Coverage Report

Created: 2026-03-23 06:45

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
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Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
57
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
143
#  define IEEE_MC68k
144
#endif
145
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
146
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
147
#endif
148
149
/* The code below assumes that the endianness of integers matches the
150
   endianness of the two 32-bit words of a double.  Check this. */
151
#if defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754)
152
#error "doubles and ints have incompatible endianness"
153
#endif
154
155
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
156
#error "doubles and ints have incompatible endianness"
157
#endif
158
159
160
typedef uint32_t ULong;
161
typedef int32_t Long;
162
typedef uint64_t ULLong;
163
164
#undef DEBUG
165
#ifdef Py_DEBUG
166
#define DEBUG
167
#endif
168
169
/* End Python #define linking */
170
171
#ifdef DEBUG
172
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
173
#endif
174
175
typedef union { double d; ULong L[2]; } U;
176
177
#ifdef IEEE_8087
178
5.31M
#define word0(x) (x)->L[1]
179
3.65M
#define word1(x) (x)->L[0]
180
#else
181
#define word0(x) (x)->L[0]
182
#define word1(x) (x)->L[1]
183
#endif
184
8.99M
#define dval(x) (x)->d
185
186
#ifndef STRTOD_DIGLIM
187
439k
#define STRTOD_DIGLIM 40
188
#endif
189
190
/* maximum permitted exponent value for strtod; exponents larger than
191
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
192
   should fit into an int. */
193
#ifndef MAX_ABS_EXP
194
1.00M
#define MAX_ABS_EXP 1100000000U
195
#endif
196
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
197
   this is used to bound the total number of digits ignoring leading zeros and
198
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
199
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
200
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
201
#ifndef MAX_DIGITS
202
3.24M
#define MAX_DIGITS 1000000000U
203
#endif
204
205
/* Guard against trying to use the above values on unusual platforms with ints
206
 * of width less than 32 bits. */
207
#if MAX_ABS_EXP > INT_MAX
208
#error "MAX_ABS_EXP should fit in an int"
209
#endif
210
#if MAX_DIGITS > INT_MAX
211
#error "MAX_DIGITS should fit in an int"
212
#endif
213
214
/* The following definition of Storeinc is appropriate for MIPS processors.
215
 * An alternative that might be better on some machines is
216
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
217
 */
218
#if defined(IEEE_8087)
219
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
220
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
221
#else
222
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
223
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
224
#endif
225
226
/* #define P DBL_MANT_DIG */
227
/* Ten_pmax = floor(P*log(2)/log(5)) */
228
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
229
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
230
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
231
232
572k
#define Exp_shift  20
233
92.6k
#define Exp_shift1 20
234
3.04M
#define Exp_msk1    0x100000
235
#define Exp_msk11   0x100000
236
2.51M
#define Exp_mask  0x7ff00000
237
2.07M
#define P 53
238
#define Nbits 53
239
1.16M
#define Bias 1023
240
#define Emax 1023
241
#define Emin (-1022)
242
1.10M
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
243
620k
#define Exp_1  0x3ff00000
244
42.5k
#define Exp_11 0x3ff00000
245
1.91M
#define Ebits 11
246
549k
#define Frac_mask  0xfffff
247
44.8k
#define Frac_mask1 0xfffff
248
1.92M
#define Ten_pmax 22
249
81
#define Bletch 0x10
250
173k
#define Bndry_mask  0xfffff
251
7.97k
#define Bndry_mask1 0xfffff
252
71.5k
#define Sign_bit 0x80000000
253
6.89k
#define Log2P 1
254
#define Tiny0 0
255
484k
#define Tiny1 1
256
46.4k
#define Quick_max 14
257
30.1k
#define Int_max 14
258
259
#ifndef Flt_Rounds
260
#ifdef FLT_ROUNDS
261
1.03M
#define Flt_Rounds FLT_ROUNDS
262
#else
263
#define Flt_Rounds 1
264
#endif
265
#endif /*Flt_Rounds*/
266
267
#define Rounding Flt_Rounds
268
269
3.64k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
270
2.30k
#define Big1 0xffffffff
271
272
/* Bits of the representation of positive infinity. */
273
274
#define POSINF_WORD0 0x7ff00000
275
#define POSINF_WORD1 0
276
277
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
278
279
typedef struct BCinfo BCinfo;
280
struct
281
BCinfo {
282
    int e0, nd, nd0, scale;
283
};
284
285
31.8M
#define FFFFFFFF 0xffffffffUL
286
287
/* struct Bigint is used to represent arbitrary-precision integers.  These
288
   integers are stored in sign-magnitude format, with the magnitude stored as
289
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
290
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
291
292
   The Bigint fields are as follows:
293
294
     - next is a header used by Balloc and Bfree to keep track of lists
295
         of freed Bigints;  it's also used for the linked list of
296
         powers of 5 of the form 5**2**i used by pow5mult.
297
     - k indicates which pool this Bigint was allocated from
298
     - maxwds is the maximum number of words space was allocated for
299
       (usually maxwds == 2**k)
300
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
301
       (ignored on inputs, set to 0 on outputs) in almost all operations
302
       involving Bigints: a notable exception is the diff function, which
303
       ignores signs on inputs but sets the sign of the output correctly.
304
     - wds is the actual number of significant words
305
     - x contains the vector of words (digits) for this Bigint, from least
306
       significant (x[0]) to most significant (x[wds-1]).
307
*/
308
309
// struct Bigint is defined in pycore_dtoa.h.
310
typedef struct Bigint Bigint;
311
312
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
313
314
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
315
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
316
   1 << k.  These pools are maintained as linked lists, with freelist[k]
317
   pointing to the head of the list for pool k.
318
319
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
320
   called to get more memory.  This memory is not returned to the system until
321
   Python quits.  There's also a private memory pool that's allocated from
322
   in preference to using MALLOC.
323
324
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
325
   decimal digits), memory is directly allocated using MALLOC, and freed using
326
   FREE.
327
328
   XXX: it would be easy to bypass this memory-management system and
329
   translate each call to Balloc into a call to PyMem_Malloc, and each
330
   Bfree to PyMem_Free.  Investigate whether this has any significant
331
   performance on impact. */
332
333
21.8M
#define freelist interp->dtoa.freelist
334
429
#define private_mem interp->dtoa.preallocated
335
1.17k
#define pmem_next interp->dtoa.preallocated_next
336
337
/* Allocate space for a Bigint with up to 1<<k digits */
338
339
static Bigint *
340
Balloc(int k)
341
5.45M
{
342
5.45M
    int x;
343
5.45M
    Bigint *rv;
344
5.45M
    unsigned int len;
345
5.45M
    PyInterpreterState *interp = _PyInterpreterState_GET();
346
347
5.45M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
348
5.45M
        freelist[k] = rv->next;
349
429
    else {
350
429
        x = 1 << k;
351
429
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
352
429
            /sizeof(double);
353
429
        if (k <= Bigint_Kmax &&
354
429
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
355
429
        ) {
356
372
            rv = (Bigint*)pmem_next;
357
372
            pmem_next += len;
358
372
        }
359
57
        else {
360
57
            rv = (Bigint*)MALLOC(len*sizeof(double));
361
57
            if (rv == NULL)
362
0
                return NULL;
363
57
        }
364
429
        rv->k = k;
365
429
        rv->maxwds = x;
366
429
    }
367
5.45M
    rv->sign = rv->wds = 0;
368
5.45M
    return rv;
369
5.45M
}
370
371
/* Free a Bigint allocated with Balloc */
372
373
static void
374
Bfree(Bigint *v)
375
8.92M
{
376
8.92M
    if (v) {
377
5.45M
        if (v->k > Bigint_Kmax)
378
0
            FREE((void*)v);
379
5.45M
        else {
380
5.45M
            PyInterpreterState *interp = _PyInterpreterState_GET();
381
5.45M
            v->next = freelist[v->k];
382
5.45M
            freelist[v->k] = v;
383
5.45M
        }
384
5.45M
    }
385
8.92M
}
386
387
#undef pmem_next
388
#undef private_mem
389
#undef freelist
390
391
#else
392
393
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
394
   PyMem_Free directly in place of the custom memory allocation scheme above.
395
   These are provided for the benefit of memory debugging tools like
396
   Valgrind. */
397
398
/* Allocate space for a Bigint with up to 1<<k digits */
399
400
static Bigint *
401
Balloc(int k)
402
{
403
    int x;
404
    Bigint *rv;
405
    unsigned int len;
406
407
    x = 1 << k;
408
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
409
        /sizeof(double);
410
411
    rv = (Bigint*)MALLOC(len*sizeof(double));
412
    if (rv == NULL)
413
        return NULL;
414
415
    rv->k = k;
416
    rv->maxwds = x;
417
    rv->sign = rv->wds = 0;
418
    return rv;
419
}
420
421
/* Free a Bigint allocated with Balloc */
422
423
static void
424
Bfree(Bigint *v)
425
{
426
    if (v) {
427
        FREE((void*)v);
428
    }
429
}
430
431
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
432
433
483k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
434
483k
                          y->wds*sizeof(Long) + 2*sizeof(int))
435
436
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
437
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
438
   On failure, return NULL.  In this case, b will have been already freed. */
439
440
static Bigint *
441
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
442
1.21M
{
443
1.21M
    int i, wds;
444
1.21M
    ULong *x;
445
1.21M
    ULLong carry, y;
446
1.21M
    Bigint *b1;
447
448
1.21M
    wds = b->wds;
449
1.21M
    x = b->x;
450
1.21M
    i = 0;
451
1.21M
    carry = a;
452
4.28M
    do {
453
4.28M
        y = *x * (ULLong)m + carry;
454
4.28M
        carry = y >> 32;
455
4.28M
        *x++ = (ULong)(y & FFFFFFFF);
456
4.28M
    }
457
4.28M
    while(++i < wds);
458
1.21M
    if (carry) {
459
73.2k
        if (wds >= b->maxwds) {
460
3.78k
            b1 = Balloc(b->k+1);
461
3.78k
            if (b1 == NULL){
462
0
                Bfree(b);
463
0
                return NULL;
464
0
            }
465
3.78k
            Bcopy(b1, b);
466
3.78k
            Bfree(b);
467
3.78k
            b = b1;
468
3.78k
        }
469
73.2k
        b->x[wds++] = (ULong)carry;
470
73.2k
        b->wds = wds;
471
73.2k
    }
472
1.21M
    return b;
473
1.21M
}
474
475
/* convert a string s containing nd decimal digits (possibly containing a
476
   decimal separator at position nd0, which is ignored) to a Bigint.  This
477
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
478
   entry, y9 contains the result of converting the first 9 digits.  Returns
479
   NULL on failure. */
480
481
static Bigint *
482
s2b(const char *s, int nd0, int nd, ULong y9)
483
439k
{
484
439k
    Bigint *b;
485
439k
    int i, k;
486
439k
    Long x, y;
487
488
439k
    x = (nd + 8) / 9;
489
495k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
490
439k
    b = Balloc(k);
491
439k
    if (b == NULL)
492
0
        return NULL;
493
439k
    b->x[0] = y9;
494
439k
    b->wds = 1;
495
496
439k
    if (nd <= 9)
497
395k
      return b;
498
499
44.2k
    s += 9;
500
330k
    for (i = 9; i < nd0; i++) {
501
285k
        b = multadd(b, 10, *s++ - '0');
502
285k
        if (b == NULL)
503
0
            return NULL;
504
285k
    }
505
44.2k
    s++;
506
158k
    for(; i < nd; i++) {
507
114k
        b = multadd(b, 10, *s++ - '0');
508
114k
        if (b == NULL)
509
0
            return NULL;
510
114k
    }
511
44.2k
    return b;
512
44.2k
}
513
514
/* count leading 0 bits in the 32-bit integer x. */
515
516
static int
517
hi0bits(ULong x)
518
662k
{
519
662k
    int k = 0;
520
521
662k
    if (!(x & 0xffff0000)) {
522
249k
        k = 16;
523
249k
        x <<= 16;
524
249k
    }
525
662k
    if (!(x & 0xff000000)) {
526
256k
        k += 8;
527
256k
        x <<= 8;
528
256k
    }
529
662k
    if (!(x & 0xf0000000)) {
530
470k
        k += 4;
531
470k
        x <<= 4;
532
470k
    }
533
662k
    if (!(x & 0xc0000000)) {
534
313k
        k += 2;
535
313k
        x <<= 2;
536
313k
    }
537
662k
    if (!(x & 0x80000000)) {
538
159k
        k++;
539
159k
        if (!(x & 0x40000000))
540
0
            return 32;
541
159k
    }
542
662k
    return k;
543
662k
}
544
545
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
546
   number of bits. */
547
548
static int
549
lo0bits(ULong *y)
550
46.3k
{
551
46.3k
    int k;
552
46.3k
    ULong x = *y;
553
554
46.3k
    if (x & 7) {
555
28.7k
        if (x & 1)
556
13.0k
            return 0;
557
15.6k
        if (x & 2) {
558
6.65k
            *y = x >> 1;
559
6.65k
            return 1;
560
6.65k
        }
561
8.99k
        *y = x >> 2;
562
8.99k
        return 2;
563
15.6k
    }
564
17.5k
    k = 0;
565
17.5k
    if (!(x & 0xffff)) {
566
6.62k
        k = 16;
567
6.62k
        x >>= 16;
568
6.62k
    }
569
17.5k
    if (!(x & 0xff)) {
570
3.34k
        k += 8;
571
3.34k
        x >>= 8;
572
3.34k
    }
573
17.5k
    if (!(x & 0xf)) {
574
8.91k
        k += 4;
575
8.91k
        x >>= 4;
576
8.91k
    }
577
17.5k
    if (!(x & 0x3)) {
578
9.77k
        k += 2;
579
9.77k
        x >>= 2;
580
9.77k
    }
581
17.5k
    if (!(x & 1)) {
582
12.5k
        k++;
583
12.5k
        x >>= 1;
584
12.5k
        if (!x)
585
0
            return 32;
586
12.5k
    }
587
17.5k
    *y = x;
588
17.5k
    return k;
589
17.5k
}
590
591
/* convert a small nonnegative integer to a Bigint */
592
593
static Bigint *
594
i2b(int i)
595
573k
{
596
573k
    Bigint *b;
597
598
573k
    b = Balloc(1);
599
573k
    if (b == NULL)
600
0
        return NULL;
601
573k
    b->x[0] = i;
602
573k
    b->wds = 1;
603
573k
    return b;
604
573k
}
605
606
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
607
   the signs of a and b. */
608
609
static Bigint *
610
mult(Bigint *a, Bigint *b)
611
1.61M
{
612
1.61M
    Bigint *c;
613
1.61M
    int k, wa, wb, wc;
614
1.61M
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
615
1.61M
    ULong y;
616
1.61M
    ULLong carry, z;
617
618
1.61M
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
619
6.42k
        c = Balloc(0);
620
6.42k
        if (c == NULL)
621
0
            return NULL;
622
6.42k
        c->wds = 1;
623
6.42k
        c->x[0] = 0;
624
6.42k
        return c;
625
6.42k
    }
626
627
1.60M
    if (a->wds < b->wds) {
628
878k
        c = a;
629
878k
        a = b;
630
878k
        b = c;
631
878k
    }
632
1.60M
    k = a->k;
633
1.60M
    wa = a->wds;
634
1.60M
    wb = b->wds;
635
1.60M
    wc = wa + wb;
636
1.60M
    if (wc > a->maxwds)
637
1.03M
        k++;
638
1.60M
    c = Balloc(k);
639
1.60M
    if (c == NULL)
640
0
        return NULL;
641
10.6M
    for(x = c->x, xa = x + wc; x < xa; x++)
642
8.99M
        *x = 0;
643
1.60M
    xa = a->x;
644
1.60M
    xae = xa + wa;
645
1.60M
    xb = b->x;
646
1.60M
    xbe = xb + wb;
647
1.60M
    xc0 = c->x;
648
4.74M
    for(; xb < xbe; xc0++) {
649
3.14M
        if ((y = *xb++)) {
650
3.13M
            x = xa;
651
3.13M
            xc = xc0;
652
3.13M
            carry = 0;
653
18.3M
            do {
654
18.3M
                z = *x++ * (ULLong)y + *xc + carry;
655
18.3M
                carry = z >> 32;
656
18.3M
                *xc++ = (ULong)(z & FFFFFFFF);
657
18.3M
            }
658
18.3M
            while(x < xae);
659
3.13M
            *xc = (ULong)carry;
660
3.13M
        }
661
3.14M
    }
662
2.69M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
663
1.60M
    c->wds = wc;
664
1.60M
    return c;
665
1.60M
}
666
667
#ifndef Py_USING_MEMORY_DEBUGGER
668
669
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
670
   failure; if the returned pointer is distinct from b then the original
671
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
672
673
static Bigint *
674
pow5mult(Bigint *b, int k)
675
525k
{
676
525k
    Bigint *b1, *p5, **p5s;
677
525k
    int i;
678
525k
    static const int p05[3] = { 5, 25, 125 };
679
680
    // For double-to-string conversion, the maximum value of k is limited by
681
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
682
    // For string-to-double conversion, the extreme case is constrained by our
683
    // hardcoded exponent limit before we underflow of -512, adjusted by
684
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
685
525k
    assert(0 <= k && k < 1024);
686
687
525k
    if ((i = k & 3)) {
688
174k
        b = multadd(b, p05[i-1], 0);
689
174k
        if (b == NULL)
690
0
            return NULL;
691
174k
    }
692
693
525k
    if (!(k >>= 2))
694
13.1k
        return b;
695
512k
    PyInterpreterState *interp = _PyInterpreterState_GET();
696
512k
    p5s = interp->dtoa.p5s;
697
2.37M
    for(;;) {
698
2.37M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
699
2.37M
        p5 = *p5s;
700
2.37M
        p5s++;
701
2.37M
        if (k & 1) {
702
1.53M
            b1 = mult(b, p5);
703
1.53M
            Bfree(b);
704
1.53M
            b = b1;
705
1.53M
            if (b == NULL)
706
0
                return NULL;
707
1.53M
        }
708
2.37M
        if (!(k >>= 1))
709
512k
            break;
710
2.37M
    }
711
512k
    return b;
712
512k
}
713
714
#else
715
716
/* Version of pow5mult that doesn't cache powers of 5. Provided for
717
   the benefit of memory debugging tools like Valgrind. */
718
719
static Bigint *
720
pow5mult(Bigint *b, int k)
721
{
722
    Bigint *b1, *p5, *p51;
723
    int i;
724
    static const int p05[3] = { 5, 25, 125 };
725
726
    if ((i = k & 3)) {
727
        b = multadd(b, p05[i-1], 0);
728
        if (b == NULL)
729
            return NULL;
730
    }
731
732
    if (!(k >>= 2))
733
        return b;
734
    p5 = i2b(625);
735
    if (p5 == NULL) {
736
        Bfree(b);
737
        return NULL;
738
    }
739
740
    for(;;) {
741
        if (k & 1) {
742
            b1 = mult(b, p5);
743
            Bfree(b);
744
            b = b1;
745
            if (b == NULL) {
746
                Bfree(p5);
747
                return NULL;
748
            }
749
        }
750
        if (!(k >>= 1))
751
            break;
752
        p51 = mult(p5, p5);
753
        Bfree(p5);
754
        p5 = p51;
755
        if (p5 == NULL) {
756
            Bfree(b);
757
            return NULL;
758
        }
759
    }
760
    Bfree(p5);
761
    return b;
762
}
763
764
#endif /* Py_USING_MEMORY_DEBUGGER */
765
766
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
767
   or NULL on failure.  If the returned pointer is distinct from b then the
768
   original b will have been Bfree'd.   Ignores the sign of b. */
769
770
static Bigint *
771
lshift(Bigint *b, int k)
772
1.13M
{
773
1.13M
    int i, k1, n, n1;
774
1.13M
    Bigint *b1;
775
1.13M
    ULong *x, *x1, *xe, z;
776
777
1.13M
    if (!k || (!b->x[0] && b->wds == 1))
778
6.95k
        return b;
779
780
1.12M
    n = k >> 5;
781
1.12M
    k1 = b->k;
782
1.12M
    n1 = n + b->wds + 1;
783
3.05M
    for(i = b->maxwds; n1 > i; i <<= 1)
784
1.92M
        k1++;
785
1.12M
    b1 = Balloc(k1);
786
1.12M
    if (b1 == NULL) {
787
0
        Bfree(b);
788
0
        return NULL;
789
0
    }
790
1.12M
    x1 = b1->x;
791
5.98M
    for(i = 0; i < n; i++)
792
4.85M
        *x1++ = 0;
793
1.12M
    x = b->x;
794
1.12M
    xe = x + b->wds;
795
1.12M
    if (k &= 0x1f) {
796
1.10M
        k1 = 32 - k;
797
1.10M
        z = 0;
798
2.96M
        do {
799
2.96M
            *x1++ = *x << k | z;
800
2.96M
            z = *x++ >> k1;
801
2.96M
        }
802
2.96M
        while(x < xe);
803
1.10M
        if ((*x1 = z))
804
295k
            ++n1;
805
1.10M
    }
806
22.4k
    else do
807
44.2k
             *x1++ = *x++;
808
44.2k
        while(x < xe);
809
1.12M
    b1->wds = n1 - 1;
810
1.12M
    Bfree(b);
811
1.12M
    return b1;
812
1.12M
}
813
814
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
815
   1 if a > b.  Ignores signs of a and b. */
816
817
static int
818
cmp(Bigint *a, Bigint *b)
819
1.97M
{
820
1.97M
    ULong *xa, *xa0, *xb, *xb0;
821
1.97M
    int i, j;
822
823
1.97M
    i = a->wds;
824
1.97M
    j = b->wds;
825
#ifdef DEBUG
826
    if (i > 1 && !a->x[i-1])
827
        Bug("cmp called with a->x[a->wds-1] == 0");
828
    if (j > 1 && !b->x[j-1])
829
        Bug("cmp called with b->x[b->wds-1] == 0");
830
#endif
831
1.97M
    if (i -= j)
832
202k
        return i;
833
1.77M
    xa0 = a->x;
834
1.77M
    xa = xa0 + j;
835
1.77M
    xb0 = b->x;
836
1.77M
    xb = xb0 + j;
837
2.60M
    for(;;) {
838
2.60M
        if (*--xa != *--xb)
839
1.75M
            return *xa < *xb ? -1 : 1;
840
845k
        if (xa <= xa0)
841
18.3k
            break;
842
845k
    }
843
18.3k
    return 0;
844
1.77M
}
845
846
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
847
   NULL on failure.  The signs of a and b are ignored, but the sign of the
848
   result is set appropriately. */
849
850
static Bigint *
851
diff(Bigint *a, Bigint *b)
852
617k
{
853
617k
    Bigint *c;
854
617k
    int i, wa, wb;
855
617k
    ULong *xa, *xae, *xb, *xbe, *xc;
856
617k
    ULLong borrow, y;
857
858
617k
    i = cmp(a,b);
859
617k
    if (!i) {
860
3.25k
        c = Balloc(0);
861
3.25k
        if (c == NULL)
862
0
            return NULL;
863
3.25k
        c->wds = 1;
864
3.25k
        c->x[0] = 0;
865
3.25k
        return c;
866
3.25k
    }
867
614k
    if (i < 0) {
868
87.3k
        c = a;
869
87.3k
        a = b;
870
87.3k
        b = c;
871
87.3k
        i = 1;
872
87.3k
    }
873
527k
    else
874
527k
        i = 0;
875
614k
    c = Balloc(a->k);
876
614k
    if (c == NULL)
877
0
        return NULL;
878
614k
    c->sign = i;
879
614k
    wa = a->wds;
880
614k
    xa = a->x;
881
614k
    xae = xa + wa;
882
614k
    wb = b->wds;
883
614k
    xb = b->x;
884
614k
    xbe = xb + wb;
885
614k
    xc = c->x;
886
614k
    borrow = 0;
887
4.44M
    do {
888
4.44M
        y = (ULLong)*xa++ - *xb++ - borrow;
889
4.44M
        borrow = y >> 32 & (ULong)1;
890
4.44M
        *xc++ = (ULong)(y & FFFFFFFF);
891
4.44M
    }
892
4.44M
    while(xb < xbe);
893
890k
    while(xa < xae) {
894
275k
        y = *xa++ - borrow;
895
275k
        borrow = y >> 32 & (ULong)1;
896
275k
        *xc++ = (ULong)(y & FFFFFFFF);
897
275k
    }
898
1.38M
    while(!*--xc)
899
767k
        wa--;
900
614k
    c->wds = wa;
901
614k
    return c;
902
614k
}
903
904
/* Given a positive normal double x, return the difference between x and the
905
   next double up.  Doesn't give correct results for subnormals. */
906
907
static double
908
ulp(U *x)
909
304k
{
910
304k
    Long L;
911
304k
    U u;
912
913
304k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
914
304k
    word0(&u) = L;
915
304k
    word1(&u) = 0;
916
304k
    return dval(&u);
917
304k
}
918
919
/* Convert a Bigint to a double plus an exponent */
920
921
static double
922
b2d(Bigint *a, int *e)
923
599k
{
924
599k
    ULong *xa, *xa0, w, y, z;
925
599k
    int k;
926
599k
    U d;
927
928
599k
    xa0 = a->x;
929
599k
    xa = xa0 + a->wds;
930
599k
    y = *--xa;
931
#ifdef DEBUG
932
    if (!y) Bug("zero y in b2d");
933
#endif
934
599k
    k = hi0bits(y);
935
599k
    *e = 32 - k;
936
599k
    if (k < Ebits) {
937
356k
        word0(&d) = Exp_1 | y >> (Ebits - k);
938
356k
        w = xa > xa0 ? *--xa : 0;
939
356k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
940
356k
        goto ret_d;
941
356k
    }
942
243k
    z = xa > xa0 ? *--xa : 0;
943
243k
    if (k -= Ebits) {
944
237k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
945
237k
        y = xa > xa0 ? *--xa : 0;
946
237k
        word1(&d) = z << k | y >> (32 - k);
947
237k
    }
948
5.33k
    else {
949
5.33k
        word0(&d) = Exp_1 | y;
950
5.33k
        word1(&d) = z;
951
5.33k
    }
952
599k
  ret_d:
953
599k
    return dval(&d);
954
243k
}
955
956
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
957
   except that it accepts the scale parameter used in _Py_dg_strtod (which
958
   should be either 0 or 2*P), and the normalization for the return value is
959
   different (see below).  On input, d should be finite and nonnegative, and d
960
   / 2**scale should be exactly representable as an IEEE 754 double.
961
962
   Returns a Bigint b and an integer e such that
963
964
     dval(d) / 2**scale = b * 2**e.
965
966
   Unlike d2b, b is not necessarily odd: b and e are normalized so
967
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
968
   and e == Etiny.  This applies equally to an input of 0.0: in that
969
   case the return values are b = 0 and e = Etiny.
970
971
   The above normalization ensures that for all possible inputs d,
972
   2**e gives ulp(d/2**scale).
973
974
   Returns NULL on failure.
975
*/
976
977
static Bigint *
978
sd2b(U *d, int scale, int *e)
979
502k
{
980
502k
    Bigint *b;
981
982
502k
    b = Balloc(1);
983
502k
    if (b == NULL)
984
0
        return NULL;
985
986
    /* First construct b and e assuming that scale == 0. */
987
502k
    b->wds = 2;
988
502k
    b->x[0] = word1(d);
989
502k
    b->x[1] = word0(d) & Frac_mask;
990
502k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
991
502k
    if (*e < Etiny)
992
6.95k
        *e = Etiny;
993
495k
    else
994
495k
        b->x[1] |= Exp_msk1;
995
996
    /* Now adjust for scale, provided that b != 0. */
997
502k
    if (scale && (b->x[0] || b->x[1])) {
998
32.9k
        *e -= scale;
999
32.9k
        if (*e < Etiny) {
1000
28.1k
            scale = Etiny - *e;
1001
28.1k
            *e = Etiny;
1002
            /* We can't shift more than P-1 bits without shifting out a 1. */
1003
28.1k
            assert(0 < scale && scale <= P - 1);
1004
28.1k
            if (scale >= 32) {
1005
                /* The bits shifted out should all be zero. */
1006
15.1k
                assert(b->x[0] == 0);
1007
15.1k
                b->x[0] = b->x[1];
1008
15.1k
                b->x[1] = 0;
1009
15.1k
                scale -= 32;
1010
15.1k
            }
1011
28.1k
            if (scale) {
1012
                /* The bits shifted out should all be zero. */
1013
26.2k
                assert(b->x[0] << (32 - scale) == 0);
1014
26.2k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1015
26.2k
                b->x[1] >>= scale;
1016
26.2k
            }
1017
28.1k
        }
1018
32.9k
    }
1019
    /* Ensure b is normalized. */
1020
502k
    if (!b->x[1])
1021
26.2k
        b->wds = 1;
1022
1023
502k
    return b;
1024
502k
}
1025
1026
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1027
1028
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1029
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1030
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1031
1032
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1033
 */
1034
1035
static Bigint *
1036
d2b(U *d, int *e, int *bits)
1037
46.3k
{
1038
46.3k
    Bigint *b;
1039
46.3k
    int de, k;
1040
46.3k
    ULong *x, y, z;
1041
46.3k
    int i;
1042
1043
46.3k
    b = Balloc(1);
1044
46.3k
    if (b == NULL)
1045
0
        return NULL;
1046
46.3k
    x = b->x;
1047
1048
46.3k
    z = word0(d) & Frac_mask;
1049
46.3k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1050
46.3k
    if ((de = (int)(word0(d) >> Exp_shift)))
1051
42.5k
        z |= Exp_msk1;
1052
46.3k
    if ((y = word1(d))) {
1053
35.2k
        if ((k = lo0bits(&y))) {
1054
22.9k
            x[0] = y | z << (32 - k);
1055
22.9k
            z >>= k;
1056
22.9k
        }
1057
12.2k
        else
1058
12.2k
            x[0] = y;
1059
35.2k
        i =
1060
35.2k
            b->wds = (x[1] = z) ? 2 : 1;
1061
35.2k
    }
1062
11.1k
    else {
1063
11.1k
        k = lo0bits(&z);
1064
11.1k
        x[0] = z;
1065
11.1k
        i =
1066
11.1k
            b->wds = 1;
1067
11.1k
        k += 32;
1068
11.1k
    }
1069
46.3k
    if (de) {
1070
42.5k
        *e = de - Bias - (P-1) + k;
1071
42.5k
        *bits = P - k;
1072
42.5k
    }
1073
3.75k
    else {
1074
3.75k
        *e = de - Bias - (P-1) + 1 + k;
1075
3.75k
        *bits = 32*i - hi0bits(x[i-1]);
1076
3.75k
    }
1077
46.3k
    return b;
1078
46.3k
}
1079
1080
/* Compute the ratio of two Bigints, as a double.  The result may have an
1081
   error of up to 2.5 ulps. */
1082
1083
static double
1084
ratio(Bigint *a, Bigint *b)
1085
299k
{
1086
299k
    U da, db;
1087
299k
    int k, ka, kb;
1088
1089
299k
    dval(&da) = b2d(a, &ka);
1090
299k
    dval(&db) = b2d(b, &kb);
1091
299k
    k = ka - kb + 32*(a->wds - b->wds);
1092
299k
    if (k > 0)
1093
45.4k
        word0(&da) += k*Exp_msk1;
1094
254k
    else {
1095
254k
        k = -k;
1096
254k
        word0(&db) += k*Exp_msk1;
1097
254k
    }
1098
299k
    return dval(&da) / dval(&db);
1099
299k
}
1100
1101
static const double
1102
tens[] = {
1103
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1104
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1105
    1e20, 1e21, 1e22
1106
};
1107
1108
static const double
1109
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1110
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1111
                                   9007199254740992.*9007199254740992.e-256
1112
                                   /* = 2^106 * 1e-256 */
1113
};
1114
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1115
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1116
35.1k
#define Scale_Bit 0x10
1117
40.7k
#define n_bigtens 5
1118
1119
#define ULbits 32
1120
#define kshift 5
1121
59.6k
#define kmask 31
1122
1123
1124
static int
1125
dshift(Bigint *b, int p2)
1126
59.6k
{
1127
59.6k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1128
59.6k
    if (p2 > 0)
1129
23.8k
        rv -= p2;
1130
59.6k
    return rv & kmask;
1131
59.6k
}
1132
1133
/* special case of Bigint division.  The quotient is always in the range 0 <=
1134
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1135
   bits (28--31) are zero and bit 27 is set. */
1136
1137
static int
1138
quorem(Bigint *b, Bigint *S)
1139
560k
{
1140
560k
    int n;
1141
560k
    ULong *bx, *bxe, q, *sx, *sxe;
1142
560k
    ULLong borrow, carry, y, ys;
1143
1144
560k
    n = S->wds;
1145
#ifdef DEBUG
1146
    /*debug*/ if (b->wds > n)
1147
        /*debug*/       Bug("oversize b in quorem");
1148
#endif
1149
560k
    if (b->wds < n)
1150
15.0k
        return 0;
1151
545k
    sx = S->x;
1152
545k
    sxe = sx + --n;
1153
545k
    bx = b->x;
1154
545k
    bxe = bx + n;
1155
545k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1156
#ifdef DEBUG
1157
    /*debug*/ if (q > 9)
1158
        /*debug*/       Bug("oversized quotient in quorem");
1159
#endif
1160
545k
    if (q) {
1161
374k
        borrow = 0;
1162
374k
        carry = 0;
1163
2.05M
        do {
1164
2.05M
            ys = *sx++ * (ULLong)q + carry;
1165
2.05M
            carry = ys >> 32;
1166
2.05M
            y = *bx - (ys & FFFFFFFF) - borrow;
1167
2.05M
            borrow = y >> 32 & (ULong)1;
1168
2.05M
            *bx++ = (ULong)(y & FFFFFFFF);
1169
2.05M
        }
1170
2.05M
        while(sx <= sxe);
1171
374k
        if (!*bxe) {
1172
2.07k
            bx = b->x;
1173
2.07k
            while(--bxe > bx && !*bxe)
1174
0
                --n;
1175
2.07k
            b->wds = n;
1176
2.07k
        }
1177
374k
    }
1178
545k
    if (cmp(b, S) >= 0) {
1179
30.1k
        q++;
1180
30.1k
        borrow = 0;
1181
30.1k
        carry = 0;
1182
30.1k
        bx = b->x;
1183
30.1k
        sx = S->x;
1184
174k
        do {
1185
174k
            ys = *sx++ + carry;
1186
174k
            carry = ys >> 32;
1187
174k
            y = *bx - (ys & FFFFFFFF) - borrow;
1188
174k
            borrow = y >> 32 & (ULong)1;
1189
174k
            *bx++ = (ULong)(y & FFFFFFFF);
1190
174k
        }
1191
174k
        while(sx <= sxe);
1192
30.1k
        bx = b->x;
1193
30.1k
        bxe = bx + n;
1194
30.1k
        if (!*bxe) {
1195
21.8k
            while(--bxe > bx && !*bxe)
1196
1.62k
                --n;
1197
20.2k
            b->wds = n;
1198
20.2k
        }
1199
30.1k
    }
1200
545k
    return q;
1201
560k
}
1202
1203
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1204
1205
   Assuming that x is finite and nonnegative (positive zero is fine
1206
   here) and x / 2^bc.scale is exactly representable as a double,
1207
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1208
1209
static double
1210
sulp(U *x, BCinfo *bc)
1211
4.75k
{
1212
4.75k
    U u;
1213
1214
4.75k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1215
        /* rv/2^bc->scale is subnormal */
1216
428
        word0(&u) = (P+2)*Exp_msk1;
1217
428
        word1(&u) = 0;
1218
428
        return u.d;
1219
428
    }
1220
4.32k
    else {
1221
4.32k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1222
4.32k
        return ulp(x);
1223
4.32k
    }
1224
4.75k
}
1225
1226
/* The bigcomp function handles some hard cases for strtod, for inputs
1227
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1228
   estimate for the double corresponding to the input string has
1229
   already been obtained by the code in _Py_dg_strtod.
1230
1231
   The bigcomp function is only called after _Py_dg_strtod has found a
1232
   double value rv such that either rv or rv + 1ulp represents the
1233
   correctly rounded value corresponding to the original string.  It
1234
   determines which of these two values is the correct one by
1235
   computing the decimal digits of rv + 0.5ulp and comparing them with
1236
   the corresponding digits of s0.
1237
1238
   In the following, write dv for the absolute value of the number represented
1239
   by the input string.
1240
1241
   Inputs:
1242
1243
     s0 points to the first significant digit of the input string.
1244
1245
     rv is a (possibly scaled) estimate for the closest double value to the
1246
        value represented by the original input to _Py_dg_strtod.  If
1247
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1248
        the input value.
1249
1250
     bc is a struct containing information gathered during the parsing and
1251
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1252
1253
        bc->e0 gives the exponent of the input value, such that dv = (integer
1254
           given by the bd->nd digits of s0) * 10**e0
1255
1256
        bc->nd gives the total number of significant digits of s0.  It will
1257
           be at least 1.
1258
1259
        bc->nd0 gives the number of significant digits of s0 before the
1260
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1261
           bc->nd.
1262
1263
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1264
           subnormal values.  It's either 0 or 2*P (=106).
1265
1266
   Outputs:
1267
1268
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1269
1270
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1271
1272
static int
1273
bigcomp(U *rv, const char *s0, BCinfo *bc)
1274
24.3k
{
1275
24.3k
    Bigint *b, *d;
1276
24.3k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1277
1278
24.3k
    nd = bc->nd;
1279
24.3k
    nd0 = bc->nd0;
1280
24.3k
    p5 = nd + bc->e0;
1281
24.3k
    b = sd2b(rv, bc->scale, &p2);
1282
24.3k
    if (b == NULL)
1283
0
        return -1;
1284
1285
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1286
       case, this is used for round to even. */
1287
24.3k
    odd = b->x[0] & 1;
1288
1289
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1290
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1291
24.3k
    b = lshift(b, 1);
1292
24.3k
    if (b == NULL)
1293
0
        return -1;
1294
24.3k
    b->x[0] |= 1;
1295
24.3k
    p2--;
1296
1297
24.3k
    p2 -= p5;
1298
24.3k
    d = i2b(1);
1299
24.3k
    if (d == NULL) {
1300
0
        Bfree(b);
1301
0
        return -1;
1302
0
    }
1303
    /* Arrange for convenient computation of quotients:
1304
     * shift left if necessary so divisor has 4 leading 0 bits.
1305
     */
1306
24.3k
    if (p5 > 0) {
1307
21.6k
        d = pow5mult(d, p5);
1308
21.6k
        if (d == NULL) {
1309
0
            Bfree(b);
1310
0
            return -1;
1311
0
        }
1312
21.6k
    }
1313
2.76k
    else if (p5 < 0) {
1314
1.80k
        b = pow5mult(b, -p5);
1315
1.80k
        if (b == NULL) {
1316
0
            Bfree(d);
1317
0
            return -1;
1318
0
        }
1319
1.80k
    }
1320
24.3k
    if (p2 > 0) {
1321
19.5k
        b2 = p2;
1322
19.5k
        d2 = 0;
1323
19.5k
    }
1324
4.83k
    else {
1325
4.83k
        b2 = 0;
1326
4.83k
        d2 = -p2;
1327
4.83k
    }
1328
24.3k
    i = dshift(d, d2);
1329
24.3k
    if ((b2 += i) > 0) {
1330
23.9k
        b = lshift(b, b2);
1331
23.9k
        if (b == NULL) {
1332
0
            Bfree(d);
1333
0
            return -1;
1334
0
        }
1335
23.9k
    }
1336
24.3k
    if ((d2 += i) > 0) {
1337
23.1k
        d = lshift(d, d2);
1338
23.1k
        if (d == NULL) {
1339
0
            Bfree(b);
1340
0
            return -1;
1341
0
        }
1342
23.1k
    }
1343
1344
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1345
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1346
     * a number in the range [0.1, 1). */
1347
24.3k
    if (cmp(b, d) >= 0)
1348
        /* b/d >= 1 */
1349
870
        dd = -1;
1350
23.5k
    else {
1351
23.5k
        i = 0;
1352
421k
        for(;;) {
1353
421k
            b = multadd(b, 10, 0);
1354
421k
            if (b == NULL) {
1355
0
                Bfree(d);
1356
0
                return -1;
1357
0
            }
1358
421k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1359
421k
            i++;
1360
1361
421k
            if (dd)
1362
21.6k
                break;
1363
399k
            if (!b->x[0] && b->wds == 1) {
1364
                /* b/d == 0 */
1365
1.12k
                dd = i < nd;
1366
1.12k
                break;
1367
1.12k
            }
1368
398k
            if (!(i < nd)) {
1369
                /* b/d != 0, but digits of s0 exhausted */
1370
783
                dd = -1;
1371
783
                break;
1372
783
            }
1373
398k
        }
1374
23.5k
    }
1375
24.3k
    Bfree(b);
1376
24.3k
    Bfree(d);
1377
24.3k
    if (dd > 0 || (dd == 0 && odd))
1378
2.82k
        dval(rv) += sulp(rv, bc);
1379
24.3k
    return 0;
1380
24.3k
}
1381
1382
1383
double
1384
_Py_dg_strtod(const char *s00, char **se)
1385
1.13M
{
1386
1.13M
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1387
1.13M
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1388
1.13M
    const char *s, *s0, *s1;
1389
1.13M
    double aadj, aadj1;
1390
1.13M
    U aadj2, adj, rv, rv0;
1391
1.13M
    ULong y, z, abs_exp;
1392
1.13M
    Long L;
1393
1.13M
    BCinfo bc;
1394
1.13M
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1395
1.13M
    size_t ndigits, fraclen;
1396
1.13M
    double result;
1397
1398
1.13M
    dval(&rv) = 0.;
1399
1400
    /* Start parsing. */
1401
1.13M
    c = *(s = s00);
1402
1403
    /* Parse optional sign, if present. */
1404
1.13M
    sign = 0;
1405
1.13M
    switch (c) {
1406
520k
    case '-':
1407
520k
        sign = 1;
1408
520k
        _Py_FALLTHROUGH;
1409
520k
    case '+':
1410
520k
        c = *++s;
1411
1.13M
    }
1412
1413
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1414
1.13M
    s1 = s;
1415
1.16M
    while (c == '0')
1416
28.6k
        c = *++s;
1417
1.13M
    lz = s != s1;
1418
1419
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1420
       number of digits between the decimal point and the end of the
1421
       digit string.  ndigits will be the total number of digits ignoring
1422
       leading zeros. */
1423
1.13M
    s0 = s1 = s;
1424
6.84M
    while ('0' <= c && c <= '9')
1425
5.70M
        c = *++s;
1426
1.13M
    ndigits = s - s1;
1427
1.13M
    fraclen = 0;
1428
1429
    /* Parse decimal point and following digits. */
1430
1.13M
    if (c == '.') {
1431
84.2k
        c = *++s;
1432
84.2k
        if (!ndigits) {
1433
30.6k
            s1 = s;
1434
110k
            while (c == '0')
1435
80.1k
                c = *++s;
1436
30.6k
            lz = lz || s != s1;
1437
30.6k
            fraclen += (s - s1);
1438
30.6k
            s0 = s;
1439
30.6k
        }
1440
84.2k
        s1 = s;
1441
31.1M
        while ('0' <= c && c <= '9')
1442
31.0M
            c = *++s;
1443
84.2k
        ndigits += s - s1;
1444
84.2k
        fraclen += s - s1;
1445
84.2k
    }
1446
1447
    /* Now lz is true if and only if there were leading zero digits, and
1448
       ndigits gives the total number of digits ignoring leading zeros.  A
1449
       valid input must have at least one digit. */
1450
1.13M
    if (!ndigits && !lz) {
1451
49.2k
        if (se)
1452
49.2k
            *se = (char *)s00;
1453
49.2k
        goto parse_error;
1454
49.2k
    }
1455
1456
    /* Range check ndigits and fraclen to make sure that they, and values
1457
       computed with them, can safely fit in an int. */
1458
1.08M
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1459
0
        if (se)
1460
0
            *se = (char *)s00;
1461
0
        goto parse_error;
1462
0
    }
1463
1.08M
    nd = (int)ndigits;
1464
1.08M
    nd0 = (int)ndigits - (int)fraclen;
1465
1466
    /* Parse exponent. */
1467
1.08M
    e = 0;
1468
1.08M
    if (c == 'e' || c == 'E') {
1469
1.00M
        s00 = s;
1470
1.00M
        c = *++s;
1471
1472
        /* Exponent sign. */
1473
1.00M
        esign = 0;
1474
1.00M
        switch (c) {
1475
41.8k
        case '-':
1476
41.8k
            esign = 1;
1477
41.8k
            _Py_FALLTHROUGH;
1478
59.9k
        case '+':
1479
59.9k
            c = *++s;
1480
1.00M
        }
1481
1482
        /* Skip zeros.  lz is true iff there are leading zeros. */
1483
1.00M
        s1 = s;
1484
1.24M
        while (c == '0')
1485
238k
            c = *++s;
1486
1.00M
        lz = s != s1;
1487
1488
        /* Get absolute value of the exponent. */
1489
1.00M
        s1 = s;
1490
1.00M
        abs_exp = 0;
1491
14.2M
        while ('0' <= c && c <= '9') {
1492
13.2M
            abs_exp = 10*abs_exp + (c - '0');
1493
13.2M
            c = *++s;
1494
13.2M
        }
1495
1496
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1497
           there are at most 9 significant exponent digits then overflow is
1498
           impossible. */
1499
1.00M
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1500
10.5k
            e = (int)MAX_ABS_EXP;
1501
992k
        else
1502
992k
            e = (int)abs_exp;
1503
1.00M
        if (esign)
1504
41.8k
            e = -e;
1505
1506
        /* A valid exponent must have at least one digit. */
1507
1.00M
        if (s == s1 && !lz)
1508
0
            s = s00;
1509
1.00M
    }
1510
1511
    /* Adjust exponent to take into account position of the point. */
1512
1.08M
    e -= nd - nd0;
1513
1.08M
    if (nd0 <= 0)
1514
35.9k
        nd0 = nd;
1515
1516
    /* Finished parsing.  Set se to indicate how far we parsed */
1517
1.08M
    if (se)
1518
1.08M
        *se = (char *)s;
1519
1520
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1521
       strip trailing zeros: scan back until we hit a nonzero digit. */
1522
1.08M
    if (!nd)
1523
16.0k
        goto ret;
1524
8.82M
    for (i = nd; i > 0; ) {
1525
8.82M
        --i;
1526
8.82M
        if (s0[i < nd0 ? i : i+1] != '0') {
1527
1.06M
            ++i;
1528
1.06M
            break;
1529
1.06M
        }
1530
8.82M
    }
1531
1.06M
    e += nd - i;
1532
1.06M
    nd = i;
1533
1.06M
    if (nd0 > nd)
1534
22.7k
        nd0 = nd;
1535
1536
    /* Summary of parsing results.  After parsing, and dealing with zero
1537
     * inputs, we have values s0, nd0, nd, e, sign, where:
1538
     *
1539
     *  - s0 points to the first significant digit of the input string
1540
     *
1541
     *  - nd is the total number of significant digits (here, and
1542
     *    below, 'significant digits' means the set of digits of the
1543
     *    significand of the input that remain after ignoring leading
1544
     *    and trailing zeros).
1545
     *
1546
     *  - nd0 indicates the position of the decimal point, if present; it
1547
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1548
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1549
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1550
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1551
     *
1552
     *  - e is the adjusted exponent: the absolute value of the number
1553
     *    represented by the original input string is n * 10**e, where
1554
     *    n is the integer represented by the concatenation of
1555
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1556
     *
1557
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1558
     *
1559
     *  - the first and last significant digits are nonzero
1560
     */
1561
1562
    /* put first DBL_DIG+1 digits into integer y and z.
1563
     *
1564
     *  - y contains the value represented by the first min(9, nd)
1565
     *    significant digits
1566
     *
1567
     *  - if nd > 9, z contains the value represented by significant digits
1568
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1569
     *    gives the value represented by the first min(16, nd) sig. digits.
1570
     */
1571
1572
1.06M
    bc.e0 = e1 = e;
1573
1.06M
    y = z = 0;
1574
4.39M
    for (i = 0; i < nd; i++) {
1575
3.38M
        if (i < 9)
1576
2.88M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1577
496k
        else if (i < DBL_DIG+1)
1578
445k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1579
50.4k
        else
1580
50.4k
            break;
1581
3.38M
    }
1582
1583
1.06M
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1584
1.06M
    dval(&rv) = y;
1585
1.06M
    if (k > 9) {
1586
77.1k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1587
77.1k
    }
1588
1.06M
    if (nd <= DBL_DIG
1589
1.00M
        && Flt_Rounds == 1
1590
1.06M
        ) {
1591
1.00M
        if (!e)
1592
13.3k
            goto ret;
1593
995k
        if (e > 0) {
1594
933k
            if (e <= Ten_pmax) {
1595
35.1k
                dval(&rv) *= tens[e];
1596
35.1k
                goto ret;
1597
35.1k
            }
1598
898k
            i = DBL_DIG - nd;
1599
898k
            if (e <= Ten_pmax + i) {
1600
                /* A fancier test would sometimes let us do
1601
                 * this for larger i values.
1602
                 */
1603
3.11k
                e -= i;
1604
3.11k
                dval(&rv) *= tens[i];
1605
3.11k
                dval(&rv) *= tens[e];
1606
3.11k
                goto ret;
1607
3.11k
            }
1608
898k
        }
1609
61.7k
        else if (e >= -Ten_pmax) {
1610
28.5k
            dval(&rv) /= tens[-e];
1611
28.5k
            goto ret;
1612
28.5k
        }
1613
995k
    }
1614
986k
    e1 += nd - k;
1615
1616
986k
    bc.scale = 0;
1617
1618
    /* Get starting approximation = rv * 10**e1 */
1619
1620
986k
    if (e1 > 0) {
1621
932k
        if ((i = e1 & 15))
1622
804k
            dval(&rv) *= tens[i];
1623
932k
        if (e1 &= ~15) {
1624
921k
            if (e1 > DBL_MAX_10_EXP)
1625
539k
                goto ovfl;
1626
381k
            e1 >>= 4;
1627
981k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1628
599k
                if (e1 & 1)
1629
327k
                    dval(&rv) *= bigtens[j];
1630
            /* The last multiplication could overflow. */
1631
381k
            word0(&rv) -= P*Exp_msk1;
1632
381k
            dval(&rv) *= bigtens[j];
1633
381k
            if ((z = word0(&rv) & Exp_mask)
1634
381k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1635
2.18k
                goto ovfl;
1636
379k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1637
                /* set to largest number */
1638
                /* (Can't trust DBL_MAX) */
1639
569
                word0(&rv) = Big0;
1640
569
                word1(&rv) = Big1;
1641
569
            }
1642
379k
            else
1643
379k
                word0(&rv) += P*Exp_msk1;
1644
379k
        }
1645
932k
    }
1646
54.7k
    else if (e1 < 0) {
1647
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1648
1649
           If e1 <= -512, underflow immediately.
1650
           If e1 <= -256, set bc.scale to 2*P.
1651
1652
           So for input value < 1e-256, bc.scale is always set;
1653
           for input value >= 1e-240, bc.scale is never set.
1654
           For input values in [1e-256, 1e-240), bc.scale may or may
1655
           not be set. */
1656
1657
51.0k
        e1 = -e1;
1658
51.0k
        if ((i = e1 & 15))
1659
40.7k
            dval(&rv) /= tens[i];
1660
51.0k
        if (e1 >>= 4) {
1661
40.7k
            if (e1 >= 1 << n_bigtens)
1662
5.62k
                goto undfl;
1663
35.1k
            if (e1 & Scale_Bit)
1664
21.2k
                bc.scale = 2*P;
1665
171k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1666
136k
                if (e1 & 1)
1667
81.2k
                    dval(&rv) *= tinytens[j];
1668
35.1k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1669
21.2k
                                            >> Exp_shift)) > 0) {
1670
                /* scaled rv is denormal; clear j low bits */
1671
19.0k
                if (j >= 32) {
1672
12.0k
                    word1(&rv) = 0;
1673
12.0k
                    if (j >= 53)
1674
6.99k
                        word0(&rv) = (P+2)*Exp_msk1;
1675
5.01k
                    else
1676
5.01k
                        word0(&rv) &= 0xffffffff << (j-32);
1677
12.0k
                }
1678
7.05k
                else
1679
7.05k
                    word1(&rv) &= 0xffffffff << j;
1680
19.0k
            }
1681
35.1k
            if (!dval(&rv))
1682
0
                goto undfl;
1683
35.1k
        }
1684
51.0k
    }
1685
1686
    /* Now the hard part -- adjusting rv to the correct value.*/
1687
1688
    /* Put digits into bd: true value = bd * 10^e */
1689
1690
439k
    bc.nd = nd;
1691
439k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1692
                        /* to silence an erroneous warning about bc.nd0 */
1693
                        /* possibly not being initialized. */
1694
439k
    if (nd > STRTOD_DIGLIM) {
1695
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1696
        /* minimum number of decimal digits to distinguish double values */
1697
        /* in IEEE arithmetic. */
1698
1699
        /* Truncate input to 18 significant digits, then discard any trailing
1700
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1701
           no need to update z; it's not reused beyond this point.) */
1702
255k
        for (i = 18; i > 0; ) {
1703
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1704
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1705
255k
            --i;
1706
255k
            if (s0[i < nd0 ? i : i+1] != '0') {
1707
30.7k
                ++i;
1708
30.7k
                break;
1709
30.7k
            }
1710
255k
        }
1711
30.7k
        e += nd - i;
1712
30.7k
        nd = i;
1713
30.7k
        if (nd0 > nd)
1714
25.8k
            nd0 = nd;
1715
30.7k
        if (nd < 9) { /* must recompute y */
1716
19.5k
            y = 0;
1717
147k
            for(i = 0; i < nd0; ++i)
1718
128k
                y = 10*y + s0[i] - '0';
1719
29.0k
            for(; i < nd; ++i)
1720
9.47k
                y = 10*y + s0[i+1] - '0';
1721
19.5k
        }
1722
30.7k
    }
1723
439k
    bd0 = s2b(s0, nd0, nd, y);
1724
439k
    if (bd0 == NULL)
1725
0
        goto failed_malloc;
1726
1727
    /* Notation for the comments below.  Write:
1728
1729
         - dv for the absolute value of the number represented by the original
1730
           decimal input string.
1731
1732
         - if we've truncated dv, write tdv for the truncated value.
1733
           Otherwise, set tdv == dv.
1734
1735
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1736
           approximation to tdv (and dv).  It should be exactly representable
1737
           in an IEEE 754 double.
1738
    */
1739
1740
478k
    for(;;) {
1741
1742
        /* This is the main correction loop for _Py_dg_strtod.
1743
1744
           We've got a decimal value tdv, and a floating-point approximation
1745
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1746
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1747
           approximation if not.
1748
1749
           To determine whether srv is close enough to tdv, compute integers
1750
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1751
           respectively, and then use integer arithmetic to determine whether
1752
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1753
        */
1754
1755
478k
        bd = Balloc(bd0->k);
1756
478k
        if (bd == NULL) {
1757
0
            goto failed_malloc;
1758
0
        }
1759
478k
        Bcopy(bd, bd0);
1760
478k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1761
478k
        if (bb == NULL) {
1762
0
            goto failed_malloc;
1763
0
        }
1764
        /* Record whether lsb of bb is odd, in case we need this
1765
           for the round-to-even step later. */
1766
478k
        odd = bb->x[0] & 1;
1767
1768
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1769
478k
        bs = i2b(1);
1770
478k
        if (bs == NULL) {
1771
0
            goto failed_malloc;
1772
0
        }
1773
1774
478k
        if (e >= 0) {
1775
411k
            bb2 = bb5 = 0;
1776
411k
            bd2 = bd5 = e;
1777
411k
        }
1778
67.3k
        else {
1779
67.3k
            bb2 = bb5 = -e;
1780
67.3k
            bd2 = bd5 = 0;
1781
67.3k
        }
1782
478k
        if (bbe >= 0)
1783
412k
            bb2 += bbe;
1784
65.8k
        else
1785
65.8k
            bd2 -= bbe;
1786
478k
        bs2 = bb2;
1787
478k
        bb2++;
1788
478k
        bd2++;
1789
1790
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1791
           and bs == 1, so:
1792
1793
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1794
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1795
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1796
1797
           It follows that:
1798
1799
              M * tdv = bd * 2**bd2 * 5**bd5
1800
              M * srv = bb * 2**bb2 * 5**bb5
1801
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1802
1803
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1804
           this fact is not needed below.)
1805
        */
1806
1807
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1808
478k
        i = bb2 < bd2 ? bb2 : bd2;
1809
478k
        if (i > bs2)
1810
64.6k
            i = bs2;
1811
478k
        if (i > 0) {
1812
477k
            bb2 -= i;
1813
477k
            bd2 -= i;
1814
477k
            bs2 -= i;
1815
477k
        }
1816
1817
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1818
478k
        if (bb5 > 0) {
1819
67.3k
            bs = pow5mult(bs, bb5);
1820
67.3k
            if (bs == NULL) {
1821
0
                goto failed_malloc;
1822
0
            }
1823
67.3k
            Bigint *bb1 = mult(bs, bb);
1824
67.3k
            Bfree(bb);
1825
67.3k
            bb = bb1;
1826
67.3k
            if (bb == NULL) {
1827
0
                goto failed_malloc;
1828
0
            }
1829
67.3k
        }
1830
478k
        if (bb2 > 0) {
1831
478k
            bb = lshift(bb, bb2);
1832
478k
            if (bb == NULL) {
1833
0
                goto failed_malloc;
1834
0
            }
1835
478k
        }
1836
478k
        if (bd5 > 0) {
1837
401k
            bd = pow5mult(bd, bd5);
1838
401k
            if (bd == NULL) {
1839
0
                goto failed_malloc;
1840
0
            }
1841
401k
        }
1842
478k
        if (bd2 > 0) {
1843
64.6k
            bd = lshift(bd, bd2);
1844
64.6k
            if (bd == NULL) {
1845
0
                goto failed_malloc;
1846
0
            }
1847
64.6k
        }
1848
478k
        if (bs2 > 0) {
1849
408k
            bs = lshift(bs, bs2);
1850
408k
            if (bs == NULL) {
1851
0
                goto failed_malloc;
1852
0
            }
1853
408k
        }
1854
1855
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1856
           respectively.  Compute the difference |tdv - srv|, and compare
1857
           with 0.5 ulp(srv). */
1858
1859
478k
        delta = diff(bb, bd);
1860
478k
        if (delta == NULL) {
1861
0
            goto failed_malloc;
1862
0
        }
1863
478k
        dsign = delta->sign;
1864
478k
        delta->sign = 0;
1865
478k
        i = cmp(delta, bs);
1866
478k
        if (bc.nd > nd && i <= 0) {
1867
30.7k
            if (dsign)
1868
23.2k
                break;  /* Must use bigcomp(). */
1869
1870
            /* Here rv overestimates the truncated decimal value by at most
1871
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1872
               value by <= 0.5 ulp(rv), or underestimates it by some small
1873
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1874
               the true decimal value, so it's possible to exit.
1875
1876
               Exception: if scaled rv is a normal exact power of 2, but not
1877
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1878
               next double, so the correctly rounded result is either rv - 0.5
1879
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1880
1881
7.49k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1882
                /* rv can't be 0, since it's an overestimate for some
1883
                   nonzero value.  So rv is a normal power of 2. */
1884
1.39k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1885
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1886
                   rv / 2^bc.scale >= 2^-1021. */
1887
1.39k
                if (j - bc.scale >= 2) {
1888
1.12k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1889
1.12k
                    break; /* Use bigcomp. */
1890
1.12k
                }
1891
1.39k
            }
1892
1893
6.37k
            {
1894
6.37k
                bc.nd = nd;
1895
6.37k
                i = -1; /* Discarded digits make delta smaller. */
1896
6.37k
            }
1897
6.37k
        }
1898
1899
454k
        if (i < 0) {
1900
            /* Error is less than half an ulp -- check for
1901
             * special case of mantissa a power of two.
1902
             */
1903
149k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1904
5.86k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1905
149k
                ) {
1906
144k
                break;
1907
144k
            }
1908
4.64k
            if (!delta->x[0] && delta->wds <= 1) {
1909
                /* exact result */
1910
579
                break;
1911
579
            }
1912
4.06k
            delta = lshift(delta,Log2P);
1913
4.06k
            if (delta == NULL) {
1914
0
                goto failed_malloc;
1915
0
            }
1916
4.06k
            if (cmp(delta, bs) > 0)
1917
953
                goto drop_down;
1918
3.11k
            break;
1919
4.06k
        }
1920
305k
        if (i == 0) {
1921
            /* exactly half-way between */
1922
5.33k
            if (dsign) {
1923
2.33k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1924
790
                    &&  word1(&rv) == (
1925
790
                        (bc.scale &&
1926
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1927
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1928
790
                        0xffffffff)) {
1929
                    /*boundary case -- increment exponent*/
1930
463
                    word0(&rv) = (word0(&rv) & Exp_mask)
1931
463
                        + Exp_msk1
1932
463
                        ;
1933
463
                    word1(&rv) = 0;
1934
                    /* dsign = 0; */
1935
463
                    break;
1936
463
                }
1937
2.33k
            }
1938
2.99k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1939
953
              drop_down:
1940
                /* boundary case -- decrement exponent */
1941
953
                if (bc.scale) {
1942
0
                    L = word0(&rv) & Exp_mask;
1943
0
                    if (L <= (2*P+1)*Exp_msk1) {
1944
0
                        if (L > (P+2)*Exp_msk1)
1945
                            /* round even ==> */
1946
                            /* accept rv */
1947
0
                            break;
1948
                        /* rv = smallest denormal */
1949
0
                        if (bc.nd > nd)
1950
0
                            break;
1951
0
                        goto undfl;
1952
0
                    }
1953
0
                }
1954
953
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1955
953
                word0(&rv) = L | Bndry_mask1;
1956
953
                word1(&rv) = 0xffffffff;
1957
953
                break;
1958
953
            }
1959
4.87k
            if (!odd)
1960
4.06k
                break;
1961
811
            if (dsign)
1962
540
                dval(&rv) += sulp(&rv, &bc);
1963
271
            else {
1964
271
                dval(&rv) -= sulp(&rv, &bc);
1965
271
                if (!dval(&rv)) {
1966
0
                    if (bc.nd >nd)
1967
0
                        break;
1968
0
                    goto undfl;
1969
0
                }
1970
271
            }
1971
            /* dsign = 1 - dsign; */
1972
811
            break;
1973
811
        }
1974
299k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1975
268k
            if (dsign)
1976
20.3k
                aadj = aadj1 = 1.;
1977
248k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1978
242k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1979
0
                    if (bc.nd >nd)
1980
0
                        break;
1981
0
                    goto undfl;
1982
0
                }
1983
242k
                aadj = 1.;
1984
242k
                aadj1 = -1.;
1985
242k
            }
1986
6.42k
            else {
1987
                /* special case -- power of FLT_RADIX to be */
1988
                /* rounded down... */
1989
1990
6.42k
                if (aadj < 2./FLT_RADIX)
1991
0
                    aadj = 1./FLT_RADIX;
1992
6.42k
                else
1993
6.42k
                    aadj *= 0.5;
1994
6.42k
                aadj1 = -aadj;
1995
6.42k
            }
1996
268k
        }
1997
30.7k
        else {
1998
30.7k
            aadj *= 0.5;
1999
30.7k
            aadj1 = dsign ? aadj : -aadj;
2000
30.7k
            if (Flt_Rounds == 0)
2001
0
                aadj1 += 0.5;
2002
30.7k
        }
2003
299k
        y = word0(&rv) & Exp_mask;
2004
2005
        /* Check for overflow */
2006
2007
299k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2008
2.41k
            dval(&rv0) = dval(&rv);
2009
2.41k
            word0(&rv) -= P*Exp_msk1;
2010
2.41k
            adj.d = aadj1 * ulp(&rv);
2011
2.41k
            dval(&rv) += adj.d;
2012
2.41k
            if ((word0(&rv) & Exp_mask) >=
2013
2.41k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2014
1.34k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2015
957
                    goto ovfl;
2016
957
                }
2017
388
                word0(&rv) = Big0;
2018
388
                word1(&rv) = Big1;
2019
388
                goto cont;
2020
1.34k
            }
2021
1.07k
            else
2022
1.07k
                word0(&rv) += P*Exp_msk1;
2023
2.41k
        }
2024
297k
        else {
2025
297k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2026
15.6k
                if (aadj <= 0x7fffffff) {
2027
15.6k
                    if ((z = (ULong)aadj) <= 0)
2028
1.84k
                        z = 1;
2029
15.6k
                    aadj = z;
2030
15.6k
                    aadj1 = dsign ? aadj : -aadj;
2031
15.6k
                }
2032
15.6k
                dval(&aadj2) = aadj1;
2033
15.6k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2034
15.6k
                aadj1 = dval(&aadj2);
2035
15.6k
            }
2036
297k
            adj.d = aadj1 * ulp(&rv);
2037
297k
            dval(&rv) += adj.d;
2038
297k
        }
2039
298k
        z = word0(&rv) & Exp_mask;
2040
298k
        if (bc.nd == nd) {
2041
279k
            if (!bc.scale)
2042
263k
                if (y == z) {
2043
                    /* Can we stop now? */
2044
262k
                    L = (Long)aadj;
2045
262k
                    aadj -= L;
2046
                    /* The tolerances below are conservative. */
2047
262k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2048
262k
                        if (aadj < .4999999 || aadj > .5000001)
2049
259k
                            break;
2050
262k
                    }
2051
23
                    else if (aadj < .4999999/FLT_RADIX)
2052
23
                        break;
2053
262k
                }
2054
279k
        }
2055
38.8k
      cont:
2056
38.8k
        Bfree(bb); bb = NULL;
2057
38.8k
        Bfree(bd); bd = NULL;
2058
38.8k
        Bfree(bs); bs = NULL;
2059
38.8k
        Bfree(delta); delta = NULL;
2060
38.8k
    }
2061
438k
    if (bc.nd > nd) {
2062
24.3k
        error = bigcomp(&rv, s0, &bc);
2063
24.3k
        if (error)
2064
0
            goto failed_malloc;
2065
24.3k
    }
2066
2067
438k
    if (bc.scale) {
2068
21.2k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2069
21.2k
        word1(&rv0) = 0;
2070
21.2k
        dval(&rv) *= dval(&rv0);
2071
21.2k
    }
2072
2073
534k
  ret:
2074
534k
    result = sign ? -dval(&rv) : dval(&rv);
2075
534k
    goto done;
2076
2077
49.2k
  parse_error:
2078
49.2k
    result = 0.0;
2079
49.2k
    goto done;
2080
2081
0
  failed_malloc:
2082
0
    errno = ENOMEM;
2083
0
    result = -1.0;
2084
0
    goto done;
2085
2086
5.62k
  undfl:
2087
5.62k
    result = sign ? -0.0 : 0.0;
2088
5.62k
    goto done;
2089
2090
542k
  ovfl:
2091
542k
    errno = ERANGE;
2092
    /* Can't trust HUGE_VAL */
2093
542k
    word0(&rv) = Exp_mask;
2094
542k
    word1(&rv) = 0;
2095
542k
    result = sign ? -dval(&rv) : dval(&rv);
2096
542k
    goto done;
2097
2098
1.13M
  done:
2099
1.13M
    Bfree(bb);
2100
1.13M
    Bfree(bd);
2101
1.13M
    Bfree(bs);
2102
1.13M
    Bfree(bd0);
2103
1.13M
    Bfree(delta);
2104
1.13M
    return result;
2105
2106
438k
}
2107
2108
static char *
2109
rv_alloc(int i)
2110
52.4k
{
2111
52.4k
    int j, k, *r;
2112
2113
52.4k
    j = sizeof(ULong);
2114
52.4k
    for(k = 0;
2115
52.4k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2116
52.4k
        j <<= 1)
2117
0
        k++;
2118
52.4k
    r = (int*)Balloc(k);
2119
52.4k
    if (r == NULL)
2120
0
        return NULL;
2121
52.4k
    *r = k;
2122
52.4k
    return (char *)(r+1);
2123
52.4k
}
2124
2125
static char *
2126
nrv_alloc(const char *s, char **rve, int n)
2127
6.11k
{
2128
6.11k
    char *rv, *t;
2129
2130
6.11k
    rv = rv_alloc(n);
2131
6.11k
    if (rv == NULL)
2132
0
        return NULL;
2133
6.11k
    t = rv;
2134
15.5k
    while((*t = *s++)) t++;
2135
6.11k
    if (rve)
2136
6.11k
        *rve = t;
2137
6.11k
    return rv;
2138
6.11k
}
2139
2140
/* freedtoa(s) must be used to free values s returned by dtoa
2141
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2142
 * but for consistency with earlier versions of dtoa, it is optional
2143
 * when MULTIPLE_THREADS is not defined.
2144
 */
2145
2146
void
2147
_Py_dg_freedtoa(char *s)
2148
52.4k
{
2149
52.4k
    Bigint *b = (Bigint *)((int *)s - 1);
2150
52.4k
    b->maxwds = 1 << (b->k = *(int*)b);
2151
52.4k
    Bfree(b);
2152
52.4k
}
2153
2154
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2155
 *
2156
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2157
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2158
 *
2159
 * Modifications:
2160
 *      1. Rather than iterating, we use a simple numeric overestimate
2161
 *         to determine k = floor(log10(d)).  We scale relevant
2162
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2163
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2164
 *         try to generate digits strictly left to right.  Instead, we
2165
 *         compute with fewer bits and propagate the carry if necessary
2166
 *         when rounding the final digit up.  This is often faster.
2167
 *      3. Under the assumption that input will be rounded nearest,
2168
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2169
 *         That is, we allow equality in stopping tests when the
2170
 *         round-nearest rule will give the same floating-point value
2171
 *         as would satisfaction of the stopping test with strict
2172
 *         inequality.
2173
 *      4. We remove common factors of powers of 2 from relevant
2174
 *         quantities.
2175
 *      5. When converting floating-point integers less than 1e16,
2176
 *         we use floating-point arithmetic rather than resorting
2177
 *         to multiple-precision integers.
2178
 *      6. When asked to produce fewer than 15 digits, we first try
2179
 *         to get by with floating-point arithmetic; we resort to
2180
 *         multiple-precision integer arithmetic only if we cannot
2181
 *         guarantee that the floating-point calculation has given
2182
 *         the correctly rounded result.  For k requested digits and
2183
 *         "uniformly" distributed input, the probability is
2184
 *         something like 10^(k-15) that we must resort to the Long
2185
 *         calculation.
2186
 */
2187
2188
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2189
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2190
   call to _Py_dg_freedtoa. */
2191
2192
char *
2193
_Py_dg_dtoa(double dd, int mode, int ndigits,
2194
            int *decpt, int *sign, char **rve)
2195
52.4k
{
2196
    /*  Arguments ndigits, decpt, sign are similar to those
2197
        of ecvt and fcvt; trailing zeros are suppressed from
2198
        the returned string.  If not null, *rve is set to point
2199
        to the end of the return value.  If d is +-Infinity or NaN,
2200
        then *decpt is set to 9999.
2201
2202
        mode:
2203
        0 ==> shortest string that yields d when read in
2204
        and rounded to nearest.
2205
        1 ==> like 0, but with Steele & White stopping rule;
2206
        e.g. with IEEE P754 arithmetic , mode 0 gives
2207
        1e23 whereas mode 1 gives 9.999999999999999e22.
2208
        2 ==> max(1,ndigits) significant digits.  This gives a
2209
        return value similar to that of ecvt, except
2210
        that trailing zeros are suppressed.
2211
        3 ==> through ndigits past the decimal point.  This
2212
        gives a return value similar to that from fcvt,
2213
        except that trailing zeros are suppressed, and
2214
        ndigits can be negative.
2215
        4,5 ==> similar to 2 and 3, respectively, but (in
2216
        round-nearest mode) with the tests of mode 0 to
2217
        possibly return a shorter string that rounds to d.
2218
        With IEEE arithmetic and compilation with
2219
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2220
        as modes 2 and 3 when FLT_ROUNDS != 1.
2221
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2222
        fast floating-point estimate (if applicable).
2223
2224
        Values of mode other than 0-9 are treated as mode 0.
2225
2226
        Sufficient space is allocated to the return value
2227
        to hold the suppressed trailing zeros.
2228
    */
2229
2230
52.4k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2231
52.4k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2232
52.4k
        spec_case, try_quick;
2233
52.4k
    Long L;
2234
52.4k
    int denorm;
2235
52.4k
    ULong x;
2236
52.4k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2237
52.4k
    U d2, eps, u;
2238
52.4k
    double ds;
2239
52.4k
    char *s, *s0;
2240
2241
    /* set pointers to NULL, to silence gcc compiler warnings and make
2242
       cleanup easier on error */
2243
52.4k
    mlo = mhi = S = 0;
2244
52.4k
    s0 = 0;
2245
2246
52.4k
    u.d = dd;
2247
52.4k
    if (word0(&u) & Sign_bit) {
2248
        /* set sign for everything, including 0's and NaNs */
2249
19.1k
        *sign = 1;
2250
19.1k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2251
19.1k
    }
2252
33.3k
    else
2253
33.3k
        *sign = 0;
2254
2255
    /* quick return for Infinities, NaNs and zeros */
2256
52.4k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2257
467
    {
2258
        /* Infinity or NaN */
2259
467
        *decpt = 9999;
2260
467
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2261
467
            return nrv_alloc("Infinity", rve, 8);
2262
0
        return nrv_alloc("NaN", rve, 3);
2263
467
    }
2264
51.9k
    if (!dval(&u)) {
2265
5.64k
        *decpt = 1;
2266
5.64k
        return nrv_alloc("0", rve, 1);
2267
5.64k
    }
2268
2269
    /* compute k = floor(log10(d)).  The computation may leave k
2270
       one too large, but should never leave k too small. */
2271
46.3k
    b = d2b(&u, &be, &bbits);
2272
46.3k
    if (b == NULL)
2273
0
        goto failed_malloc;
2274
46.3k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2275
42.5k
        dval(&d2) = dval(&u);
2276
42.5k
        word0(&d2) &= Frac_mask1;
2277
42.5k
        word0(&d2) |= Exp_11;
2278
2279
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2280
         * log10(x)      =  log(x) / log(10)
2281
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2282
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2283
         *
2284
         * This suggests computing an approximation k to log10(d) by
2285
         *
2286
         * k = (i - Bias)*0.301029995663981
2287
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2288
         *
2289
         * We want k to be too large rather than too small.
2290
         * The error in the first-order Taylor series approximation
2291
         * is in our favor, so we just round up the constant enough
2292
         * to compensate for any error in the multiplication of
2293
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2294
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2295
         * adding 1e-13 to the constant term more than suffices.
2296
         * Hence we adjust the constant term to 0.1760912590558.
2297
         * (We could get a more accurate k by invoking log10,
2298
         *  but this is probably not worthwhile.)
2299
         */
2300
2301
42.5k
        i -= Bias;
2302
42.5k
        denorm = 0;
2303
42.5k
    }
2304
3.75k
    else {
2305
        /* d is denormalized */
2306
2307
3.75k
        i = bbits + be + (Bias + (P-1) - 1);
2308
3.75k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2309
3.75k
            : word1(&u) << (32 - i);
2310
3.75k
        dval(&d2) = x;
2311
3.75k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2312
3.75k
        i -= (Bias + (P-1) - 1) + 1;
2313
3.75k
        denorm = 1;
2314
3.75k
    }
2315
46.3k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2316
46.3k
        i*0.301029995663981;
2317
46.3k
    k = (int)ds;
2318
46.3k
    if (ds < 0. && ds != k)
2319
12.2k
        k--;    /* want k = floor(ds) */
2320
46.3k
    k_check = 1;
2321
46.3k
    if (k >= 0 && k <= Ten_pmax) {
2322
18.2k
        if (dval(&u) < tens[k])
2323
1.85k
            k--;
2324
18.2k
        k_check = 0;
2325
18.2k
    }
2326
46.3k
    j = bbits - i - 1;
2327
46.3k
    if (j >= 0) {
2328
18.0k
        b2 = 0;
2329
18.0k
        s2 = j;
2330
18.0k
    }
2331
28.2k
    else {
2332
28.2k
        b2 = -j;
2333
28.2k
        s2 = 0;
2334
28.2k
    }
2335
46.3k
    if (k >= 0) {
2336
33.3k
        b5 = 0;
2337
33.3k
        s5 = k;
2338
33.3k
        s2 += k;
2339
33.3k
    }
2340
12.9k
    else {
2341
12.9k
        b2 -= k;
2342
12.9k
        b5 = -k;
2343
12.9k
        s5 = 0;
2344
12.9k
    }
2345
46.3k
    if (mode < 0 || mode > 9)
2346
0
        mode = 0;
2347
2348
46.3k
    try_quick = 1;
2349
2350
46.3k
    if (mode > 5) {
2351
0
        mode -= 4;
2352
0
        try_quick = 0;
2353
0
    }
2354
46.3k
    leftright = 1;
2355
46.3k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2356
    /* silence erroneous "gcc -Wall" warning. */
2357
46.3k
    switch(mode) {
2358
46.2k
    case 0:
2359
46.2k
    case 1:
2360
46.2k
        i = 18;
2361
46.2k
        ndigits = 0;
2362
46.2k
        break;
2363
0
    case 2:
2364
0
        leftright = 0;
2365
0
        _Py_FALLTHROUGH;
2366
0
    case 4:
2367
0
        if (ndigits <= 0)
2368
0
            ndigits = 1;
2369
0
        ilim = ilim1 = i = ndigits;
2370
0
        break;
2371
103
    case 3:
2372
103
        leftright = 0;
2373
103
        _Py_FALLTHROUGH;
2374
103
    case 5:
2375
103
        i = ndigits + k + 1;
2376
103
        ilim = i;
2377
103
        ilim1 = i - 1;
2378
103
        if (i <= 0)
2379
0
            i = 1;
2380
46.3k
    }
2381
46.3k
    s0 = rv_alloc(i);
2382
46.3k
    if (s0 == NULL)
2383
0
        goto failed_malloc;
2384
46.3k
    s = s0;
2385
2386
2387
46.3k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2388
2389
        /* Try to get by with floating-point arithmetic. */
2390
2391
103
        i = 0;
2392
103
        dval(&d2) = dval(&u);
2393
103
        k0 = k;
2394
103
        ilim0 = ilim;
2395
103
        ieps = 2; /* conservative */
2396
103
        if (k > 0) {
2397
81
            ds = tens[k&0xf];
2398
81
            j = k >> 4;
2399
81
            if (j & Bletch) {
2400
                /* prevent overflows */
2401
0
                j &= Bletch - 1;
2402
0
                dval(&u) /= bigtens[n_bigtens-1];
2403
0
                ieps++;
2404
0
            }
2405
81
            for(; j; j >>= 1, i++)
2406
0
                if (j & 1) {
2407
0
                    ieps++;
2408
0
                    ds *= bigtens[i];
2409
0
                }
2410
81
            dval(&u) /= ds;
2411
81
        }
2412
22
        else if ((j1 = -k)) {
2413
0
            dval(&u) *= tens[j1 & 0xf];
2414
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2415
0
                if (j & 1) {
2416
0
                    ieps++;
2417
0
                    dval(&u) *= bigtens[i];
2418
0
                }
2419
0
        }
2420
103
        if (k_check && dval(&u) < 1. && ilim > 0) {
2421
0
            if (ilim1 <= 0)
2422
0
                goto fast_failed;
2423
0
            ilim = ilim1;
2424
0
            k--;
2425
0
            dval(&u) *= 10.;
2426
0
            ieps++;
2427
0
        }
2428
103
        dval(&eps) = ieps*dval(&u) + 7.;
2429
103
        word0(&eps) -= (P-1)*Exp_msk1;
2430
103
        if (ilim == 0) {
2431
0
            S = mhi = 0;
2432
0
            dval(&u) -= 5.;
2433
0
            if (dval(&u) > dval(&eps))
2434
0
                goto one_digit;
2435
0
            if (dval(&u) < -dval(&eps))
2436
0
                goto no_digits;
2437
0
            goto fast_failed;
2438
0
        }
2439
103
        if (leftright) {
2440
            /* Use Steele & White method of only
2441
             * generating digits needed.
2442
             */
2443
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2444
0
            for(i = 0;;) {
2445
0
                L = (Long)dval(&u);
2446
0
                dval(&u) -= L;
2447
0
                *s++ = '0' + (int)L;
2448
0
                if (dval(&u) < dval(&eps))
2449
0
                    goto ret1;
2450
0
                if (1. - dval(&u) < dval(&eps))
2451
0
                    goto bump_up;
2452
0
                if (++i >= ilim)
2453
0
                    break;
2454
0
                dval(&eps) *= 10.;
2455
0
                dval(&u) *= 10.;
2456
0
            }
2457
0
        }
2458
103
        else {
2459
            /* Generate ilim digits, then fix them up. */
2460
103
            dval(&eps) *= tens[ilim-1];
2461
280
            for(i = 1;; i++, dval(&u) *= 10.) {
2462
280
                L = (Long)(dval(&u));
2463
280
                if (!(dval(&u) -= L))
2464
13
                    ilim = i;
2465
280
                *s++ = '0' + (int)L;
2466
280
                if (i == ilim) {
2467
103
                    if (dval(&u) > 0.5 + dval(&eps))
2468
56
                        goto bump_up;
2469
47
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2470
52
                        while(*--s == '0');
2471
47
                        s++;
2472
47
                        goto ret1;
2473
47
                    }
2474
0
                    break;
2475
103
                }
2476
280
            }
2477
103
        }
2478
0
      fast_failed:
2479
0
        s = s0;
2480
0
        dval(&u) = dval(&d2);
2481
0
        k = k0;
2482
0
        ilim = ilim0;
2483
0
    }
2484
2485
    /* Do we have a "small" integer? */
2486
2487
46.2k
    if (be >= 0 && k <= Int_max) {
2488
        /* Yes. */
2489
10.9k
        ds = tens[k];
2490
10.9k
        if (ndigits < 0 && ilim <= 0) {
2491
0
            S = mhi = 0;
2492
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2493
0
                goto no_digits;
2494
0
            goto one_digit;
2495
0
        }
2496
15.9k
        for(i = 1;; i++, dval(&u) *= 10.) {
2497
15.9k
            L = (Long)(dval(&u) / ds);
2498
15.9k
            dval(&u) -= L*ds;
2499
15.9k
            *s++ = '0' + (int)L;
2500
15.9k
            if (!dval(&u)) {
2501
10.9k
                break;
2502
10.9k
            }
2503
5.04k
            if (i == ilim) {
2504
0
                dval(&u) += dval(&u);
2505
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2506
56
                  bump_up:
2507
60
                    while(*--s == '9')
2508
4
                        if (s == s0) {
2509
0
                            k++;
2510
0
                            *s = '0';
2511
0
                            break;
2512
0
                        }
2513
56
                    ++*s++;
2514
56
                }
2515
0
                else {
2516
                    /* Strip trailing zeros. This branch was missing from the
2517
                       original dtoa.c, leading to surplus trailing zeros in
2518
                       some cases. See bugs.python.org/issue40780. */
2519
0
                    while (s > s0 && s[-1] == '0') {
2520
0
                        --s;
2521
0
                    }
2522
0
                }
2523
56
                break;
2524
0
            }
2525
5.04k
        }
2526
10.9k
        goto ret1;
2527
10.9k
    }
2528
2529
35.2k
    m2 = b2;
2530
35.2k
    m5 = b5;
2531
35.2k
    if (leftright) {
2532
35.2k
        i =
2533
35.2k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2534
35.2k
            1 + P - bbits;
2535
35.2k
        b2 += i;
2536
35.2k
        s2 += i;
2537
35.2k
        mhi = i2b(1);
2538
35.2k
        if (mhi == NULL)
2539
0
            goto failed_malloc;
2540
35.2k
    }
2541
35.2k
    if (m2 > 0 && s2 > 0) {
2542
32.1k
        i = m2 < s2 ? m2 : s2;
2543
32.1k
        b2 -= i;
2544
32.1k
        m2 -= i;
2545
32.1k
        s2 -= i;
2546
32.1k
    }
2547
35.2k
    if (b5 > 0) {
2548
12.9k
        if (leftright) {
2549
12.9k
            if (m5 > 0) {
2550
12.9k
                mhi = pow5mult(mhi, m5);
2551
12.9k
                if (mhi == NULL)
2552
0
                    goto failed_malloc;
2553
12.9k
                b1 = mult(mhi, b);
2554
12.9k
                Bfree(b);
2555
12.9k
                b = b1;
2556
12.9k
                if (b == NULL)
2557
0
                    goto failed_malloc;
2558
12.9k
            }
2559
12.9k
            if ((j = b5 - m5)) {
2560
0
                b = pow5mult(b, j);
2561
0
                if (b == NULL)
2562
0
                    goto failed_malloc;
2563
0
            }
2564
12.9k
        }
2565
0
        else {
2566
0
            b = pow5mult(b, b5);
2567
0
            if (b == NULL)
2568
0
                goto failed_malloc;
2569
0
        }
2570
12.9k
    }
2571
35.2k
    S = i2b(1);
2572
35.2k
    if (S == NULL)
2573
0
        goto failed_malloc;
2574
35.2k
    if (s5 > 0) {
2575
20.6k
        S = pow5mult(S, s5);
2576
20.6k
        if (S == NULL)
2577
0
            goto failed_malloc;
2578
20.6k
    }
2579
2580
    /* Check for special case that d is a normalized power of 2. */
2581
2582
35.2k
    spec_case = 0;
2583
35.2k
    if ((mode < 2 || leftright)
2584
35.2k
        ) {
2585
35.2k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2586
1.21k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2587
35.2k
            ) {
2588
            /* The special case */
2589
943
            b2 += Log2P;
2590
943
            s2 += Log2P;
2591
943
            spec_case = 1;
2592
943
        }
2593
35.2k
    }
2594
2595
    /* Arrange for convenient computation of quotients:
2596
     * shift left if necessary so divisor has 4 leading 0 bits.
2597
     *
2598
     * Perhaps we should just compute leading 28 bits of S once
2599
     * and for all and pass them and a shift to quorem, so it
2600
     * can do shifts and ors to compute the numerator for q.
2601
     */
2602
35.2k
#define iInc 28
2603
35.2k
    i = dshift(S, s2);
2604
35.2k
    b2 += i;
2605
35.2k
    m2 += i;
2606
35.2k
    s2 += i;
2607
35.2k
    if (b2 > 0) {
2608
35.2k
        b = lshift(b, b2);
2609
35.2k
        if (b == NULL)
2610
0
            goto failed_malloc;
2611
35.2k
    }
2612
35.2k
    if (s2 > 0) {
2613
34.8k
        S = lshift(S, s2);
2614
34.8k
        if (S == NULL)
2615
0
            goto failed_malloc;
2616
34.8k
    }
2617
35.2k
    if (k_check) {
2618
28.0k
        if (cmp(b,S) < 0) {
2619
4.44k
            k--;
2620
4.44k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2621
4.44k
            if (b == NULL)
2622
0
                goto failed_malloc;
2623
4.44k
            if (leftright) {
2624
4.44k
                mhi = multadd(mhi, 10, 0);
2625
4.44k
                if (mhi == NULL)
2626
0
                    goto failed_malloc;
2627
4.44k
            }
2628
4.44k
            ilim = ilim1;
2629
4.44k
        }
2630
28.0k
    }
2631
35.2k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2632
0
        if (ilim < 0) {
2633
            /* no digits, fcvt style */
2634
0
          no_digits:
2635
0
            k = -1 - ndigits;
2636
0
            goto ret;
2637
0
        }
2638
0
        else {
2639
0
            S = multadd(S, 5, 0);
2640
0
            if (S == NULL)
2641
0
                goto failed_malloc;
2642
0
            if (cmp(b, S) <= 0)
2643
0
                goto no_digits;
2644
0
        }
2645
0
      one_digit:
2646
0
        *s++ = '1';
2647
0
        k++;
2648
0
        goto ret;
2649
0
    }
2650
35.2k
    if (leftright) {
2651
35.2k
        if (m2 > 0) {
2652
34.6k
            mhi = lshift(mhi, m2);
2653
34.6k
            if (mhi == NULL)
2654
0
                goto failed_malloc;
2655
34.6k
        }
2656
2657
        /* Compute mlo -- check for special case
2658
         * that d is a normalized power of 2.
2659
         */
2660
2661
35.2k
        mlo = mhi;
2662
35.2k
        if (spec_case) {
2663
943
            mhi = Balloc(mhi->k);
2664
943
            if (mhi == NULL)
2665
0
                goto failed_malloc;
2666
943
            Bcopy(mhi, mlo);
2667
943
            mhi = lshift(mhi, Log2P);
2668
943
            if (mhi == NULL)
2669
0
                goto failed_malloc;
2670
943
        }
2671
2672
139k
        for(i = 1;;i++) {
2673
139k
            dig = quorem(b,S) + '0';
2674
            /* Do we yet have the shortest decimal string
2675
             * that will round to d?
2676
             */
2677
139k
            j = cmp(b, mlo);
2678
139k
            delta = diff(S, mhi);
2679
139k
            if (delta == NULL)
2680
0
                goto failed_malloc;
2681
139k
            j1 = delta->sign ? 1 : cmp(b, delta);
2682
139k
            Bfree(delta);
2683
139k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2684
139k
                ) {
2685
1.69k
                if (dig == '9')
2686
232
                    goto round_9_up;
2687
1.46k
                if (j > 0)
2688
752
                    dig++;
2689
1.46k
                *s++ = dig;
2690
1.46k
                goto ret;
2691
1.69k
            }
2692
137k
            if (j < 0 || (j == 0 && mode != 1
2693
1.75k
                          && !(word1(&u) & 1)
2694
121k
                    )) {
2695
17.1k
                if (!b->x[0] && b->wds <= 1) {
2696
2.11k
                    goto accept_dig;
2697
2.11k
                }
2698
15.0k
                if (j1 > 0) {
2699
2.91k
                    b = lshift(b, 1);
2700
2.91k
                    if (b == NULL)
2701
0
                        goto failed_malloc;
2702
2.91k
                    j1 = cmp(b, S);
2703
2.91k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2704
1.69k
                        && dig++ == '9')
2705
236
                        goto round_9_up;
2706
2.91k
                }
2707
16.9k
              accept_dig:
2708
16.9k
                *s++ = dig;
2709
16.9k
                goto ret;
2710
15.0k
            }
2711
120k
            if (j1 > 0) {
2712
16.4k
                if (dig == '9') { /* possible if i == 1 */
2713
4.40k
                  round_9_up:
2714
4.40k
                    *s++ = '9';
2715
4.40k
                    goto roundoff;
2716
3.93k
                }
2717
12.4k
                *s++ = dig + 1;
2718
12.4k
                goto ret;
2719
16.4k
            }
2720
103k
            *s++ = dig;
2721
103k
            if (i == ilim)
2722
0
                break;
2723
103k
            b = multadd(b, 10, 0);
2724
103k
            if (b == NULL)
2725
0
                goto failed_malloc;
2726
103k
            if (mlo == mhi) {
2727
100k
                mlo = mhi = multadd(mhi, 10, 0);
2728
100k
                if (mlo == NULL)
2729
0
                    goto failed_malloc;
2730
100k
            }
2731
3.24k
            else {
2732
3.24k
                mlo = multadd(mlo, 10, 0);
2733
3.24k
                if (mlo == NULL)
2734
0
                    goto failed_malloc;
2735
3.24k
                mhi = multadd(mhi, 10, 0);
2736
3.24k
                if (mhi == NULL)
2737
0
                    goto failed_malloc;
2738
3.24k
            }
2739
103k
        }
2740
35.2k
    }
2741
0
    else
2742
0
        for(i = 1;; i++) {
2743
0
            *s++ = dig = quorem(b,S) + '0';
2744
0
            if (!b->x[0] && b->wds <= 1) {
2745
0
                goto ret;
2746
0
            }
2747
0
            if (i >= ilim)
2748
0
                break;
2749
0
            b = multadd(b, 10, 0);
2750
0
            if (b == NULL)
2751
0
                goto failed_malloc;
2752
0
        }
2753
2754
    /* Round off last digit */
2755
2756
0
    b = lshift(b, 1);
2757
0
    if (b == NULL)
2758
0
        goto failed_malloc;
2759
0
    j = cmp(b, S);
2760
0
    if (j > 0 || (j == 0 && dig & 1)) {
2761
4.40k
      roundoff:
2762
4.40k
        while(*--s == '9')
2763
4.40k
            if (s == s0) {
2764
4.40k
                k++;
2765
4.40k
                *s++ = '1';
2766
4.40k
                goto ret;
2767
4.40k
            }
2768
0
        ++*s++;
2769
0
    }
2770
0
    else {
2771
0
        while(*--s == '0');
2772
0
        s++;
2773
0
    }
2774
35.2k
  ret:
2775
35.2k
    Bfree(S);
2776
35.2k
    if (mhi) {
2777
35.2k
        if (mlo && mlo != mhi)
2778
943
            Bfree(mlo);
2779
35.2k
        Bfree(mhi);
2780
35.2k
    }
2781
46.3k
  ret1:
2782
46.3k
    Bfree(b);
2783
46.3k
    *s = 0;
2784
46.3k
    *decpt = k + 1;
2785
46.3k
    if (rve)
2786
46.3k
        *rve = s;
2787
46.3k
    return s0;
2788
0
  failed_malloc:
2789
0
    if (S)
2790
0
        Bfree(S);
2791
0
    if (mlo && mlo != mhi)
2792
0
        Bfree(mlo);
2793
0
    if (mhi)
2794
0
        Bfree(mhi);
2795
0
    if (b)
2796
0
        Bfree(b);
2797
0
    if (s0)
2798
0
        _Py_dg_freedtoa(s0);
2799
0
    return NULL;
2800
35.2k
}
2801
2802
#endif  // _PY_SHORT_FLOAT_REPR == 1
2803
2804
PyStatus
2805
_PyDtoa_Init(PyInterpreterState *interp)
2806
36
{
2807
36
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2808
36
    Bigint **p5s = interp->dtoa.p5s;
2809
2810
    // 5**4 = 625
2811
36
    Bigint *p5 = i2b(625);
2812
36
    if (p5 == NULL) {
2813
0
        return PyStatus_NoMemory();
2814
0
    }
2815
36
    p5s[0] = p5;
2816
2817
    // compute 5**8, 5**16, 5**32, ..., 5**512
2818
288
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2819
252
        p5 = mult(p5, p5);
2820
252
        if (p5 == NULL) {
2821
0
            return PyStatus_NoMemory();
2822
0
        }
2823
252
        p5s[i] = p5;
2824
252
    }
2825
2826
36
#endif
2827
36
    return PyStatus_Ok();
2828
36
}
2829
2830
void
2831
_PyDtoa_Fini(PyInterpreterState *interp)
2832
0
{
2833
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2834
0
    Bigint **p5s = interp->dtoa.p5s;
2835
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2836
0
        Bigint *p5 = p5s[i];
2837
        p5s[i] = NULL;
2838
0
        Bfree(p5);
2839
0
    }
2840
0
#endif
2841
0
}