
998k
#define Bias 1023
242
#define Emax 1023
243
#define Emin (-1022)
244
983k
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
245
534k
#define Exp_1  0x3ff00000
246
39.6k
#define Exp_11 0x3ff00000
247
1.62M
#define Ebits 11
248
487k
#define Frac_mask  0xfffff
249
41.9k
#define Frac_mask1 0xfffff
250
1.71M
#define Ten_pmax 22
251
85
#define Bletch 0x10
252
155k
#define Bndry_mask  0xfffff
253
7.83k
#define Bndry_mask1 0xfffff
254
67.4k
#define Sign_bit 0x80000000
255
6.95k
#define Log2P 1
256
#define Tiny0 0
257
408k
#define Tiny1 1
258
43.6k
#define Quick_max 14
259
28.2k
#define Int_max 14
260
261
#ifndef Flt_Rounds
262
#ifdef FLT_ROUNDS
263
924k
#define Flt_Rounds FLT_ROUNDS
264
#else
265
#define Flt_Rounds 1
266
#endif
267
#endif /*Flt_Rounds*/
268
269
#define Rounding Flt_Rounds
270
271
3.68k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
272
2.32k
#define Big1 0xffffffff
273
274
/* Bits of the representation of positive infinity. */
275
276
#define POSINF_WORD0 0x7ff00000
277
#define POSINF_WORD1 0
278
279
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
280
281
typedef struct BCinfo BCinfo;
282
struct
283
BCinfo {
284
    int e0, nd, nd0, scale;
285
};
286
287
29.4M
#define FFFFFFFF 0xffffffffUL
288
289
/* struct Bigint is used to represent arbitrary-precision integers.  These
290
   integers are stored in sign-magnitude format, with the magnitude stored as
291
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
292
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
293
294
   The Bigint fields are as follows:
295
296
     - next is a header used by Balloc and Bfree to keep track of lists
297
         of freed Bigints;  it's also used for the linked list of
298
         powers of 5 of the form 5**2**i used by pow5mult.
299
     - k indicates which pool this Bigint was allocated from
300
     - maxwds is the maximum number of words space was allocated for
301
       (usually maxwds == 2**k)
302
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
303
       (ignored on inputs, set to 0 on outputs) in almost all operations
304
       involving Bigints: a notable exception is the diff function, which
305
       ignores signs on inputs but sets the sign of the output correctly.
306
     - wds is the actual number of significant words
307
     - x contains the vector of words (digits) for this Bigint, from least
308
       significant (x[0]) to most significant (x[wds-1]).
309
*/
310
311
// struct Bigint is defined in pycore_dtoa.h.
312
typedef struct Bigint Bigint;
313
314
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
315
316
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
317
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
318
   1 << k.  These pools are maintained as linked lists, with freelist[k]
319
   pointing to the head of the list for pool k.
320
321
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
322
   called to get more memory.  This memory is not returned to the system until
323
   Python quits.  There's also a private memory pool that's allocated from
324
   in preference to using MALLOC.
325
326
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
327
   decimal digits), memory is directly allocated using MALLOC, and freed using
328
   FREE.
329
330
   XXX: it would be easy to bypass this memory-management system and
331
   translate each call to Balloc into a call to PyMem_Malloc, and each
332
   Bfree to PyMem_Free.  Investigate whether this has any significant
333
   performance on impact. */
334
335
19.2M
#define freelist interp->dtoa.freelist
336
413
#define private_mem interp->dtoa.preallocated
337
1.12k
#define pmem_next interp->dtoa.preallocated_next
338
339
/* Allocate space for a Bigint with up to 1<<k digits */
340
341
static Bigint *
342
Balloc(int k)
343
4.80M
{
344
4.80M
    int x;
345
4.80M
    Bigint *rv;
346
4.80M
    unsigned int len;
347
4.80M
    PyInterpreterState *interp = _PyInterpreterState_GET();
348
349
4.80M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
350
4.80M
        freelist[k] = rv->next;
351
413
    else {
352
413
        x = 1 << k;
353
413
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
354
413
            /sizeof(double);
355
413
        if (k <= Bigint_Kmax &&
356
413
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
357
413
        ) {
358
356
            rv = (Bigint*)pmem_next;
359
356
            pmem_next += len;
360
356
        }
361
57
        else {
362
57
            rv = (Bigint*)MALLOC(len*sizeof(double));
363
57
            if (rv == NULL)
364
0
                return NULL;
365
57
        }
366
413
        rv->k = k;
367
413
        rv->maxwds = x;
368
413
    }
369
4.80M
    rv->sign = rv->wds = 0;
370
4.80M
    return rv;
371
4.80M
}
372
373
/* Free a Bigint allocated with Balloc */
374
375
static void
376
Bfree(Bigint *v)
377
8.07M
{
378
8.07M
    if (v) {
379
4.80M
        if (v->k > Bigint_Kmax)
380
0
            FREE((void*)v);
381
4.80M
        else {
382
4.80M
            PyInterpreterState *interp = _PyInterpreterState_GET();
383
4.80M
            v->next = freelist[v->k];
384
4.80M
            freelist[v->k] = v;
385
4.80M
        }
386
4.80M
    }
387
8.07M
}
388
389
#undef pmem_next
390
#undef private_mem
391
#undef freelist
392
393
#else
394
395
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
396
   PyMem_Free directly in place of the custom memory allocation scheme above.
397
   These are provided for the benefit of memory debugging tools like
398
   Valgrind. */
399
400
/* Allocate space for a Bigint with up to 1<<k digits */
401
402
static Bigint *
403
Balloc(int k)
404
{
405
    int x;
406
    Bigint *rv;
407
    unsigned int len;
408
409
    x = 1 << k;
410
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
411
        /sizeof(double);
412
413
    rv = (Bigint*)MALLOC(len*sizeof(double));
414
    if (rv == NULL)
415
        return NULL;
416
417
    rv->k = k;
418
    rv->maxwds = x;
419
    rv->sign = rv->wds = 0;
420
    return rv;
421
}
422
423
/* Free a Bigint allocated with Balloc */
424
425
static void
426
Bfree(Bigint *v)
427
{
428
    if (v) {
429
        FREE((void*)v);
430
    }
431
}
432
433
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
434
435
422k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
436
422k
                          y->wds*sizeof(Long) + 2*sizeof(int))
437
438
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
439
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
440
   On failure, return NULL.  In this case, b will have been already freed. */
441
442
static Bigint *
443
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
444
1.16M
{
445
1.16M
    int i, wds;
446
1.16M
    ULong *x;
447
1.16M
    ULLong carry, y;
448
1.16M
    Bigint *b1;
449
450
1.16M
    wds = b->wds;
451
1.16M
    x = b->x;
452
1.16M
    i = 0;
453
1.16M
    carry = a;
454
4.15M
    do {
455
4.15M
        y = *x * (ULLong)m + carry;
456
4.15M
        carry = y >> 32;
457
4.15M
        *x++ = (ULong)(y & FFFFFFFF);
458
4.15M
    }
459
4.15M
    while(++i < wds);
460
1.16M
    if (carry) {
461
67.5k
        if (wds >= b->maxwds) {
462
3.74k
            b1 = Balloc(b->k+1);
463
3.74k
            if (b1 == NULL){
464
0
                Bfree(b);
465
0
                return NULL;
466
0
            }
467
3.74k
            Bcopy(b1, b);
468
3.74k
            Bfree(b);
469
3.74k
            b = b1;
470
3.74k
        }
471
67.5k
        b->x[wds++] = (ULong)carry;
472
67.5k
        b->wds = wds;
473
67.5k
    }
474
1.16M
    return b;
475
1.16M
}
476
477
/* convert a string s containing nd decimal digits (possibly containing a
478
   decimal separator at position nd0, which is ignored) to a Bigint.  This
479
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
480
   entry, y9 contains the result of converting the first 9 digits.  Returns
481
   NULL on failure. */
482
483
static Bigint *
484
s2b(const char *s, int nd0, int nd, ULong y9)
485
377k
{
486
377k
    Bigint *b;
487
377k
    int i, k;
488
377k
    Long x, y;
489
490
377k
    x = (nd + 8) / 9;
491
428k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
492
377k
    b = Balloc(k);
493
377k
    if (b == NULL)
494
0
        return NULL;
495
377k
    b->x[0] = y9;
496
377k
    b->wds = 1;
497
498
377k
    if (nd <= 9)
499
337k
      return b;
500
501
40.0k
    s += 9;
502
303k
    for (i = 9; i < nd0; i++) {
503
263k
        b = multadd(b, 10, *s++ - '0');
504
263k
        if (b == NULL)
505
0
            return NULL;
506
263k
    }
507
40.0k
    s++;
508
144k
    for(; i < nd; i++) {
509
104k
        b = multadd(b, 10, *s++ - '0');
510
104k
        if (b == NULL)
511
0
            return NULL;
512
104k
    }
513
40.0k
    return b;
514
40.0k
}
515
516
/* count leading 0 bits in the 32-bit integer x. */
517
518
static int
519
hi0bits(ULong x)
520
575k
{
521
575k
    int k = 0;
522
523
575k
    if (!(x & 0xffff0000)) {
524
220k
        k = 16;
525
220k
        x <<= 16;
526
220k
    }
527
575k
    if (!(x & 0xff000000)) {
528
235k
        k += 8;
529
235k
        x <<= 8;
530
235k
    }
531
575k
    if (!(x & 0xf0000000)) {
532
400k
        k += 4;
533
400k
        x <<= 4;
534
400k
    }
535
575k
    if (!(x & 0xc0000000)) {
536
280k
        k += 2;
537
280k
        x <<= 2;
538
280k
    }
539
575k
    if (!(x & 0x80000000)) {
540
150k
        k++;
541
150k
        if (!(x & 0x40000000))
542
0
            return 32;
543
150k
    }
544
575k
    return k;
545
575k
}
546
547
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
548
   number of bits. */
549
550
static int
551
lo0bits(ULong *y)
552
43.5k
{
553
43.5k
    int k;
554
43.5k
    ULong x = *y;
555
556
43.5k
    if (x & 7) {
557
27.0k
        if (x & 1)
558
12.3k
            return 0;
559
14.6k
        if (x & 2) {
560
6.60k
            *y = x >> 1;
561
6.60k
            return 1;
562
6.60k
        }
563
8.04k
        *y = x >> 2;
564
8.04k
        return 2;
565
14.6k
    }
566
16.5k
    k = 0;
567
16.5k
    if (!(x & 0xffff)) {
568
6.69k
        k = 16;
569
6.69k
        x >>= 16;
570
6.69k
    }
571
16.5k
    if (!(x & 0xff)) {
572
2.97k
        k += 8;
573
2.97k
        x >>= 8;
574
2.97k
    }
575
16.5k
    if (!(x & 0xf)) {
576
8.35k
        k += 4;
577
8.35k
        x >>= 4;
578
8.35k
    }
579
16.5k
    if (!(x & 0x3)) {
580
9.16k
        k += 2;
581
9.16k
        x >>= 2;
582
9.16k
    }
583
16.5k
    if (!(x & 1)) {
584
11.6k
        k++;
585
11.6k
        x >>= 1;
586
11.6k
        if (!x)
587
0
            return 32;
588
11.6k
    }
589
16.5k
    *y = x;
590
16.5k
    return k;
591
16.5k
}
592
593
/* convert a small nonnegative integer to a Bigint */
594
595
static Bigint *
596
i2b(int i)
597
509k
{
598
509k
    Bigint *b;
599
600
509k
    b = Balloc(1);
601
509k
    if (b == NULL)
602
0
        return NULL;
603
509k
    b->x[0] = i;
604
509k
    b->wds = 1;
605
509k
    return b;
606
509k
}
607
608
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
609
   the signs of a and b. */
610
611
static Bigint *
612
mult(Bigint *a, Bigint *b)
613
1.41M
{
614
1.41M
    Bigint *c;
615
1.41M
    int k, wa, wb, wc;
616
1.41M
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
617
1.41M
    ULong y;
618
1.41M
    ULLong carry, z;
619
620
1.41M
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
621
6.36k
        c = Balloc(0);
622
6.36k
        if (c == NULL)
623
0
            return NULL;
624
6.36k
        c->wds = 1;
625
6.36k
        c->x[0] = 0;
626
6.36k
        return c;
627
6.36k
    }
628
629
1.41M
    if (a->wds < b->wds) {
630
767k
        c = a;
631
767k
        a = b;
632
767k
        b = c;
633
767k
    }
634
1.41M
    k = a->k;
635
1.41M
    wa = a->wds;
636
1.41M
    wb = b->wds;
637
1.41M
    wc = wa + wb;
638
1.41M
    if (wc > a->maxwds)
639
903k
        k++;
640
1.41M
    c = Balloc(k);
641
1.41M
    if (c == NULL)
642
0
        return NULL;
643
9.48M
    for(x = c->x, xa = x + wc; x < xa; x++)
644
8.07M
        *x = 0;
645
1.41M
    xa = a->x;
646
1.41M
    xae = xa + wa;
647
1.41M
    xb = b->x;
648
1.41M
    xbe = xb + wb;
649
1.41M
    xc0 = c->x;
650
4.16M
    for(; xb < xbe; xc0++) {
651
2.75M
        if ((y = *xb++)) {
652
2.74M
            x = xa;
653
2.74M
            xc = xc0;
654
2.74M
            carry = 0;
655
16.5M
            do {
656
16.5M
                z = *x++ * (ULLong)y + *xc + carry;
657
16.5M
                carry = z >> 32;
658
16.5M
                *xc++ = (ULong)(z & FFFFFFFF);
659
16.5M
            }
660
16.5M
            while(x < xae);
661
2.74M
            *xc = (ULong)carry;
662
2.74M
        }
663
2.75M
    }
664
2.36M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
665
1.41M
    c->wds = wc;
666
1.41M
    return c;
667
1.41M
}
668
669
#ifndef Py_USING_MEMORY_DEBUGGER
670
671
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
672
   failure; if the returned pointer is distinct from b then the original
673
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
674
675
static Bigint *
676
pow5mult(Bigint *b, int k)
677
463k
{
678
463k
    Bigint *b1, *p5, **p5s;
679
463k
    int i;
680
463k
    static const int p05[3] = { 5, 25, 125 };
681
682
    // For double-to-string conversion, the maximum value of k is limited by
683
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
684
    // For string-to-double conversion, the extreme case is constrained by our
685
    // hardcoded exponent limit before we underflow of -512, adjusted by
686
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
687
463k
    assert(0 <= k && k < 1024);
688
689
463k
    if ((i = k & 3)) {
690
171k
        b = multadd(b, p05[i-1], 0);
691
171k
        if (b == NULL)
692
0
            return NULL;
693
171k
    }
694
695
463k
    if (!(k >>= 2))
696
11.4k
        return b;
697
452k
    PyInterpreterState *interp = _PyInterpreterState_GET();
698
452k
    p5s = interp->dtoa.p5s;
699
2.10M
    for(;;) {
700
2.10M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
701
2.10M
        p5 = *p5s;
702
2.10M
        p5s++;
703
2.10M
        if (k & 1) {
704
1.34M
            b1 = mult(b, p5);
705
1.34M
            Bfree(b);
706
1.34M
            b = b1;
707
1.34M
            if (b == NULL)
708
0
                return NULL;
709
1.34M
        }
710
2.10M
        if (!(k >>= 1))
711
452k
            break;
712
2.10M
    }
713
452k
    return b;
714
452k
}
715
716
#else
717
718
/* Version of pow5mult that doesn't cache powers of 5. Provided for
719
   the benefit of memory debugging tools like Valgrind. */
720
721
static Bigint *
722
pow5mult(Bigint *b, int k)
723
{
724
    Bigint *b1, *p5, *p51;
725
    int i;
726
    static const int p05[3] = { 5, 25, 125 };
727
728
    if ((i = k & 3)) {
729
        b = multadd(b, p05[i-1], 0);
730
        if (b == NULL)
731
            return NULL;
732
    }
733
734
    if (!(k >>= 2))
735
        return b;
736
    p5 = i2b(625);
737
    if (p5 == NULL) {
738
        Bfree(b);
739
        return NULL;
740
    }
741
742
    for(;;) {
743
        if (k & 1) {
744
            b1 = mult(b, p5);
745
            Bfree(b);
746
            b = b1;
747
            if (b == NULL) {
748
                Bfree(p5);
749
                return NULL;
750
            }
751
        }
752
        if (!(k >>= 1))
753
            break;
754
        p51 = mult(p5, p5);
755
        Bfree(p5);
756
        p5 = p51;
757
        if (p5 == NULL) {
758
            Bfree(b);
759
            return NULL;
760
        }
761
    }
762
    Bfree(p5);
763
    return b;
764
}
765
766
#endif /* Py_USING_MEMORY_DEBUGGER */
767
768
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
769
   or NULL on failure.  If the returned pointer is distinct from b then the
770
   original b will have been Bfree'd.   Ignores the sign of b. */
771
772
static Bigint *
773
lshift(Bigint *b, int k)
774
1.01M
{
775
1.01M
    int i, k1, n, n1;
776
1.01M
    Bigint *b1;
777
1.01M
    ULong *x, *x1, *xe, z;
778
779
1.01M
    if (!k || (!b->x[0] && b->wds == 1))
780
6.90k
        return b;
781
782
1.00M
    n = k >> 5;
783
1.00M
    k1 = b->k;
784
1.00M
    n1 = n + b->wds + 1;
785
2.69M
    for(i = b->maxwds; n1 > i; i <<= 1)
786
1.69M
        k1++;
787
1.00M
    b1 = Balloc(k1);
788
1.00M
    if (b1 == NULL) {
789
0
        Bfree(b);
790
0
        return NULL;
791
0
    }
792
1.00M
    x1 = b1->x;
793
5.29M
    for(i = 0; i < n; i++)
794
4.29M
        *x1++ = 0;
795
1.00M
    x = b->x;
796
1.00M
    xe = x + b->wds;
797
1.00M
    if (k &= 0x1f) {
798
986k
        k1 = 32 - k;
799
986k
        z = 0;
800
2.77M
        do {
801
2.77M
            *x1++ = *x << k | z;
802
2.77M
            z = *x++ >> k1;
803
2.77M
        }
804
2.77M
        while(x < xe);
805
986k
        if ((*x1 = z))
806
252k
            ++n1;
807
986k
    }
808
18.1k
    else do
809
33.3k
             *x1++ = *x++;
810
33.3k
        while(x < xe);
811
1.00M
    b1->wds = n1 - 1;
812
1.00M
    Bfree(b);
813
1.00M
    return b1;
814
1.00M
}
815
816
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
817
   1 if a > b.  Ignores signs of a and b. */
818
819
static int
820
cmp(Bigint *a, Bigint *b)
821
1.80M
{
822
1.80M
    ULong *xa, *xa0, *xb, *xb0;
823
1.80M
    int i, j;
824
825
1.80M
    i = a->wds;
826
1.80M
    j = b->wds;
827
#ifdef DEBUG
828
    if (i > 1 && !a->x[i-1])
829
        Bug("cmp called with a->x[a->wds-1] == 0");
830
    if (j > 1 && !b->x[j-1])
831
        Bug("cmp called with b->x[b->wds-1] == 0");
832
#endif
833
1.80M
    if (i -= j)
834
182k
        return i;
835
1.62M
    xa0 = a->x;
836
1.62M
    xa = xa0 + j;
837
1.62M
    xb0 = b->x;
838
1.62M
    xb = xb0 + j;
839
2.33M
    for(;;) {
840
2.33M
        if (*--xa != *--xb)
841
1.60M
            return *xa < *xb ? -1 : 1;
842
731k
        if (xa <= xa0)
843
17.6k
            break;
844
731k
    }
845
17.6k
    return 0;
846
1.62M
}
847
848
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
849
   NULL on failure.  The signs of a and b are ignored, but the sign of the
850
   result is set appropriately. */
851
852
static Bigint *
853
diff(Bigint *a, Bigint *b)
854
540k
{
855
540k
    Bigint *c;
856
540k
    int i, wa, wb;
857
540k
    ULong *xa, *xae, *xb, *xbe, *xc;
858
540k
    ULLong borrow, y;
859
860
540k
    i = cmp(a,b);
861
540k
    if (!i) {
862
3.14k
        c = Balloc(0);
863
3.14k
        if (c == NULL)
864
0
            return NULL;
865
3.14k
        c->wds = 1;
866
3.14k
        c->x[0] = 0;
867
3.14k
        return c;
868
3.14k
    }
869
537k
    if (i < 0) {
870
84.8k
        c = a;
871
84.8k
        a = b;
872
84.8k
        b = c;
873
84.8k
        i = 1;
874
84.8k
    }
875
452k
    else
876
452k
        i = 0;
877
537k
    c = Balloc(a->k);
878
537k
    if (c == NULL)
879
0
        return NULL;
880
537k
    c->sign = i;
881
537k
    wa = a->wds;
882
537k
    xa = a->x;
883
537k
    xae = xa + wa;
884
537k
    wb = b->wds;
885
537k
    xb = b->x;
886
537k
    xbe = xb + wb;
887
537k
    xc = c->x;
888
537k
    borrow = 0;
889
3.94M
    do {
890
3.94M
        y = (ULLong)*xa++ - *xb++ - borrow;
891
3.94M
        borrow = y >> 32 & (ULong)1;
892
3.94M
        *xc++ = (ULong)(y & FFFFFFFF);
893
3.94M
    }
894
3.94M
    while(xb < xbe);
895
800k
    while(xa < xae) {
896
262k
        y = *xa++ - borrow;
897
262k
        borrow = y >> 32 & (ULong)1;
898
262k
        *xc++ = (ULong)(y & FFFFFFFF);
899
262k
    }
900
1.19M
    while(!*--xc)
901
658k
        wa--;
902
537k
    c->wds = wa;
903
537k
    return c;
904
537k
}
905
906
/* Given a positive normal double x, return the difference between x and the
907
   next double up.  Doesn't give correct results for subnormals. */
908
909
static double
910
ulp(U *x)
911
260k
{
912
260k
    Long L;
913
260k
    U u;
914
915
260k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
916
260k
    word0(&u) = L;
917
260k
    word1(&u) = 0;
918
260k
    return dval(&u);
919
260k
}
920
921
/* Convert a Bigint to a double plus an exponent */
922
923
static double
924
b2d(Bigint *a, int *e)
925
512k
{
926
512k
    ULong *xa, *xa0, w, y, z;
927
512k
    int k;
928
512k
    U d;
929
930
512k
    xa0 = a->x;
931
512k
    xa = xa0 + a->wds;
932
512k
    y = *--xa;
933
#ifdef DEBUG
934
    if (!y) Bug("zero y in b2d");
935
#endif
936
512k
    k = hi0bits(y);
937
512k
    *e = 32 - k;
938
512k
    if (k < Ebits) {
939
298k
        word0(&d) = Exp_1 | y >> (Ebits - k);
940
298k
        w = xa > xa0 ? *--xa : 0;
941
298k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
942
298k
        goto ret_d;
943
298k
    }
944
214k
    z = xa > xa0 ? *--xa : 0;
945
214k
    if (k -= Ebits) {
946
209k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
947
209k
        y = xa > xa0 ? *--xa : 0;
948
209k
        word1(&d) = z << k | y >> (32 - k);
949
209k
    }
950
5.36k
    else {
951
5.36k
        word0(&d) = Exp_1 | y;
952
5.36k
        word1(&d) = z;
953
5.36k
    }
954
512k
  ret_d:
955
512k
    return dval(&d);
956
214k
}
957
958
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
959
   except that it accepts the scale parameter used in _Py_dg_strtod (which
960
   should be either 0 or 2*P), and the normalization for the return value is
961
   different (see below).  On input, d should be finite and nonnegative, and d
962
   / 2**scale should be exactly representable as an IEEE 754 double.
963
964
   Returns a Bigint b and an integer e such that
965
966
     dval(d) / 2**scale = b * 2**e.
967
968
   Unlike d2b, b is not necessarily odd: b and e are normalized so
969
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
970
   and e == Etiny.  This applies equally to an input of 0.0: in that
971
   case the return values are b = 0 and e = Etiny.
972
973
   The above normalization ensures that for all possible inputs d,
974
   2**e gives ulp(d/2**scale).
975
976
   Returns NULL on failure.
977
*/
978
979
static Bigint *
980
sd2b(U *d, int scale, int *e)
981
443k
{
982
443k
    Bigint *b;
983
984
443k
    b = Balloc(1);
985
443k
    if (b == NULL)
986
0
        return NULL;
987
988
    /* First construct b and e assuming that scale == 0. */
989
443k
    b->wds = 2;
990
443k
    b->x[0] = word1(d);
991
443k
    b->x[1] = word0(d) & Frac_mask;
992
443k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
993
443k
    if (*e < Etiny)
994
6.90k
        *e = Etiny;
995
436k
    else
996
436k
        b->x[1] |= Exp_msk1;
997
998
    /* Now adjust for scale, provided that b != 0. */
999
443k
    if (scale && (b->x[0] || b->x[1])) {
1000
32.5k
        *e -= scale;
1001
32.5k
        if (*e < Etiny) {
1002
28.0k
            scale = Etiny - *e;
1003
28.0k
            *e = Etiny;
1004
            /* We can't shift more than P-1 bits without shifting out a 1. */
1005
28.0k
            assert(0 < scale && scale <= P - 1);
1006
28.0k
            if (scale >= 32) {
1007
                /* The bits shifted out should all be zero. */
1008
16.0k
                assert(b->x[0] == 0);
1009
16.0k
                b->x[0] = b->x[1];
1010
16.0k
                b->x[1] = 0;
1011
16.0k
                scale -= 32;
1012
16.0k
            }
1013
28.0k
            if (scale) {
1014
                /* The bits shifted out should all be zero. */
1015
25.8k
                assert(b->x[0] << (32 - scale) == 0);
1016
25.8k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1017
25.8k
                b->x[1] >>= scale;
1018
25.8k
            }
1019
28.0k
        }
1020
32.5k
    }
1021
    /* Ensure b is normalized. */
1022
443k
    if (!b->x[1])
1023
27.5k
        b->wds = 1;
1024
1025
443k
    return b;
1026
443k
}
1027
1028
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1029
1030
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1031
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1032
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1033
1034
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1035
 */
1036
1037
static Bigint *
1038
d2b(U *d, int *e, int *bits)
1039
43.5k
{
1040
43.5k
    Bigint *b;
1041
43.5k
    int de, k;
1042
43.5k
    ULong *x, y, z;
1043
43.5k
    int i;
1044
1045
43.5k
    b = Balloc(1);
1046
43.5k
    if (b == NULL)
1047
0
        return NULL;
1048
43.5k
    x = b->x;
1049
1050
43.5k
    z = word0(d) & Frac_mask;
1051
43.5k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1052
43.5k
    if ((de = (int)(word0(d) >> Exp_shift)))
1053
39.6k
        z |= Exp_msk1;
1054
43.5k
    if ((y = word1(d))) {
1055
32.2k
        if ((k = lo0bits(&y))) {
1056
20.8k
            x[0] = y | z << (32 - k);
1057
20.8k
            z >>= k;
1058
20.8k
        }
1059
11.4k
        else
1060
11.4k
            x[0] = y;
1061
32.2k
        i =
1062
32.2k
            b->wds = (x[1] = z) ? 2 : 1;
1063
32.2k
    }
1064
11.2k
    else {
1065
11.2k
        k = lo0bits(&z);
1066
11.2k
        x[0] = z;
1067
11.2k
        i =
1068
11.2k
            b->wds = 1;
1069
11.2k
        k += 32;
1070
11.2k
    }
1071
43.5k
    if (de) {
1072
39.6k
        *e = de - Bias - (P-1) + k;
1073
39.6k
        *bits = P - k;
1074
39.6k
    }
1075
3.91k
    else {
1076
3.91k
        *e = de - Bias - (P-1) + 1 + k;
1077
3.91k
        *bits = 32*i - hi0bits(x[i-1]);
1078
3.91k
    }
1079
43.5k
    return b;
1080
43.5k
}
1081
1082
/* Compute the ratio of two Bigints, as a double.  The result may have an
1083
   error of up to 2.5 ulps. */
1084
1085
static double
1086
ratio(Bigint *a, Bigint *b)
1087
256k
{
1088
256k
    U da, db;
1089
256k
    int k, ka, kb;
1090
1091
256k
    dval(&da) = b2d(a, &ka);
1092
256k
    dval(&db) = b2d(b, &kb);
1093
256k
    k = ka - kb + 32*(a->wds - b->wds);
1094
256k
    if (k > 0)
1095
40.7k
        word0(&da) += k*Exp_msk1;
1096
215k
    else {
1097
215k
        k = -k;
1098
215k
        word0(&db) += k*Exp_msk1;
1099
215k
    }
1100
256k
    return dval(&da) / dval(&db);
1101
256k
}
1102
1103
static const double
1104
tens[] = {
1105
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1106
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1107
    1e20, 1e21, 1e22
1108
};
1109
1110
static const double
1111
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1112
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1113
                                   9007199254740992.*9007199254740992.e-256
1114
                                   /* = 2^106 * 1e-256 */
1115
};
1116
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1117
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1118
33.7k
#define Scale_Bit 0x10
1119
38.8k
#define n_bigtens 5
1120
1121
#define ULbits 32
1122
#define kshift 5
1123
58.2k
#define kmask 31
1124
1125
1126
static int
1127
dshift(Bigint *b, int p2)
1128
58.2k
{
1129
58.2k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1130
58.2k
    if (p2 > 0)
1131
22.1k
        rv -= p2;
1132
58.2k
    return rv & kmask;
1133
58.2k
}
1134
1135
/* special case of Bigint division.  The quotient is always in the range 0 <=
1136
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1137
   bits (28--31) are zero and bit 27 is set. */
1138
1139
static int
1140
quorem(Bigint *b, Bigint *S)
1141
557k
{
1142
557k
    int n;
1143
557k
    ULong *bx, *bxe, q, *sx, *sxe;
1144
557k
    ULLong borrow, carry, y, ys;
1145
1146
557k
    n = S->wds;
1147
#ifdef DEBUG
1148
    /*debug*/ if (b->wds > n)
1149
        /*debug*/       Bug("oversize b in quorem");
1150
#endif
1151
557k
    if (b->wds < n)
1152
12.4k
        return 0;
1153
545k
    sx = S->x;
1154
545k
    sxe = sx + --n;
1155
545k
    bx = b->x;
1156
545k
    bxe = bx + n;
1157
545k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1158
#ifdef DEBUG
1159
    /*debug*/ if (q > 9)
1160
        /*debug*/       Bug("oversized quotient in quorem");
1161
#endif
1162
545k
    if (q) {
1163
365k
        borrow = 0;
1164
365k
        carry = 0;
1165
2.05M
        do {
1166
2.05M
            ys = *sx++ * (ULLong)q + carry;
1167
2.05M
            carry = ys >> 32;
1168
2.05M
            y = *bx - (ys & FFFFFFFF) - borrow;
1169
2.05M
            borrow = y >> 32 & (ULong)1;
1170
2.05M
            *bx++ = (ULong)(y & FFFFFFFF);
1171
2.05M
        }
1172
2.05M
        while(sx <= sxe);
1173
365k
        if (!*bxe) {
1174
2.45k
            bx = b->x;
1175
2.45k
            while(--bxe > bx && !*bxe)
1176
0
                --n;
1177
2.45k
            b->wds = n;
1178
2.45k
        }
1179
365k
    }
1180
545k
    if (cmp(b, S) >= 0) {
1181
31.0k
        q++;
1182
31.0k
        borrow = 0;
1183
31.0k
        carry = 0;
1184
31.0k
        bx = b->x;
1185
31.0k
        sx = S->x;
1186
178k
        do {
1187
178k
            ys = *sx++ + carry;
1188
178k
            carry = ys >> 32;
1189
178k
            y = *bx - (ys & FFFFFFFF) - borrow;
1190
178k
            borrow = y >> 32 & (ULong)1;
1191
178k
            *bx++ = (ULong)(y & FFFFFFFF);
1192
178k
        }
1193
178k
        while(sx <= sxe);
1194
31.0k
        bx = b->x;
1195
31.0k
        bxe = bx + n;
1196
31.0k
        if (!*bxe) {
1197
20.5k
            while(--bxe > bx && !*bxe)
1198
1.63k
                --n;
1199
18.9k
            b->wds = n;
1200
18.9k
        }
1201
31.0k
    }
1202
545k
    return q;
1203
557k
}
1204
1205
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1206
1207
   Assuming that x is finite and nonnegative (positive zero is fine
1208
   here) and x / 2^bc.scale is exactly representable as a double,
1209
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1210
1211
static double
1212
sulp(U *x, BCinfo *bc)
1213
4.26k
{
1214
4.26k
    U u;
1215
1216
4.26k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1217
        /* rv/2^bc->scale is subnormal */
1218
302
        word0(&u) = (P+2)*Exp_msk1;
1219
302
        word1(&u) = 0;
1220
302
        return u.d;
1221
302
    }
1222
3.96k
    else {
1223
3.96k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1224
3.96k
        return ulp(x);
1225
3.96k
    }
1226
4.26k
}
1227
1228
/* The bigcomp function handles some hard cases for strtod, for inputs
1229
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1230
   estimate for the double corresponding to the input string has
1231
   already been obtained by the code in _Py_dg_strtod.
1232
1233
   The bigcomp function is only called after _Py_dg_strtod has found a
1234
   double value rv such that either rv or rv + 1ulp represents the
1235
   correctly rounded value corresponding to the original string.  It
1236
   determines which of these two values is the correct one by
1237
   computing the decimal digits of rv + 0.5ulp and comparing them with
1238
   the corresponding digits of s0.
1239
1240
   In the following, write dv for the absolute value of the number represented
1241
   by the input string.
1242
1243
   Inputs:
1244
1245
     s0 points to the first significant digit of the input string.
1246
1247
     rv is a (possibly scaled) estimate for the closest double value to the
1248
        value represented by the original input to _Py_dg_strtod.  If
1249
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1250
        the input value.
1251
1252
     bc is a struct containing information gathered during the parsing and
1253
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1254
1255
        bc->e0 gives the exponent of the input value, such that dv = (integer
1256
           given by the bd->nd digits of s0) * 10**e0
1257
1258
        bc->nd gives the total number of significant digits of s0.  It will
1259
           be at least 1.
1260
1261
        bc->nd0 gives the number of significant digits of s0 before the
1262
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1263
           bc->nd.
1264
1265
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1266
           subnormal values.  It's either 0 or 2*P (=106).
1267
1268
   Outputs:
1269
1270
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1271
1272
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1273
1274
static int
1275
bigcomp(U *rv, const char *s0, BCinfo *bc)
1276
25.6k
{
1277
25.6k
    Bigint *b, *d;
1278
25.6k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1279
1280
25.6k
    nd = bc->nd;
1281
25.6k
    nd0 = bc->nd0;
1282
25.6k
    p5 = nd + bc->e0;
1283
25.6k
    b = sd2b(rv, bc->scale, &p2);
1284
25.6k
    if (b == NULL)
1285
0
        return -1;
1286
1287
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1288
       case, this is used for round to even. */
1289
25.6k
    odd = b->x[0] & 1;
1290
1291
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1292
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1293
25.6k
    b = lshift(b, 1);
1294
25.6k
    if (b == NULL)
1295
0
        return -1;
1296
25.6k
    b->x[0] |= 1;
1297
25.6k
    p2--;
1298
1299
25.6k
    p2 -= p5;
1300
25.6k
    d = i2b(1);
1301
25.6k
    if (d == NULL) {
1302
0
        Bfree(b);
1303
0
        return -1;
1304
0
    }
1305
    /* Arrange for convenient computation of quotients:
1306
     * shift left if necessary so divisor has 4 leading 0 bits.
1307
     */
1308
25.6k
    if (p5 > 0) {
1309
23.2k
        d = pow5mult(d, p5);
1310
23.2k
        if (d == NULL) {
1311
0
            Bfree(b);
1312
0
            return -1;
1313
0
        }
1314
23.2k
    }
1315
2.40k
    else if (p5 < 0) {
1316
1.53k
        b = pow5mult(b, -p5);
1317
1.53k
        if (b == NULL) {
1318
0
            Bfree(d);
1319
0
            return -1;
1320
0
        }
1321
1.53k
    }
1322
25.6k
    if (p2 > 0) {
1323
21.3k
        b2 = p2;
1324
21.3k
        d2 = 0;
1325
21.3k
    }
1326
4.25k
    else {
1327
4.25k
        b2 = 0;
1328
4.25k
        d2 = -p2;
1329
4.25k
    }
1330
25.6k
    i = dshift(d, d2);
1331
25.6k
    if ((b2 += i) > 0) {
1332
25.3k
        b = lshift(b, b2);
1333
25.3k
        if (b == NULL) {
1334
0
            Bfree(d);
1335
0
            return -1;
1336
0
        }
1337
25.3k
    }
1338
25.6k
    if ((d2 += i) > 0) {
1339
24.4k
        d = lshift(d, d2);
1340
24.4k
        if (d == NULL) {
1341
0
            Bfree(b);
1342
0
            return -1;
1343
0
        }
1344
24.4k
    }
1345
1346
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1347
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1348
     * a number in the range [0.1, 1). */
1349
25.6k
    if (cmp(b, d) >= 0)
1350
        /* b/d >= 1 */
1351
854
        dd = -1;
1352
24.7k
    else {
1353
24.7k
        i = 0;
1354
435k
        for(;;) {
1355
435k
            b = multadd(b, 10, 0);
1356
435k
            if (b == NULL) {
1357
0
                Bfree(d);
1358
0
                return -1;
1359
0
            }
1360
435k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1361
435k
            i++;
1362
1363
435k
            if (dd)
1364
23.2k
                break;
1365
412k
            if (!b->x[0] && b->wds == 1) {
1366
                /* b/d == 0 */
1367
982
                dd = i < nd;
1368
982
                break;
1369
982
            }
1370
411k
            if (!(i < nd)) {
1371
                /* b/d != 0, but digits of s0 exhausted */
1372
520
                dd = -1;
1373
520
                break;
1374
520
            }
1375
411k
        }
1376
24.7k
    }
1377
25.6k
    Bfree(b);
1378
25.6k
    Bfree(d);
1379
25.6k
    if (dd > 0 || (dd == 0 && odd))
1380
2.50k
        dval(rv) += sulp(rv, bc);
1381
25.6k
    return 0;
1382
25.6k
}
1383
1384
1385
double
1386
_Py_dg_strtod(const char *s00, char **se)
1387
1.02M
{
1388
1.02M
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1389
1.02M
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1390
1.02M
    const char *s, *s0, *s1;
1391
1.02M
    double aadj, aadj1;
1392
1.02M
    U aadj2, adj, rv, rv0;
1393
1.02M
    ULong y, z, abs_exp;
1394
1.02M
    Long L;
1395
1.02M
    BCinfo bc;
1396
1.02M
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1397
1.02M
    size_t ndigits, fraclen;
1398
1.02M
    double result;
1399
1400
1.02M
    dval(&rv) = 0.;
1401
1402
    /* Start parsing. */
1403
1.02M
    c = *(s = s00);
1404
1405
    /* Parse optional sign, if present. */
1406
1.02M
    sign = 0;
1407
1.02M
    switch (c) {
1408
482k
    case '-':
1409
482k
        sign = 1;
1410
482k
        _Py_FALLTHROUGH;
1411
482k
    case '+':
1412
482k
        c = *++s;
1413
1.02M
    }
1414
1415
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1416
1.02M
    s1 = s;
1417
1.05M
    while (c == '0')
1418
26.6k
        c = *++s;
1419
1.02M
    lz = s != s1;
1420
1421
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1422
       number of digits between the decimal point and the end of the
1423
       digit string.  ndigits will be the total number of digits ignoring
1424
       leading zeros. */
1425
1.02M
    s0 = s1 = s;
1426
6.96M
    while ('0' <= c && c <= '9')
1427
5.93M
        c = *++s;
1428
1.02M
    ndigits = s - s1;
1429
1.02M
    fraclen = 0;
1430
1431
    /* Parse decimal point and following digits. */
1432
1.02M
    if (c == '.') {
1433
76.0k
        c = *++s;
1434
76.0k
        if (!ndigits) {
1435
26.9k
            s1 = s;
1436
353k
            while (c == '0')
1437
326k
                c = *++s;
1438
26.9k
            lz = lz || s != s1;
1439
26.9k
            fraclen += (s - s1);
1440
26.9k
            s0 = s;
1441
26.9k
        }
1442
76.0k
        s1 = s;
1443
33.2M
        while ('0' <= c && c <= '9')
1444
33.1M
            c = *++s;
1445
76.0k
        ndigits += s - s1;
1446
76.0k
        fraclen += s - s1;
1447
76.0k
    }
1448
1449
    /* Now lz is true if and only if there were leading zero digits, and
1450
       ndigits gives the total number of digits ignoring leading zeros.  A
1451
       valid input must have at least one digit. */
1452
1.02M
    if (!ndigits && !lz) {
1453
58.1k
        if (se)
1454
58.1k
            *se = (char *)s00;
1455
58.1k
        goto parse_error;
1456
58.1k
    }
1457
1458
    /* Range check ndigits and fraclen to make sure that they, and values
1459
       computed with them, can safely fit in an int. */
1460
971k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1461
0
        if (se)
1462
0
            *se = (char *)s00;
1463
0
        goto parse_error;
1464
0
    }
1465
971k
    nd = (int)ndigits;
1466
971k
    nd0 = (int)ndigits - (int)fraclen;
1467
1468
    /* Parse exponent. */
1469
971k
    e = 0;
1470
971k
    if (c == 'e' || c == 'E') {
1471
897k
        s00 = s;
1472
897k
        c = *++s;
1473
1474
        /* Exponent sign. */
1475
897k
        esign = 0;
1476
897k
        switch (c) {
1477
39.9k
        case '-':
1478
39.9k
            esign = 1;
1479
39.9k
            _Py_FALLTHROUGH;
1480
56.3k
        case '+':
1481
56.3k
            c = *++s;
1482
897k
        }
1483
1484
        /* Skip zeros.  lz is true iff there are leading zeros. */
1485
897k
        s1 = s;
1486
1.13M
        while (c == '0')
1487
236k
            c = *++s;
1488
897k
        lz = s != s1;
1489
1490
        /* Get absolute value of the exponent. */
1491
897k
        s1 = s;
1492
897k
        abs_exp = 0;
1493
13.4M
        while ('0' <= c && c <= '9') {
1494
12.5M
            abs_exp = 10*abs_exp + (c - '0');
1495
12.5M
            c = *++s;
1496
12.5M
        }
1497
1498
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1499
           there are at most 9 significant exponent digits then overflow is
1500
           impossible. */
1501
897k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1502
9.56k
            e = (int)MAX_ABS_EXP;
1503
888k
        else
1504
888k
            e = (int)abs_exp;
1505
897k
        if (esign)
1506
39.9k
            e = -e;
1507
1508
        /* A valid exponent must have at least one digit. */
1509
897k
        if (s == s1 && !lz)
1510
0
            s = s00;
1511
897k
    }
1512
1513
    /* Adjust exponent to take into account position of the point. */
1514
971k
    e -= nd - nd0;
1515
971k
    if (nd0 <= 0)
1516
32.7k
        nd0 = nd;
1517
1518
    /* Finished parsing.  Set se to indicate how far we parsed */
1519
971k
    if (se)
1520
971k
        *se = (char *)s;
1521
1522
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1523
       strip trailing zeros: scan back until we hit a nonzero digit. */
1524
971k
    if (!nd)
1525
15.2k
        goto ret;
1526
9.93M
    for (i = nd; i > 0; ) {
1527
9.93M
        --i;
1528
9.93M
        if (s0[i < nd0 ? i : i+1] != '0') {
1529
956k
            ++i;
1530
956k
            break;
1531
956k
        }
1532
9.93M
    }
1533
956k
    e += nd - i;
1534
956k
    nd = i;
1535
956k
    if (nd0 > nd)
1536
25.4k
        nd0 = nd;
1537
1538
    /* Summary of parsing results.  After parsing, and dealing with zero
1539
     * inputs, we have values s0, nd0, nd, e, sign, where:
1540
     *
1541
     *  - s0 points to the first significant digit of the input string
1542
     *
1543
     *  - nd is the total number of significant digits (here, and
1544
     *    below, 'significant digits' means the set of digits of the
1545
     *    significand of the input that remain after ignoring leading
1546
     *    and trailing zeros).
1547
     *
1548
     *  - nd0 indicates the position of the decimal point, if present; it
1549
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1550
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1551
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1552
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1553
     *
1554
     *  - e is the adjusted exponent: the absolute value of the number
1555
     *    represented by the original input string is n * 10**e, where
1556
     *    n is the integer represented by the concatenation of
1557
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1558
     *
1559
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1560
     *
1561
     *  - the first and last significant digits are nonzero
1562
     */
1563
1564
    /* put first DBL_DIG+1 digits into integer y and z.
1565
     *
1566
     *  - y contains the value represented by the first min(9, nd)
1567
     *    significant digits
1568
     *
1569
     *  - if nd > 9, z contains the value represented by significant digits
1570
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1571
     *    gives the value represented by the first min(16, nd) sig. digits.
1572
     */
1573
1574
956k
    bc.e0 = e1 = e;
1575
956k
    y = z = 0;
1576
3.96M
    for (i = 0; i < nd; i++) {
1577
3.05M
        if (i < 9)
1578
2.56M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1579
495k
        else if (i < DBL_DIG+1)
1580
444k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1581
51.2k
        else
1582
51.2k
            break;
1583
3.05M
    }
1584
1585
956k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1586
956k
    dval(&rv) = y;
1587
956k
    if (k > 9) {
1588
74.8k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1589
74.8k
    }
1590
956k
    if (nd <= DBL_DIG
1591
897k
        && Flt_Rounds == 1
1592
956k
        ) {
1593
897k
        if (!e)
1594
13.3k
            goto ret;
1595
884k
        if (e > 0) {
1596
826k
            if (e <= Ten_pmax) {
1597
32.8k
                dval(&rv) *= tens[e];
1598
32.8k
                goto ret;
1599
32.8k
            }
1600
793k
            i = DBL_DIG - nd;
1601
793k
            if (e <= Ten_pmax + i) {
1602
                /* A fancier test would sometimes let us do
1603
                 * this for larger i values.
1604
                 */
1605
3.15k
                e -= i;
1606
3.15k
                dval(&rv) *= tens[i];
1607
3.15k
                dval(&rv) *= tens[e];
1608
3.15k
                goto ret;
1609
3.15k
            }
1610
793k
        }
1611
57.4k
        else if (e >= -Ten_pmax) {
1612
25.5k
            dval(&rv) /= tens[-e];
1613
25.5k
            goto ret;
1614
25.5k
        }
1615
884k
    }
1616
881k
    e1 += nd - k;
1617
1618
881k
    bc.scale = 0;
1619
1620
    /* Get starting approximation = rv * 10**e1 */
1621
1622
881k
    if (e1 > 0) {
1623
828k
        if ((i = e1 & 15))
1624
724k
            dval(&rv) *= tens[i];
1625
828k
        if (e1 &= ~15) {
1626
818k
            if (e1 > DBL_MAX_10_EXP)
1627
496k
                goto ovfl;
1628
321k
            e1 >>= 4;
1629
828k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1630
506k
                if (e1 & 1)
1631
268k
                    dval(&rv) *= bigtens[j];
1632
            /* The last multiplication could overflow. */
1633
321k
            word0(&rv) -= P*Exp_msk1;
1634
321k
            dval(&rv) *= bigtens[j];
1635
321k
            if ((z = word0(&rv) & Exp_mask)
1636
321k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1637
1.92k
                goto ovfl;
1638
319k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1639
                /* set to largest number */
1640
                /* (Can't trust DBL_MAX) */
1641
584
                word0(&rv) = Big0;
1642
584
                word1(&rv) = Big1;
1643
584
            }
1644
319k
            else
1645
319k
                word0(&rv) += P*Exp_msk1;
1646
319k
        }
1647
828k
    }
1648
52.3k
    else if (e1 < 0) {
1649
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1650
1651
           If e1 <= -512, underflow immediately.
1652
           If e1 <= -256, set bc.scale to 2*P.
1653
1654
           So for input value < 1e-256, bc.scale is always set;
1655
           for input value >= 1e-240, bc.scale is never set.
1656
           For input values in [1e-256, 1e-240), bc.scale may or may
1657
           not be set. */
1658
1659
48.7k
        e1 = -e1;
1660
48.7k
        if ((i = e1 & 15))
1661
39.1k
            dval(&rv) /= tens[i];
1662
48.7k
        if (e1 >>= 4) {
1663
38.8k
            if (e1 >= 1 << n_bigtens)
1664
5.07k
                goto undfl;
1665
33.7k
            if (e1 & Scale_Bit)
1666
21.2k
                bc.scale = 2*P;
1667
166k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1668
132k
                if (e1 & 1)
1669
77.8k
                    dval(&rv) *= tinytens[j];
1670
33.7k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1671
21.2k
                                            >> Exp_shift)) > 0) {
1672
                /* scaled rv is denormal; clear j low bits */
1673
19.2k
                if (j >= 32) {
1674
12.6k
                    word1(&rv) = 0;
1675
12.6k
                    if (j >= 53)
1676
6.85k
                        word0(&rv) = (P+2)*Exp_msk1;
1677
5.80k
                    else
1678
5.80k
                        word0(&rv) &= 0xffffffff << (j-32);
1679
12.6k
                }
1680
6.59k
                else
1681
6.59k
                    word1(&rv) &= 0xffffffff << j;
1682
19.2k
            }
1683
33.7k
            if (!dval(&rv))
1684
0
                goto undfl;
1685
33.7k
        }
1686
48.7k
    }
1687
1688
    /* Now the hard part -- adjusting rv to the correct value.*/
1689
1690
    /* Put digits into bd: true value = bd * 10^e */
1691
1692
377k
    bc.nd = nd;
1693
377k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1694
                        /* to silence an erroneous warning about bc.nd0 */
1695
                        /* possibly not being initialized. */
1696
377k
    if (nd > STRTOD_DIGLIM) {
1697
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1698
        /* minimum number of decimal digits to distinguish double values */
1699
        /* in IEEE arithmetic. */
1700
1701
        /* Truncate input to 18 significant digits, then discard any trailing
1702
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1703
           no need to update z; it's not reused beyond this point.) */
1704
282k
        for (i = 18; i > 0; ) {
1705
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1706
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1707
282k
            --i;
1708
282k
            if (s0[i < nd0 ? i : i+1] != '0') {
1709
32.3k
                ++i;
1710
32.3k
                break;
1711
32.3k
            }
1712
282k
        }
1713
32.3k
        e += nd - i;
1714
32.3k
        nd = i;
1715
32.3k
        if (nd0 > nd)
1716
27.4k
            nd0 = nd;
1717
32.3k
        if (nd < 9) { /* must recompute y */
1718
22.5k
            y = 0;
1719
176k
            for(i = 0; i < nd0; ++i)
1720
154k
                y = 10*y + s0[i] - '0';
1721
31.6k
            for(; i < nd; ++i)
1722
9.12k
                y = 10*y + s0[i+1] - '0';
1723
22.5k
        }
1724
32.3k
    }
1725
377k
    bd0 = s2b(s0, nd0, nd, y);
1726
377k
    if (bd0 == NULL)
1727
0
        goto failed_malloc;
1728
1729
    /* Notation for the comments below.  Write:
1730
1731
         - dv for the absolute value of the number represented by the original
1732
           decimal input string.
1733
1734
         - if we've truncated dv, write tdv for the truncated value.
1735
           Otherwise, set tdv == dv.
1736
1737
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1738
           approximation to tdv (and dv).  It should be exactly representable
1739
           in an IEEE 754 double.
1740
    */
1741
1742
418k
    for(;;) {
1743
1744
        /* This is the main correction loop for _Py_dg_strtod.
1745
1746
           We've got a decimal value tdv, and a floating-point approximation
1747
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1748
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1749
           approximation if not.
1750
1751
           To determine whether srv is close enough to tdv, compute integers
1752
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1753
           respectively, and then use integer arithmetic to determine whether
1754
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1755
        */
1756
1757
418k
        bd = Balloc(bd0->k);
1758
418k
        if (bd == NULL) {
1759
0
            goto failed_malloc;
1760
0
        }
1761
418k
        Bcopy(bd, bd0);
1762
418k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1763
418k
        if (bb == NULL) {
1764
0
            goto failed_malloc;
1765
0
        }
1766
        /* Record whether lsb of bb is odd, in case we need this
1767
           for the round-to-even step later. */
1768
418k
        odd = bb->x[0] & 1;
1769
1770
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1771
418k
        bs = i2b(1);
1772
418k
        if (bs == NULL) {
1773
0
            goto failed_malloc;
1774
0
        }
1775
1776
418k
        if (e >= 0) {
1777
353k
            bb2 = bb5 = 0;
1778
353k
            bd2 = bd5 = e;
1779
353k
        }
1780
64.9k
        else {
1781
64.9k
            bb2 = bb5 = -e;
1782
64.9k
            bd2 = bd5 = 0;
1783
64.9k
        }
1784
418k
        if (bbe >= 0)
1785
354k
            bb2 += bbe;
1786
63.9k
        else
1787
63.9k
            bd2 -= bbe;
1788
418k
        bs2 = bb2;
1789
418k
        bb2++;
1790
418k
        bd2++;
1791
1792
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1793
           and bs == 1, so:
1794
1795
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1796
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1797
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1798
1799
           It follows that:
1800
1801
              M * tdv = bd * 2**bd2 * 5**bd5
1802
              M * srv = bb * 2**bb2 * 5**bb5
1803
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1804
1805
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1806
           this fact is not needed below.)
1807
        */
1808
1809
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1810
418k
        i = bb2 < bd2 ? bb2 : bd2;
1811
418k
        if (i > bs2)
1812
62.6k
            i = bs2;
1813
418k
        if (i > 0) {
1814
417k
            bb2 -= i;
1815
417k
            bd2 -= i;
1816
417k
            bs2 -= i;
1817
417k
        }
1818
1819
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1820
418k
        if (bb5 > 0) {
1821
64.9k
            bs = pow5mult(bs, bb5);
1822
64.9k
            if (bs == NULL) {
1823
0
                goto failed_malloc;
1824
0
            }
1825
64.9k
            Bigint *bb1 = mult(bs, bb);
1826
64.9k
            Bfree(bb);
1827
64.9k
            bb = bb1;
1828
64.9k
            if (bb == NULL) {
1829
0
                goto failed_malloc;
1830
0
            }
1831
64.9k
        }
1832
418k
        if (bb2 > 0) {
1833
418k
            bb = lshift(bb, bb2);
1834
418k
            if (bb == NULL) {
1835
0
                goto failed_malloc;
1836
0
            }
1837
418k
        }
1838
418k
        if (bd5 > 0) {
1839
343k
            bd = pow5mult(bd, bd5);
1840
343k
            if (bd == NULL) {
1841
0
                goto failed_malloc;
1842
0
            }
1843
343k
        }
1844
418k
        if (bd2 > 0) {
1845
62.6k
            bd = lshift(bd, bd2);
1846
62.6k
            if (bd == NULL) {
1847
0
                goto failed_malloc;
1848
0
            }
1849
62.6k
        }
1850
418k
        if (bs2 > 0) {
1851
350k
            bs = lshift(bs, bs2);
1852
350k
            if (bs == NULL) {
1853
0
                goto failed_malloc;
1854
0
            }
1855
350k
        }
1856
1857
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1858
           respectively.  Compute the difference |tdv - srv|, and compare
1859
           with 0.5 ulp(srv). */
1860
1861
418k
        delta = diff(bb, bd);
1862
418k
        if (delta == NULL) {
1863
0
            goto failed_malloc;
1864
0
        }
1865
418k
        dsign = delta->sign;
1866
418k
        delta->sign = 0;
1867
418k
        i = cmp(delta, bs);
1868
418k
        if (bc.nd > nd && i <= 0) {
1869
32.3k
            if (dsign)
1870
24.5k
                break;  /* Must use bigcomp(). */
1871
1872
            /* Here rv overestimates the truncated decimal value by at most
1873
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1874
               value by <= 0.5 ulp(rv), or underestimates it by some small
1875
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1876
               the true decimal value, so it's possible to exit.
1877
1878
               Exception: if scaled rv is a normal exact power of 2, but not
1879
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1880
               next double, so the correctly rounded result is either rv - 0.5
1881
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1882
1883
7.84k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1884
                /* rv can't be 0, since it's an overestimate for some
1885
                   nonzero value.  So rv is a normal power of 2. */
1886
1.37k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1887
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1888
                   rv / 2^bc.scale >= 2^-1021. */
1889
1.37k
                if (j - bc.scale >= 2) {
1890
1.11k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1891
1.11k
                    break; /* Use bigcomp. */
1892
1.11k
                }
1893
1.37k
            }
1894
1895
6.73k
            {
1896
6.73k
                bc.nd = nd;
1897
6.73k
                i = -1; /* Discarded digits make delta smaller. */
1898
6.73k
            }
1899
6.73k
        }
1900
1901
392k
        if (i < 0) {
1902
            /* Error is less than half an ulp -- check for
1903
             * special case of mantissa a power of two.
1904
             */
1905
130k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1906
5.89k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1907
130k
                ) {
1908
126k
                break;
1909
126k
            }
1910
4.71k
            if (!delta->x[0] && delta->wds <= 1) {
1911
                /* exact result */
1912
579
                break;
1913
579
            }
1914
4.13k
            delta = lshift(delta,Log2P);
1915
4.13k
            if (delta == NULL) {
1916
0
                goto failed_malloc;
1917
0
            }
1918
4.13k
            if (cmp(delta, bs) > 0)
1919
1.09k
                goto drop_down;
1920
3.04k
            break;
1921
4.13k
        }
1922
261k
        if (i == 0) {
1923
            /* exactly half-way between */
1924
5.27k
            if (dsign) {
1925
2.24k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1926
795
                    &&  word1(&rv) == (
1927
795
                        (bc.scale &&
1928
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1929
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1930
795
                        0xffffffff)) {
1931
                    /*boundary case -- increment exponent*/
1932
466
                    word0(&rv) = (word0(&rv) & Exp_mask)
1933
466
                        + Exp_msk1
1934
466
                        ;
1935
466
                    word1(&rv) = 0;
1936
                    /* dsign = 0; */
1937
466
                    break;
1938
466
                }
1939
2.24k
            }
1940
3.02k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1941
1.09k
              drop_down:
1942
                /* boundary case -- decrement exponent */
1943
1.09k
                if (bc.scale) {
1944
0
                    L = word0(&rv) & Exp_mask;
1945
0
                    if (L <= (2*P+1)*Exp_msk1) {
1946
0
                        if (L > (P+2)*Exp_msk1)
1947
                            /* round even ==> */
1948
                            /* accept rv */
1949
0
                            break;
1950
                        /* rv = smallest denormal */
1951
0
                        if (bc.nd > nd)
1952
0
                            break;
1953
0
                        goto undfl;
1954
0
                    }
1955
0
                }
1956
1.09k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1957
1.09k
                word0(&rv) = L | Bndry_mask1;
1958
1.09k
                word1(&rv) = 0xffffffff;
1959
1.09k
                break;
1960
1.09k
            }
1961
4.80k
            if (!odd)
1962
4.16k
                break;
1963
643
            if (dsign)
1964
403
                dval(&rv) += sulp(&rv, &bc);
1965
240
            else {
1966
240
                dval(&rv) -= sulp(&rv, &bc);
1967
240
                if (!dval(&rv)) {
1968
0
                    if (bc.nd >nd)
1969
0
                        break;
1970
0
                    goto undfl;
1971
0
                }
1972
240
            }
1973
            /* dsign = 1 - dsign; */
1974
643
            break;
1975
643
        }
1976
256k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1977
230k
            if (dsign)
1978
19.2k
                aadj = aadj1 = 1.;
1979
210k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1980
204k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1981
0
                    if (bc.nd >nd)
1982
0
                        break;
1983
0
                    goto undfl;
1984
0
                }
1985
204k
                aadj = 1.;
1986
204k
                aadj1 = -1.;
1987
204k
            }
1988
6.36k
            else {
1989
                /* special case -- power of FLT_RADIX to be */
1990
                /* rounded down... */
1991
1992
6.36k
                if (aadj < 2./FLT_RADIX)
1993
0
                    aadj = 1./FLT_RADIX;
1994
6.36k
                else
1995
6.36k
                    aadj *= 0.5;
1996
6.36k
                aadj1 = -aadj;
1997
6.36k
            }
1998
230k
        }
1999
26.4k
        else {
2000
26.4k
            aadj *= 0.5;
2001
26.4k
            aadj1 = dsign ? aadj : -aadj;
2002
26.4k
            if (Flt_Rounds == 0)
2003
0
                aadj1 += 0.5;
2004
26.4k
        }
2005
256k
        y = word0(&rv) & Exp_mask;
2006
2007
        /* Check for overflow */
2008
2009
256k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2010
2.80k
            dval(&rv0) = dval(&rv);
2011
2.80k
            word0(&rv) -= P*Exp_msk1;
2012
2.80k
            adj.d = aadj1 * ulp(&rv);
2013
2.80k
            dval(&rv) += adj.d;
2014
2.80k
            if ((word0(&rv) & Exp_mask) >=
2015
2.80k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2016
1.35k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2017
971
                    goto ovfl;
2018
971
                }
2019
387
                word0(&rv) = Big0;
2020
387
                word1(&rv) = Big1;
2021
387
                goto cont;
2022
1.35k
            }
2023
1.44k
            else
2024
1.44k
                word0(&rv) += P*Exp_msk1;
2025
2.80k
        }
2026
253k
        else {
2027
253k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2028
15.4k
                if (aadj <= 0x7fffffff) {
2029
15.4k
                    if ((z = (ULong)aadj) <= 0)
2030
1.93k
                        z = 1;
2031
15.4k
                    aadj = z;
2032
15.4k
                    aadj1 = dsign ? aadj : -aadj;
2033
15.4k
                }
2034
15.4k
                dval(&aadj2) = aadj1;
2035
15.4k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2036
15.4k
                aadj1 = dval(&aadj2);
2037
15.4k
            }
2038
253k
            adj.d = aadj1 * ulp(&rv);
2039
253k
            dval(&rv) += adj.d;
2040
253k
        }
2041
255k
        z = word0(&rv) & Exp_mask;
2042
255k
        if (bc.nd == nd) {
2043
234k
            if (!bc.scale)
2044
218k
                if (y == z) {
2045
                    /* Can we stop now? */
2046
217k
                    L = (Long)aadj;
2047
217k
                    aadj -= L;
2048
                    /* The tolerances below are conservative. */
2049
217k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2050
217k
                        if (aadj < .4999999 || aadj > .5000001)
2051
214k
                            break;
2052
217k
                    }
2053
27
                    else if (aadj < .4999999/FLT_RADIX)
2054
27
                        break;
2055
217k
                }
2056
234k
        }
2057
40.8k
      cont:
2058
40.8k
        Bfree(bb); bb = NULL;
2059
40.8k
        Bfree(bd); bd = NULL;
2060
40.8k
        Bfree(bs); bs = NULL;
2061
40.8k
        Bfree(delta); delta = NULL;
2062
40.8k
    }
2063
376k
    if (bc.nd > nd) {
2064
25.6k
        error = bigcomp(&rv, s0, &bc);
2065
25.6k
        if (error)
2066
0
            goto failed_malloc;
2067
25.6k
    }
2068
2069
376k
    if (bc.scale) {
2070
21.2k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2071
21.2k
        word1(&rv0) = 0;
2072
21.2k
        dval(&rv) *= dval(&rv0);
2073
21.2k
    }
2074
2075
466k
  ret:
2076
466k
    result = sign ? -dval(&rv) : dval(&rv);
2077
466k
    goto done;
2078
2079
58.1k
  parse_error:
2080
58.1k
    result = 0.0;
2081
58.1k
    goto done;
2082
2083
0
  failed_malloc:
2084
0
    errno = ENOMEM;
2085
0
    result = -1.0;
2086
0
    goto done;
2087
2088
5.07k
  undfl:
2089
5.07k
    result = sign ? -0.0 : 0.0;
2090
5.07k
    goto done;
2091
2092
499k
  ovfl:
2093
499k
    errno = ERANGE;
2094
    /* Can't trust HUGE_VAL */
2095
499k
    word0(&rv) = Exp_mask;
2096
499k
    word1(&rv) = 0;
2097
499k
    result = sign ? -dval(&rv) : dval(&rv);
2098
499k
    goto done;
2099
2100
1.02M
  done:
2101
1.02M
    Bfree(bb);
2102
1.02M
    Bfree(bd);
2103
1.02M
    Bfree(bs);
2104
1.02M
    Bfree(bd0);
2105
1.02M
    Bfree(delta);
2106
1.02M
    return result;
2107
2108
376k
}
2109
2110
static char *
2111
rv_alloc(int i)
2112
49.7k
{
2113
49.7k
    int j, k, *r;
2114
2115
49.7k
    j = sizeof(ULong);
2116
49.7k
    for(k = 0;
2117
49.7k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2118
49.7k
        j <<= 1)
2119
0
        k++;
2120
49.7k
    r = (int*)Balloc(k);
2121
49.7k
    if (r == NULL)
2122
0
        return NULL;
2123
49.7k
    *r = k;
2124
49.7k
    return (char *)(r+1);
2125
49.7k
}
2126
2127
static char *
2128
nrv_alloc(const char *s, char **rve, int n)
2129
6.19k
{
2130
6.19k
    char *rv, *t;
2131
2132
6.19k
    rv = rv_alloc(n);
2133
6.19k
    if (rv == NULL)
2134
0
        return NULL;
2135
6.19k
    t = rv;
2136
15.7k
    while((*t = *s++)) t++;
2137
6.19k
    if (rve)
2138
6.19k
        *rve = t;
2139
6.19k
    return rv;
2140
6.19k
}
2141
2142
/* freedtoa(s) must be used to free values s returned by dtoa
2143
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2144
 * but for consistency with earlier versions of dtoa, it is optional
2145
 * when MULTIPLE_THREADS is not defined.
2146
 */
2147
2148
void
2149
_Py_dg_freedtoa(char *s)
2150
49.7k
{
2151
49.7k
    Bigint *b = (Bigint *)((int *)s - 1);
2152
49.7k
    b->maxwds = 1 << (b->k = *(int*)b);
2153
49.7k
    Bfree(b);
2154
49.7k
}
2155
2156
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2157
 *
2158
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2159
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2160
 *
2161
 * Modifications:
2162
 *      1. Rather than iterating, we use a simple numeric overestimate
2163
 *         to determine k = floor(log10(d)).  We scale relevant
2164
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2165
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2166
 *         try to generate digits strictly left to right.  Instead, we
2167
 *         compute with fewer bits and propagate the carry if necessary
2168
 *         when rounding the final digit up.  This is often faster.
2169
 *      3. Under the assumption that input will be rounded nearest,
2170
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2171
 *         That is, we allow equality in stopping tests when the
2172
 *         round-nearest rule will give the same floating-point value
2173
 *         as would satisfaction of the stopping test with strict
2174
 *         inequality.
2175
 *      4. We remove common factors of powers of 2 from relevant
2176
 *         quantities.
2177
 *      5. When converting floating-point integers less than 1e16,
2178
 *         we use floating-point arithmetic rather than resorting
2179
 *         to multiple-precision integers.
2180
 *      6. When asked to produce fewer than 15 digits, we first try
2181
 *         to get by with floating-point arithmetic; we resort to
2182
 *         multiple-precision integer arithmetic only if we cannot
2183
 *         guarantee that the floating-point calculation has given
2184
 *         the correctly rounded result.  For k requested digits and
2185
 *         "uniformly" distributed input, the probability is
2186
 *         something like 10^(k-15) that we must resort to the Long
2187
 *         calculation.
2188
 */
2189
2190
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2191
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2192
   call to _Py_dg_freedtoa. */
2193
2194
char *
2195
_Py_dg_dtoa(double dd, int mode, int ndigits,
2196
            int *decpt, int *sign, char **rve)
2197
49.7k
{
2198
    /*  Arguments ndigits, decpt, sign are similar to those
2199
        of ecvt and fcvt; trailing zeros are suppressed from
2200
        the returned string.  If not null, *rve is set to point
2201
        to the end of the return value.  If d is +-Infinity or NaN,
2202
        then *decpt is set to 9999.
2203
2204
        mode:
2205
        0 ==> shortest string that yields d when read in
2206
        and rounded to nearest.
2207
        1 ==> like 0, but with Steele & White stopping rule;
2208
        e.g. with IEEE P754 arithmetic , mode 0 gives
2209
        1e23 whereas mode 1 gives 9.999999999999999e22.
2210
        2 ==> max(1,ndigits) significant digits.  This gives a
2211
        return value similar to that of ecvt, except
2212
        that trailing zeros are suppressed.
2213
        3 ==> through ndigits past the decimal point.  This
2214
        gives a return value similar to that from fcvt,
2215
        except that trailing zeros are suppressed, and
2216
        ndigits can be negative.
2217
        4,5 ==> similar to 2 and 3, respectively, but (in
2218
        round-nearest mode) with the tests of mode 0 to
2219
        possibly return a shorter string that rounds to d.
2220
        With IEEE arithmetic and compilation with
2221
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2222
        as modes 2 and 3 when FLT_ROUNDS != 1.
2223
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2224
        fast floating-point estimate (if applicable).
2225
2226
        Values of mode other than 0-9 are treated as mode 0.
2227
2228
        Sufficient space is allocated to the return value
2229
        to hold the suppressed trailing zeros.
2230
    */
2231
2232
49.7k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2233
49.7k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2234
49.7k
        spec_case, try_quick;
2235
49.7k
    Long L;
2236
49.7k
    int denorm;
2237
49.7k
    ULong x;
2238
49.7k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2239
49.7k
    U d2, eps, u;
2240
49.7k
    double ds;
2241
49.7k
    char *s, *s0;
2242
2243
    /* set pointers to NULL, to silence gcc compiler warnings and make
2244
       cleanup easier on error */
2245
49.7k
    mlo = mhi = S = 0;
2246
49.7k
    s0 = 0;
2247
2248
49.7k
    u.d = dd;
2249
49.7k
    if (word0(&u) & Sign_bit) {
2250
        /* set sign for everything, including 0's and NaNs */
2251
17.6k
        *sign = 1;
2252
17.6k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2253
17.6k
    }
2254
32.0k
    else
2255
32.0k
        *sign = 0;
2256
2257
    /* quick return for Infinities, NaNs and zeros */
2258
49.7k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2259
486
    {
2260
        /* Infinity or NaN */
2261
486
        *decpt = 9999;
2262
486
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2263
486
            return nrv_alloc("Infinity", rve, 8);
2264
0
        return nrv_alloc("NaN", rve, 3);
2265
486
    }
2266
49.2k
    if (!dval(&u)) {
2267
5.70k
        *decpt = 1;
2268
5.70k
        return nrv_alloc("0", rve, 1);
2269
5.70k
    }
2270
2271
    /* compute k = floor(log10(d)).  The computation may leave k
2272
       one too large, but should never leave k too small. */
2273
43.5k
    b = d2b(&u, &be, &bbits);
2274
43.5k
    if (b == NULL)
2275
0
        goto failed_malloc;
2276
43.5k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2277
39.6k
        dval(&d2) = dval(&u);
2278
39.6k
        word0(&d2) &= Frac_mask1;
2279
39.6k
        word0(&d2) |= Exp_11;
2280
2281
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2282
         * log10(x)      =  log(x) / log(10)
2283
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2284
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2285
         *
2286
         * This suggests computing an approximation k to log10(d) by
2287
         *
2288
         * k = (i - Bias)*0.301029995663981
2289
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2290
         *
2291
         * We want k to be too large rather than too small.
2292
         * The error in the first-order Taylor series approximation
2293
         * is in our favor, so we just round up the constant enough
2294
         * to compensate for any error in the multiplication of
2295
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2296
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2297
         * adding 1e-13 to the constant term more than suffices.
2298
         * Hence we adjust the constant term to 0.1760912590558.
2299
         * (We could get a more accurate k by invoking log10,
2300
         *  but this is probably not worthwhile.)
2301
         */
2302
2303
39.6k
        i -= Bias;
2304
39.6k
        denorm = 0;
2305
39.6k
    }
2306
3.91k
    else {
2307
        /* d is denormalized */
2308
2309
3.91k
        i = bbits + be + (Bias + (P-1) - 1);
2310
3.91k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2311
3.91k
            : word1(&u) << (32 - i);
2312
3.91k
        dval(&d2) = x;
2313
3.91k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2314
3.91k
        i -= (Bias + (P-1) - 1) + 1;
2315
3.91k
        denorm = 1;
2316
3.91k
    }
2317
43.5k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2318
43.5k
        i*0.301029995663981;
2319
43.5k
    k = (int)ds;
2320
43.5k
    if (ds < 0. && ds != k)
2321
11.5k
        k--;    /* want k = floor(ds) */
2322
43.5k
    k_check = 1;
2323
43.5k
    if (k >= 0 && k <= Ten_pmax) {
2324
17.6k
        if (dval(&u) < tens[k])
2325
1.71k
            k--;
2326
17.6k
        k_check = 0;
2327
17.6k
    }
2328
43.5k
    j = bbits - i - 1;
2329
43.5k
    if (j >= 0) {
2330
17.0k
        b2 = 0;
2331
17.0k
        s2 = j;
2332
17.0k
    }
2333
26.4k
    else {
2334
26.4k
        b2 = -j;
2335
26.4k
        s2 = 0;
2336
26.4k
    }
2337
43.5k
    if (k >= 0) {
2338
31.4k
        b5 = 0;
2339
31.4k
        s5 = k;
2340
31.4k
        s2 += k;
2341
31.4k
    }
2342
12.0k
    else {
2343
12.0k
        b2 -= k;
2344
12.0k
        b5 = -k;
2345
12.0k
        s5 = 0;
2346
12.0k
    }
2347
43.5k
    if (mode < 0 || mode > 9)
2348
0
        mode = 0;
2349
2350
43.5k
    try_quick = 1;
2351
2352
43.5k
    if (mode > 5) {
2353
0
        mode -= 4;
2354
0
        try_quick = 0;
2355
0
    }
2356
43.5k
    leftright = 1;
2357
43.5k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2358
    /* silence erroneous "gcc -Wall" warning. */
2359
43.5k
    switch(mode) {
2360
43.4k
    case 0:
2361
43.4k
    case 1:
2362
43.4k
        i = 18;
2363
43.4k
        ndigits = 0;
2364
43.4k
        break;
2365
0
    case 2:
2366
0
        leftright = 0;
2367
0
        _Py_FALLTHROUGH;
2368
0
    case 4:
2369
0
        if (ndigits <= 0)
2370
0
            ndigits = 1;
2371
0
        ilim = ilim1 = i = ndigits;
2372
0
        break;
2373
109
    case 3:
2374
109
        leftright = 0;
2375
109
        _Py_FALLTHROUGH;
2376
109
    case 5:
2377
109
        i = ndigits + k + 1;
2378
109
        ilim = i;
2379
109
        ilim1 = i - 1;
2380
109
        if (i <= 0)
2381
0
            i = 1;
2382
43.5k
    }
2383
43.5k
    s0 = rv_alloc(i);
2384
43.5k
    if (s0 == NULL)
2385
0
        goto failed_malloc;
2386
43.5k
    s = s0;
2387
2388
2389
43.5k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2390
2391
        /* Try to get by with floating-point arithmetic. */
2392
2393
109
        i = 0;
2394
109
        dval(&d2) = dval(&u);
2395
109
        k0 = k;
2396
109
        ilim0 = ilim;
2397
109
        ieps = 2; /* conservative */
2398
109
        if (k > 0) {
2399
85
            ds = tens[k&0xf];
2400
85
            j = k >> 4;
2401
85
            if (j & Bletch) {
2402
                /* prevent overflows */
2403
0
                j &= Bletch - 1;
2404
0
                dval(&u) /= bigtens[n_bigtens-1];
2405
0
                ieps++;
2406
0
            }
2407
85
            for(; j; j >>= 1, i++)
2408
0
                if (j & 1) {
2409
0
                    ieps++;
2410
0
                    ds *= bigtens[i];
2411
0
                }
2412
85
            dval(&u) /= ds;
2413
85
        }
2414
24
        else if ((j1 = -k)) {
2415
0
            dval(&u) *= tens[j1 & 0xf];
2416
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2417
0
                if (j & 1) {
2418
0
                    ieps++;
2419
0
                    dval(&u) *= bigtens[i];
2420
0
                }
2421
0
        }
2422
109
        if (k_check && dval(&u) < 1. && ilim > 0) {
2423
0
            if (ilim1 <= 0)
2424
0
                goto fast_failed;
2425
0
            ilim = ilim1;
2426
0
            k--;
2427
0
            dval(&u) *= 10.;
2428
0
            ieps++;
2429
0
        }
2430
109
        dval(&eps) = ieps*dval(&u) + 7.;
2431
109
        word0(&eps) -= (P-1)*Exp_msk1;
2432
109
        if (ilim == 0) {
2433
0
            S = mhi = 0;
2434
0
            dval(&u) -= 5.;
2435
0
            if (dval(&u) > dval(&eps))
2436
0
                goto one_digit;
2437
0
            if (dval(&u) < -dval(&eps))
2438
0
                goto no_digits;
2439
0
            goto fast_failed;
2440
0
        }
2441
109
        if (leftright) {
2442
            /* Use Steele & White method of only
2443
             * generating digits needed.
2444
             */
2445
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2446
0
            for(i = 0;;) {
2447
0
                L = (Long)dval(&u);
2448
0
                dval(&u) -= L;
2449
0
                *s++ = '0' + (int)L;
2450
0
                if (dval(&u) < dval(&eps))
2451
0
                    goto ret1;
2452
0
                if (1. - dval(&u) < dval(&eps))
2453
0
                    goto bump_up;
2454
0
                if (++i >= ilim)
2455
0
                    break;
2456
0
                dval(&eps) *= 10.;
2457
0
                dval(&u) *= 10.;
2458
0
            }
2459
0
        }
2460
109
        else {
2461
            /* Generate ilim digits, then fix them up. */
2462
109
            dval(&eps) *= tens[ilim-1];
2463
295
            for(i = 1;; i++, dval(&u) *= 10.) {
2464
295
                L = (Long)(dval(&u));
2465
295
                if (!(dval(&u) -= L))
2466
16
                    ilim = i;
2467
295
                *s++ = '0' + (int)L;
2468
295
                if (i == ilim) {
2469
109
                    if (dval(&u) > 0.5 + dval(&eps))
2470
53
                        goto bump_up;
2471
56
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2472
61
                        while(*--s == '0');
2473
56
                        s++;
2474
56
                        goto ret1;
2475
56
                    }
2476
0
                    break;
2477
109
                }
2478
295
            }
2479
109
        }
2480
0
      fast_failed:
2481
0
        s = s0;
2482
0
        dval(&u) = dval(&d2);
2483
0
        k = k0;
2484
0
        ilim = ilim0;
2485
0
    }
2486
2487
    /* Do we have a "small" integer? */
2488
2489
43.4k
    if (be >= 0 && k <= Int_max) {
2490
        /* Yes. */
2491
10.7k
        ds = tens[k];
2492
10.7k
        if (ndigits < 0 && ilim <= 0) {
2493
0
            S = mhi = 0;
2494
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2495
0
                goto no_digits;
2496
0
            goto one_digit;
2497
0
        }
2498
15.2k
        for(i = 1;; i++, dval(&u) *= 10.) {
2499
15.2k
            L = (Long)(dval(&u) / ds);
2500
15.2k
            dval(&u) -= L*ds;
2501
15.2k
            *s++ = '0' + (int)L;
2502
15.2k
            if (!dval(&u)) {
2503
10.7k
                break;
2504
10.7k
            }
2505
4.46k
            if (i == ilim) {
2506
0
                dval(&u) += dval(&u);
2507
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2508
53
                  bump_up:
2509
56
                    while(*--s == '9')
2510
3
                        if (s == s0) {
2511
0
                            k++;
2512
0
                            *s = '0';
2513
0
                            break;
2514
0
                        }
2515
53
                    ++*s++;
2516
53
                }
2517
0
                else {
2518
                    /* Strip trailing zeros. This branch was missing from the
2519
                       original dtoa.c, leading to surplus trailing zeros in
2520
                       some cases. See bugs.python.org/issue40780. */
2521
0
                    while (s > s0 && s[-1] == '0') {
2522
0
                        --s;
2523
0
                    }
2524
0
                }
2525
53
                break;
2526
0
            }
2527
4.46k
        }
2528
10.8k
        goto ret1;
2529
10.7k
    }
2530
2531
32.6k
    m2 = b2;
2532
32.6k
    m5 = b5;
2533
32.6k
    if (leftright) {
2534
32.6k
        i =
2535
32.6k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2536
32.6k
            1 + P - bbits;
2537
32.6k
        b2 += i;
2538
32.6k
        s2 += i;
2539
32.6k
        mhi = i2b(1);
2540
32.6k
        if (mhi == NULL)
2541
0
            goto failed_malloc;
2542
32.6k
    }
2543
32.6k
    if (m2 > 0 && s2 > 0) {
2544
29.5k
        i = m2 < s2 ? m2 : s2;
2545
29.5k
        b2 -= i;
2546
29.5k
        m2 -= i;
2547
29.5k
        s2 -= i;
2548
29.5k
    }
2549
32.6k
    if (b5 > 0) {
2550
12.0k
        if (leftright) {
2551
12.0k
            if (m5 > 0) {
2552
12.0k
                mhi = pow5mult(mhi, m5);
2553
12.0k
                if (mhi == NULL)
2554
0
                    goto failed_malloc;
2555
12.0k
                b1 = mult(mhi, b);
2556
12.0k
                Bfree(b);
2557
12.0k
                b = b1;
2558
12.0k
                if (b == NULL)
2559
0
                    goto failed_malloc;
2560
12.0k
            }
2561
12.0k
            if ((j = b5 - m5)) {
2562
0
                b = pow5mult(b, j);
2563
0
                if (b == NULL)
2564
0
                    goto failed_malloc;
2565
0
            }
2566
12.0k
        }
2567
0
        else {
2568
0
            b = pow5mult(b, b5);
2569
0
            if (b == NULL)
2570
0
                goto failed_malloc;
2571
0
        }
2572
12.0k
    }
2573
32.6k
    S = i2b(1);
2574
32.6k
    if (S == NULL)
2575
0
        goto failed_malloc;
2576
32.6k
    if (s5 > 0) {
2577
18.8k
        S = pow5mult(S, s5);
2578
18.8k
        if (S == NULL)
2579
0
            goto failed_malloc;
2580
18.8k
    }
2581
2582
    /* Check for special case that d is a normalized power of 2. */
2583
2584
32.6k
    spec_case = 0;
2585
32.6k
    if ((mode < 2 || leftright)
2586
32.6k
        ) {
2587
32.6k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2588
1.22k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2589
32.6k
            ) {
2590
            /* The special case */
2591
939
            b2 += Log2P;
2592
939
            s2 += Log2P;
2593
939
            spec_case = 1;
2594
939
        }
2595
32.6k
    }
2596
2597
    /* Arrange for convenient computation of quotients:
2598
     * shift left if necessary so divisor has 4 leading 0 bits.
2599
     *
2600
     * Perhaps we should just compute leading 28 bits of S once
2601
     * and for all and pass them and a shift to quorem, so it
2602
     * can do shifts and ors to compute the numerator for q.
2603
     */
2604
32.6k
#define iInc 28
2605
32.6k
    i = dshift(S, s2);
2606
32.6k
    b2 += i;
2607
32.6k
    m2 += i;
2608
32.6k
    s2 += i;
2609
32.6k
    if (b2 > 0) {
2610
32.6k
        b = lshift(b, b2);
2611
32.6k
        if (b == NULL)
2612
0
            goto failed_malloc;
2613
32.6k
    }
2614
32.6k
    if (s2 > 0) {
2615
32.1k
        S = lshift(S, s2);
2616
32.1k
        if (S == NULL)
2617
0
            goto failed_malloc;
2618
32.1k
    }
2619
32.6k
    if (k_check) {
2620
25.8k
        if (cmp(b,S) < 0) {
2621
3.93k
            k--;
2622
3.93k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2623
3.93k
            if (b == NULL)
2624
0
                goto failed_malloc;
2625
3.93k
            if (leftright) {
2626
3.93k
                mhi = multadd(mhi, 10, 0);
2627
3.93k
                if (mhi == NULL)
2628
0
                    goto failed_malloc;
2629
3.93k
            }
2630
3.93k
            ilim = ilim1;
2631
3.93k
        }
2632
25.8k
    }
2633
32.6k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2634
0
        if (ilim < 0) {
2635
            /* no digits, fcvt style */
2636
0
          no_digits:
2637
0
            k = -1 - ndigits;
2638
0
            goto ret;
2639
0
        }
2640
0
        else {
2641
0
            S = multadd(S, 5, 0);
2642
0
            if (S == NULL)
2643
0
                goto failed_malloc;
2644
0
            if (cmp(b, S) <= 0)
2645
0
                goto no_digits;
2646
0
        }
2647
0
      one_digit:
2648
0
        *s++ = '1';
2649
0
        k++;
2650
0
        goto ret;
2651
0
    }
2652
32.6k
    if (leftright) {
2653
32.6k
        if (m2 > 0) {
2654
31.9k
            mhi = lshift(mhi, m2);
2655
31.9k
            if (mhi == NULL)
2656
0
                goto failed_malloc;
2657
31.9k
        }
2658
2659
        /* Compute mlo -- check for special case
2660
         * that d is a normalized power of 2.
2661
         */
2662
2663
32.6k
        mlo = mhi;
2664
32.6k
        if (spec_case) {
2665
939
            mhi = Balloc(mhi->k);
2666
939
            if (mhi == NULL)
2667
0
                goto failed_malloc;
2668
939
            Bcopy(mhi, mlo);
2669
939
            mhi = lshift(mhi, Log2P);
2670
939
            if (mhi == NULL)
2671
0
                goto failed_malloc;
2672
939
        }
2673
2674
122k
        for(i = 1;;i++) {
2675
122k
            dig = quorem(b,S) + '0';
2676
            /* Do we yet have the shortest decimal string
2677
             * that will round to d?
2678
             */
2679
122k
            j = cmp(b, mlo);
2680
122k
            delta = diff(S, mhi);
2681
122k
            if (delta == NULL)
2682
0
                goto failed_malloc;
2683
122k
            j1 = delta->sign ? 1 : cmp(b, delta);
2684
122k
            Bfree(delta);
2685
122k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2686
122k
                ) {
2687
1.58k
                if (dig == '9')
2688
232
                    goto round_9_up;
2689
1.35k
                if (j > 0)
2690
752
                    dig++;
2691
1.35k
                *s++ = dig;
2692
1.35k
                goto ret;
2693
1.58k
            }
2694
120k
            if (j < 0 || (j == 0 && mode != 1
2695
1.76k
                          && !(word1(&u) & 1)
2696
105k
                    )) {
2697
16.4k
                if (!b->x[0] && b->wds <= 1) {
2698
2.16k
                    goto accept_dig;
2699
2.16k
                }
2700
14.3k
                if (j1 > 0) {
2701
3.05k
                    b = lshift(b, 1);
2702
3.05k
                    if (b == NULL)
2703
0
                        goto failed_malloc;
2704
3.05k
                    j1 = cmp(b, S);
2705
3.05k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2706
1.65k
                        && dig++ == '9')
2707
235
                        goto round_9_up;
2708
3.05k
                }
2709
16.2k
              accept_dig:
2710
16.2k
                *s++ = dig;
2711
16.2k
                goto ret;
2712
14.3k
            }
2713
104k
            if (j1 > 0) {
2714
14.6k
                if (dig == '9') { /* possible if i == 1 */
2715
3.89k
                  round_9_up:
2716
3.89k
                    *s++ = '9';
2717
3.89k
                    goto roundoff;
2718
3.43k
                }
2719
11.1k
                *s++ = dig + 1;
2720
11.1k
                goto ret;
2721
14.6k
            }
2722
89.7k
            *s++ = dig;
2723
89.7k
            if (i == ilim)
2724
0
                break;
2725
89.7k
            b = multadd(b, 10, 0);
2726
89.7k
            if (b == NULL)
2727
0
                goto failed_malloc;
2728
89.7k
            if (mlo == mhi) {
2729
86.7k
                mlo = mhi = multadd(mhi, 10, 0);
2730
86.7k
                if (mlo == NULL)
2731
0
                    goto failed_malloc;
2732
86.7k
            }
2733
3.02k
            else {
2734
3.02k
                mlo = multadd(mlo, 10, 0);
2735
3.02k
                if (mlo == NULL)
2736
0
                    goto failed_malloc;
2737
3.02k
                mhi = multadd(mhi, 10, 0);
2738
3.02k
                if (mhi == NULL)
2739
0
                    goto failed_malloc;
2740
3.02k
            }
2741
89.7k
        }
2742
32.6k
    }
2743
0
    else
2744
0
        for(i = 1;; i++) {
2745
0
            *s++ = dig = quorem(b,S) + '0';
2746
0
            if (!b->x[0] && b->wds <= 1) {
2747
0
                goto ret;
2748
0
            }
2749
0
            if (i >= ilim)
2750
0
                break;
2751
0
            b = multadd(b, 10, 0);
2752
0
            if (b == NULL)
2753
0
                goto failed_malloc;
2754
0
        }
2755
2756
    /* Round off last digit */
2757
2758
0
    b = lshift(b, 1);
2759
0
    if (b == NULL)
2760
0
        goto failed_malloc;
2761
0
    j = cmp(b, S);
2762
0
    if (j > 0 || (j == 0 && dig & 1)) {
2763
3.89k
      roundoff:
2764
3.89k
        while(*--s == '9')
2765
3.89k
            if (s == s0) {
2766
3.89k
                k++;
2767
3.89k
                *s++ = '1';
2768
3.89k
                goto ret;
2769
3.89k
            }
2770
0
        ++*s++;
2771
0
    }
2772
0
    else {
2773
0
        while(*--s == '0');
2774
0
        s++;
2775
0
    }
2776
32.6k
  ret:
2777
32.6k
    Bfree(S);
2778
32.6k
    if (mhi) {
2779
32.6k
        if (mlo && mlo != mhi)
2780
939
            Bfree(mlo);
2781
32.6k
        Bfree(mhi);
2782
32.6k
    }
2783
43.5k
  ret1:
2784
43.5k
    Bfree(b);
2785
43.5k
    *s = 0;
2786
43.5k
    *decpt = k + 1;
2787
43.5k
    if (rve)
2788
43.5k
        *rve = s;
2789
43.5k
    return s0;
2790
0
  failed_malloc:
2791
0
    if (S)
2792
0
        Bfree(S);
2793
0
    if (mlo && mlo != mhi)
2794
0
        Bfree(mlo);
2795
0
    if (mhi)
2796
0
        Bfree(mhi);
2797
0
    if (b)
2798
0
        Bfree(b);
2799
0
    if (s0)
2800
0
        _Py_dg_freedtoa(s0);
2801
0
    return NULL;
2802
32.6k
}
2803
2804
#endif  // _PY_SHORT_FLOAT_REPR == 1
2805
2806
PyStatus
2807
_PyDtoa_Init(PyInterpreterState *interp)
2808
34
{
2809
34
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2810
34
    Bigint **p5s = interp->dtoa.p5s;
2811
2812
    // 5**4 = 625
2813
34
    Bigint *p5 = i2b(625);
2814
34
    if (p5 == NULL) {
2815
0
        return PyStatus_NoMemory();
2816
0
    }
2817
34
    p5s[0] = p5;
2818
2819
    // compute 5**8, 5**16, 5**32, ..., 5**512
2820
272
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2821
238
        p5 = mult(p5, p5);
2822
238
        if (p5 == NULL) {
2823
0
            return PyStatus_NoMemory();
2824
0
        }
2825
238
        p5s[i] = p5;
2826
238
    }
2827
2828
34
#endif
2829
34
    return PyStatus_Ok();
2830
34
}
2831
2832
void
2833
_PyDtoa_Fini(PyInterpreterState *interp)
2834
0
{
2835
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2836
0
    Bigint **p5s = interp->dtoa.p5s;
2837
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2838
0
        Bigint *p5 = p5s[i];
2839
        p5s[i] = NULL;
2840
0
        Bfree(p5);
2841
0
    }
2842
0
#endif
2843
0
}