Coverage Report

Created: 2026-06-21 06:15

next uncovered line (L), next uncovered region (R), next uncovered branch (B)
/src/cpython/Python/dtoa.c
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Count
Source
1
/****************************************************************
2
 *
3
 * The author of this software is David M. Gay.
4
 *
5
 * Copyright (c) 1991, 2000, 2001 by Lucent Technologies.
6
 *
7
 * Permission to use, copy, modify, and distribute this software for any
8
 * purpose without fee is hereby granted, provided that this entire notice
9
 * is included in all copies of any software which is or includes a copy
10
 * or modification of this software and in all copies of the supporting
11
 * documentation for such software.
12
 *
13
 * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED
14
 * WARRANTY.  IN PARTICULAR, NEITHER THE AUTHOR NOR LUCENT MAKES ANY
15
 * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY
16
 * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE.
17
 *
18
 ***************************************************************/
19
20
/****************************************************************
21
 * This is dtoa.c by David M. Gay, downloaded from
22
 * http://www.netlib.org/fp/dtoa.c on April 15, 2009 and modified for
23
 * inclusion into the Python core by Mark E. T. Dickinson and Eric V. Smith.
24
 *
25
 * Please remember to check http://www.netlib.org/fp regularly (and especially
26
 * before any Python release) for bugfixes and updates.
27
 *
28
 * The major modifications from Gay's original code are as follows:
29
 *
30
 *  0. The original code has been specialized to Python's needs by removing
31
 *     many of the #ifdef'd sections.  In particular, code to support VAX and
32
 *     IBM floating-point formats, hex NaNs, hex floats, locale-aware
33
 *     treatment of the decimal point, and setting of the inexact flag have
34
 *     been removed.
35
 *
36
 *  1. We use PyMem_Malloc and PyMem_Free in place of malloc and free.
37
 *
38
 *  2. The public functions strtod, dtoa and freedtoa all now have
39
 *     a _Py_dg_ prefix.
40
 *
41
 *  3. Instead of assuming that PyMem_Malloc always succeeds, we thread
42
 *     PyMem_Malloc failures through the code.  The functions
43
 *
44
 *       Balloc, multadd, s2b, i2b, mult, pow5mult, lshift, diff, d2b
45
 *
46
 *     of return type *Bigint all return NULL to indicate a malloc failure.
47
 *     Similarly, rv_alloc and nrv_alloc (return type char *) return NULL on
48
 *     failure.  bigcomp now has return type int (it used to be void) and
49
 *     returns -1 on failure and 0 otherwise.  _Py_dg_dtoa returns NULL
50
 *     on failure.  _Py_dg_strtod indicates failure due to malloc failure
51
 *     by returning -1.0, setting errno=ENOMEM and *se to s00.
52
 *
53
 *  4. The static variable dtoa_result has been removed.  Callers of
54
 *     _Py_dg_dtoa are expected to call _Py_dg_freedtoa to free
55
 *     the memory allocated by _Py_dg_dtoa.
56
 *
57
 *  5. The code has been reformatted to better fit with Python's
58
 *     C style guide (PEP 7).
59
 *
60
 *  6. A bug in the memory allocation has been fixed: to avoid FREEing memory
61
 *     that hasn't been MALLOC'ed, private_mem should only be used when k <=
62
 *     Kmax.
63
 *
64
 *  7. _Py_dg_strtod has been modified so that it doesn't accept strings with
65
 *     leading whitespace.
66
 *
67
 *  8. A corner case where _Py_dg_dtoa didn't strip trailing zeros has been
68
 *     fixed. (bugs.python.org/issue40780)
69
 *
70
 ***************************************************************/
71
72
/* Please send bug reports for the original dtoa.c code to David M. Gay (dmg
73
 * at acm dot org, with " at " changed at "@" and " dot " changed to ".").
74
 * Please report bugs for this modified version using the Python issue tracker
75
 * as detailed at (https://devguide.python.org/triage/issue-tracker/). */
76
77
/* On a machine with IEEE extended-precision registers, it is
78
 * necessary to specify double-precision (53-bit) rounding precision
79
 * before invoking strtod or dtoa.  If the machine uses (the equivalent
80
 * of) Intel 80x87 arithmetic, the call
81
 *      _control87(PC_53, MCW_PC);
82
 * does this with many compilers.  Whether this or another call is
83
 * appropriate depends on the compiler; for this to work, it may be
84
 * necessary to #include "float.h" or another system-dependent header
85
 * file.
86
 */
87
88
/* strtod for IEEE-, VAX-, and IBM-arithmetic machines.
89
 *
90
 * This strtod returns a nearest machine number to the input decimal
91
 * string (or sets errno to ERANGE).  With IEEE arithmetic, ties are
92
 * broken by the IEEE round-even rule.  Otherwise ties are broken by
93
 * biased rounding (add half and chop).
94
 *
95
 * Inspired loosely by William D. Clinger's paper "How to Read Floating
96
 * Point Numbers Accurately" [Proc. ACM SIGPLAN '90, pp. 92-101].
97
 *
98
 * Modifications:
99
 *
100
 *      1. We only require IEEE, IBM, or VAX double-precision
101
 *              arithmetic (not IEEE double-extended).
102
 *      2. We get by with floating-point arithmetic in a case that
103
 *              Clinger missed -- when we're computing d * 10^n
104
 *              for a small integer d and the integer n is not too
105
 *              much larger than 22 (the maximum integer k for which
106
 *              we can represent 10^k exactly), we may be able to
107
 *              compute (d*10^k) * 10^(e-k) with just one roundoff.
108
 *      3. Rather than a bit-at-a-time adjustment of the binary
109
 *              result in the hard case, we use floating-point
110
 *              arithmetic to determine the adjustment to within
111
 *              one bit; only in really hard cases do we need to
112
 *              compute a second residual.
113
 *      4. Because of 3., we don't need a large table of powers of 10
114
 *              for ten-to-e (just some small tables, e.g. of 10^k
115
 *              for 0 <= k <= 22).
116
 */
117
118
/* Linking of Python's #defines to Gay's #defines starts here. */
119
120
#include "Python.h"
121
#include "pycore_dtoa.h"          // _PY_SHORT_FLOAT_REPR
122
#include "pycore_interp_structs.h"// struct Bigint
123
#include "pycore_pystate.h"       // _PyInterpreterState_GET()
124
#include <stdlib.h>               // exit()
125
126
127
/* if _PY_SHORT_FLOAT_REPR == 0, then don't even try to compile
128
   the following code */
129
#if _PY_SHORT_FLOAT_REPR == 1
130
131
#include "float.h"
132
133
62
#define MALLOC PyMem_Malloc
134
0
#define FREE PyMem_Free
135
136
/* This code should also work for ARM mixed-endian format on little-endian
137
   machines, where doubles have byte order 45670123 (in increasing address
138
   order, 0 being the least significant byte). */
139
#ifdef DOUBLE_IS_LITTLE_ENDIAN_IEEE754
140
#  define IEEE_8087
141
#endif
142
#if defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
143
#  define IEEE_MC68k
144
#endif
145
#if defined(IEEE_8087) + defined(IEEE_MC68k) != 1
146
#error "Exactly one of IEEE_8087 or IEEE_MC68k should be defined."
147
#endif
148
149
/* The code below assumes that the endianness of integers matches the
150
   endianness of the two 32-bit words of a double.  Check this. */
151
#if defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_LITTLE_ENDIAN_IEEE754)
152
#error "doubles and ints have incompatible endianness"
153
#endif
154
155
#if !defined(WORDS_BIGENDIAN) && defined(DOUBLE_IS_BIG_ENDIAN_IEEE754)
156
#error "doubles and ints have incompatible endianness"
157
#endif
158
159
160
typedef uint32_t ULong;
161
typedef int32_t Long;
162
typedef uint64_t ULLong;
163
164
#undef DEBUG
165
#ifdef Py_DEBUG
166
#define DEBUG
167
#endif
168
169
/* End Python #define linking */
170
171
#ifdef DEBUG
172
#define Bug(x) {fprintf(stderr, "%s\n", x); exit(1);}
173
#endif
174
175
typedef union { double d; ULong L[2]; } U;
176
177
#ifdef IEEE_8087
178
5.06M
#define word0(x) (x)->L[1]
179
3.43M
#define word1(x) (x)->L[0]
180
#else
181
#define word0(x) (x)->L[0]
182
#define word1(x) (x)->L[1]
183
#endif
184
7.91M
#define dval(x) (x)->d
185
186
#ifndef STRTOD_DIGLIM
187
439k
#define STRTOD_DIGLIM 40
188
#endif
189
190
/* maximum permitted exponent value for strtod; exponents larger than
191
   MAX_ABS_EXP in absolute value get truncated to +-MAX_ABS_EXP.  MAX_ABS_EXP
192
   should fit into an int. */
193
#ifndef MAX_ABS_EXP
194
786k
#define MAX_ABS_EXP 1100000000U
195
#endif
196
/* Bound on length of pieces of input strings in _Py_dg_strtod; specifically,
197
   this is used to bound the total number of digits ignoring leading zeros and
198
   the number of digits that follow the decimal point.  Ideally, MAX_DIGITS
199
   should satisfy MAX_DIGITS + 400 < MAX_ABS_EXP; that ensures that the
200
   exponent clipping in _Py_dg_strtod can't affect the value of the output. */
201
#ifndef MAX_DIGITS
202
2.59M
#define MAX_DIGITS 1000000000U
203
#endif
204
205
/* Guard against trying to use the above values on unusual platforms with ints
206
 * of width less than 32 bits. */
207
#if MAX_ABS_EXP > INT_MAX
208
#error "MAX_ABS_EXP should fit in an int"
209
#endif
210
#if MAX_DIGITS > INT_MAX
211
#error "MAX_DIGITS should fit in an int"
212
#endif
213
214
/* The following definition of Storeinc is appropriate for MIPS processors.
215
 * An alternative that might be better on some machines is
216
 * #define Storeinc(a,b,c) (*a++ = b << 16 | c & 0xffff)
217
 */
218
#if defined(IEEE_8087)
219
#define Storeinc(a,b,c) (((unsigned short *)a)[1] = (unsigned short)b,  \
220
                         ((unsigned short *)a)[0] = (unsigned short)c, a++)
221
#else
222
#define Storeinc(a,b,c) (((unsigned short *)a)[0] = (unsigned short)b,  \
223
                         ((unsigned short *)a)[1] = (unsigned short)c, a++)
224
#endif
225
226
/* #define P DBL_MANT_DIG */
227
/* Ten_pmax = floor(P*log(2)/log(5)) */
228
/* Bletch = (highest power of 2 < DBL_MAX_10_EXP) / 16 */
229
/* Quick_max = floor((P-1)*log(FLT_RADIX)/log(10) - 1) */
230
/* Int_max = floor(P*log(FLT_RADIX)/log(10) - 1) */
231
232
571k
#define Exp_shift  20
233
83.5k
#define Exp_shift1 20
234
3.03M
#define Exp_msk1    0x100000
235
#define Exp_msk11   0x100000
236
2.29M
#define Exp_mask  0x7ff00000
237
2.05M
#define P 53
238
#define Nbits 53
239
1.15M
#define Bias 1023
240
#define Emax 1023
241
#define Emin (-1022)
242
1.11M
#define Etiny (-1074)  /* smallest denormal is 2**Etiny */
243
625k
#define Exp_1  0x3ff00000
244
36.9k
#define Exp_11 0x3ff00000
245
1.92M
#define Ebits 11
246
545k
#define Frac_mask  0xfffff
247
38.9k
#define Frac_mask1 0xfffff
248
1.48M
#define Ten_pmax 22
249
85
#define Bletch 0x10
250
174k
#define Bndry_mask  0xfffff
251
8.75k
#define Bndry_mask1 0xfffff
252
58.1k
#define Sign_bit 0x80000000
253
8.86k
#define Log2P 1
254
#define Tiny0 0
255
482k
#define Tiny1 1
256
41.8k
#define Quick_max 14
257
24.9k
#define Int_max 14
258
259
#ifndef Flt_Rounds
260
#ifdef FLT_ROUNDS
261
823k
#define Flt_Rounds FLT_ROUNDS
262
#else
263
#define Flt_Rounds 1
264
#endif
265
#endif /*Flt_Rounds*/
266
267
#define Rounding Flt_Rounds
268
269
3.18k
#define Big0 (Frac_mask1 | Exp_msk1*(DBL_MAX_EXP+Bias-1))
270
1.99k
#define Big1 0xffffffff
271
272
/* Bits of the representation of positive infinity. */
273
274
#define POSINF_WORD0 0x7ff00000
275
#define POSINF_WORD1 0
276
277
/* struct BCinfo is used to pass information from _Py_dg_strtod to bigcomp */
278
279
typedef struct BCinfo BCinfo;
280
struct
281
BCinfo {
282
    int e0, nd, nd0, scale;
283
};
284
285
32.0M
#define FFFFFFFF 0xffffffffUL
286
287
/* struct Bigint is used to represent arbitrary-precision integers.  These
288
   integers are stored in sign-magnitude format, with the magnitude stored as
289
   an array of base 2**32 digits.  Bigints are always normalized: if x is a
290
   Bigint then x->wds >= 1, and either x->wds == 1 or x[wds-1] is nonzero.
291
292
   The Bigint fields are as follows:
293
294
     - next is a header used by Balloc and Bfree to keep track of lists
295
         of freed Bigints;  it's also used for the linked list of
296
         powers of 5 of the form 5**2**i used by pow5mult.
297
     - k indicates which pool this Bigint was allocated from
298
     - maxwds is the maximum number of words space was allocated for
299
       (usually maxwds == 2**k)
300
     - sign is 1 for negative Bigints, 0 for positive.  The sign is unused
301
       (ignored on inputs, set to 0 on outputs) in almost all operations
302
       involving Bigints: a notable exception is the diff function, which
303
       ignores signs on inputs but sets the sign of the output correctly.
304
     - wds is the actual number of significant words
305
     - x contains the vector of words (digits) for this Bigint, from least
306
       significant (x[0]) to most significant (x[wds-1]).
307
*/
308
309
// struct Bigint is defined in pycore_dtoa.h.
310
typedef struct Bigint Bigint;
311
312
#if !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER)
313
314
/* Memory management: memory is allocated from, and returned to, Kmax+1 pools
315
   of memory, where pool k (0 <= k <= Kmax) is for Bigints b with b->maxwds ==
316
   1 << k.  These pools are maintained as linked lists, with freelist[k]
317
   pointing to the head of the list for pool k.
318
319
   On allocation, if there's no free slot in the appropriate pool, MALLOC is
320
   called to get more memory.  This memory is not returned to the system until
321
   Python quits.  There's also a private memory pool that's allocated from
322
   in preference to using MALLOC.
323
324
   For Bigints with more than (1 << Kmax) digits (which implies at least 1233
325
   decimal digits), memory is directly allocated using MALLOC, and freed using
326
   FREE.
327
328
   XXX: it would be easy to bypass this memory-management system and
329
   translate each call to Balloc into a call to PyMem_Malloc, and each
330
   Bfree to PyMem_Free.  Investigate whether this has any significant
331
   performance on impact. */
332
333
21.7M
#define freelist interp->dtoa.freelist
334
440
#define private_mem interp->dtoa.preallocated
335
1.19k
#define pmem_next interp->dtoa.preallocated_next
336
337
/* Allocate space for a Bigint with up to 1<<k digits */
338
339
static Bigint *
340
Balloc(int k)
341
5.43M
{
342
5.43M
    int x;
343
5.43M
    Bigint *rv;
344
5.43M
    unsigned int len;
345
5.43M
    PyInterpreterState *interp = _PyInterpreterState_GET();
346
347
5.43M
    if (k <= Bigint_Kmax && (rv = freelist[k]))
348
5.43M
        freelist[k] = rv->next;
349
440
    else {
350
440
        x = 1 << k;
351
440
        len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
352
440
            /sizeof(double);
353
440
        if (k <= Bigint_Kmax &&
354
440
            pmem_next - private_mem + len <= (Py_ssize_t)Bigint_PREALLOC_SIZE
355
440
        ) {
356
378
            rv = (Bigint*)pmem_next;
357
378
            pmem_next += len;
358
378
        }
359
62
        else {
360
62
            rv = (Bigint*)MALLOC(len*sizeof(double));
361
62
            if (rv == NULL)
362
0
                return NULL;
363
62
        }
364
440
        rv->k = k;
365
440
        rv->maxwds = x;
366
440
    }
367
5.43M
    rv->sign = rv->wds = 0;
368
5.43M
    return rv;
369
5.43M
}
370
371
/* Free a Bigint allocated with Balloc */
372
373
static void
374
Bfree(Bigint *v)
375
7.86M
{
376
7.86M
    if (v) {
377
5.43M
        if (v->k > Bigint_Kmax)
378
0
            FREE((void*)v);
379
5.43M
        else {
380
5.43M
            PyInterpreterState *interp = _PyInterpreterState_GET();
381
5.43M
            v->next = freelist[v->k];
382
5.43M
            freelist[v->k] = v;
383
5.43M
        }
384
5.43M
    }
385
7.86M
}
386
387
#undef pmem_next
388
#undef private_mem
389
#undef freelist
390
391
#else
392
393
/* Alternative versions of Balloc and Bfree that use PyMem_Malloc and
394
   PyMem_Free directly in place of the custom memory allocation scheme above.
395
   These are provided for the benefit of memory debugging tools like
396
   Valgrind. */
397
398
/* Allocate space for a Bigint with up to 1<<k digits */
399
400
static Bigint *
401
Balloc(int k)
402
{
403
    int x;
404
    Bigint *rv;
405
    unsigned int len;
406
407
    x = 1 << k;
408
    len = (sizeof(Bigint) + (x-1)*sizeof(ULong) + sizeof(double) - 1)
409
        /sizeof(double);
410
411
    rv = (Bigint*)MALLOC(len*sizeof(double));
412
    if (rv == NULL)
413
        return NULL;
414
415
    rv->k = k;
416
    rv->maxwds = x;
417
    rv->sign = rv->wds = 0;
418
    return rv;
419
}
420
421
/* Free a Bigint allocated with Balloc */
422
423
static void
424
Bfree(Bigint *v)
425
{
426
    if (v) {
427
        FREE((void*)v);
428
    }
429
}
430
431
#endif /* !defined(Py_GIL_DISABLED) && !defined(Py_USING_MEMORY_DEBUGGER) */
432
433
485k
#define Bcopy(x,y) memcpy((char *)&x->sign, (char *)&y->sign,   \
434
485k
                          y->wds*sizeof(Long) + 2*sizeof(int))
435
436
/* Multiply a Bigint b by m and add a.  Either modifies b in place and returns
437
   a pointer to the modified b, or Bfrees b and returns a pointer to a copy.
438
   On failure, return NULL.  In this case, b will have been already freed. */
439
440
static Bigint *
441
multadd(Bigint *b, int m, int a)       /* multiply by m and add a */
442
1.22M
{
443
1.22M
    int i, wds;
444
1.22M
    ULong *x;
445
1.22M
    ULLong carry, y;
446
1.22M
    Bigint *b1;
447
448
1.22M
    wds = b->wds;
449
1.22M
    x = b->x;
450
1.22M
    i = 0;
451
1.22M
    carry = a;
452
4.19M
    do {
453
4.19M
        y = *x * (ULLong)m + carry;
454
4.19M
        carry = y >> 32;
455
4.19M
        *x++ = (ULong)(y & FFFFFFFF);
456
4.19M
    }
457
4.19M
    while(++i < wds);
458
1.22M
    if (carry) {
459
76.7k
        if (wds >= b->maxwds) {
460
3.76k
            b1 = Balloc(b->k+1);
461
3.76k
            if (b1 == NULL){
462
0
                Bfree(b);
463
0
                return NULL;
464
0
            }
465
3.76k
            Bcopy(b1, b);
466
3.76k
            Bfree(b);
467
3.76k
            b = b1;
468
3.76k
        }
469
76.7k
        b->x[wds++] = (ULong)carry;
470
76.7k
        b->wds = wds;
471
76.7k
    }
472
1.22M
    return b;
473
1.22M
}
474
475
/* convert a string s containing nd decimal digits (possibly containing a
476
   decimal separator at position nd0, which is ignored) to a Bigint.  This
477
   function carries on where the parsing code in _Py_dg_strtod leaves off: on
478
   entry, y9 contains the result of converting the first 9 digits.  Returns
479
   NULL on failure. */
480
481
static Bigint *
482
s2b(const char *s, int nd0, int nd, ULong y9)
483
439k
{
484
439k
    Bigint *b;
485
439k
    int i, k;
486
439k
    Long x, y;
487
488
439k
    x = (nd + 8) / 9;
489
498k
    for(k = 0, y = 1; x > y; y <<= 1, k++) ;
490
439k
    b = Balloc(k);
491
439k
    if (b == NULL)
492
0
        return NULL;
493
439k
    b->x[0] = y9;
494
439k
    b->wds = 1;
495
496
439k
    if (nd <= 9)
497
392k
      return b;
498
499
46.7k
    s += 9;
500
359k
    for (i = 9; i < nd0; i++) {
501
312k
        b = multadd(b, 10, *s++ - '0');
502
312k
        if (b == NULL)
503
0
            return NULL;
504
312k
    }
505
46.7k
    s++;
506
162k
    for(; i < nd; i++) {
507
116k
        b = multadd(b, 10, *s++ - '0');
508
116k
        if (b == NULL)
509
0
            return NULL;
510
116k
    }
511
46.7k
    return b;
512
46.7k
}
513
514
/* count leading 0 bits in the 32-bit integer x. */
515
516
static int
517
hi0bits(ULong x)
518
664k
{
519
664k
    int k = 0;
520
521
664k
    if (!(x & 0xffff0000)) {
522
248k
        k = 16;
523
248k
        x <<= 16;
524
248k
    }
525
664k
    if (!(x & 0xff000000)) {
526
262k
        k += 8;
527
262k
        x <<= 8;
528
262k
    }
529
664k
    if (!(x & 0xf0000000)) {
530
469k
        k += 4;
531
469k
        x <<= 4;
532
469k
    }
533
664k
    if (!(x & 0xc0000000)) {
534
315k
        k += 2;
535
315k
        x <<= 2;
536
315k
    }
537
664k
    if (!(x & 0x80000000)) {
538
161k
        k++;
539
161k
        if (!(x & 0x40000000))
540
0
            return 32;
541
161k
    }
542
664k
    return k;
543
664k
}
544
545
/* count trailing 0 bits in the 32-bit integer y, and shift y right by that
546
   number of bits. */
547
548
static int
549
lo0bits(ULong *y)
550
41.7k
{
551
41.7k
    int k;
552
41.7k
    ULong x = *y;
553
554
41.7k
    if (x & 7) {
555
27.0k
        if (x & 1)
556
12.0k
            return 0;
557
15.0k
        if (x & 2) {
558
6.63k
            *y = x >> 1;
559
6.63k
            return 1;
560
6.63k
        }
561
8.38k
        *y = x >> 2;
562
8.38k
        return 2;
563
15.0k
    }
564
14.6k
    k = 0;
565
14.6k
    if (!(x & 0xffff)) {
566
7.40k
        k = 16;
567
7.40k
        x >>= 16;
568
7.40k
    }
569
14.6k
    if (!(x & 0xff)) {
570
3.65k
        k += 8;
571
3.65k
        x >>= 8;
572
3.65k
    }
573
14.6k
    if (!(x & 0xf)) {
574
8.03k
        k += 4;
575
8.03k
        x >>= 4;
576
8.03k
    }
577
14.6k
    if (!(x & 0x3)) {
578
7.45k
        k += 2;
579
7.45k
        x >>= 2;
580
7.45k
    }
581
14.6k
    if (!(x & 1)) {
582
8.60k
        k++;
583
8.60k
        x >>= 1;
584
8.60k
        if (!x)
585
0
            return 32;
586
8.60k
    }
587
14.6k
    *y = x;
588
14.6k
    return k;
589
14.6k
}
590
591
/* convert a small nonnegative integer to a Bigint */
592
593
static Bigint *
594
i2b(int i)
595
568k
{
596
568k
    Bigint *b;
597
598
568k
    b = Balloc(1);
599
568k
    if (b == NULL)
600
0
        return NULL;
601
568k
    b->x[0] = i;
602
568k
    b->wds = 1;
603
568k
    return b;
604
568k
}
605
606
/* multiply two Bigints.  Returns a new Bigint, or NULL on failure.  Ignores
607
   the signs of a and b. */
608
609
static Bigint *
610
mult(Bigint *a, Bigint *b)
611
1.61M
{
612
1.61M
    Bigint *c;
613
1.61M
    int k, wa, wb, wc;
614
1.61M
    ULong *x, *xa, *xae, *xb, *xbe, *xc, *xc0;
615
1.61M
    ULong y;
616
1.61M
    ULLong carry, z;
617
618
1.61M
    if ((!a->x[0] && a->wds == 1) || (!b->x[0] && b->wds == 1)) {
619
5.49k
        c = Balloc(0);
620
5.49k
        if (c == NULL)
621
0
            return NULL;
622
5.49k
        c->wds = 1;
623
5.49k
        c->x[0] = 0;
624
5.49k
        return c;
625
5.49k
    }
626
627
1.61M
    if (a->wds < b->wds) {
628
880k
        c = a;
629
880k
        a = b;
630
880k
        b = c;
631
880k
    }
632
1.61M
    k = a->k;
633
1.61M
    wa = a->wds;
634
1.61M
    wb = b->wds;
635
1.61M
    wc = wa + wb;
636
1.61M
    if (wc > a->maxwds)
637
1.03M
        k++;
638
1.61M
    c = Balloc(k);
639
1.61M
    if (c == NULL)
640
0
        return NULL;
641
10.8M
    for(x = c->x, xa = x + wc; x < xa; x++)
642
9.21M
        *x = 0;
643
1.61M
    xa = a->x;
644
1.61M
    xae = xa + wa;
645
1.61M
    xb = b->x;
646
1.61M
    xbe = xb + wb;
647
1.61M
    xc0 = c->x;
648
4.77M
    for(; xb < xbe; xc0++) {
649
3.15M
        if ((y = *xb++)) {
650
3.15M
            x = xa;
651
3.15M
            xc = xc0;
652
3.15M
            carry = 0;
653
18.7M
            do {
654
18.7M
                z = *x++ * (ULLong)y + *xc + carry;
655
18.7M
                carry = z >> 32;
656
18.7M
                *xc++ = (ULong)(z & FFFFFFFF);
657
18.7M
            }
658
18.7M
            while(x < xae);
659
3.15M
            *xc = (ULong)carry;
660
3.15M
        }
661
3.15M
    }
662
2.70M
    for(xc0 = c->x, xc = xc0 + wc; wc > 0 && !*--xc; --wc) ;
663
1.61M
    c->wds = wc;
664
1.61M
    return c;
665
1.61M
}
666
667
#ifndef Py_USING_MEMORY_DEBUGGER
668
669
/* multiply the Bigint b by 5**k.  Returns a pointer to the result, or NULL on
670
   failure; if the returned pointer is distinct from b then the original
671
   Bigint b will have been Bfree'd.   Ignores the sign of b. */
672
673
static Bigint *
674
pow5mult(Bigint *b, int k)
675
522k
{
676
522k
    Bigint *b1, *p5, **p5s;
677
522k
    int i;
678
522k
    static const int p05[3] = { 5, 25, 125 };
679
680
    // For double-to-string conversion, the maximum value of k is limited by
681
    // DBL_MAX_10_EXP (308), the maximum decimal base-10 exponent for binary64.
682
    // For string-to-double conversion, the extreme case is constrained by our
683
    // hardcoded exponent limit before we underflow of -512, adjusted by
684
    // STRTOD_DIGLIM-DBL_DIG-1, giving a maximum of k=535.
685
522k
    assert(0 <= k && k < 1024);
686
687
522k
    if ((i = k & 3)) {
688
172k
        b = multadd(b, p05[i-1], 0);
689
172k
        if (b == NULL)
690
0
            return NULL;
691
172k
    }
692
693
522k
    if (!(k >>= 2))
694
13.5k
        return b;
695
508k
    PyInterpreterState *interp = _PyInterpreterState_GET();
696
508k
    p5s = interp->dtoa.p5s;
697
2.38M
    for(;;) {
698
2.38M
        assert(p5s != interp->dtoa.p5s + Bigint_Pow5size);
699
2.38M
        p5 = *p5s;
700
2.38M
        p5s++;
701
2.38M
        if (k & 1) {
702
1.53M
            b1 = mult(b, p5);
703
1.53M
            Bfree(b);
704
1.53M
            b = b1;
705
1.53M
            if (b == NULL)
706
0
                return NULL;
707
1.53M
        }
708
2.38M
        if (!(k >>= 1))
709
508k
            break;
710
2.38M
    }
711
508k
    return b;
712
508k
}
713
714
#else
715
716
/* Version of pow5mult that doesn't cache powers of 5. Provided for
717
   the benefit of memory debugging tools like Valgrind. */
718
719
static Bigint *
720
pow5mult(Bigint *b, int k)
721
{
722
    Bigint *b1, *p5, *p51;
723
    int i;
724
    static const int p05[3] = { 5, 25, 125 };
725
726
    if ((i = k & 3)) {
727
        b = multadd(b, p05[i-1], 0);
728
        if (b == NULL)
729
            return NULL;
730
    }
731
732
    if (!(k >>= 2))
733
        return b;
734
    p5 = i2b(625);
735
    if (p5 == NULL) {
736
        Bfree(b);
737
        return NULL;
738
    }
739
740
    for(;;) {
741
        if (k & 1) {
742
            b1 = mult(b, p5);
743
            Bfree(b);
744
            b = b1;
745
            if (b == NULL) {
746
                Bfree(p5);
747
                return NULL;
748
            }
749
        }
750
        if (!(k >>= 1))
751
            break;
752
        p51 = mult(p5, p5);
753
        Bfree(p5);
754
        p5 = p51;
755
        if (p5 == NULL) {
756
            Bfree(b);
757
            return NULL;
758
        }
759
    }
760
    Bfree(p5);
761
    return b;
762
}
763
764
#endif /* Py_USING_MEMORY_DEBUGGER */
765
766
/* shift a Bigint b left by k bits.  Return a pointer to the shifted result,
767
   or NULL on failure.  If the returned pointer is distinct from b then the
768
   original b will have been Bfree'd.   Ignores the sign of b. */
769
770
static Bigint *
771
lshift(Bigint *b, int k)
772
1.12M
{
773
1.12M
    int i, k1, n, n1;
774
1.12M
    Bigint *b1;
775
1.12M
    ULong *x, *x1, *xe, z;
776
777
1.12M
    if (!k || (!b->x[0] && b->wds == 1))
778
6.05k
        return b;
779
780
1.12M
    n = k >> 5;
781
1.12M
    k1 = b->k;
782
1.12M
    n1 = n + b->wds + 1;
783
3.05M
    for(i = b->maxwds; n1 > i; i <<= 1)
784
1.93M
        k1++;
785
1.12M
    b1 = Balloc(k1);
786
1.12M
    if (b1 == NULL) {
787
0
        Bfree(b);
788
0
        return NULL;
789
0
    }
790
1.12M
    x1 = b1->x;
791
6.09M
    for(i = 0; i < n; i++)
792
4.96M
        *x1++ = 0;
793
1.12M
    x = b->x;
794
1.12M
    xe = x + b->wds;
795
1.12M
    if (k &= 0x1f) {
796
1.10M
        k1 = 32 - k;
797
1.10M
        z = 0;
798
3.08M
        do {
799
3.08M
            *x1++ = *x << k | z;
800
3.08M
            z = *x++ >> k1;
801
3.08M
        }
802
3.08M
        while(x < xe);
803
1.10M
        if ((*x1 = z))
804
290k
            ++n1;
805
1.10M
    }
806
22.2k
    else do
807
41.1k
             *x1++ = *x++;
808
41.1k
        while(x < xe);
809
1.12M
    b1->wds = n1 - 1;
810
1.12M
    Bfree(b);
811
1.12M
    return b1;
812
1.12M
}
813
814
/* Do a three-way compare of a and b, returning -1 if a < b, 0 if a == b and
815
   1 if a > b.  Ignores signs of a and b. */
816
817
static int
818
cmp(Bigint *a, Bigint *b)
819
1.93M
{
820
1.93M
    ULong *xa, *xa0, *xb, *xb0;
821
1.93M
    int i, j;
822
823
1.93M
    i = a->wds;
824
1.93M
    j = b->wds;
825
#ifdef DEBUG
826
    if (i > 1 && !a->x[i-1])
827
        Bug("cmp called with a->x[a->wds-1] == 0");
828
    if (j > 1 && !b->x[j-1])
829
        Bug("cmp called with b->x[b->wds-1] == 0");
830
#endif
831
1.93M
    if (i -= j)
832
188k
        return i;
833
1.74M
    xa0 = a->x;
834
1.74M
    xa = xa0 + j;
835
1.74M
    xb0 = b->x;
836
1.74M
    xb = xb0 + j;
837
2.56M
    for(;;) {
838
2.56M
        if (*--xa != *--xb)
839
1.72M
            return *xa < *xb ? -1 : 1;
840
843k
        if (xa <= xa0)
841
21.2k
            break;
842
843k
    }
843
21.2k
    return 0;
844
1.74M
}
845
846
/* Take the difference of Bigints a and b, returning a new Bigint.  Returns
847
   NULL on failure.  The signs of a and b are ignored, but the sign of the
848
   result is set appropriately. */
849
850
static Bigint *
851
diff(Bigint *a, Bigint *b)
852
609k
{
853
609k
    Bigint *c;
854
609k
    int i, wa, wb;
855
609k
    ULong *xa, *xae, *xb, *xbe, *xc;
856
609k
    ULLong borrow, y;
857
858
609k
    i = cmp(a,b);
859
609k
    if (!i) {
860
3.58k
        c = Balloc(0);
861
3.58k
        if (c == NULL)
862
0
            return NULL;
863
3.58k
        c->wds = 1;
864
3.58k
        c->x[0] = 0;
865
3.58k
        return c;
866
3.58k
    }
867
605k
    if (i < 0) {
868
90.2k
        c = a;
869
90.2k
        a = b;
870
90.2k
        b = c;
871
90.2k
        i = 1;
872
90.2k
    }
873
515k
    else
874
515k
        i = 0;
875
605k
    c = Balloc(a->k);
876
605k
    if (c == NULL)
877
0
        return NULL;
878
605k
    c->sign = i;
879
605k
    wa = a->wds;
880
605k
    xa = a->x;
881
605k
    xae = xa + wa;
882
605k
    wb = b->wds;
883
605k
    xb = b->x;
884
605k
    xbe = xb + wb;
885
605k
    xc = c->x;
886
605k
    borrow = 0;
887
4.48M
    do {
888
4.48M
        y = (ULLong)*xa++ - *xb++ - borrow;
889
4.48M
        borrow = y >> 32 & (ULong)1;
890
4.48M
        *xc++ = (ULong)(y & FFFFFFFF);
891
4.48M
    }
892
4.48M
    while(xb < xbe);
893
845k
    while(xa < xae) {
894
239k
        y = *xa++ - borrow;
895
239k
        borrow = y >> 32 & (ULong)1;
896
239k
        *xc++ = (ULong)(y & FFFFFFFF);
897
239k
    }
898
1.37M
    while(!*--xc)
899
766k
        wa--;
900
605k
    c->wds = wa;
901
605k
    return c;
902
605k
}
903
904
/* Given a positive normal double x, return the difference between x and the
905
   next double up.  Doesn't give correct results for subnormals. */
906
907
static double
908
ulp(U *x)
909
306k
{
910
306k
    Long L;
911
306k
    U u;
912
913
306k
    L = (word0(x) & Exp_mask) - (P-1)*Exp_msk1;
914
306k
    word0(&u) = L;
915
306k
    word1(&u) = 0;
916
306k
    return dval(&u);
917
306k
}
918
919
/* Convert a Bigint to a double plus an exponent */
920
921
static double
922
b2d(Bigint *a, int *e)
923
602k
{
924
602k
    ULong *xa, *xa0, w, y, z;
925
602k
    int k;
926
602k
    U d;
927
928
602k
    xa0 = a->x;
929
602k
    xa = xa0 + a->wds;
930
602k
    y = *--xa;
931
#ifdef DEBUG
932
    if (!y) Bug("zero y in b2d");
933
#endif
934
602k
    k = hi0bits(y);
935
602k
    *e = 32 - k;
936
602k
    if (k < Ebits) {
937
358k
        word0(&d) = Exp_1 | y >> (Ebits - k);
938
358k
        w = xa > xa0 ? *--xa : 0;
939
358k
        word1(&d) = y << ((32-Ebits) + k) | w >> (Ebits - k);
940
358k
        goto ret_d;
941
358k
    }
942
244k
    z = xa > xa0 ? *--xa : 0;
943
244k
    if (k -= Ebits) {
944
238k
        word0(&d) = Exp_1 | y << k | z >> (32 - k);
945
238k
        y = xa > xa0 ? *--xa : 0;
946
238k
        word1(&d) = z << k | y >> (32 - k);
947
238k
    }
948
6.13k
    else {
949
6.13k
        word0(&d) = Exp_1 | y;
950
6.13k
        word1(&d) = z;
951
6.13k
    }
952
602k
  ret_d:
953
602k
    return dval(&d);
954
244k
}
955
956
/* Convert a scaled double to a Bigint plus an exponent.  Similar to d2b,
957
   except that it accepts the scale parameter used in _Py_dg_strtod (which
958
   should be either 0 or 2*P), and the normalization for the return value is
959
   different (see below).  On input, d should be finite and nonnegative, and d
960
   / 2**scale should be exactly representable as an IEEE 754 double.
961
962
   Returns a Bigint b and an integer e such that
963
964
     dval(d) / 2**scale = b * 2**e.
965
966
   Unlike d2b, b is not necessarily odd: b and e are normalized so
967
   that either 2**(P-1) <= b < 2**P and e >= Etiny, or b < 2**P
968
   and e == Etiny.  This applies equally to an input of 0.0: in that
969
   case the return values are b = 0 and e = Etiny.
970
971
   The above normalization ensures that for all possible inputs d,
972
   2**e gives ulp(d/2**scale).
973
974
   Returns NULL on failure.
975
*/
976
977
static Bigint *
978
sd2b(U *d, int scale, int *e)
979
503k
{
980
503k
    Bigint *b;
981
982
503k
    b = Balloc(1);
983
503k
    if (b == NULL)
984
0
        return NULL;
985
986
    /* First construct b and e assuming that scale == 0. */
987
503k
    b->wds = 2;
988
503k
    b->x[0] = word1(d);
989
503k
    b->x[1] = word0(d) & Frac_mask;
990
503k
    *e = Etiny - 1 + (int)((word0(d) & Exp_mask) >> Exp_shift);
991
503k
    if (*e < Etiny)
992
6.05k
        *e = Etiny;
993
497k
    else
994
497k
        b->x[1] |= Exp_msk1;
995
996
    /* Now adjust for scale, provided that b != 0. */
997
503k
    if (scale && (b->x[0] || b->x[1])) {
998
37.1k
        *e -= scale;
999
37.1k
        if (*e < Etiny) {
1000
31.5k
            scale = Etiny - *e;
1001
31.5k
            *e = Etiny;
1002
            /* We can't shift more than P-1 bits without shifting out a 1. */
1003
31.5k
            assert(0 < scale && scale <= P - 1);
1004
31.5k
            if (scale >= 32) {
1005
                /* The bits shifted out should all be zero. */
1006
17.1k
                assert(b->x[0] == 0);
1007
17.1k
                b->x[0] = b->x[1];
1008
17.1k
                b->x[1] = 0;
1009
17.1k
                scale -= 32;
1010
17.1k
            }
1011
31.5k
            if (scale) {
1012
                /* The bits shifted out should all be zero. */
1013
26.5k
                assert(b->x[0] << (32 - scale) == 0);
1014
26.5k
                b->x[0] = (b->x[0] >> scale) | (b->x[1] << (32 - scale));
1015
26.5k
                b->x[1] >>= scale;
1016
26.5k
            }
1017
31.5k
        }
1018
37.1k
    }
1019
    /* Ensure b is normalized. */
1020
503k
    if (!b->x[1])
1021
26.9k
        b->wds = 1;
1022
1023
503k
    return b;
1024
503k
}
1025
1026
/* Convert a double to a Bigint plus an exponent.  Return NULL on failure.
1027
1028
   Given a finite nonzero double d, return an odd Bigint b and exponent *e
1029
   such that fabs(d) = b * 2**e.  On return, *bbits gives the number of
1030
   significant bits of b; that is, 2**(*bbits-1) <= b < 2**(*bbits).
1031
1032
   If d is zero, then b == 0, *e == -1010, *bbits = 0.
1033
 */
1034
1035
static Bigint *
1036
d2b(U *d, int *e, int *bits)
1037
41.7k
{
1038
41.7k
    Bigint *b;
1039
41.7k
    int de, k;
1040
41.7k
    ULong *x, y, z;
1041
41.7k
    int i;
1042
1043
41.7k
    b = Balloc(1);
1044
41.7k
    if (b == NULL)
1045
0
        return NULL;
1046
41.7k
    x = b->x;
1047
1048
41.7k
    z = word0(d) & Frac_mask;
1049
41.7k
    word0(d) &= 0x7fffffff;   /* clear sign bit, which we ignore */
1050
41.7k
    if ((de = (int)(word0(d) >> Exp_shift)))
1051
36.9k
        z |= Exp_msk1;
1052
41.7k
    if ((y = word1(d))) {
1053
31.6k
        if ((k = lo0bits(&y))) {
1054
20.2k
            x[0] = y | z << (32 - k);
1055
20.2k
            z >>= k;
1056
20.2k
        }
1057
11.3k
        else
1058
11.3k
            x[0] = y;
1059
31.6k
        i =
1060
31.6k
            b->wds = (x[1] = z) ? 2 : 1;
1061
31.6k
    }
1062
10.1k
    else {
1063
10.1k
        k = lo0bits(&z);
1064
10.1k
        x[0] = z;
1065
10.1k
        i =
1066
10.1k
            b->wds = 1;
1067
10.1k
        k += 32;
1068
10.1k
    }
1069
41.7k
    if (de) {
1070
36.9k
        *e = de - Bias - (P-1) + k;
1071
36.9k
        *bits = P - k;
1072
36.9k
    }
1073
4.84k
    else {
1074
4.84k
        *e = de - Bias - (P-1) + 1 + k;
1075
4.84k
        *bits = 32*i - hi0bits(x[i-1]);
1076
4.84k
    }
1077
41.7k
    return b;
1078
41.7k
}
1079
1080
/* Compute the ratio of two Bigints, as a double.  The result may have an
1081
   error of up to 2.5 ulps. */
1082
1083
static double
1084
ratio(Bigint *a, Bigint *b)
1085
301k
{
1086
301k
    U da, db;
1087
301k
    int k, ka, kb;
1088
1089
301k
    dval(&da) = b2d(a, &ka);
1090
301k
    dval(&db) = b2d(b, &kb);
1091
301k
    k = ka - kb + 32*(a->wds - b->wds);
1092
301k
    if (k > 0)
1093
46.2k
        word0(&da) += k*Exp_msk1;
1094
255k
    else {
1095
255k
        k = -k;
1096
255k
        word0(&db) += k*Exp_msk1;
1097
255k
    }
1098
301k
    return dval(&da) / dval(&db);
1099
301k
}
1100
1101
static const double
1102
tens[] = {
1103
    1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
1104
    1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
1105
    1e20, 1e21, 1e22
1106
};
1107
1108
static const double
1109
bigtens[] = { 1e16, 1e32, 1e64, 1e128, 1e256 };
1110
static const double tinytens[] = { 1e-16, 1e-32, 1e-64, 1e-128,
1111
                                   9007199254740992.*9007199254740992.e-256
1112
                                   /* = 2^106 * 1e-256 */
1113
};
1114
/* The factor of 2^53 in tinytens[4] helps us avoid setting the underflow */
1115
/* flag unnecessarily.  It leads to a song and dance at the end of strtod. */
1116
37.7k
#define Scale_Bit 0x10
1117
43.5k
#define n_bigtens 5
1118
1119
#define ULbits 32
1120
#define kshift 5
1121
56.4k
#define kmask 31
1122
1123
1124
static int
1125
dshift(Bigint *b, int p2)
1126
56.4k
{
1127
56.4k
    int rv = hi0bits(b->x[b->wds-1]) - 4;
1128
56.4k
    if (p2 > 0)
1129
24.8k
        rv -= p2;
1130
56.4k
    return rv & kmask;
1131
56.4k
}
1132
1133
/* special case of Bigint division.  The quotient is always in the range 0 <=
1134
   quotient < 10, and on entry the divisor S is normalized so that its top 4
1135
   bits (28--31) are zero and bit 27 is set. */
1136
1137
static int
1138
quorem(Bigint *b, Bigint *S)
1139
547k
{
1140
547k
    int n;
1141
547k
    ULong *bx, *bxe, q, *sx, *sxe;
1142
547k
    ULLong borrow, carry, y, ys;
1143
1144
547k
    n = S->wds;
1145
#ifdef DEBUG
1146
    /*debug*/ if (b->wds > n)
1147
        /*debug*/       Bug("oversize b in quorem");
1148
#endif
1149
547k
    if (b->wds < n)
1150
14.1k
        return 0;
1151
533k
    sx = S->x;
1152
533k
    sxe = sx + --n;
1153
533k
    bx = b->x;
1154
533k
    bxe = bx + n;
1155
533k
    q = *bxe / (*sxe + 1);      /* ensure q <= true quotient */
1156
#ifdef DEBUG
1157
    /*debug*/ if (q > 9)
1158
        /*debug*/       Bug("oversized quotient in quorem");
1159
#endif
1160
533k
    if (q) {
1161
366k
        borrow = 0;
1162
366k
        carry = 0;
1163
2.03M
        do {
1164
2.03M
            ys = *sx++ * (ULLong)q + carry;
1165
2.03M
            carry = ys >> 32;
1166
2.03M
            y = *bx - (ys & FFFFFFFF) - borrow;
1167
2.03M
            borrow = y >> 32 & (ULong)1;
1168
2.03M
            *bx++ = (ULong)(y & FFFFFFFF);
1169
2.03M
        }
1170
2.03M
        while(sx <= sxe);
1171
366k
        if (!*bxe) {
1172
2.41k
            bx = b->x;
1173
2.41k
            while(--bxe > bx && !*bxe)
1174
0
                --n;
1175
2.41k
            b->wds = n;
1176
2.41k
        }
1177
366k
    }
1178
533k
    if (cmp(b, S) >= 0) {
1179
29.3k
        q++;
1180
29.3k
        borrow = 0;
1181
29.3k
        carry = 0;
1182
29.3k
        bx = b->x;
1183
29.3k
        sx = S->x;
1184
171k
        do {
1185
171k
            ys = *sx++ + carry;
1186
171k
            carry = ys >> 32;
1187
171k
            y = *bx - (ys & FFFFFFFF) - borrow;
1188
171k
            borrow = y >> 32 & (ULong)1;
1189
171k
            *bx++ = (ULong)(y & FFFFFFFF);
1190
171k
        }
1191
171k
        while(sx <= sxe);
1192
29.3k
        bx = b->x;
1193
29.3k
        bxe = bx + n;
1194
29.3k
        if (!*bxe) {
1195
20.8k
            while(--bxe > bx && !*bxe)
1196
1.20k
                --n;
1197
19.6k
            b->wds = n;
1198
19.6k
        }
1199
29.3k
    }
1200
533k
    return q;
1201
547k
}
1202
1203
/* sulp(x) is a version of ulp(x) that takes bc.scale into account.
1204
1205
   Assuming that x is finite and nonnegative (positive zero is fine
1206
   here) and x / 2^bc.scale is exactly representable as a double,
1207
   sulp(x) is equivalent to 2^bc.scale * ulp(x / 2^bc.scale). */
1208
1209
static double
1210
sulp(U *x, BCinfo *bc)
1211
4.97k
{
1212
4.97k
    U u;
1213
1214
4.97k
    if (bc->scale && 2*P + 1 > (int)((word0(x) & Exp_mask) >> Exp_shift)) {
1215
        /* rv/2^bc->scale is subnormal */
1216
268
        word0(&u) = (P+2)*Exp_msk1;
1217
268
        word1(&u) = 0;
1218
268
        return u.d;
1219
268
    }
1220
4.71k
    else {
1221
4.71k
        assert(word0(x) || word1(x)); /* x != 0.0 */
1222
4.71k
        return ulp(x);
1223
4.71k
    }
1224
4.97k
}
1225
1226
/* The bigcomp function handles some hard cases for strtod, for inputs
1227
   with more than STRTOD_DIGLIM digits.  It's called once an initial
1228
   estimate for the double corresponding to the input string has
1229
   already been obtained by the code in _Py_dg_strtod.
1230
1231
   The bigcomp function is only called after _Py_dg_strtod has found a
1232
   double value rv such that either rv or rv + 1ulp represents the
1233
   correctly rounded value corresponding to the original string.  It
1234
   determines which of these two values is the correct one by
1235
   computing the decimal digits of rv + 0.5ulp and comparing them with
1236
   the corresponding digits of s0.
1237
1238
   In the following, write dv for the absolute value of the number represented
1239
   by the input string.
1240
1241
   Inputs:
1242
1243
     s0 points to the first significant digit of the input string.
1244
1245
     rv is a (possibly scaled) estimate for the closest double value to the
1246
        value represented by the original input to _Py_dg_strtod.  If
1247
        bc->scale is nonzero, then rv/2^(bc->scale) is the approximation to
1248
        the input value.
1249
1250
     bc is a struct containing information gathered during the parsing and
1251
        estimation steps of _Py_dg_strtod.  Description of fields follows:
1252
1253
        bc->e0 gives the exponent of the input value, such that dv = (integer
1254
           given by the bd->nd digits of s0) * 10**e0
1255
1256
        bc->nd gives the total number of significant digits of s0.  It will
1257
           be at least 1.
1258
1259
        bc->nd0 gives the number of significant digits of s0 before the
1260
           decimal separator.  If there's no decimal separator, bc->nd0 ==
1261
           bc->nd.
1262
1263
        bc->scale is the value used to scale rv to avoid doing arithmetic with
1264
           subnormal values.  It's either 0 or 2*P (=106).
1265
1266
   Outputs:
1267
1268
     On successful exit, rv/2^(bc->scale) is the closest double to dv.
1269
1270
     Returns 0 on success, -1 on failure (e.g., due to a failed malloc call). */
1271
1272
static int
1273
bigcomp(U *rv, const char *s0, BCinfo *bc)
1274
23.8k
{
1275
23.8k
    Bigint *b, *d;
1276
23.8k
    int b2, d2, dd, i, nd, nd0, odd, p2, p5;
1277
1278
23.8k
    nd = bc->nd;
1279
23.8k
    nd0 = bc->nd0;
1280
23.8k
    p5 = nd + bc->e0;
1281
23.8k
    b = sd2b(rv, bc->scale, &p2);
1282
23.8k
    if (b == NULL)
1283
0
        return -1;
1284
1285
    /* record whether the lsb of rv/2^(bc->scale) is odd:  in the exact halfway
1286
       case, this is used for round to even. */
1287
23.8k
    odd = b->x[0] & 1;
1288
1289
    /* left shift b by 1 bit and or a 1 into the least significant bit;
1290
       this gives us b * 2**p2 = rv/2^(bc->scale) + 0.5 ulp. */
1291
23.8k
    b = lshift(b, 1);
1292
23.8k
    if (b == NULL)
1293
0
        return -1;
1294
23.8k
    b->x[0] |= 1;
1295
23.8k
    p2--;
1296
1297
23.8k
    p2 -= p5;
1298
23.8k
    d = i2b(1);
1299
23.8k
    if (d == NULL) {
1300
0
        Bfree(b);
1301
0
        return -1;
1302
0
    }
1303
    /* Arrange for convenient computation of quotients:
1304
     * shift left if necessary so divisor has 4 leading 0 bits.
1305
     */
1306
23.8k
    if (p5 > 0) {
1307
21.1k
        d = pow5mult(d, p5);
1308
21.1k
        if (d == NULL) {
1309
0
            Bfree(b);
1310
0
            return -1;
1311
0
        }
1312
21.1k
    }
1313
2.72k
    else if (p5 < 0) {
1314
1.82k
        b = pow5mult(b, -p5);
1315
1.82k
        if (b == NULL) {
1316
0
            Bfree(d);
1317
0
            return -1;
1318
0
        }
1319
1.82k
    }
1320
23.8k
    if (p2 > 0) {
1321
18.6k
        b2 = p2;
1322
18.6k
        d2 = 0;
1323
18.6k
    }
1324
5.22k
    else {
1325
5.22k
        b2 = 0;
1326
5.22k
        d2 = -p2;
1327
5.22k
    }
1328
23.8k
    i = dshift(d, d2);
1329
23.8k
    if ((b2 += i) > 0) {
1330
23.5k
        b = lshift(b, b2);
1331
23.5k
        if (b == NULL) {
1332
0
            Bfree(d);
1333
0
            return -1;
1334
0
        }
1335
23.5k
    }
1336
23.8k
    if ((d2 += i) > 0) {
1337
22.7k
        d = lshift(d, d2);
1338
22.7k
        if (d == NULL) {
1339
0
            Bfree(b);
1340
0
            return -1;
1341
0
        }
1342
22.7k
    }
1343
1344
    /* Compare s0 with b/d: set dd to -1, 0, or 1 according as s0 < b/d, s0 ==
1345
     * b/d, or s0 > b/d.  Here the digits of s0 are thought of as representing
1346
     * a number in the range [0.1, 1). */
1347
23.8k
    if (cmp(b, d) >= 0)
1348
        /* b/d >= 1 */
1349
897
        dd = -1;
1350
22.9k
    else {
1351
22.9k
        i = 0;
1352
418k
        for(;;) {
1353
418k
            b = multadd(b, 10, 0);
1354
418k
            if (b == NULL) {
1355
0
                Bfree(d);
1356
0
                return -1;
1357
0
            }
1358
418k
            dd = s0[i < nd0 ? i : i+1] - '0' - quorem(b, d);
1359
418k
            i++;
1360
1361
418k
            if (dd)
1362
20.5k
                break;
1363
398k
            if (!b->x[0] && b->wds == 1) {
1364
                /* b/d == 0 */
1365
1.45k
                dd = i < nd;
1366
1.45k
                break;
1367
1.45k
            }
1368
396k
            if (!(i < nd)) {
1369
                /* b/d != 0, but digits of s0 exhausted */
1370
976
                dd = -1;
1371
976
                break;
1372
976
            }
1373
396k
        }
1374
22.9k
    }
1375
23.8k
    Bfree(b);
1376
23.8k
    Bfree(d);
1377
23.8k
    if (dd > 0 || (dd == 0 && odd))
1378
2.99k
        dval(rv) += sulp(rv, bc);
1379
23.8k
    return 0;
1380
23.8k
}
1381
1382
1383
double
1384
_Py_dg_strtod(const char *s00, char **se)
1385
925k
{
1386
925k
    int bb2, bb5, bbe, bd2, bd5, bs2, c, dsign, e, e1, error;
1387
925k
    int esign, i, j, k, lz, nd, nd0, odd, sign;
1388
925k
    const char *s, *s0, *s1;
1389
925k
    double aadj, aadj1;
1390
925k
    U aadj2, adj, rv, rv0;
1391
925k
    ULong y, z, abs_exp;
1392
925k
    Long L;
1393
925k
    BCinfo bc;
1394
925k
    Bigint *bb = NULL, *bd = NULL, *bd0 = NULL, *bs = NULL, *delta = NULL;
1395
925k
    size_t ndigits, fraclen;
1396
925k
    double result;
1397
1398
925k
    dval(&rv) = 0.;
1399
1400
    /* Start parsing. */
1401
925k
    c = *(s = s00);
1402
1403
    /* Parse optional sign, if present. */
1404
925k
    sign = 0;
1405
925k
    switch (c) {
1406
296k
    case '-':
1407
296k
        sign = 1;
1408
296k
        _Py_FALLTHROUGH;
1409
297k
    case '+':
1410
297k
        c = *++s;
1411
925k
    }
1412
1413
    /* Skip leading zeros: lz is true iff there were leading zeros. */
1414
925k
    s1 = s;
1415
949k
    while (c == '0')
1416
23.5k
        c = *++s;
1417
925k
    lz = s != s1;
1418
1419
    /* Point s0 at the first nonzero digit (if any).  fraclen will be the
1420
       number of digits between the decimal point and the end of the
1421
       digit string.  ndigits will be the total number of digits ignoring
1422
       leading zeros. */
1423
925k
    s0 = s1 = s;
1424
6.76M
    while ('0' <= c && c <= '9')
1425
5.83M
        c = *++s;
1426
925k
    ndigits = s - s1;
1427
925k
    fraclen = 0;
1428
1429
    /* Parse decimal point and following digits. */
1430
925k
    if (c == '.') {
1431
78.5k
        c = *++s;
1432
78.5k
        if (!ndigits) {
1433
24.7k
            s1 = s;
1434
172k
            while (c == '0')
1435
147k
                c = *++s;
1436
24.7k
            lz = lz || s != s1;
1437
24.7k
            fraclen += (s - s1);
1438
24.7k
            s0 = s;
1439
24.7k
        }
1440
78.5k
        s1 = s;
1441
32.3M
        while ('0' <= c && c <= '9')
1442
32.3M
            c = *++s;
1443
78.5k
        ndigits += s - s1;
1444
78.5k
        fraclen += s - s1;
1445
78.5k
    }
1446
1447
    /* Now lz is true if and only if there were leading zero digits, and
1448
       ndigits gives the total number of digits ignoring leading zeros.  A
1449
       valid input must have at least one digit. */
1450
925k
    if (!ndigits && !lz) {
1451
61.3k
        if (se)
1452
61.3k
            *se = (char *)s00;
1453
61.3k
        goto parse_error;
1454
61.3k
    }
1455
1456
    /* Range check ndigits and fraclen to make sure that they, and values
1457
       computed with them, can safely fit in an int. */
1458
864k
    if (ndigits > MAX_DIGITS || fraclen > MAX_DIGITS) {
1459
0
        if (se)
1460
0
            *se = (char *)s00;
1461
0
        goto parse_error;
1462
0
    }
1463
864k
    nd = (int)ndigits;
1464
864k
    nd0 = (int)ndigits - (int)fraclen;
1465
1466
    /* Parse exponent. */
1467
864k
    e = 0;
1468
864k
    if (c == 'e' || c == 'E') {
1469
786k
        s00 = s;
1470
786k
        c = *++s;
1471
1472
        /* Exponent sign. */
1473
786k
        esign = 0;
1474
786k
        switch (c) {
1475
43.1k
        case '-':
1476
43.1k
            esign = 1;
1477
43.1k
            _Py_FALLTHROUGH;
1478
58.1k
        case '+':
1479
58.1k
            c = *++s;
1480
786k
        }
1481
1482
        /* Skip zeros.  lz is true iff there are leading zeros. */
1483
786k
        s1 = s;
1484
1.02M
        while (c == '0')
1485
239k
            c = *++s;
1486
786k
        lz = s != s1;
1487
1488
        /* Get absolute value of the exponent. */
1489
786k
        s1 = s;
1490
786k
        abs_exp = 0;
1491
13.2M
        while ('0' <= c && c <= '9') {
1492
12.4M
            abs_exp = 10*abs_exp + (c - '0');
1493
12.4M
            c = *++s;
1494
12.4M
        }
1495
1496
        /* abs_exp will be correct modulo 2**32.  But 10**9 < 2**32, so if
1497
           there are at most 9 significant exponent digits then overflow is
1498
           impossible. */
1499
786k
        if (s - s1 > 9 || abs_exp > MAX_ABS_EXP)
1500
10.3k
            e = (int)MAX_ABS_EXP;
1501
776k
        else
1502
776k
            e = (int)abs_exp;
1503
786k
        if (esign)
1504
43.1k
            e = -e;
1505
1506
        /* A valid exponent must have at least one digit. */
1507
786k
        if (s == s1 && !lz)
1508
0
            s = s00;
1509
786k
    }
1510
1511
    /* Adjust exponent to take into account position of the point. */
1512
864k
    e -= nd - nd0;
1513
864k
    if (nd0 <= 0)
1514
30.2k
        nd0 = nd;
1515
1516
    /* Finished parsing.  Set se to indicate how far we parsed */
1517
864k
    if (se)
1518
864k
        *se = (char *)s;
1519
1520
    /* If all digits were zero, exit with return value +-0.0.  Otherwise,
1521
       strip trailing zeros: scan back until we hit a nonzero digit. */
1522
864k
    if (!nd)
1523
12.8k
        goto ret;
1524
9.55M
    for (i = nd; i > 0; ) {
1525
9.55M
        --i;
1526
9.55M
        if (s0[i < nd0 ? i : i+1] != '0') {
1527
851k
            ++i;
1528
851k
            break;
1529
851k
        }
1530
9.55M
    }
1531
851k
    e += nd - i;
1532
851k
    nd = i;
1533
851k
    if (nd0 > nd)
1534
20.6k
        nd0 = nd;
1535
1536
    /* Summary of parsing results.  After parsing, and dealing with zero
1537
     * inputs, we have values s0, nd0, nd, e, sign, where:
1538
     *
1539
     *  - s0 points to the first significant digit of the input string
1540
     *
1541
     *  - nd is the total number of significant digits (here, and
1542
     *    below, 'significant digits' means the set of digits of the
1543
     *    significand of the input that remain after ignoring leading
1544
     *    and trailing zeros).
1545
     *
1546
     *  - nd0 indicates the position of the decimal point, if present; it
1547
     *    satisfies 1 <= nd0 <= nd.  The nd significant digits are in
1548
     *    s0[0:nd0] and s0[nd0+1:nd+1] using the usual Python half-open slice
1549
     *    notation.  (If nd0 < nd, then s0[nd0] contains a '.'  character; if
1550
     *    nd0 == nd, then s0[nd0] could be any non-digit character.)
1551
     *
1552
     *  - e is the adjusted exponent: the absolute value of the number
1553
     *    represented by the original input string is n * 10**e, where
1554
     *    n is the integer represented by the concatenation of
1555
     *    s0[0:nd0] and s0[nd0+1:nd+1]
1556
     *
1557
     *  - sign gives the sign of the input:  1 for negative, 0 for positive
1558
     *
1559
     *  - the first and last significant digits are nonzero
1560
     */
1561
1562
    /* put first DBL_DIG+1 digits into integer y and z.
1563
     *
1564
     *  - y contains the value represented by the first min(9, nd)
1565
     *    significant digits
1566
     *
1567
     *  - if nd > 9, z contains the value represented by significant digits
1568
     *    with indices in [9, min(16, nd)).  So y * 10**(min(16, nd) - 9) + z
1569
     *    gives the value represented by the first min(16, nd) sig. digits.
1570
     */
1571
1572
851k
    bc.e0 = e1 = e;
1573
851k
    y = z = 0;
1574
3.97M
    for (i = 0; i < nd; i++) {
1575
3.17M
        if (i < 9)
1576
2.67M
            y = 10*y + s0[i < nd0 ? i : i+1] - '0';
1577
504k
        else if (i < DBL_DIG+1)
1578
452k
            z = 10*z + s0[i < nd0 ? i : i+1] - '0';
1579
51.3k
        else
1580
51.3k
            break;
1581
3.17M
    }
1582
1583
851k
    k = nd < DBL_DIG + 1 ? nd : DBL_DIG + 1;
1584
851k
    dval(&rv) = y;
1585
851k
    if (k > 9) {
1586
77.8k
        dval(&rv) = tens[k - 9] * dval(&rv) + z;
1587
77.8k
    }
1588
851k
    if (nd <= DBL_DIG
1589
792k
        && Flt_Rounds == 1
1590
851k
        ) {
1591
792k
        if (!e)
1592
15.5k
            goto ret;
1593
776k
        if (e > 0) {
1594
714k
            if (e <= Ten_pmax) {
1595
31.4k
                dval(&rv) *= tens[e];
1596
31.4k
                goto ret;
1597
31.4k
            }
1598
682k
            i = DBL_DIG - nd;
1599
682k
            if (e <= Ten_pmax + i) {
1600
                /* A fancier test would sometimes let us do
1601
                 * this for larger i values.
1602
                 */
1603
3.47k
                e -= i;
1604
3.47k
                dval(&rv) *= tens[i];
1605
3.47k
                dval(&rv) *= tens[e];
1606
3.47k
                goto ret;
1607
3.47k
            }
1608
682k
        }
1609
62.5k
        else if (e >= -Ten_pmax) {
1610
26.6k
            dval(&rv) /= tens[-e];
1611
26.6k
            goto ret;
1612
26.6k
        }
1613
776k
    }
1614
774k
    e1 += nd - k;
1615
1616
774k
    bc.scale = 0;
1617
1618
    /* Get starting approximation = rv * 10**e1 */
1619
1620
774k
    if (e1 > 0) {
1621
716k
        if ((i = e1 & 15))
1622
590k
            dval(&rv) *= tens[i];
1623
716k
        if (e1 &= ~15) {
1624
704k
            if (e1 > DBL_MAX_10_EXP)
1625
326k
                goto ovfl;
1626
377k
            e1 >>= 4;
1627
975k
            for(j = 0; e1 > 1; j++, e1 >>= 1)
1628
598k
                if (e1 & 1)
1629
329k
                    dval(&rv) *= bigtens[j];
1630
            /* The last multiplication could overflow. */
1631
377k
            word0(&rv) -= P*Exp_msk1;
1632
377k
            dval(&rv) *= bigtens[j];
1633
377k
            if ((z = word0(&rv) & Exp_mask)
1634
377k
                > Exp_msk1*(DBL_MAX_EXP+Bias-P))
1635
2.29k
                goto ovfl;
1636
375k
            if (z > Exp_msk1*(DBL_MAX_EXP+Bias-1-P)) {
1637
                /* set to largest number */
1638
                /* (Can't trust DBL_MAX) */
1639
393
                word0(&rv) = Big0;
1640
393
                word1(&rv) = Big1;
1641
393
            }
1642
374k
            else
1643
374k
                word0(&rv) += P*Exp_msk1;
1644
375k
        }
1645
716k
    }
1646
58.1k
    else if (e1 < 0) {
1647
        /* The input decimal value lies in [10**e1, 10**(e1+16)).
1648
1649
           If e1 <= -512, underflow immediately.
1650
           If e1 <= -256, set bc.scale to 2*P.
1651
1652
           So for input value < 1e-256, bc.scale is always set;
1653
           for input value >= 1e-240, bc.scale is never set.
1654
           For input values in [1e-256, 1e-240), bc.scale may or may
1655
           not be set. */
1656
1657
53.7k
        e1 = -e1;
1658
53.7k
        if ((i = e1 & 15))
1659
43.4k
            dval(&rv) /= tens[i];
1660
53.7k
        if (e1 >>= 4) {
1661
43.5k
            if (e1 >= 1 << n_bigtens)
1662
5.80k
                goto undfl;
1663
37.7k
            if (e1 & Scale_Bit)
1664
22.9k
                bc.scale = 2*P;
1665
184k
            for(j = 0; e1 > 0; j++, e1 >>= 1)
1666
146k
                if (e1 & 1)
1667
86.7k
                    dval(&rv) *= tinytens[j];
1668
37.7k
            if (bc.scale && (j = 2*P + 1 - ((word0(&rv) & Exp_mask)
1669
22.9k
                                            >> Exp_shift)) > 0) {
1670
                /* scaled rv is denormal; clear j low bits */
1671
20.3k
                if (j >= 32) {
1672
12.2k
                    word1(&rv) = 0;
1673
12.2k
                    if (j >= 53)
1674
5.92k
                        word0(&rv) = (P+2)*Exp_msk1;
1675
6.31k
                    else
1676
6.31k
                        word0(&rv) &= 0xffffffff << (j-32);
1677
12.2k
                }
1678
8.08k
                else
1679
8.08k
                    word1(&rv) &= 0xffffffff << j;
1680
20.3k
            }
1681
37.7k
            if (!dval(&rv))
1682
0
                goto undfl;
1683
37.7k
        }
1684
53.7k
    }
1685
1686
    /* Now the hard part -- adjusting rv to the correct value.*/
1687
1688
    /* Put digits into bd: true value = bd * 10^e */
1689
1690
439k
    bc.nd = nd;
1691
439k
    bc.nd0 = nd0;       /* Only needed if nd > STRTOD_DIGLIM, but done here */
1692
                        /* to silence an erroneous warning about bc.nd0 */
1693
                        /* possibly not being initialized. */
1694
439k
    if (nd > STRTOD_DIGLIM) {
1695
        /* ASSERT(STRTOD_DIGLIM >= 18); 18 == one more than the */
1696
        /* minimum number of decimal digits to distinguish double values */
1697
        /* in IEEE arithmetic. */
1698
1699
        /* Truncate input to 18 significant digits, then discard any trailing
1700
           zeros on the result by updating nd, nd0, e and y suitably. (There's
1701
           no need to update z; it's not reused beyond this point.) */
1702
238k
        for (i = 18; i > 0; ) {
1703
            /* scan back until we hit a nonzero digit.  significant digit 'i'
1704
            is s0[i] if i < nd0, s0[i+1] if i >= nd0. */
1705
238k
            --i;
1706
238k
            if (s0[i < nd0 ? i : i+1] != '0') {
1707
30.1k
                ++i;
1708
30.1k
                break;
1709
30.1k
            }
1710
238k
        }
1711
30.1k
        e += nd - i;
1712
30.1k
        nd = i;
1713
30.1k
        if (nd0 > nd)
1714
25.6k
            nd0 = nd;
1715
30.1k
        if (nd < 9) { /* must recompute y */
1716
18.3k
            y = 0;
1717
141k
            for(i = 0; i < nd0; ++i)
1718
123k
                y = 10*y + s0[i] - '0';
1719
25.6k
            for(; i < nd; ++i)
1720
7.28k
                y = 10*y + s0[i+1] - '0';
1721
18.3k
        }
1722
30.1k
    }
1723
439k
    bd0 = s2b(s0, nd0, nd, y);
1724
439k
    if (bd0 == NULL)
1725
0
        goto failed_malloc;
1726
1727
    /* Notation for the comments below.  Write:
1728
1729
         - dv for the absolute value of the number represented by the original
1730
           decimal input string.
1731
1732
         - if we've truncated dv, write tdv for the truncated value.
1733
           Otherwise, set tdv == dv.
1734
1735
         - srv for the quantity rv/2^bc.scale; so srv is the current binary
1736
           approximation to tdv (and dv).  It should be exactly representable
1737
           in an IEEE 754 double.
1738
    */
1739
1740
479k
    for(;;) {
1741
1742
        /* This is the main correction loop for _Py_dg_strtod.
1743
1744
           We've got a decimal value tdv, and a floating-point approximation
1745
           srv=rv/2^bc.scale to tdv.  The aim is to determine whether srv is
1746
           close enough (i.e., within 0.5 ulps) to tdv, and to compute a new
1747
           approximation if not.
1748
1749
           To determine whether srv is close enough to tdv, compute integers
1750
           bd, bb and bs proportional to tdv, srv and 0.5 ulp(srv)
1751
           respectively, and then use integer arithmetic to determine whether
1752
           |tdv - srv| is less than, equal to, or greater than 0.5 ulp(srv).
1753
        */
1754
1755
479k
        bd = Balloc(bd0->k);
1756
479k
        if (bd == NULL) {
1757
0
            goto failed_malloc;
1758
0
        }
1759
479k
        Bcopy(bd, bd0);
1760
479k
        bb = sd2b(&rv, bc.scale, &bbe);   /* srv = bb * 2^bbe */
1761
479k
        if (bb == NULL) {
1762
0
            goto failed_malloc;
1763
0
        }
1764
        /* Record whether lsb of bb is odd, in case we need this
1765
           for the round-to-even step later. */
1766
479k
        odd = bb->x[0] & 1;
1767
1768
        /* tdv = bd * 10**e;  srv = bb * 2**bbe */
1769
479k
        bs = i2b(1);
1770
479k
        if (bs == NULL) {
1771
0
            goto failed_malloc;
1772
0
        }
1773
1774
479k
        if (e >= 0) {
1775
407k
            bb2 = bb5 = 0;
1776
407k
            bd2 = bd5 = e;
1777
407k
        }
1778
72.6k
        else {
1779
72.6k
            bb2 = bb5 = -e;
1780
72.6k
            bd2 = bd5 = 0;
1781
72.6k
        }
1782
479k
        if (bbe >= 0)
1783
409k
            bb2 += bbe;
1784
70.0k
        else
1785
70.0k
            bd2 -= bbe;
1786
479k
        bs2 = bb2;
1787
479k
        bb2++;
1788
479k
        bd2++;
1789
1790
        /* At this stage bd5 - bb5 == e == bd2 - bb2 + bbe, bb2 - bs2 == 1,
1791
           and bs == 1, so:
1792
1793
              tdv == bd * 10**e = bd * 2**(bbe - bb2 + bd2) * 5**(bd5 - bb5)
1794
              srv == bb * 2**bbe = bb * 2**(bbe - bb2 + bb2)
1795
              0.5 ulp(srv) == 2**(bbe-1) = bs * 2**(bbe - bb2 + bs2)
1796
1797
           It follows that:
1798
1799
              M * tdv = bd * 2**bd2 * 5**bd5
1800
              M * srv = bb * 2**bb2 * 5**bb5
1801
              M * 0.5 ulp(srv) = bs * 2**bs2 * 5**bb5
1802
1803
           for some constant M.  (Actually, M == 2**(bb2 - bbe) * 5**bb5, but
1804
           this fact is not needed below.)
1805
        */
1806
1807
        /* Remove factor of 2**i, where i = min(bb2, bd2, bs2). */
1808
479k
        i = bb2 < bd2 ? bb2 : bd2;
1809
479k
        if (i > bs2)
1810
69.0k
            i = bs2;
1811
479k
        if (i > 0) {
1812
478k
            bb2 -= i;
1813
478k
            bd2 -= i;
1814
478k
            bs2 -= i;
1815
478k
        }
1816
1817
        /* Scale bb, bd, bs by the appropriate powers of 2 and 5. */
1818
479k
        if (bb5 > 0) {
1819
72.6k
            bs = pow5mult(bs, bb5);
1820
72.6k
            if (bs == NULL) {
1821
0
                goto failed_malloc;
1822
0
            }
1823
72.6k
            Bigint *bb1 = mult(bs, bb);
1824
72.6k
            Bfree(bb);
1825
72.6k
            bb = bb1;
1826
72.6k
            if (bb == NULL) {
1827
0
                goto failed_malloc;
1828
0
            }
1829
72.6k
        }
1830
479k
        if (bb2 > 0) {
1831
479k
            bb = lshift(bb, bb2);
1832
479k
            if (bb == NULL) {
1833
0
                goto failed_malloc;
1834
0
            }
1835
479k
        }
1836
479k
        if (bd5 > 0) {
1837
396k
            bd = pow5mult(bd, bd5);
1838
396k
            if (bd == NULL) {
1839
0
                goto failed_malloc;
1840
0
            }
1841
396k
        }
1842
479k
        if (bd2 > 0) {
1843
69.0k
            bd = lshift(bd, bd2);
1844
69.0k
            if (bd == NULL) {
1845
0
                goto failed_malloc;
1846
0
            }
1847
69.0k
        }
1848
479k
        if (bs2 > 0) {
1849
405k
            bs = lshift(bs, bs2);
1850
405k
            if (bs == NULL) {
1851
0
                goto failed_malloc;
1852
0
            }
1853
405k
        }
1854
1855
        /* Now bd, bb and bs are scaled versions of tdv, srv and 0.5 ulp(srv),
1856
           respectively.  Compute the difference |tdv - srv|, and compare
1857
           with 0.5 ulp(srv). */
1858
1859
479k
        delta = diff(bb, bd);
1860
479k
        if (delta == NULL) {
1861
0
            goto failed_malloc;
1862
0
        }
1863
479k
        dsign = delta->sign;
1864
479k
        delta->sign = 0;
1865
479k
        i = cmp(delta, bs);
1866
479k
        if (bc.nd > nd && i <= 0) {
1867
30.1k
            if (dsign)
1868
22.6k
                break;  /* Must use bigcomp(). */
1869
1870
            /* Here rv overestimates the truncated decimal value by at most
1871
               0.5 ulp(rv).  Hence rv either overestimates the true decimal
1872
               value by <= 0.5 ulp(rv), or underestimates it by some small
1873
               amount (< 0.1 ulp(rv)); either way, rv is within 0.5 ulps of
1874
               the true decimal value, so it's possible to exit.
1875
1876
               Exception: if scaled rv is a normal exact power of 2, but not
1877
               DBL_MIN, then rv - 0.5 ulp(rv) takes us all the way down to the
1878
               next double, so the correctly rounded result is either rv - 0.5
1879
               ulp(rv) or rv; in this case, use bigcomp to distinguish. */
1880
1881
7.53k
            if (!word1(&rv) && !(word0(&rv) & Bndry_mask)) {
1882
                /* rv can't be 0, since it's an overestimate for some
1883
                   nonzero value.  So rv is a normal power of 2. */
1884
1.45k
                j = (int)(word0(&rv) & Exp_mask) >> Exp_shift;
1885
                /* rv / 2^bc.scale = 2^(j - 1023 - bc.scale); use bigcomp if
1886
                   rv / 2^bc.scale >= 2^-1021. */
1887
1.45k
                if (j - bc.scale >= 2) {
1888
1.20k
                    dval(&rv) -= 0.5 * sulp(&rv, &bc);
1889
1.20k
                    break; /* Use bigcomp. */
1890
1.20k
                }
1891
1.45k
            }
1892
1893
6.32k
            {
1894
6.32k
                bc.nd = nd;
1895
6.32k
                i = -1; /* Discarded digits make delta smaller. */
1896
6.32k
            }
1897
6.32k
        }
1898
1899
456k
        if (i < 0) {
1900
            /* Error is less than half an ulp -- check for
1901
             * special case of mantissa a power of two.
1902
             */
1903
148k
            if (dsign || word1(&rv) || word0(&rv) & Bndry_mask
1904
6.67k
                || (word0(&rv) & Exp_mask) <= (2*P+1)*Exp_msk1
1905
148k
                ) {
1906
143k
                break;
1907
143k
            }
1908
5.18k
            if (!delta->x[0] && delta->wds <= 1) {
1909
                /* exact result */
1910
626
                break;
1911
626
            }
1912
4.55k
            delta = lshift(delta,Log2P);
1913
4.55k
            if (delta == NULL) {
1914
0
                goto failed_malloc;
1915
0
            }
1916
4.55k
            if (cmp(delta, bs) > 0)
1917
1.11k
                goto drop_down;
1918
3.44k
            break;
1919
4.55k
        }
1920
307k
        if (i == 0) {
1921
            /* exactly half-way between */
1922
5.64k
            if (dsign) {
1923
2.54k
                if ((word0(&rv) & Bndry_mask1) == Bndry_mask1
1924
797
                    &&  word1(&rv) == (
1925
797
                        (bc.scale &&
1926
0
                         (y = word0(&rv) & Exp_mask) <= 2*P*Exp_msk1) ?
1927
0
                        (0xffffffff & (0xffffffff << (2*P+1-(y>>Exp_shift)))) :
1928
797
                        0xffffffff)) {
1929
                    /*boundary case -- increment exponent*/
1930
467
                    word0(&rv) = (word0(&rv) & Exp_mask)
1931
467
                        + Exp_msk1
1932
467
                        ;
1933
467
                    word1(&rv) = 0;
1934
                    /* dsign = 0; */
1935
467
                    break;
1936
467
                }
1937
2.54k
            }
1938
3.09k
            else if (!(word0(&rv) & Bndry_mask) && !word1(&rv)) {
1939
1.11k
              drop_down:
1940
                /* boundary case -- decrement exponent */
1941
1.11k
                if (bc.scale) {
1942
0
                    L = word0(&rv) & Exp_mask;
1943
0
                    if (L <= (2*P+1)*Exp_msk1) {
1944
0
                        if (L > (P+2)*Exp_msk1)
1945
                            /* round even ==> */
1946
                            /* accept rv */
1947
0
                            break;
1948
                        /* rv = smallest denormal */
1949
0
                        if (bc.nd > nd)
1950
0
                            break;
1951
0
                        goto undfl;
1952
0
                    }
1953
0
                }
1954
1.11k
                L = (word0(&rv) & Exp_mask) - Exp_msk1;
1955
1.11k
                word0(&rv) = L | Bndry_mask1;
1956
1.11k
                word1(&rv) = 0xffffffff;
1957
1.11k
                break;
1958
1.11k
            }
1959
5.17k
            if (!odd)
1960
4.39k
                break;
1961
781
            if (dsign)
1962
558
                dval(&rv) += sulp(&rv, &bc);
1963
223
            else {
1964
223
                dval(&rv) -= sulp(&rv, &bc);
1965
223
                if (!dval(&rv)) {
1966
0
                    if (bc.nd >nd)
1967
0
                        break;
1968
0
                    goto undfl;
1969
0
                }
1970
223
            }
1971
            /* dsign = 1 - dsign; */
1972
781
            break;
1973
781
        }
1974
301k
        if ((aadj = ratio(delta, bs)) <= 2.) {
1975
270k
            if (dsign)
1976
23.5k
                aadj = aadj1 = 1.;
1977
246k
            else if (word1(&rv) || word0(&rv) & Bndry_mask) {
1978
241k
                if (word1(&rv) == Tiny1 && !word0(&rv)) {
1979
0
                    if (bc.nd >nd)
1980
0
                        break;
1981
0
                    goto undfl;
1982
0
                }
1983
241k
                aadj = 1.;
1984
241k
                aadj1 = -1.;
1985
241k
            }
1986
5.49k
            else {
1987
                /* special case -- power of FLT_RADIX to be */
1988
                /* rounded down... */
1989
1990
5.49k
                if (aadj < 2./FLT_RADIX)
1991
0
                    aadj = 1./FLT_RADIX;
1992
5.49k
                else
1993
5.49k
                    aadj *= 0.5;
1994
5.49k
                aadj1 = -aadj;
1995
5.49k
            }
1996
270k
        }
1997
31.0k
        else {
1998
31.0k
            aadj *= 0.5;
1999
31.0k
            aadj1 = dsign ? aadj : -aadj;
2000
31.0k
            if (Flt_Rounds == 0)
2001
0
                aadj1 += 0.5;
2002
31.0k
        }
2003
301k
        y = word0(&rv) & Exp_mask;
2004
2005
        /* Check for overflow */
2006
2007
301k
        if (y == Exp_msk1*(DBL_MAX_EXP+Bias-1)) {
2008
2.72k
            dval(&rv0) = dval(&rv);
2009
2.72k
            word0(&rv) -= P*Exp_msk1;
2010
2.72k
            adj.d = aadj1 * ulp(&rv);
2011
2.72k
            dval(&rv) += adj.d;
2012
2.72k
            if ((word0(&rv) & Exp_mask) >=
2013
2.72k
                Exp_msk1*(DBL_MAX_EXP+Bias-P)) {
2014
1.19k
                if (word0(&rv0) == Big0 && word1(&rv0) == Big1) {
2015
795
                    goto ovfl;
2016
795
                }
2017
402
                word0(&rv) = Big0;
2018
402
                word1(&rv) = Big1;
2019
402
                goto cont;
2020
1.19k
            }
2021
1.53k
            else
2022
1.53k
                word0(&rv) += P*Exp_msk1;
2023
2.72k
        }
2024
298k
        else {
2025
298k
            if (bc.scale && y <= 2*P*Exp_msk1) {
2026
16.9k
                if (aadj <= 0x7fffffff) {
2027
16.9k
                    if ((z = (ULong)aadj) <= 0)
2028
1.84k
                        z = 1;
2029
16.9k
                    aadj = z;
2030
16.9k
                    aadj1 = dsign ? aadj : -aadj;
2031
16.9k
                }
2032
16.9k
                dval(&aadj2) = aadj1;
2033
16.9k
                word0(&aadj2) += (2*P+1)*Exp_msk1 - y;
2034
16.9k
                aadj1 = dval(&aadj2);
2035
16.9k
            }
2036
298k
            adj.d = aadj1 * ulp(&rv);
2037
298k
            dval(&rv) += adj.d;
2038
298k
        }
2039
300k
        z = word0(&rv) & Exp_mask;
2040
300k
        if (bc.nd == nd) {
2041
281k
            if (!bc.scale)
2042
264k
                if (y == z) {
2043
                    /* Can we stop now? */
2044
262k
                    L = (Long)aadj;
2045
262k
                    aadj -= L;
2046
                    /* The tolerances below are conservative. */
2047
262k
                    if (dsign || word1(&rv) || word0(&rv) & Bndry_mask) {
2048
262k
                        if (aadj < .4999999 || aadj > .5000001)
2049
260k
                            break;
2050
262k
                    }
2051
23
                    else if (aadj < .4999999/FLT_RADIX)
2052
23
                        break;
2053
262k
                }
2054
281k
        }
2055
40.4k
      cont:
2056
40.4k
        Bfree(bb); bb = NULL;
2057
40.4k
        Bfree(bd); bd = NULL;
2058
40.4k
        Bfree(bs); bs = NULL;
2059
40.4k
        Bfree(delta); delta = NULL;
2060
40.4k
    }
2061
438k
    if (bc.nd > nd) {
2062
23.8k
        error = bigcomp(&rv, s0, &bc);
2063
23.8k
        if (error)
2064
0
            goto failed_malloc;
2065
23.8k
    }
2066
2067
438k
    if (bc.scale) {
2068
22.9k
        word0(&rv0) = Exp_1 - 2*P*Exp_msk1;
2069
22.9k
        word1(&rv0) = 0;
2070
22.9k
        dval(&rv) *= dval(&rv0);
2071
22.9k
    }
2072
2073
528k
  ret:
2074
528k
    result = sign ? -dval(&rv) : dval(&rv);
2075
528k
    goto done;
2076
2077
61.3k
  parse_error:
2078
61.3k
    result = 0.0;
2079
61.3k
    goto done;
2080
2081
0
  failed_malloc:
2082
0
    errno = ENOMEM;
2083
0
    result = -1.0;
2084
0
    goto done;
2085
2086
5.80k
  undfl:
2087
5.80k
    result = sign ? -0.0 : 0.0;
2088
5.80k
    goto done;
2089
2090
329k
  ovfl:
2091
329k
    errno = ERANGE;
2092
    /* Can't trust HUGE_VAL */
2093
329k
    word0(&rv) = Exp_mask;
2094
329k
    word1(&rv) = 0;
2095
329k
    result = sign ? -dval(&rv) : dval(&rv);
2096
329k
    goto done;
2097
2098
925k
  done:
2099
925k
    Bfree(bb);
2100
925k
    Bfree(bd);
2101
925k
    Bfree(bs);
2102
925k
    Bfree(bd0);
2103
925k
    Bfree(delta);
2104
925k
    return result;
2105
2106
438k
}
2107
2108
static char *
2109
rv_alloc(int i)
2110
46.2k
{
2111
46.2k
    int j, k, *r;
2112
2113
46.2k
    j = sizeof(ULong);
2114
46.2k
    for(k = 0;
2115
46.2k
        sizeof(Bigint) - sizeof(ULong) - sizeof(int) + j <= (unsigned)i;
2116
46.2k
        j <<= 1)
2117
0
        k++;
2118
46.2k
    r = (int*)Balloc(k);
2119
46.2k
    if (r == NULL)
2120
0
        return NULL;
2121
46.2k
    *r = k;
2122
46.2k
    return (char *)(r+1);
2123
46.2k
}
2124
2125
static char *
2126
nrv_alloc(const char *s, char **rve, int n)
2127
4.42k
{
2128
4.42k
    char *rv, *t;
2129
2130
4.42k
    rv = rv_alloc(n);
2131
4.42k
    if (rv == NULL)
2132
0
        return NULL;
2133
4.42k
    t = rv;
2134
14.3k
    while((*t = *s++)) t++;
2135
4.42k
    if (rve)
2136
4.42k
        *rve = t;
2137
4.42k
    return rv;
2138
4.42k
}
2139
2140
/* freedtoa(s) must be used to free values s returned by dtoa
2141
 * when MULTIPLE_THREADS is #defined.  It should be used in all cases,
2142
 * but for consistency with earlier versions of dtoa, it is optional
2143
 * when MULTIPLE_THREADS is not defined.
2144
 */
2145
2146
void
2147
_Py_dg_freedtoa(char *s)
2148
46.2k
{
2149
46.2k
    Bigint *b = (Bigint *)((int *)s - 1);
2150
46.2k
    b->maxwds = 1 << (b->k = *(int*)b);
2151
46.2k
    Bfree(b);
2152
46.2k
}
2153
2154
/* dtoa for IEEE arithmetic (dmg): convert double to ASCII string.
2155
 *
2156
 * Inspired by "How to Print Floating-Point Numbers Accurately" by
2157
 * Guy L. Steele, Jr. and Jon L. White [Proc. ACM SIGPLAN '90, pp. 112-126].
2158
 *
2159
 * Modifications:
2160
 *      1. Rather than iterating, we use a simple numeric overestimate
2161
 *         to determine k = floor(log10(d)).  We scale relevant
2162
 *         quantities using O(log2(k)) rather than O(k) multiplications.
2163
 *      2. For some modes > 2 (corresponding to ecvt and fcvt), we don't
2164
 *         try to generate digits strictly left to right.  Instead, we
2165
 *         compute with fewer bits and propagate the carry if necessary
2166
 *         when rounding the final digit up.  This is often faster.
2167
 *      3. Under the assumption that input will be rounded nearest,
2168
 *         mode 0 renders 1e23 as 1e23 rather than 9.999999999999999e22.
2169
 *         That is, we allow equality in stopping tests when the
2170
 *         round-nearest rule will give the same floating-point value
2171
 *         as would satisfaction of the stopping test with strict
2172
 *         inequality.
2173
 *      4. We remove common factors of powers of 2 from relevant
2174
 *         quantities.
2175
 *      5. When converting floating-point integers less than 1e16,
2176
 *         we use floating-point arithmetic rather than resorting
2177
 *         to multiple-precision integers.
2178
 *      6. When asked to produce fewer than 15 digits, we first try
2179
 *         to get by with floating-point arithmetic; we resort to
2180
 *         multiple-precision integer arithmetic only if we cannot
2181
 *         guarantee that the floating-point calculation has given
2182
 *         the correctly rounded result.  For k requested digits and
2183
 *         "uniformly" distributed input, the probability is
2184
 *         something like 10^(k-15) that we must resort to the Long
2185
 *         calculation.
2186
 */
2187
2188
/* Additional notes (METD): (1) returns NULL on failure.  (2) to avoid memory
2189
   leakage, a successful call to _Py_dg_dtoa should always be matched by a
2190
   call to _Py_dg_freedtoa. */
2191
2192
char *
2193
_Py_dg_dtoa(double dd, int mode, int ndigits,
2194
            int *decpt, int *sign, char **rve)
2195
46.2k
{
2196
    /*  Arguments ndigits, decpt, sign are similar to those
2197
        of ecvt and fcvt; trailing zeros are suppressed from
2198
        the returned string.  If not null, *rve is set to point
2199
        to the end of the return value.  If d is +-Infinity or NaN,
2200
        then *decpt is set to 9999.
2201
2202
        mode:
2203
        0 ==> shortest string that yields d when read in
2204
        and rounded to nearest.
2205
        1 ==> like 0, but with Steele & White stopping rule;
2206
        e.g. with IEEE P754 arithmetic , mode 0 gives
2207
        1e23 whereas mode 1 gives 9.999999999999999e22.
2208
        2 ==> max(1,ndigits) significant digits.  This gives a
2209
        return value similar to that of ecvt, except
2210
        that trailing zeros are suppressed.
2211
        3 ==> through ndigits past the decimal point.  This
2212
        gives a return value similar to that from fcvt,
2213
        except that trailing zeros are suppressed, and
2214
        ndigits can be negative.
2215
        4,5 ==> similar to 2 and 3, respectively, but (in
2216
        round-nearest mode) with the tests of mode 0 to
2217
        possibly return a shorter string that rounds to d.
2218
        With IEEE arithmetic and compilation with
2219
        -DHonor_FLT_ROUNDS, modes 4 and 5 behave the same
2220
        as modes 2 and 3 when FLT_ROUNDS != 1.
2221
        6-9 ==> Debugging modes similar to mode - 4:  don't try
2222
        fast floating-point estimate (if applicable).
2223
2224
        Values of mode other than 0-9 are treated as mode 0.
2225
2226
        Sufficient space is allocated to the return value
2227
        to hold the suppressed trailing zeros.
2228
    */
2229
2230
46.2k
    int bbits, b2, b5, be, dig, i, ieps, ilim, ilim0, ilim1,
2231
46.2k
        j, j1, k, k0, k_check, leftright, m2, m5, s2, s5,
2232
46.2k
        spec_case, try_quick;
2233
46.2k
    Long L;
2234
46.2k
    int denorm;
2235
46.2k
    ULong x;
2236
46.2k
    Bigint *b, *b1, *delta, *mlo, *mhi, *S;
2237
46.2k
    U d2, eps, u;
2238
46.2k
    double ds;
2239
46.2k
    char *s, *s0;
2240
2241
    /* set pointers to NULL, to silence gcc compiler warnings and make
2242
       cleanup easier on error */
2243
46.2k
    mlo = mhi = S = 0;
2244
46.2k
    s0 = 0;
2245
2246
46.2k
    u.d = dd;
2247
46.2k
    if (word0(&u) & Sign_bit) {
2248
        /* set sign for everything, including 0's and NaNs */
2249
11.9k
        *sign = 1;
2250
11.9k
        word0(&u) &= ~Sign_bit; /* clear sign bit */
2251
11.9k
    }
2252
34.3k
    else
2253
34.3k
        *sign = 0;
2254
2255
    /* quick return for Infinities, NaNs and zeros */
2256
46.2k
    if ((word0(&u) & Exp_mask) == Exp_mask)
2257
784
    {
2258
        /* Infinity or NaN */
2259
784
        *decpt = 9999;
2260
784
        if (!word1(&u) && !(word0(&u) & 0xfffff))
2261
784
            return nrv_alloc("Infinity", rve, 8);
2262
0
        return nrv_alloc("NaN", rve, 3);
2263
784
    }
2264
45.4k
    if (!dval(&u)) {
2265
3.64k
        *decpt = 1;
2266
3.64k
        return nrv_alloc("0", rve, 1);
2267
3.64k
    }
2268
2269
    /* compute k = floor(log10(d)).  The computation may leave k
2270
       one too large, but should never leave k too small. */
2271
41.7k
    b = d2b(&u, &be, &bbits);
2272
41.7k
    if (b == NULL)
2273
0
        goto failed_malloc;
2274
41.7k
    if ((i = (int)(word0(&u) >> Exp_shift1 & (Exp_mask>>Exp_shift1)))) {
2275
36.9k
        dval(&d2) = dval(&u);
2276
36.9k
        word0(&d2) &= Frac_mask1;
2277
36.9k
        word0(&d2) |= Exp_11;
2278
2279
        /* log(x)       ~=~ log(1.5) + (x-1.5)/1.5
2280
         * log10(x)      =  log(x) / log(10)
2281
         *              ~=~ log(1.5)/log(10) + (x-1.5)/(1.5*log(10))
2282
         * log10(d) = (i-Bias)*log(2)/log(10) + log10(d2)
2283
         *
2284
         * This suggests computing an approximation k to log10(d) by
2285
         *
2286
         * k = (i - Bias)*0.301029995663981
2287
         *      + ( (d2-1.5)*0.289529654602168 + 0.176091259055681 );
2288
         *
2289
         * We want k to be too large rather than too small.
2290
         * The error in the first-order Taylor series approximation
2291
         * is in our favor, so we just round up the constant enough
2292
         * to compensate for any error in the multiplication of
2293
         * (i - Bias) by 0.301029995663981; since |i - Bias| <= 1077,
2294
         * and 1077 * 0.30103 * 2^-52 ~=~ 7.2e-14,
2295
         * adding 1e-13 to the constant term more than suffices.
2296
         * Hence we adjust the constant term to 0.1760912590558.
2297
         * (We could get a more accurate k by invoking log10,
2298
         *  but this is probably not worthwhile.)
2299
         */
2300
2301
36.9k
        i -= Bias;
2302
36.9k
        denorm = 0;
2303
36.9k
    }
2304
4.84k
    else {
2305
        /* d is denormalized */
2306
2307
4.84k
        i = bbits + be + (Bias + (P-1) - 1);
2308
4.84k
        x = i > 32  ? word0(&u) << (64 - i) | word1(&u) >> (i - 32)
2309
4.84k
            : word1(&u) << (32 - i);
2310
4.84k
        dval(&d2) = x;
2311
4.84k
        word0(&d2) -= 31*Exp_msk1; /* adjust exponent */
2312
4.84k
        i -= (Bias + (P-1) - 1) + 1;
2313
4.84k
        denorm = 1;
2314
4.84k
    }
2315
41.7k
    ds = (dval(&d2)-1.5)*0.289529654602168 + 0.1760912590558 +
2316
41.7k
        i*0.301029995663981;
2317
41.7k
    k = (int)ds;
2318
41.7k
    if (ds < 0. && ds != k)
2319
11.8k
        k--;    /* want k = floor(ds) */
2320
41.7k
    k_check = 1;
2321
41.7k
    if (k >= 0 && k <= Ten_pmax) {
2322
17.3k
        if (dval(&u) < tens[k])
2323
1.80k
            k--;
2324
17.3k
        k_check = 0;
2325
17.3k
    }
2326
41.7k
    j = bbits - i - 1;
2327
41.7k
    if (j >= 0) {
2328
18.6k
        b2 = 0;
2329
18.6k
        s2 = j;
2330
18.6k
    }
2331
23.1k
    else {
2332
23.1k
        b2 = -j;
2333
23.1k
        s2 = 0;
2334
23.1k
    }
2335
41.7k
    if (k >= 0) {
2336
29.4k
        b5 = 0;
2337
29.4k
        s5 = k;
2338
29.4k
        s2 += k;
2339
29.4k
    }
2340
12.3k
    else {
2341
12.3k
        b2 -= k;
2342
12.3k
        b5 = -k;
2343
12.3k
        s5 = 0;
2344
12.3k
    }
2345
41.7k
    if (mode < 0 || mode > 9)
2346
0
        mode = 0;
2347
2348
41.7k
    try_quick = 1;
2349
2350
41.7k
    if (mode > 5) {
2351
0
        mode -= 4;
2352
0
        try_quick = 0;
2353
0
    }
2354
41.7k
    leftright = 1;
2355
41.7k
    ilim = ilim1 = -1;  /* Values for cases 0 and 1; done here to */
2356
    /* silence erroneous "gcc -Wall" warning. */
2357
41.7k
    switch(mode) {
2358
41.6k
    case 0:
2359
41.6k
    case 1:
2360
41.6k
        i = 18;
2361
41.6k
        ndigits = 0;
2362
41.6k
        break;
2363
0
    case 2:
2364
0
        leftright = 0;
2365
0
        _Py_FALLTHROUGH;
2366
0
    case 4:
2367
0
        if (ndigits <= 0)
2368
0
            ndigits = 1;
2369
0
        ilim = ilim1 = i = ndigits;
2370
0
        break;
2371
106
    case 3:
2372
106
        leftright = 0;
2373
106
        _Py_FALLTHROUGH;
2374
106
    case 5:
2375
106
        i = ndigits + k + 1;
2376
106
        ilim = i;
2377
106
        ilim1 = i - 1;
2378
106
        if (i <= 0)
2379
0
            i = 1;
2380
41.7k
    }
2381
41.7k
    s0 = rv_alloc(i);
2382
41.7k
    if (s0 == NULL)
2383
0
        goto failed_malloc;
2384
41.7k
    s = s0;
2385
2386
2387
41.7k
    if (ilim >= 0 && ilim <= Quick_max && try_quick) {
2388
2389
        /* Try to get by with floating-point arithmetic. */
2390
2391
106
        i = 0;
2392
106
        dval(&d2) = dval(&u);
2393
106
        k0 = k;
2394
106
        ilim0 = ilim;
2395
106
        ieps = 2; /* conservative */
2396
106
        if (k > 0) {
2397
85
            ds = tens[k&0xf];
2398
85
            j = k >> 4;
2399
85
            if (j & Bletch) {
2400
                /* prevent overflows */
2401
0
                j &= Bletch - 1;
2402
0
                dval(&u) /= bigtens[n_bigtens-1];
2403
0
                ieps++;
2404
0
            }
2405
85
            for(; j; j >>= 1, i++)
2406
0
                if (j & 1) {
2407
0
                    ieps++;
2408
0
                    ds *= bigtens[i];
2409
0
                }
2410
85
            dval(&u) /= ds;
2411
85
        }
2412
21
        else if ((j1 = -k)) {
2413
0
            dval(&u) *= tens[j1 & 0xf];
2414
0
            for(j = j1 >> 4; j; j >>= 1, i++)
2415
0
                if (j & 1) {
2416
0
                    ieps++;
2417
0
                    dval(&u) *= bigtens[i];
2418
0
                }
2419
0
        }
2420
106
        if (k_check && dval(&u) < 1. && ilim > 0) {
2421
0
            if (ilim1 <= 0)
2422
0
                goto fast_failed;
2423
0
            ilim = ilim1;
2424
0
            k--;
2425
0
            dval(&u) *= 10.;
2426
0
            ieps++;
2427
0
        }
2428
106
        dval(&eps) = ieps*dval(&u) + 7.;
2429
106
        word0(&eps) -= (P-1)*Exp_msk1;
2430
106
        if (ilim == 0) {
2431
0
            S = mhi = 0;
2432
0
            dval(&u) -= 5.;
2433
0
            if (dval(&u) > dval(&eps))
2434
0
                goto one_digit;
2435
0
            if (dval(&u) < -dval(&eps))
2436
0
                goto no_digits;
2437
0
            goto fast_failed;
2438
0
        }
2439
106
        if (leftright) {
2440
            /* Use Steele & White method of only
2441
             * generating digits needed.
2442
             */
2443
0
            dval(&eps) = 0.5/tens[ilim-1] - dval(&eps);
2444
0
            for(i = 0;;) {
2445
0
                L = (Long)dval(&u);
2446
0
                dval(&u) -= L;
2447
0
                *s++ = '0' + (int)L;
2448
0
                if (dval(&u) < dval(&eps))
2449
0
                    goto ret1;
2450
0
                if (1. - dval(&u) < dval(&eps))
2451
0
                    goto bump_up;
2452
0
                if (++i >= ilim)
2453
0
                    break;
2454
0
                dval(&eps) *= 10.;
2455
0
                dval(&u) *= 10.;
2456
0
            }
2457
0
        }
2458
106
        else {
2459
            /* Generate ilim digits, then fix them up. */
2460
106
            dval(&eps) *= tens[ilim-1];
2461
291
            for(i = 1;; i++, dval(&u) *= 10.) {
2462
291
                L = (Long)(dval(&u));
2463
291
                if (!(dval(&u) -= L))
2464
12
                    ilim = i;
2465
291
                *s++ = '0' + (int)L;
2466
291
                if (i == ilim) {
2467
106
                    if (dval(&u) > 0.5 + dval(&eps))
2468
53
                        goto bump_up;
2469
53
                    else if (dval(&u) < 0.5 - dval(&eps)) {
2470
61
                        while(*--s == '0');
2471
53
                        s++;
2472
53
                        goto ret1;
2473
53
                    }
2474
0
                    break;
2475
106
                }
2476
291
            }
2477
106
        }
2478
0
      fast_failed:
2479
0
        s = s0;
2480
0
        dval(&u) = dval(&d2);
2481
0
        k = k0;
2482
0
        ilim = ilim0;
2483
0
    }
2484
2485
    /* Do we have a "small" integer? */
2486
2487
41.6k
    if (be >= 0 && k <= Int_max) {
2488
        /* Yes. */
2489
9.11k
        ds = tens[k];
2490
9.11k
        if (ndigits < 0 && ilim <= 0) {
2491
0
            S = mhi = 0;
2492
0
            if (ilim < 0 || dval(&u) <= 5*ds)
2493
0
                goto no_digits;
2494
0
            goto one_digit;
2495
0
        }
2496
13.7k
        for(i = 1;; i++, dval(&u) *= 10.) {
2497
13.7k
            L = (Long)(dval(&u) / ds);
2498
13.7k
            dval(&u) -= L*ds;
2499
13.7k
            *s++ = '0' + (int)L;
2500
13.7k
            if (!dval(&u)) {
2501
9.11k
                break;
2502
9.11k
            }
2503
4.61k
            if (i == ilim) {
2504
0
                dval(&u) += dval(&u);
2505
0
                if (dval(&u) > ds || (dval(&u) == ds && L & 1)) {
2506
53
                  bump_up:
2507
58
                    while(*--s == '9')
2508
5
                        if (s == s0) {
2509
0
                            k++;
2510
0
                            *s = '0';
2511
0
                            break;
2512
0
                        }
2513
53
                    ++*s++;
2514
53
                }
2515
0
                else {
2516
                    /* Strip trailing zeros. This branch was missing from the
2517
                       original dtoa.c, leading to surplus trailing zeros in
2518
                       some cases. See bugs.python.org/issue40780. */
2519
0
                    while (s > s0 && s[-1] == '0') {
2520
0
                        --s;
2521
0
                    }
2522
0
                }
2523
53
                break;
2524
0
            }
2525
4.61k
        }
2526
9.17k
        goto ret1;
2527
9.11k
    }
2528
2529
32.5k
    m2 = b2;
2530
32.5k
    m5 = b5;
2531
32.5k
    if (leftright) {
2532
32.5k
        i =
2533
32.5k
            denorm ? be + (Bias + (P-1) - 1 + 1) :
2534
32.5k
            1 + P - bbits;
2535
32.5k
        b2 += i;
2536
32.5k
        s2 += i;
2537
32.5k
        mhi = i2b(1);
2538
32.5k
        if (mhi == NULL)
2539
0
            goto failed_malloc;
2540
32.5k
    }
2541
32.5k
    if (m2 > 0 && s2 > 0) {
2542
28.1k
        i = m2 < s2 ? m2 : s2;
2543
28.1k
        b2 -= i;
2544
28.1k
        m2 -= i;
2545
28.1k
        s2 -= i;
2546
28.1k
    }
2547
32.5k
    if (b5 > 0) {
2548
12.3k
        if (leftright) {
2549
12.3k
            if (m5 > 0) {
2550
12.3k
                mhi = pow5mult(mhi, m5);
2551
12.3k
                if (mhi == NULL)
2552
0
                    goto failed_malloc;
2553
12.3k
                b1 = mult(mhi, b);
2554
12.3k
                Bfree(b);
2555
12.3k
                b = b1;
2556
12.3k
                if (b == NULL)
2557
0
                    goto failed_malloc;
2558
12.3k
            }
2559
12.3k
            if ((j = b5 - m5)) {
2560
0
                b = pow5mult(b, j);
2561
0
                if (b == NULL)
2562
0
                    goto failed_malloc;
2563
0
            }
2564
12.3k
        }
2565
0
        else {
2566
0
            b = pow5mult(b, b5);
2567
0
            if (b == NULL)
2568
0
                goto failed_malloc;
2569
0
        }
2570
12.3k
    }
2571
32.5k
    S = i2b(1);
2572
32.5k
    if (S == NULL)
2573
0
        goto failed_malloc;
2574
32.5k
    if (s5 > 0) {
2575
17.7k
        S = pow5mult(S, s5);
2576
17.7k
        if (S == NULL)
2577
0
            goto failed_malloc;
2578
17.7k
    }
2579
2580
    /* Check for special case that d is a normalized power of 2. */
2581
2582
32.5k
    spec_case = 0;
2583
32.5k
    if ((mode < 2 || leftright)
2584
32.5k
        ) {
2585
32.5k
        if (!word1(&u) && !(word0(&u) & Bndry_mask)
2586
1.68k
            && word0(&u) & (Exp_mask & ~Exp_msk1)
2587
32.5k
            ) {
2588
            /* The special case */
2589
1.43k
            b2 += Log2P;
2590
1.43k
            s2 += Log2P;
2591
1.43k
            spec_case = 1;
2592
1.43k
        }
2593
32.5k
    }
2594
2595
    /* Arrange for convenient computation of quotients:
2596
     * shift left if necessary so divisor has 4 leading 0 bits.
2597
     *
2598
     * Perhaps we should just compute leading 28 bits of S once
2599
     * and for all and pass them and a shift to quorem, so it
2600
     * can do shifts and ors to compute the numerator for q.
2601
     */
2602
32.5k
#define iInc 28
2603
32.5k
    i = dshift(S, s2);
2604
32.5k
    b2 += i;
2605
32.5k
    m2 += i;
2606
32.5k
    s2 += i;
2607
32.5k
    if (b2 > 0) {
2608
32.5k
        b = lshift(b, b2);
2609
32.5k
        if (b == NULL)
2610
0
            goto failed_malloc;
2611
32.5k
    }
2612
32.5k
    if (s2 > 0) {
2613
32.0k
        S = lshift(S, s2);
2614
32.0k
        if (S == NULL)
2615
0
            goto failed_malloc;
2616
32.0k
    }
2617
32.5k
    if (k_check) {
2618
24.4k
        if (cmp(b,S) < 0) {
2619
4.87k
            k--;
2620
4.87k
            b = multadd(b, 10, 0);      /* we botched the k estimate */
2621
4.87k
            if (b == NULL)
2622
0
                goto failed_malloc;
2623
4.87k
            if (leftright) {
2624
4.87k
                mhi = multadd(mhi, 10, 0);
2625
4.87k
                if (mhi == NULL)
2626
0
                    goto failed_malloc;
2627
4.87k
            }
2628
4.87k
            ilim = ilim1;
2629
4.87k
        }
2630
24.4k
    }
2631
32.5k
    if (ilim <= 0 && (mode == 3 || mode == 5)) {
2632
0
        if (ilim < 0) {
2633
            /* no digits, fcvt style */
2634
0
          no_digits:
2635
0
            k = -1 - ndigits;
2636
0
            goto ret;
2637
0
        }
2638
0
        else {
2639
0
            S = multadd(S, 5, 0);
2640
0
            if (S == NULL)
2641
0
                goto failed_malloc;
2642
0
            if (cmp(b, S) <= 0)
2643
0
                goto no_digits;
2644
0
        }
2645
0
      one_digit:
2646
0
        *s++ = '1';
2647
0
        k++;
2648
0
        goto ret;
2649
0
    }
2650
32.5k
    if (leftright) {
2651
32.5k
        if (m2 > 0) {
2652
31.3k
            mhi = lshift(mhi, m2);
2653
31.3k
            if (mhi == NULL)
2654
0
                goto failed_malloc;
2655
31.3k
        }
2656
2657
        /* Compute mlo -- check for special case
2658
         * that d is a normalized power of 2.
2659
         */
2660
2661
32.5k
        mlo = mhi;
2662
32.5k
        if (spec_case) {
2663
1.43k
            mhi = Balloc(mhi->k);
2664
1.43k
            if (mhi == NULL)
2665
0
                goto failed_malloc;
2666
1.43k
            Bcopy(mhi, mlo);
2667
1.43k
            mhi = lshift(mhi, Log2P);
2668
1.43k
            if (mhi == NULL)
2669
0
                goto failed_malloc;
2670
1.43k
        }
2671
2672
129k
        for(i = 1;;i++) {
2673
129k
            dig = quorem(b,S) + '0';
2674
            /* Do we yet have the shortest decimal string
2675
             * that will round to d?
2676
             */
2677
129k
            j = cmp(b, mlo);
2678
129k
            delta = diff(S, mhi);
2679
129k
            if (delta == NULL)
2680
0
                goto failed_malloc;
2681
129k
            j1 = delta->sign ? 1 : cmp(b, delta);
2682
129k
            Bfree(delta);
2683
129k
            if (j1 == 0 && mode != 1 && !(word1(&u) & 1)
2684
129k
                ) {
2685
1.90k
                if (dig == '9')
2686
268
                    goto round_9_up;
2687
1.63k
                if (j > 0)
2688
758
                    dig++;
2689
1.63k
                *s++ = dig;
2690
1.63k
                goto ret;
2691
1.90k
            }
2692
127k
            if (j < 0 || (j == 0 && mode != 1
2693
2.23k
                          && !(word1(&u) & 1)
2694
110k
                    )) {
2695
17.1k
                if (!b->x[0] && b->wds <= 1) {
2696
2.76k
                    goto accept_dig;
2697
2.76k
                }
2698
14.4k
                if (j1 > 0) {
2699
3.09k
                    b = lshift(b, 1);
2700
3.09k
                    if (b == NULL)
2701
0
                        goto failed_malloc;
2702
3.09k
                    j1 = cmp(b, S);
2703
3.09k
                    if ((j1 > 0 || (j1 == 0 && dig & 1))
2704
1.96k
                        && dig++ == '9')
2705
435
                        goto round_9_up;
2706
3.09k
                }
2707
16.7k
              accept_dig:
2708
16.7k
                *s++ = dig;
2709
16.7k
                goto ret;
2710
14.4k
            }
2711
110k
            if (j1 > 0) {
2712
13.4k
                if (dig == '9') { /* possible if i == 1 */
2713
4.81k
                  round_9_up:
2714
4.81k
                    *s++ = '9';
2715
4.81k
                    goto roundoff;
2716
4.11k
                }
2717
9.36k
                *s++ = dig + 1;
2718
9.36k
                goto ret;
2719
13.4k
            }
2720
96.7k
            *s++ = dig;
2721
96.7k
            if (i == ilim)
2722
0
                break;
2723
96.7k
            b = multadd(b, 10, 0);
2724
96.7k
            if (b == NULL)
2725
0
                goto failed_malloc;
2726
96.7k
            if (mlo == mhi) {
2727
92.1k
                mlo = mhi = multadd(mhi, 10, 0);
2728
92.1k
                if (mlo == NULL)
2729
0
                    goto failed_malloc;
2730
92.1k
            }
2731
4.66k
            else {
2732
4.66k
                mlo = multadd(mlo, 10, 0);
2733
4.66k
                if (mlo == NULL)
2734
0
                    goto failed_malloc;
2735
4.66k
                mhi = multadd(mhi, 10, 0);
2736
4.66k
                if (mhi == NULL)
2737
0
                    goto failed_malloc;
2738
4.66k
            }
2739
96.7k
        }
2740
32.5k
    }
2741
0
    else
2742
0
        for(i = 1;; i++) {
2743
0
            *s++ = dig = quorem(b,S) + '0';
2744
0
            if (!b->x[0] && b->wds <= 1) {
2745
0
                goto ret;
2746
0
            }
2747
0
            if (i >= ilim)
2748
0
                break;
2749
0
            b = multadd(b, 10, 0);
2750
0
            if (b == NULL)
2751
0
                goto failed_malloc;
2752
0
        }
2753
2754
    /* Round off last digit */
2755
2756
0
    b = lshift(b, 1);
2757
0
    if (b == NULL)
2758
0
        goto failed_malloc;
2759
0
    j = cmp(b, S);
2760
0
    if (j > 0 || (j == 0 && dig & 1)) {
2761
4.81k
      roundoff:
2762
4.81k
        while(*--s == '9')
2763
4.81k
            if (s == s0) {
2764
4.81k
                k++;
2765
4.81k
                *s++ = '1';
2766
4.81k
                goto ret;
2767
4.81k
            }
2768
0
        ++*s++;
2769
0
    }
2770
0
    else {
2771
0
        while(*--s == '0');
2772
0
        s++;
2773
0
    }
2774
32.5k
  ret:
2775
32.5k
    Bfree(S);
2776
32.5k
    if (mhi) {
2777
32.5k
        if (mlo && mlo != mhi)
2778
1.43k
            Bfree(mlo);
2779
32.5k
        Bfree(mhi);
2780
32.5k
    }
2781
41.7k
  ret1:
2782
41.7k
    Bfree(b);
2783
41.7k
    *s = 0;
2784
41.7k
    *decpt = k + 1;
2785
41.7k
    if (rve)
2786
41.7k
        *rve = s;
2787
41.7k
    return s0;
2788
0
  failed_malloc:
2789
0
    if (S)
2790
0
        Bfree(S);
2791
0
    if (mlo && mlo != mhi)
2792
0
        Bfree(mlo);
2793
0
    if (mhi)
2794
0
        Bfree(mhi);
2795
0
    if (b)
2796
0
        Bfree(b);
2797
0
    if (s0)
2798
0
        _Py_dg_freedtoa(s0);
2799
0
    return NULL;
2800
32.5k
}
2801
2802
#endif  // _PY_SHORT_FLOAT_REPR == 1
2803
2804
PyStatus
2805
_PyDtoa_Init(PyInterpreterState *interp)
2806
36
{
2807
36
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2808
36
    Bigint **p5s = interp->dtoa.p5s;
2809
2810
    // 5**4 = 625
2811
36
    Bigint *p5 = i2b(625);
2812
36
    if (p5 == NULL) {
2813
0
        return PyStatus_NoMemory();
2814
0
    }
2815
36
    p5s[0] = p5;
2816
2817
    // compute 5**8, 5**16, 5**32, ..., 5**512
2818
288
    for (Py_ssize_t i = 1; i < Bigint_Pow5size; i++) {
2819
252
        p5 = mult(p5, p5);
2820
252
        if (p5 == NULL) {
2821
0
            return PyStatus_NoMemory();
2822
0
        }
2823
252
        p5s[i] = p5;
2824
252
    }
2825
2826
36
#endif
2827
36
    return PyStatus_Ok();
2828
36
}
2829
2830
void
2831
_PyDtoa_Fini(PyInterpreterState *interp)
2832
0
{
2833
0
#if _PY_SHORT_FLOAT_REPR == 1 && !defined(Py_USING_MEMORY_DEBUGGER)
2834
0
    Bigint **p5s = interp->dtoa.p5s;
2835
0
    for (Py_ssize_t i = 0; i < Bigint_Pow5size; i++) {
2836
0
        Bigint *p5 = p5s[i];
2837
        p5s[i] = NULL;
2838
0
        Bfree(p5);
2839
0
    }
2840
0
#endif
2841
0
}