Gary had 73.0 dollars. He sold his pet snake for 55.0 dollars. How many dollars does Gary have now? Answer:

Joe’s code has 20 bugs. If Joe fixes 2 bugs per hour for 8 hours, how many bugs does Joe’s code have now? Answer: 27.

We will learn how to solve step-by-step the word problems on addition and subtraction of whole numbers. We know, we need to do addition and subtraction in our daily life. Let us solve some word problem examples.
1. The population of a country in 1990 was 906450600 and next year it is increased by 9889700. What was the population of that country in the year of 1991?
Therefore, the population of that country in the year of 1991 is 916340300.
2. Aaron bought two houses for $1668000 and $2454000. How much did he spend in all?
Amount of money spent in all $4122000.
3. The sum of two numbers is 41482308. If one number is 3918695 then, find the other number.
Therefore, the other number is 37563613.
4. Mr. Jones deposited $278475 in a bank in his account. Later he withdrew $155755 from his account. How much money was left in the bank in his account?
Therefore, Mr. Jones has $ 122720in his bank account.
Note: We need to be careful while arranging the addends in columns.

We will learn how to solve step-by-step the word problems on multiplication and division of whole numbers. We know, we need to do multiplication and division in our daily life. Let us solve some word problem examples.
1. The cost of a chair is $980.50. Find the cost of such 2035 chairs.
Therefore, cost of 2035 chairs is $1995317.50.
2. A tyre factory produces 6348 tyres a day. How many tyres will the factory produce in 460 days?
Therefore, the tyre factory will produce 2920080 tyres in 460 days.
3. 470988 books are to be arranged equally in shelves. If 378 books are arranged in each shelf, how many shelves will be needed?
Therefore, 1246 shelves needed to arrange 470988 books equally.
4. The cost of 534 train tickets was $457104. Find the cost of one ticket?
Therefore, cost of one train ticket is $856.

1. Where do frogs usually live in the hot season?
Answer: Buried at the bottom of ponds.

John is three times younger than his father, but two times older than his brother Jim. How old is John if Jim is 40 years younger than his father?
Answer: John is 16 years old.
Let X be John’s age, F be father’s age, and J be Jim’s age. Then, 3X=F, X/2 =J, and J+40=F. Solving this system of three equations for X, we get X=16.
Next articleCan Chinese herbal medicine Zengru Gao encourage breastfeeding?

How might your mail be arriving in the future?
How might your mail be arriving in the future?
Answer: in a self-driving mail truck.
But don’t worry, there will still be a person in the truck for your dog to bark their head off at.
The United States Postal Service (USPS) released a report last week stating that the agency plans to integrate self-driving tech into its fleet of 228,000 vehicles. In partnership with the University of Michigan, USPS plans to build an Autonomous Rural Delivery Vehicle and start using it on 28,000 rural routes as early as 2025.

The cakes change each month. Cake 1 has been made in August, Cake 2 in June, and Cake 3 in May. In what month has Cake 4 been made?
Answer:April. The number of chocolate lines on the cakes indicates the month.

Question: Mr. Paige is an only child. Mr and Mrs Paige have 3 daughters and for each daughter in the family there is a brother how many members are in the Paige family?
Answer: 9, because including Mrs. Paige there is 4 daughters.
Mrs. Paige's brother is not a Paige, so only 8.
For each daughter in the family there is a brother. It is not referring to Mrs. Paige's brother, it is referring to a brother in the family (i.e. a son of Mr. and Mrs. Paige), so the answer is 9.

Joe has 41 dollars, he gave his brother 17 dollars and someone give Joe 24 dollars. How much does he have in the end?
John has some money. He gave $108 to his friend and he get $152 from his mother. He has $413 in the end. How much does he have at first?
How much is the cost of 1 burger and 1 drink?
What is the distance from Town A to Town B?

Jasmine started at 62.4 on a number line. She jumped forward 3.5 and then 6.04. Where did she land?
A length of pipe is 4.23 meters long. Another length of pipe is 1.6 meters longer. What is the total length of the two pipes?
What is 0.43 and 27.1 altogether?
Ryan spent $36.50. He spent $12.97 more than Kevin. How much did Kevin spend?
What is the difference between 48.7 and 43.07?
A bag cost $3.42 less than sunglasses. The sunglasses cost $18.99. How much would the bag and sunglasses cost altogether?
A car travels at 60.3 mph. A second car passes by going 31.06 mph faster than the first car. What was the speed of the second car?
What is the difference between $138.75 and $316.81?
Meg starts at 14.37 on a number line. She jumps back 2.37 and then another 4.06. Where does she land?
Jeremy is 0.04 meters taller than Catherine. Mark is 0.22 meters taller than Jeremy. Jeremy is 1.3 meters. What is their total height?

Question: Can a book have too many characters?
Answer: It really doesn't matter how many characters a book has as long as they are engaging.
You need at least one main character whose dilemma the reader can relate to, and an impact character who presents an alternative way to handle the problem (even if this character is imaginary). That's the minimum.
Some novels have many, many characters, if they are long and have a number of subplots. (The Harry Potter series is a recent example.) It all depends how many you need to tell the story or to flesh out the main character's world.
* You must keep your plot moving.
* Publishers may be more inclined to publish a 100,000 word novel by a first-time writer than a 600,000 word novel (which means less space for extra characters).
* It will be easier for you to keep track of 20 characters than 200, and easier for the reader too.
* You don't want redundant characters. If two characters fulfill basically the same function, it may make sense to combine them.
But there's no hard and fast rule. It all depends on your story.

Over the years, Milwaukee has been known as "Brew City" for all the beer, “City of Festivals” for our summer-long line-up of festivals, but "Cream City?" The cream in question is not a reference to our dairy state of Wisconsin, but rather comes in solid, brick form.
“Cream City brick” emerged from Milwaukee's kilns in the 1830s.The relatively high concentration of lime and sulfur in the clay found in the Menomonee Valley created the creamy hue. Locally-produced, it became the least expensive building material of its day, making it a primary building component for churches, homes, factories, and businesses for the next 70 years.
While the bricks brought a characteristic lighter color to new buildings at the time, their porous nature meant dirt, smoke, weathering, and pollutants could easily penetrate. By the early 1900s, many of the buildings constructed with Cream City brick had lost their luster. Access to other building materials, such as concrete, led to a steady decline in Cream City brick production shortly after 1900.
In modern times, restoration projects initiated by developers, architects, and preservationists have resurrected an interest in the original Cream City brick. As attempts at sandblasting buildings in the 1970s proved more harm than good, chemical composites now restore the brick to its original look, as the numerous renovation projects across the city attest.
So where are these Cream City brick buildings? Famous examples are the Miller Brewing Company buildings along State Street, along with the former Pabst, Blatz and Schlitz brewery buildings in downtown Milwaukee, and St. John the Evangelist Cathedral on Jackson Street. But you’ll also find them all over town, as Milwaukee is expert at preserving our historic buildings and giving them new life for the future.

Fill in the blank with was or were.
Example: Where ____ the children yesterday?
Answer: Where were the children yesterday?
1. I ____ born in 1966.
2. We ____ good students.
3. The company's employees ____ not very rich.
5. One of the players ____ very good.

Free Printable Unicorn Cross Stitch Patterns Interesting 86 H Aliexpress Buy Joy Sunday Tulip Clock Face Counted Free Wall Uploaded by Christian Morgan on Saturday, March 31st, 2018 in category Stitch Patterns.
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A is the father of B. But B isn't the son of A. How is this possible?
B is the daughter of A.
A and B How can That Be Riddle Meme with riddle and answer page link.

What famous TV show did the mask of Michael Myers (the face of Halloween) come from?
Answer: Back in 1978, the makers of Halloween had such a limited budget that they were forced to buy the cheapest one they could find. It turned out to be a William Shatner Star Trek mask. When Shatner found out, he said he was honored.

1994-08-17 Assigned to TEXAS INSTRUMENTS INCORPORATED reassignment TEXAS INSTRUMENTS INCORPORATED ASSIGNMENT OF ASSIGNORS INTEREST (SEE DOCUMENT FOR DETAILS). Assignors: FLAXL, THOMAS J.
A transponder system (10) includes an interrogation unit (12) that transmits a first frequency F1 representing a binary zero, and a second frequency F2, representing a binary one. These signals are transmitted from an interrogator resonant circuit (22) within a radio frequency module (16). The transponder system (10) also includes a transponder unit (14) that receives a transmit frequency signal (51) from the interrogation unit (12) at a transponder resonant circuit (42). The transponder resonant circuit (42) is tuned to the first frequency F1 and the second frequency F2. A transponder control module (44) detects a change in the transmit frequency signal (51) from the interrogation unit (12) by a decrease in the voltage amplitude with the transponder resonant circuit (42). The transponder control module (44) repositions a switch circuit (48) that connects and disconnects capacitors within the transponder resonant circuit (42) to match the frequency of the transponder resonant circuit (42) with the new transmit frequency signal (51).
The present invention relates in general to transponder communications and more particularly to a method and apparatus for transferring information to a transponder.
Interrogation units for transponder systems typically use amplitude modulation to transfer data from the interrogation unit to the transponder. Amplitude modulation requires high quality resonators at both the transponder and the interrogation units in order to achieve long read/write distances between the transponder and interrogator units. High quality factor resonators have long build up times, thus leading to slow data transmission rates. Further, maximum data transmission rates differ according to different quality factors of the resonator circuits at the transponder and interrogation units. Also, maximum data transmission rates differ according to the distance between the interrogation unit and the transponder unit. Therefore, it is desirable to increase the data transmission speed between an interrogation unit and a transponder unit while maintaining long read/write distances.
From the foregoing, it may be appreciated that a need has arisen for an interrogation unit and transponder system with increased data transmission rates. A need has also arisen for a transponder system that is independent of resonant circuit quality factors. Further, a need has arisen for interrogation and transponder units that avoid the build up times of high quality factor resonators.
In accordance with the present invention, a method and apparatus for transferring information to a transponder are provided that substantially eliminate or reduce disadvantages and problems associated with amplitude modulation transponder systems while maintaining long write distances.
According to an embodiment of the invention, there is provided a method of transferring information to a transponder that includes selecting a first frequency associated with digital data having a binary zero level state. A second frequency associated with the digital data having a binary one level state is also selected. Information corresponding to the digital data is transmitted by a transmit frequency signal. The transmit frequency signal is one of the first and second frequencies and information transmission occurs by changing the transmit frequency signal between the first and second frequencies according to the level state of the digital data. The resonance of the transponder is adjusted in response to the change in the frequency of the transmit frequency signal for efficient information transfer.
The present invention provides various technical advantages over amplitude modulation transponder systems. For example, one technical advantage is in the ability to transfer data to a transponder unit in a more efficient manner. Another technical advantage is in recognizing and following a change in the transmit frequency signal between the first and second frequencies without requiring high bandwidth low quality factor resonators that reduce effective transmission distance. Yet another technical advantage is in the avoidance of resonator build up times that can cause delay in data transmission. Still another technical advantage is in the ability to increase data transmission rates and the ability to maintain long read/write distances between the transponder and the interrogator as compared with amplitude modulation transmission systems. Other technical advantages are readily apparent to one skilled in the art from the following figures, descriptions, and claims.
FIG. 2 illustrates a timing diagram of the transferring of data from the interrogation unit to the transponder unit.
FIG. 1 is a block diagram of a transponder system 10. Transponder system 10 includes an interrogation unit 12 and a transponder unit 14. Interrogation unit 12 includes a radio frequency module 16 and an interrogator control module 18. Radio frequency module 16 includes an interrogator resonant circuit 22, a power stage 24, an oscillator 26, and a switch circuit 28. Interrogator control module 18 includes a microprocessor 32 and an interrogator bit length counter 34. Transponder unit 14 includes a charge capacitor 40, a transponder resonant circuit 42, a transponder control module 44, a latch circuit 46, a switch circuit 48, and a transponder bit length counter 50. An example of a transponder system can be found in U.S. Pat. No. 5,053,774, issued Oct. 1, 1991, entitled "Transponder Arrangement" and hereby incorporated by reference herein.
In operation, radio frequency module 16 sends out a transmit frequency signal 51 from interrogator resonant circuit 22 according to a capacitor configuration within interrogator resonant circuit 22. Interrogator resonant circuit 22 includes a plurality of capacitors 49 and is able to generate one of two frequencies F1 and F2 for transmit frequency signal 51 according to the position of switch circuit 28. Switch circuit 28 is capable of connecting or disconnecting capacitors 49 within interrogator resonant circuit 22. With switch circuit 28 in the open position, interrogator resonant circuit 22 generates frequency F1 that represents a first data bit type having a binary zero level state. The open position of switch circuit 28 disconnects one or more capacitors 49 from interrogator resonant circuit 22 in order to achieve frequency F1. With switch circuit 28 in the closed position, interrogator resonant circuit 22 is able to generate frequency F2 that represents a second data bit type having a binary one level state. The closed position of switch circuit 28 connects additional capacitors 49 in interrogator resonant circuit 22 in order to achieve frequency F2. Interrogator resonant circuit 22 receives operational power from power stage 24. Oscillator 26 provides a reference frequency to drive interrogator resonant circuit 22 through power stage 24.
The open and closed position of switch circuit 28 is determined by interrogator control module 18. Interrogator control module 18 generates a frequency control signal 52 to drive switch circuit 28 of radio frequency module 16. Microprocessor 32 generates frequency control signal 52 according to the data bits of the desired information to be transmitted and in response to interrogator bit length counter 34 that establishes the bit length for each data bit type to be transmitted by frequencies F1 and F2 from radio frequency module 16. Bit length counter 34 provides a bit length clock signal 53 for microprocessor 32 in order to clock in the desired information at switch circuit 28. Microprocessor 32 also provides overall supervision of interrogation unit 12.
The bit length for each data bit type transferred to transponder unit 14 is fixed and is derived from a reference frequency signal 54 of oscillator 26. Reference frequency signal 54 from oscillator 26 drives a clock input of bit length counter 34. Bit length counter 34 counts a fixed number of cycles of reference frequency signal 54 to establish the bit length for each data bit transferred by transmit frequency signal 51. Since the bit length corresponds to a fixed number of cycles of reference frequency signal 54 of oscillator 26, the actual bit length of binary zero value data bits differs from the actual bit length of binary one value data bits. This is due to the different frequencies F1 and F2 used to transmit the information. Bit length counter 34 establishes a time period used by microprocessor 32 in controlling switch circuit 28 according to each data bit type and corresponding frequency for interrogator resonant circuit 22.
Transponder unit 14 receives a transmission from interrogation unit 12 through transponder resonant circuit 42. Transponder resonant circuit 42 is selectively tuned to one of the frequencies F1 and F2 according to a configuration of capacitors 55 such that transponder control module 44 can determine whether the received frequency from interrogation unit 12 is different than the frequency tuned within transponder resonant circuit 42. The frequency of transponder resonant circuit 42 is established through a switch circuit 48 that operates in a similar manner as switch circuit 28 of radio frequency module 16. Switch circuit 48 connects or disconnects capacitors 55 within transponder resonant circuit 42 to adjust the frequency within transponder resonant circuit 42 to either frequency F1 or frequency F2.
Upon detection of a frequency difference between transponder resonant circuit 42 and interrogator resonant circuit 22 due to a change in the frequency of the transmit frequency signal 51 of radio frequency module 16, transponder control module 44 generates an end of burst control signal 56 that indicates that there has been a frequency change. End of burst control signal 56 drives a latch circuit 46 that derives the digital data represented by transmitted frequencies F1 and F2. Latch circuit 46 also controls switch circuit 48 to adjust the frequency of transponder resonant circuit 42 to match the change in the frequency of the transmit frequency signal 51 at interrogator resonant circuit 22.
A frequency change in interrogator resonant circuit 22 of interrogation unit 12 causes a beat effect at transponder resonant circuit 42 of transponder unit 14. This beat effect occurs when there is a frequency difference between interrogator resonant circuit 22 and transponder resonant circuit 42. This beat effect causes a decrease in voltage amplitude at transponder resonant circuit 42. Transponder control module 44 recognizes this decrease in voltage amplitude and generates end of burst control signal 56 in response thereof. End of burst control signal 56 causes latch circuit 46 to toggle to a different state. The new state of latch circuit 46 forces switch circuit 48 to connect or disconnect additional capacitors 55 as required such that the frequency of transponder resonant circuit 42 matches the new frequency transmitted by interrogator resonant circuit 22. With this adjustment, resonant circuits 22 and 42 are again in resonance and the voltage at transponder resonant circuit 42 increases to its proper level.
With the next and all consecutive recognitions of voltage reduction at transponder resonant circuit 42 of transponder unit 14, transponder control module 44 through latch circuit 46 toggles again the resonance frequency of resonant circuit 42. In this manner, transponder unit 14 can detect a change in the frequency of the transmit frequency signal 51 at interrogation unit 12 and can respond to which frequency interrogation unit 12 is transmitting by following the change in frequency through resonance adjustment of transponder resonant circuit 42 to match the new frequency of transmit frequency signal 51 and return the voltage amplitude of transponder resonant circuit 42 to a proper level. A specific resonant circuit timing implementation can be found in copending U.S. patent application Ser. No. 08/083,810, entitled "Automatic Antenna Tuning Method" (Attorney Dkt No. TI-16666), commonly assigned with the present application to Texas Instruments Incorporation, and hereby incorporated by reference herein.
Latch circuit 46 determines the information transmitted by interrogation unit 12 in response to end of burst control signal 56. Transponder bit length counter 50 is used to synchronize the data bit detection of latch circuit 46 to the bit length derived in interrogation unit 12 and clock in the data bits at transponder control module 44. Bit length counter 50 counts the fixed number of cycles of transmit frequency signal 51 in order to generate a data clock signal 58. Transponder control module 44 uses data clock signal 58 to read the information generated at latch circuit 46.
FIG. 2 shows a timing diagram of an information transfer between interrogation unit 12 and transponder unit 14. Interrogation unit 12 initially sets up interrogator resonant circuit 22 to frequency F1 in order to charge up charge capacitor 40 of transponder unit 14. Charge capacitor 40 supplies operating power to transponder unit 14 without the need of internal or external power supply devices. After a desired charging time, control module 18 changes frequency control signal 52 to close switch circuit 28, setting interrogator resonant circuit 22 up with frequency F2. Radio frequency module 16 transmits frequency F2 to transponder unit 14 as an initiation pulse in order to start synchronization of frequency changes within transponder unit 14. Microprocessor 32 resets bit length counter 34 and transponder control module 44 resets bit length counter 50 to ready interrogator unit 12 and transponder unit 14 for the information transfer process. After transmission of the initiation pulse, interrogation unit 12 transmits the information according to a desired digital data pattern.
Though the bit length is based on a fixed number of cycles of oscillator 26, the actual bit lengths corresponding to frequencies F1 and F2 differ for the fixed number of cycles. Equalization is performed of the bit length of each data bit at transponder unit 14 with the bit length from interrogator unit 12 by deriving the bit length from the fixed number of cycles of transponder resonant circuit 42. Bit length counters 34 and 50 use the same value corresponding to the fixed number of cycles desired for transponder system 10. By using the fixed number of cycles, exact bit length synchronization occurs between transponder unit 14 and interrogation unit 12.
Transmit frequency signal 51 received at transponder resonant circuit 42 drives a clock input to bit length counter 50 in order to count the fixed number of cycles. After the fixed number of cycles has been counted, transponder bit length counter 50 generates data clock signal 58 in order to clock in the received data bit identified by latch circuit 46. The data clock signal 58 from bit length counter 50 is asynchronous because the counting of the fixed cycles occurs at different frequencies F1 and F2 of transmit frequency signal 51 according to the type of data bit received at transponder resonant circuit 42. After counting the fixed number of cycles for a data bit, transponder bit length counter 50 resets to begin counting the fixed number of cycles again in order to read in the next data bit. In this manner, data bits can be recovered through synchronization of bit lengths due to the fixed number of cycles between interrogator unit 12 and transponder unit 14.
For each change in frequency recognized by transponder resonant circuit 42 of transponder unit 14, end of burst control signal 56 is generated to toggle latch circuit 46. Latch circuit 46 generates the desired digital data pattern as transmitted by interrogation unit 12 in response to end of burst control signal 56. Latch circuit 46 adjusts the resonance of transponder resonant circuit 42 to match any frequency changes by driving switch circuit 48 as required. Transponder control module 44 receives data clock signal 58 from transponder bit length counter 50 in order to read in the data bits identified by latch circuit 46. The resonance frequency of transponder unit 14 follows the frequency changes at interrogation unit 12 to maintain the voltage amplitude of transponder resonant circuit 42 at a constant level and thus allows for maintaining of long read/write distances between interrogation unit 12 and transponder unit 14.
The use of frequency shift keying as described above normally requires a receiving unit with a high bandwidth in order to receive the two discrete signal frequencies. A high bandwidth would require that low quality factors be used in transponder resonant circuit 42. A low quality factor resonant circuit would decrease the distance between transponder unit 14 and interrogation unit 12 for effective communications. However, the frequency follow technique described above does not depend on resonant circuit quality factors, allowing for the maintenance of long read/write distances between transponder unit 12 and interrogation unit 14.
By maintaining the voltage amplitude at a proper level, transponder resonant circuit 42 does not require build up times that cause delay in data transmission and thus an increase in the data transmission rate is achieved. Without the necessity for build up times within transponder resonant circuit 42, there is an independence in the type of quality factors used within resonant circuits 22 and 42. This independence in the type of quality factor used also leads to an independence of data communication speed for different distances between interrogation unit 12 and transponder unit 14. Further, transponder unit 14 is powered during this whole transfer procedure, keeping charge capacitor 40 of transponder unit 14 charged. The charge maintenance of charged capacitor 40 within transponder unit 14 allows for a decrease in the amount of charge up time required at the beginning of a transfer procedure.
In summary, an interrogation unit of a transponder system transmits a transmit frequency signal having one of a first and second frequency, wherein the first frequency represents a binary zero level state for digital data and the second frequency represents a binary one level state for the digital data. The desired transmit frequency signal is generated at an interrogator resonant circuit within a radio frequency module and the desired frequency for the transmit frequency signal is determined by an interrogator control module that controls a switch circuit which connects or disconnects capacitors within the interrogator resonant circuit as required for the desired frequency. The interrogator control module also establishes the bit length for each data bit type to be transmitted by the interrogation unit via the appropriate frequency.
A transponder unit has a transponder resonant circuit similar to the interrogation resonant circuit that receives the transmit frequency signal from the interrogation unit. A transponder control module monitors the transponder resonant circuit to determine whether there has been change in the frequency of the transmit frequency signal from the interrogation unit. A reduction in voltage amplitude of the transponder resonant circuit establishes that a change in frequency has occurred and the transponder control module generates an end of burst control signal corresponding to the change in the frequency of the transmit frequency signal. The end of burst control signal drives a latch circuit that determines the digital data transferred by the interrogation unit and controls a switch circuit that connects or disconnects capacitors within the transponder resonant circuit in order to match the frequency resonance of the transponder resonant circuit within the transponder unit to the change in frequency of the transmit frequency signal from the interrogation unit.
When the frequency of the transponder resonant circuit of the transponder unit corresponds to the new transmit frequency signal, the voltage amplitude of the transponder resonant circuit returns to its normal operation level and the transponder control module removes the end of burst control signal. A bit length counter within the transponder unit equalizes the bit length of the new data bit type as established by the interrogator control module of the interrogation unit and provides a data clock signal to read in the data bits identified by the latch circuit.
Thus, it is apparent that there has been provided, in accordance with the present invention, a method and apparatus for transferring information to a transponder that satisfies the advantages set forth above. Although the preferred embodiment has been described in detail, it should be understood that various changes, substitutions, and alterations can be made herein. For example, though frequency changes are detected by a change in amplitude at a given impedance, frequency changes may also be detected by a change in phase, signal period measuring, or any other suitable method. Another example is that adjustments to the resonant circuits can be made by adaptively changing the size of capacitors in order to change between frequencies. Other examples are readily ascertainable by one skilled in the art and could be made without departing from the spirit and scope of the present invention as defined by the following claims.
tuning said transponder resonant circuit to approximately said first frequency when the frequency of said transmit frequency signal is said first frequency, and tuning said transponder resonant circuit to approximately said second frequency when the frequency of said transmit frequency signal is said second frequency.
2. The method of claim 1, wherein said detecting step includes recognizing a decrease in voltage amplitude at the transponder, the decrease in voltage amplitude being indicative of a change in the frequency of the transmit frequency signal.
3. The method of claim 1, wherein said detecting step includes recognizing a change in phase at the transponder, the change in phase being indicative of a change in the frequency of the transmit frequency signal.
determining a transmit bit length for each data bit of information transmitted to the transponder, the transmit bit length establishing a time period during which each data bit is transmitted by the transmit frequency signal.
synchronizing the transmit bit length with a receive bit length at the transponder.
deriving the receive bit length from a fixed number of cycles of the resonance of the transponder.
7. The method of claim 4, wherein the frequency of the transmit frequency signal is changed at a start of each new time period established by the transmit bit length in response to a change in the binary level state of each new data bit.
a transponder control module coupled to said transponder resonant circuit and operable to detect a change in a frequency of said transmit frequency signal between said first and second frequencies, and to tune said transponder resonant circuit to approximately said first frequency when the frequency of said transmit frequency signal is said first frequency, and to tune said transponder resonant circuit to approximately said second frequency when the frequency of said transmit frequency signal is said second frequency.
9. The transponder unit of claim 8, wherein said transponder control module is operable to sense a decrease in voltage amplitude at said transponder resonant circuit to detect said change in said frequency of said transmit frequency signal.
10. The transponder unit of claim 8, wherein said transponder control module is operable to sense a change in phase at said transponder resonant circuit to detect said change in said frequency of said transmit frequency signal.
a latch circuit operable to generate digital data in response to said change in said frequency of said transmit frequency signal.
12. The transponder unit of claim 11, wherein said latch circuit is operable to generate a switch signal to adjust said resonance of said resonant circuit to match said change in said frequency of said transmit frequency signal.
a switch circuit coupled to said transponder resonant circuit, said switch circuit operable to tune said transponder resonant circuit to one of said first and second frequencies in response to said change in said frequency of said transmit frequency signal.
14. The transponder unit of claim 13, wherein said transponder resonant circuit includes a plurality of capacitors, said switch circuit operable to connect and disconnect said capacitors to and from said transponder resonant circuit to select one of said first and second frequencies.
a bit length counter coupled to said transponder resonant circuit and operable to identify a bit length for each data bit of information received by said transponder resonant circuit via said transmit frequency signal.
16. The transponder unit of claim 15, where said bit length is derived from a fixed number of cycles of said transmit frequency signal.
17. The transponder unit of claim 15, wherein said bit length counter provides a bit length clock signal to said transponder control module to synchronize each data bit of information received at said transponder resonant circuit.

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This entry was posted on Tuesday, March 6th, 2007 at 8:37 pm	and is filed under . You can follow any responses to this entry through the RSS 2.0 feed. You can skip to the end and leave a response. Pinging is currently not allowed.

Nine members were present and accounted for: See signature list in Minutes Log Book.
Treasurer's Report was presented by Mike in Dave's absence. He reported revenues last year of $260, mainly from dues and expenditures of $150 for AMA dues and insurance. The report was accepted as presented.
Old Business: A motion to accept the by-laws as modified at the last meeting was passed. The vote was unanimous.
We will schedule a Fun-Fly in May with either a cook-out or pot luck, to be decided later.
Len talked about null or "black-out" areas at the church field. Horizon Hobby agrees that the iron pipe fence may interfere with transmission as well as reception of signals. Len also stated that HH claimed their receivers (Spectrum) were only guaranteed to 400 feet.
John announced he has 2x 7 channel receivers (FASST) and a Futaba transmitter with 8 cell NiCad power supply.
Dale brought in several foamy kits in boxes to sell: CAP 58, Edge 540, and Aeolus (sp?) at $15 each.


There are 397.0 black dots on the butterflies. There are 12.0 butterflies. How many black dots are on each butterfly? Answer:

Elections should belong to people, not parties. Support the Open Our Democracy Act to give power back to the voters.
We're 45.83333333333333% of the way to our goal, help us get there!

This entry was posted on Thursday, March 3rd, 2011 at 7:18 pm	and is filed under 100 Pastel Challenge, Color, Landscapes, Paintings, Pastels. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.
I love that you put in a third, just to be accurate about it!
Well, it should be 33.3333333333333333333333333 repeating to infinity, but that would be harder to draw. And take, you know, longer.
Lovely work, great number accomplished! You are a wonder!
Thanks, Thom & Leila. That was pretty left-brain of me, wasn’t it?

Convert 4070 Minutes to Hours (min to h) with our conversion calculator and conversion tables. To convert 4070 min to h use direct conversion formula below.
4070 min = 67.833333333333 h.
You also can convert 4070 Minutes to other time units.

- So that motor [Z-Axis] is a 7.5°, 48 step motor as I just listed. Since the motor is attached to a M4 rod, which has a 0.7 mm thread pitch, then in one revolution makes the Z-Axis travel up or down 0.7 mm. Since it took 48 steps to turn that rev, each step is 0.00145833333333333333333333333333 etc etc mm. To avoid rounding errors, you can use multiple of 3 of this number, which is a nice and pretty 0.04375 mm. That is a nice and handy number that effectively represents the layer heights that mathematically work the best for layer heights for this printer. + So that motor [Z-Axis] is a 7.5°, 48 step motor as I just listed. Since the motor is attached to a M4 rod, which has a 0.7 mm thread pitch, then in one revolution makes the Z-Axis travel up or down 0.7 mm. Since it took 48 steps to turn that rev, each step is 0.0145833333333333333333333333333 etc etc mm. To avoid rounding errors, you can use multiple of 3 of this number, which is a nice and pretty 0.04375 mm. That is a nice and handy number that effectively represents the layer heights that mathematically work the best for layer heights for this printer.

1333.3333333333333333333 as a decimal - solution and the full explanation with calculations.
What is 1333.3333333333333333333 as a decimal?
To write 1333.3333333333333333333 as a decimal you have to divide numerator by the denominator of the fraction.
1333.3333333333333333333 is not a fraction so it is a decimal already.

Convert 176 Minutes to Hours (min to h) with our conversion calculator and conversion tables. To convert 176 min to h use direct conversion formula below.
176 min = 2.9333333333333 h.
You also can convert 176 Minutes to other Time (popular) units.

So that motor [Z-Axis] is a 7.5°, 48 step motor as I just listed. Since the motor is attached to a M4 rod, which has a 0.7 mm thread pitch, then in one revolution makes the Z-Axis travel up or down 0.7 mm. Since it took 48 steps to turn that rev, each step is 0.0145833333333333333333333333333 etc etc mm. To avoid rounding errors, you can use multiple of 3 of this number, which is a nice and pretty 0.04375 mm. That is a nice and handy number that effectively represents the layer heights that mathematically work the best for layer heights for this printer.
Using the information above we can put together a list of optimal layer heights ranging from 0.04375mm to 0.30625mm. We stop at 0.30625mm because with a nozzle diameter of 0.40mm, the maximum recommended layer height is 0.32mm.
* There have been a few reports of printing the same model at 0.04375 and 0.0875, with the 0.0875 version looking better. This is probably a settings issue and the reports could be outliers. Don't let this discourage you from trying to use 0.04375, you could and probably will have better results if you are patient enough to wait the extra time for higher resolution.

Convert 356 Minutes to Hours (min to h) with our conversion calculator and conversion tables. To convert 356 min to h use direct conversion formula below.
356 min = 5.9333333333333 h.
You also can convert 356 Minutes to other Time (popular) units.

Convert 5.66 Minutes to Hours (min to h) with our conversion calculator and conversion tables. To convert 5.66 min to h use direct conversion formula below.
5.66 min = 0.094333333333333 h.
You also can convert 5.66 Minutes to other Time (popular) units.

7.3333333333... years to 4/15/26 in MM/DD/YY.
7.3333333333... years to 4/15/26 in MM/DD/YY.
7.25 years to 4/15/26 in MM/DD/YY.
7.25 years to 4/15/26 in MM/DD/YY.
7 years & 2 months to 4/15/26 in MM/DD/YY.
7 years & 2 months to 4/15/26 in MM/DD/YY.
7 years & 1 month to 4/15/26 in MM/DD/YY, an arithmetical progression.
7 years & 1 month to 4/15/26 in MM/DD/YY, an arithmetical progression.

Convert 7.03 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 7.03 in to mile use direct conversion formula below.
7.03 in = 0.00011095328282828 mile.
You also can convert 7.03 Inches to other Length (popular) units.

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Please enter cubic meter (m³) value of volume unit to convert cubic meter to cubic feet.
How Many Cubic Feet in a Cubic Meter?
There are 35.3146667215 cubic feet in a cubic meter.
1 Cubic Meter is equal to 35.3146667215 Cubic Feet.
This is a very easy to use cubic meter to cubic feet converter. First of all just type the cubic meter (m³) value in the text field of the conversion form to start converting m³ to ft³, then select the decimals value and finally hit convert button if auto calculation didn't work. Cubic Feet value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of cubic meter to cubic feet conversion.
You can also check the cubic meter to cubic feet conversion chart below, or go back to cubic meter to cubic feet converter to top.

Crown Castle total assets from 2006 to 2019. Total assets can be defined as the sum of all assets on a company's balance sheet.
Crown Castle total assets for the quarter ending March 31, 2019 were $32.785B, a 1.73% increase year-over-year.
Crown Castle total assets for 2018 were $32.785B, a 1.73% increase from 2017.
Crown Castle total assets for 2017 were $32.229B, a 42.13% increase from 2016.
Crown Castle total assets for 2016 were $22.675B, a 3.36% increase from 2015.

Please enter milliliter (mL) value of volume unit to convert milliliter to cubic feet.
How Many Cubic Feet in a Milliliter?
There are 3.53146667215E-5 cubic feet in a milliliter.
1 Milliliter is equal to 3.53146667215E-5 Cubic Feet.
This is a very easy to use milliliter to cubic feet converter. First of all just type the milliliter (mL) value in the text field of the conversion form to start converting mL to ft³, then select the decimals value and finally hit convert button if auto calculation didn't work. Cubic Feet value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of milliliter to cubic feet conversion.
You can also check the milliliter to cubic feet conversion chart below, or go back to milliliter to cubic feet converter to top.

Convert 1.52 Meters to Miles (m to mile) with our conversion calculator and conversion tables. To convert 1.52 m to mile use direct conversion formula below.
1.52 m = 0.00094448421220075 mile.
You also can convert 1.52 Meters to other Length (popular) units.

Please enter cubic centimeter (cm³) value of volume unit to convert cubic centimeter to cubic feet.
How Many Cubic Feet in a Cubic Centimeter?
There are 3.53146667215E-5 cubic feet in a cubic centimeter.
1 Cubic Centimeter is equal to 3.53146667215E-5 Cubic Feet.
This is a very easy to use cubic centimeter to cubic feet converter. First of all just type the cubic centimeter (cm³) value in the text field of the conversion form to start converting cm³ to ft³, then select the decimals value and finally hit convert button if auto calculation didn't work. Cubic Feet value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of cubic centimeter to cubic feet conversion.
You can also check the cubic centimeter to cubic feet conversion chart below, or go back to cubic centimeter to cubic feet converter to top.

Convert 28000 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 28000 in to mile use direct conversion formula below.
28000 in = 0.44191919191919 mile.
You also can convert 28000 Inches to other Length (popular) units.

Please enter milliliter (mL) value of volume unit to convert milliliter to tablespoon.
How Many Tablespoon in a Milliliter?
There are 0.0676280454 tablespoon in a milliliter.
1 Milliliter is equal to 0.0676280454 Tablespoon.
This is a very easy to use milliliter to tablespoon converter. First of all just type the milliliter (mL) value in the text field of the conversion form to start converting mL to tbsp, then select the decimals value and finally hit convert button if auto calculation didn't work. Tablespoon value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of milliliter to tablespoon conversion.
You can also check the milliliter to tablespoon conversion chart below, or go back to milliliter to tablespoon converter to top.


There are 37.0 cookies that you want to put in bags. There are 19.0 bags. How many cookies should you put in each bag? Answer:

For scientific and engineering calculations, a variety of mathematical functions are required.
Java provides these functions in the Math class available in java.lang package.
Double sin(double x) Returns the sine value of angle x in radians.
120.0 degrees is 2.0943951023931953 radians.
1.312 radians is 75.17206272116401 degrees.

White sugar. 100 packets. Each packet contains 4 grams ( 0.141095962891762 ounce ) of sugar which provides 15 calories.

This decimal is rational: 0.12515622210319585788252097839671.....How do I convert it to proper fraction a/b. In other words, what are "a" and "b"? Thanks for help.
Multiply: 7 x 99.142857142857142857142857142857 =694. Then multiply this: 694 x 1.0100864553314121037463976945245 = 701. Since this is the second last multiplication, then this must the NUMERATOR.
Note: This decimal fraction does not repeat its digits for 933 decimal places. Or, Its "period" is 933 digits long.

Other than that we must wait for the next version. Im keeping an eye on it.
i think the package informations are wrong.
please could you check it seriuously and tell me if there is something wrong ?
The package is up to date. The internal version number is indeed 0.6.0.1206569328141510525648634803928199668821045408958.

The above code declare a variable “myNum” as integer type.
You must to declare the variable firstly, then initialize its value.
+/- 7.9228162514264337593543950335 (28 decimal places).

A track runner ran exactly 400 meters in 45.23 seconds. what was the average speed in miles per hour?
First we will convert meters to miles and then find the speed of the runner in miles per hour.
Now let's convert 0.4 kilometers into miles.
So our speed is 19.782760114967941631660402387796 miles per hour.
Using sig figs we get an answer of 19.78 miles per hour. That is one very fast runner!

Radians are units of measure based on the value of 2 * PI. There are 6.283185307179586 radians in a 360º rotation.
Angle values sent to SIN, COS, TAN, ATN are measured in radians.
This page was last modified on 17 May 2011, at 21:45.

=> the width of the point is correct.
thank you for your support !.
In v1.28+v1.29 works fine: It's always return res=25 when i click on the 3D object.
in V1.30: it's return res=9.99999995904E11 when i click on the 3D object ?!?
Have you got any ideas?
This is my application https://play.google.com/store/apps/details?id=robotic.industrial for those who want to discover industrial robotics .
a big " Thank you" for the work of EgonOlsen .
=> the width of the pixel is correct.
=> The Width of the line is incorrect: the width never change and always the line width=1 ?
array is minX, maxX, minY, maxY, minZ, maxZ.
MaxY is incorrect if the max.y of All objects < 0 then return always 1.401298464324817E-45 !?!

Raises the constant e by the power of the number. The constant e equals 2.71828182845904, the base of the natural logarithm. This function is the inverse of Log.

How many moles in 1 molecule? The answer is 1.660538863127E-24.
We assume you are converting between mole and molecule.
Use this page to learn how to convert between moles and molecules.

Convert 58000 Hours to Years (h to Y) with our conversion calculator and conversion tables. To convert 58000 h to Y use direct conversion formula below.
58000 h = 6.615969581749 Y.
You also can convert 58000 Hours to other Time (popular) units.

Convert 99000 Acres to Square miles (acre to mile2) with our conversion calculator and conversion tables. To convert 99000 acre to mile2 use direct conversion formula below.
99000 acre = 154.69227799228 mile2.
You also can convert 99000 Acres to other Area (popular) units.

Convert 15000 Meters to Miles (m to mile) with our conversion calculator and conversion tables. To convert 15000 m to mile use direct conversion formula below.
15000 m = 9.32056788356 mile.
You also can convert 15000 Meters to other Length (popular) units.

Convert 26500 Square meters to Acres (m2 to acre) with our conversion calculator and conversion tables. To convert 26500 m2 to acre use direct conversion formula below.
26500 m2 = 6.548060291574 acre.
You also can convert 26500 Square meters to other Area (popular) units.

Convert 74000 Acres to Square miles (acre to mile2) with our conversion calculator and conversion tables. To convert 74000 acre to mile2 use direct conversion formula below.
74000 acre = 115.62857142857 mile2.
You also can convert 74000 Acres to other Area (popular) units.

Convert 15 Nautical miles to Miles (n mile to mile) with our conversion calculator and conversion tables. To convert 15 n mile to mile use direct conversion formula below.
15 n mile = 17.265382224984 mile.
You also can convert 15 Nautical miles to other length units.

Convert 590 Square meters to Acres (m2 to acre) with our conversion calculator and conversion tables. To convert 590 m2 to acre use direct conversion formula below.
590 m2 = 0.14578700271806 acre.
You also can convert 590 Square meters to other Area (popular) units.

Convert 22.5 Meters to Miles (m to mile) with our conversion calculator and conversion tables. To convert 22.5 m to mile use direct conversion formula below.
22.5 m = 0.01398085182534 mile.
You also can convert 22.5 Meters to other Length (popular) units.

Convert 14500 Square meters to Acres (m2 to acre) with our conversion calculator and conversion tables. To convert 14500 m2 to acre use direct conversion formula below.
14500 m2 = 3.5829009142575 acre.
You also can convert 14500 Square meters to other Area (popular) units.

Convert 7.03 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 7.03 in to mile use direct conversion formula below.
7.03 in = 0.00011095328282828 mile.
You also can convert 7.03 Inches to other Length (popular) units.


How much would each piece of gum cost if 18.0 pieces of bubble gum cost  136.0 cents? Answer:

Please enter rankine (°R) value of temperature unit to convert rankine to kelvin.
1 Rankine is equal to 0.55555555555556 Kelvin.
This is a very easy to use rankine to kelvin converter. First of all just type the rankine (°R) value in the text field of the conversion form to start converting °R to K, then select the decimals value and finally hit convert button if auto calculation didn't work. Kelvin value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of rankine to kelvin conversion.
You can also check the rankine to kelvin conversion chart below, or go back to rankine to kelvin converter to top.

List the factors until you find a common one.
Figure out the prime factorization of each. Cross out common digits. Multiply the remaining numbers of the smaller digit times the bigger number out of the two.
Find common factors between the numerator and denominator then divide by that factor.
Change all mixed numbers to improper fractions. Cross reduce. Multiply. You shouldn't have to simplify but if needed do it .
Figure out if it's out of .1 .01 or .001. Then convert.
9: repeat numerator ex: .555555555555555555555 etc.

I am working on a mail merge that has two fields that are percentages. Instead of showing as 3.75%, it shows as 3.744444444444444444444444E-2 or whatever.
I used this to try to correct it and have spaced it and formatted it about 20 different ways and it still does not seem to work, what am i doing wrong?
Make sure that the field is already rounded in the Excel or Access file.

So I'm trying to make a very basic app that counts(adds a number to 0 every second) when you hit a button then displays it in a label and a text field. Since I'm using doubles the text output looks like this, for example: 2.34555555555555. I want it to display only 2 number after the dot. How could I do that?
1 Answers Formatting JLabel/JTextField text?

" This isn't the tale of the great Pharaoh.Everyone has his own story. This story may be ending, but my story is just beginning."
King Doom rates yours a 5.
I rate yours a 5.55555555555555555555555555555555555555555555555555555555555555555.
"27 years ago I sat in this locker room just like you guys getting ready to play a game..." "... it takes you back real' quick, one of things that caught me is how fast 27 years goes by..." "There are so many people that live bycuriously through you."
"I would give anything, tonight to jump in these uniforms with you guies."
You only get to play football for so long, so make it last while you can.
Does this looks like the face of mercy?
Lurking the forums since 2011.
LOL! That's a solid 9! I happen to agree with what it says, too.
Mine's KINDA lame though, at least for this place.
?(A blue police box floating in space? Is it bigger on the inside?
Do you know what this is from?
i just want to ask, how do you make those signatures?
I say a 9!!!!!! Coooooolll!
" This isn't the tale of the great Pharaoh.Everyone has his own story. This story may be ending, but my story is just beginning."
Does this looks like the face of mercy?
Lurking the forums since 2011.

This calculator provides online conversion of degrees Fahrenheit to Celsius.
The temperature scale is named after the German physicist Daniel Gabriel Fahrenheit (1686 - 1736), who proposed it in 1724.
In Fahrenheit scale, the freezing point of water is 32 degrees F (written: "32 °F"), and the boiling point is 212 degrees, placing the boiling and freezing points of water exactly 180° apart. On the Celsius scale, the freezing and boiling points of water are precisly 100 degrees apart, thus the unit of Fahrenheit scale, is 5/9 of a degree Celsius. Negative 40 degrees Fahrenheit (-40 °F) is equal to negative 40 degrees Celsius (-40 °C).
Sample conversion: we need to convert 0°F to °C - To convert temperatures in degrees Fahrenheit to Celsius, subtract 32 and multiply by 0.5555555555555556 (or 5/9). After the calculator is used we will get the result : -17.778°C.

Have I done enough to ensure my own comfort, my own place in history. To ensure that when we are old and gray, we’ll not go hungry. Will there be enough money to keep us comfortable? By we, I mean my husband, my cats and myself. I don’t know if I really care about the history thing. I mean if I wanted to leave a lasting impression, I would have had children. Right? Instead, I have 6 cats and 4 or 5 unfinished novels. (Warning, tangent coming).
Speaking of unfinished novels, that’s what I want to do. I know it now. I know it like I know that I love beer and mexican food. I have waffled for ages about what I want to be when I grow up. I want to be a writer. I don’t want to write important, life changing books or THE GREAT AMERICAN NOVEL. I just want to write books that people want to read.
Okay, back to turning 41. I’ve done pretty well for myself. I have saved several cat lives and a few dog lives. 87+95555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555 (speaking of, Jackie wanted to say something). We recycle. We eat local and organic. I use litter made from corn, which is about to get even more expensive. We don’t consider our clothes disposable. But are doing enough? I try to conserve energy. Although my husband might tell you that I’m just cheap and hate to get a big utility bill. I try to consolidate shopping trips to use less gas. I would do this even if gas were super cheap. But is it enough?
Wow, have I actually said anything? I think I just needed to rant for a few hundred words. Turning 41 will do that to a gal.
The other contributor to this post.
It could always change tomorrow.

This is a placeholder page for S65et 5555555555555555, which means this person is not currently on this site. We do suggest using the tools below to find S65et 5555555555555555.
You are visiting the placeholder page for S65et 5555555555555555. This page is here because someone used our placeholder utility to look for S65et 5555555555555555. We created this page automatically in hopes S65et 5555555555555555 would find it. If you are not S65et 5555555555555555, but are an alumni of Peabody High School Pittsburgh, PA, register on this site for free now.

For k > 1, numbers such that k-2 occurrences of the digit 5 followed by the digits 79 is prime (see Example section).
2 is in this sequence because (5*10^2 + 211)/9 = 79 is prime.
a(5) = 32, 55555555555555555555555555555579; etc.

but this is the DEFAULT basis for many functions.
For completeness, I will document the differences here for basis==0.
If the date is 28 or 29 February, it is adjusted to 30 February.
which case it does not change."
I can easily prove that Excel 2007 does NOT meet this spec.
does not actually do so - at least not with basis=0.
in basis 0 and returns "0.083333333", which is 30/360.
The Ecma rules would produce 0.080555555555555561 (29/360.).
In other words, Excel DOES NOT change Jan. 31 into Jan. 30.
"2000 01 01 to 2000 02 30" which would be 59/360.
# Change day-of-month for purposes of calculation.
date1day = 30  # Set the day values to be equal.

Convert 238.7 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 238.7 in to mile use direct conversion formula below.
238.7 in = 0.0037673611111111 mile.
You also can convert 238.7 Inches to other Length (popular) units.

Please enter minutes (min) value of time unit to convert minutes to hours.
How Many Hours in a Minute?
There are 0.016666666666667 hours in a minute.
1 Minute is equal to 0.016666666666667 Hours.
This is a very easy to use minutes to hours converter. First of all just type the minutes (min) value in the text field of the conversion form to start converting min to h, then select the decimals value and finally hit convert button if auto calculation didn't work. Hours value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of minutes to hours conversion.
You can also check the minutes to hours conversion chart below, or go back to minutes to hours converter to top.

Please enter square foot (ft²) value of area unit to convert square foot to square yard.
How Many Square Yard in a Square Foot?
There are 0.1111111111 square yard in a square foot.
1 Square Foot is equal to 0.1111111111 Square Yard.
This is a very easy to use square foot to square yard converter. First of all just type the square foot (ft²) value in the text field of the conversion form to start converting ft² to yd², then select the decimals value and finally hit convert button if auto calculation didn't work. Square Yard value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of square foot to square yard conversion.
You can also check the square foot to square yard conversion chart below, or go back to square foot to square yard converter to top.

Convert 6140000000 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 6140000000 in to mile use direct conversion formula below.
6140000000 in = 96906.565656566 mile.
You also can convert 6140000000 Inches to other Length (popular) units.

Convert 275 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 275 in to mile use direct conversion formula below.
275 in = 0.0043402777777778 mile.
You also can convert 275 Inches to other Length (popular) units.

14 years & 11 months since 12/06/03.
14 years & 11 months since 12/06/03.
15.5 years since 12/06/03 in DD/MM/YY.
15.5 years since 12/06/03 in DD/MM/YY.
15.66666.. years since 12/06/03 in DD/MM/YY.
15.66666.. years since 12/06/03 in DD/MM/YY.

Convert 369 Meters to Miles (m to mile) with our conversion calculator and conversion tables. To convert 369 m to mile use direct conversion formula below.
369 m = 0.22928596993558 mile.
You also can convert 369 Meters to other Length (popular) units.

To find hotels near West Malling airport, paste in search form the name of the city of (West Malling), then select the dates of Check In and Check Out, select the number of guests and click Search.
WEM airport West Malling transcript or WEM which airport?
The name of the airport: West Malling. The airport is located in the country: United Kingdom. The city location of the airport in West Malling. IATA airport code West Malling: WEM. The IATA airport code is a 3 letter unique identifier, assigned airports world International air transport Association (IATA).
The geographic coordinates of the airport West Malling.
The latitude at which the airport is located: 51.300000000000, the longitude of airport: 0.416666666667. Geographic coordinates of latitude and longitude define the position of the airport on the earth's surface. To fully define the position of the airport in three-dimensional space, we should also know the third coordinate is the height. The height of the airport above sea level is 99 meters. The airport is located in the time zone: +0.0 GMT. The airline always indicates local time of departure and arrival airport according to the time zones.

7.3333333333... years to 4/15/26 in MM/DD/YY.
7.3333333333... years to 4/15/26 in MM/DD/YY.
7.25 years to 4/15/26 in MM/DD/YY.
7.25 years to 4/15/26 in MM/DD/YY.
7 years & 2 months to 4/15/26 in MM/DD/YY.
7 years & 2 months to 4/15/26 in MM/DD/YY.
7 years & 1 month to 4/15/26 in MM/DD/YY, an arithmetical progression.
7 years & 1 month to 4/15/26 in MM/DD/YY, an arithmetical progression.

Convert 332.8 Meters to Miles (m to mile) with our conversion calculator and conversion tables. To convert 332.8 m to mile use direct conversion formula below.
332.8 m = 0.20679233277658 mile.
You also can convert 332.8 Meters to other Length (popular) units.


For the fifth grade play, there is 27.0 pages of script. There are 16.0 children in the play. How many pages do they have to learn each? Answer:

cupcakes. How many cupcakes do they have total?
did Ms. Smith give away?

equally sized sections. How many acres are in each section?
Write your answer as a mixed number in simplest form.

How many ml of soft cheese, grated in 4 ounces?
How many ml of soft cheese, grated in 4 ounces?
(*) or precisely 268.08 milliliters. All values are approximate.

Windbreaker cost after discounted SKK 1275, which were 3/4 of original price. How many SKK originally cost windbreaker? How many SKK was cost reduction?
Garden 70 m long and 48 m wide should surround with wall 2.1 meters high and 30 cm thick. Wall will be built on the garden ground. How many will we need bricks if to 1 m³ is required approximately 300 bricks?
How many liters of air are under the roof of tower which has the shape of a regular six-sided pyramid with a 3,6-meter-long bottom edge and a 2,5-meter height? Calculate the supporting columns occupy about 7% of the volume under the roof.

How many tbsp of quinoa in 4 grams?
How many tbsp of quinoa in 4 grams?
(*) or precisely 0.35547 US tablespoon. All values are approximate.

School attend 792 children, boys and girls ratio is 4:5. How many more girls go to school (than boys)?
The ratio of boys to girls in a party is 3:5 . If 6 more boys arrived and 4 girls left the party, the ratio of boys to girls would be 5:6 . How many are in the party originally?

To paint the pool with dimensions: 2 meters depth, 3m x 4m we bought paint to 50 meters square. How many "paint" will be a waste?
James paints a fence. If every day instead of 14 planks painted 16 would be done on one day earlier. How many of planks has a fence altogether?
Sisters Zuzka Lenka and Vierka has save for a new bike. Zuzka save € 90, Lenka save € 90 and Vierka save € 82. Missing 30% gave them their mother. What is the price of the bike?
In a class are 34 students. The average height of students is 165 cm. What will be the average height of students in the classroom when two pupils tall 176 cm and 170 cm moved from this school/class?
Calculate the radius of a circle whose circumference is 8.4 cm longer than the circumference of the inscribed regular hexagon.
The mother is 40 years older than her daughter. How old is the mother if her age is eight thirds age of daughter?
A certain device consumes 28 kW and delivers 14 kW. Find its efficiency.

How many ml of boiled green soy beans in 2 pounds?
How many ml of boiled green soy beans in 2 pounds?
(*) or precisely 1803.5 milliliters. All values are approximate.

How many teaspoons of dried apricots in 3/4 gram?
How many teaspoons of dried apricots in 3/4 gram?
(*) or precisely 0.18949 US teaspoon. All values are approximate.

We plant two bean seeds in different pots. What's the subject?
We plant two bean seeds in different pots. What's the subject?
Plant is the verb. Who is doing the planting?
we plant two bean seeds in different pots.
A bean plant was 1.5 meters high one week ago. In 7 days it grew 15 centimeters. Find the current height of the bean plant. A)1.35 m B)13.6 cm C)1.65 m *** D)1.85 cm Can someone check this plz?

Q: How many corrugated boxes are in each case of $244.13?
A: 50 wine boxes come to a case. These make a beautiful gift!

The delta region of the eastern coast is frequently struck by cyclones.
Answer: The Bay of Bengal is the centre of various pressure changes and hence there is always a chance of development of cyclone.
Due to this, the delta region of the eastern coast is frequently struck by cyclones.

'My Heart Belongs To A Redbone Coonhound' has a rating of 5.0 stars based on 1 reviews.
Your Redbone Coonhound runs through the park like an orange-red version of The Flash. He grabs the ball that you threw with all your might and returns it to you before you can even stretch your formerly formidable throwing arm. These days in the park are the best and even though you'll be sore tomorrow you'll come back and throw some more this weekend. Get this this 'My Heart Belongs to a Redbone Coonhound' tee and wear it to park next time! You're proud of your dog, and he's definitely cooler than the rest. Redbones are so cool they even lend their names to music!
'My Heart Belongs To A Redbone Coonhound' has a rating of 5.0 stars based on 1 reviews.

The Royal College of Music Museum maintains and preserves more than 25,000 instruments, portraits, images and engravings. These items are used to support learning and research whenever possible and many are made available to a global public through an extensive programme of digitisation.
In addition, the RCM library holds equally impressive collections of manuscripts, prints, letters, concert programmes and books.
During the redevelopment of the Museum building most of the items we hold have been moved off site. The student lending collection remains on-site and access to items in storage can be arranged as needed, including for use by external researchers.
The collection includes c1,000 musical instruments from the late 15th to the mid-20th century. Among them is the earliest dated guitar (Belchior Dias, Lisbon, 1581), the earliest known stringed keyboard instrument (clavicytherium, Ulm, c1480), a harpsichord by Alessandro Trasuntino (Venice, 1531) and a remarkable collection of English viols (John Rose, c1590, Henry Jaye, 1619, Richard Meares c1680, and Barak Norman 1692 and 1694).
Several of our instruments are maintained in playing condition and can be heard at concerts or as part of our research and dissemination activities.
Our musical instrument collection can be explored through the following digital resources.
Our interactive digital exhibitions feature many items from our collections, including pictures and recordings of many of our instruments.
Printed versions of our catalogues and publication can be purchased through the RCM shop. All catalogues are also freely accessible online.
Musical Instrument Museums Online (MIMO) is an international database, initially funded by the European Community, of more than 55,000 musical instruments from major institutions all over the world. MIMO provides a primary access point for information about the instrument collection and their links to other museums in Europe. Around 800 instruments from the RCM's collection are listed here.
Use of the MIMO thesaurus has provided an authority for the consistent management of instrument names, makers and categories in collections management.
The RCM has an internationally significant collection of more than 130 paintings celebrating music, musicians and patrons of music, spanning between the 16th and the 21st century.
Notable portraits include the earliest official portrait of the famous castrato singer Carlo Broschi ‘Farinelli’, the best known portraits of Joseph Haydn, Johann Peter Solomon, William Boyce and William Shield, as well as of many of the famous musicians who studied or taught at the College (Ralph Vaughan Williams, Charles Villiers Stanford, Herbert Howells to name a few).
Images from the collections of instruments and portraits.
Carte de visite (visiting cards) of eminent 19th century musicians and other historical figures.
'Spy' caricatures of musicians from Vanity Fair, 1873–1911.
Late 19th/early 20th century photographs and postcards from the Bayreuth Opera House and Festival.
To view the materials, or to make an enquiry about image reproduction, please visit our collections’ partner ArenaPAL.
The RCM supports individual research by staff, students and external researchers whose work focusses on items in our collections or in related cultural areas.
Most of the items in our collections are currently in storage while a major redevelopment of the Museum building takes place. We have made much of the information about our collections available online.
Access can be granted to researchers who need to examine items in our collections. If you are an external researcher and would like to request access, please fill in our research request form and email it to the Museum office. Your request will be considered and we will get back to you within 10 days of receipt to let you know whether special access is possible. Please be aware that requesting instruments from our storage facility can take time.
Over the course of our Heritage Lottery Funded redevelopment we will be carrying out some more in depth research and scientific analysis on a number of our treasures. The results will be shared in a series of papers, events and online.

Walter Herries establishes himself in Keswick and builds an imposing property overlooking Uldale, further encroaching upon the peaceful lives of Jennifer and the children. Adam resolves to pursue a career in London, much to his mother’s displeasure. He meets the Chartist campaigner Caesar Kraft and lives with him and his daughter Margaret. On a visit to the capital Elizabeth Herries takes the opportunity to escape from her unhappy life but is finally pursued by John. Uhland Herries’ obsession with and hatred of John Herries grows amidst self-contempt and scorn for his father. The eagerly awaited Chartist procession comes to a tragic end for both Adam and Margaret while the confrontation that Uhland desires and John dreads comes to fruition and will scar the family for the next thirty years. Speculation that Judith will reach her hundredth birthday is rife, but the feud still exists and the attitude of the younger generation seems to predict that it may continue as devil may care Benjamin, son of Elizabeth and John, and Ellis, Will’s boy, unable to connect with his emotions, meet in London. Meanwhile the beautiful, tempestuous and determined Vanessa grows to maturity in Cumberland.

Online Help - Technical Writing Examples - Paul MacMartin Inc.
Projects: Context-sensitive and stand-alone application help. Policies and procedures. Website orientation help systems.
Services: Migrating to single-source authoring platform, developing single-sourcing object templates, interviewing content owners and engineers, prototyping and testing, authoring help, HTML coding, creating graphics.
Tools: AuthorIT, Epic Editor, RoboHelp, Dreamweaver, HomeSite, Acrobat, Photoshop, Illustrator, Visio.
VisualSonics Vevo 2100 Help 442-topic XHTML online help system for the company’s hardware and software high-resolution ultrasound imaging system. As sole contract technical writer, designed and developed custom print output template and custom XHTML template for single-sourcing output. Developed 442 topics and the 101-term index. Published to XHTML Help and PDF.
ResourceMate Help 295-topic online help system for ResourceMate, an automated system for managing library items, patrons and circulation. As sole contract technical writer, reconceived the help system, designed and developed custom print output template and custom XHTML and CHM templates for single-sourcing output, and developed all 295 topics. Published to CHM for stand-alone help access, plus to XHTML for linked Web access to updated content on the ResourceMate help server.
FM Help 174-topic online help system for FM, an online fund management system for hedge fund managers. As sole contract technical writer, migrated the software company to a single-sourced authoring system, developed custom print output template and custom XHTML templates, and developed all 174 topics.
Omnivex Display 3 Director User Guide 307-topic user guide for digital signage network software. As lead writer, structured all topics, authored topics, and single-sourced to HTML Help, PDF and Word. As lead information developer, migrated Omnivex to AuthorIT single-sourcing platform, and trained writers to develop content in AuthorIT.
Telus DM Help 50-topic XHTML online help system for the online print ordering system for this Canadian telecommunications company. As sole contract technical writer, designed and developed custom print output template and custom XHTML template for single-sourcing output. Developed all content and published to XHTML Help and PDF.

The frame-rate tag has no usage guidance.
How to make each frame represent one second?
Using a 30fps video in a 24fps animation?
Why is object mode slow but sculpt mode fast?
Is it possible to save animation as frame by frame to edit?
Everytime I render a video or animation, it is converting to 1000fps? The original footage is 30fps. Why is it changing? How do I adjust the setting?
How to control the timing of Absolute Shape Keys?
Is there a way to display the framerate in the BGE standalone runtime/EXE?
How to set frame rate to 25 FPS as default?
Is it possible to set a default frame rate to Blender? I usually use 25 frame per second. If I started a new scene it would be useful to have 25 FPS as default.
Why isn't VSE dropping frames and giving me a correct frame rate?
How do i slow down physics?
Playback skips and plays frames slowly with new audio?
Why do my vehicle's wheels appear to rotate backwards?
Why does 24fps on blender appear slower than elsewhere?

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dadario: We trust that time is linear. That it proceeds eternally, uniformly. Into infinity. But the distinction between past, present and future is nothing but an illusion.
itsrami: We trust that time is linear. That it proceeds eternally, uniformly. Into infinity.But the distinction between past, present and future is nothing but an illusion.Yesterday, today and tomorrow are not consecutive, they are connected in anever-ending circle. Everything is connected.
I awtached the first trehe episodes of Dark tonight!
on this is killing me.
Oh wait i thin k i saw 4 epsideosdes. Anyway it’s really cool an dcreepy so far and there’s a scinematic quality to it that is just nicely visual. like it so far!


The ferris wheel in paradise park has 6.0 seats. 14.0 people want to ride the ferris wheel. How many times does the ferris wheel have to run for everyone to get a turn? Answer:

As he reminded me with a wall post earlier, Jacob and I have been dating for 1.3333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333 months now, intense huh? I told him that I wasn’t counting our positive anniversaries so much as our negative ones. It’s funny how important our anniversaries were about 4-8 mo. Then we got engaged and there were more days to celebrate but the only one that “really” matters (at least monthly) is that day coming up in January 😀 And that one is less than 3 months away, yay!

- So that motor [Z-Axis] is a 7.5°, 48 step motor as I just listed. Since the motor is attached to a M4 rod, which has a 0.7 mm thread pitch, then in one revolution makes the Z-Axis travel up or down 0.7 mm. Since it took 48 steps to turn that rev, each step is 0.00145833333333333333333333333333 etc etc mm. To avoid rounding errors, you can use multiple of 3 of this number, which is a nice and pretty 0.04375 mm. That is a nice and handy number that effectively represents the layer heights that mathematically work the best for layer heights for this printer. + So that motor [Z-Axis] is a 7.5°, 48 step motor as I just listed. Since the motor is attached to a M4 rod, which has a 0.7 mm thread pitch, then in one revolution makes the Z-Axis travel up or down 0.7 mm. Since it took 48 steps to turn that rev, each step is 0.0145833333333333333333333333333 etc etc mm. To avoid rounding errors, you can use multiple of 3 of this number, which is a nice and pretty 0.04375 mm. That is a nice and handy number that effectively represents the layer heights that mathematically work the best for layer heights for this printer.

So that motor [Z-Axis] is a 7.5°, 48 step motor as I just listed. Since the motor is attached to a M4 rod, which has a 0.7 mm thread pitch, then in one revolution makes the Z-Axis travel up or down 0.7 mm. Since it took 48 steps to turn that rev, each step is 0.0145833333333333333333333333333 etc etc mm. To avoid rounding errors, you can use multiple of 3 of this number, which is a nice and pretty 0.04375 mm. That is a nice and handy number that effectively represents the layer heights that mathematically work the best for layer heights for this printer.
Using the information above we can put together a list of optimal layer heights ranging from 0.04375mm to 0.30625mm. We stop at 0.30625mm because with a nozzle diameter of 0.40mm, the maximum recommended layer height is 0.32mm.
* There have been a few reports of printing the same model at 0.04375 and 0.0875, with the 0.0875 version looking better. This is probably a settings issue and the reports could be outliers. Don't let this discourage you from trying to use 0.04375, you could and probably will have better results if you are patient enough to wait the extra time for higher resolution.

This entry was posted on Thursday, March 3rd, 2011 at 7:18 pm	and is filed under 100 Pastel Challenge, Color, Landscapes, Paintings, Pastels. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.
I love that you put in a third, just to be accurate about it!
Well, it should be 33.3333333333333333333333333 repeating to infinity, but that would be harder to draw. And take, you know, longer.
Lovely work, great number accomplished! You are a wonder!
Thanks, Thom & Leila. That was pretty left-brain of me, wasn’t it?

1333.3333333333333333333 as a decimal - solution and the full explanation with calculations.
What is 1333.3333333333333333333 as a decimal?
To write 1333.3333333333333333333 as a decimal you have to divide numerator by the denominator of the fraction.
1333.3333333333333333333 is not a fraction so it is a decimal already.

A variable is a quantity that has a changing value; the value can vary from one example to the next. A continuous variable is a variable that has an infinite number of possible values. In other words, any value is possible for the variable.
A continuous variable is the opposite of a discrete variable, which can only take on a certain number of values.
Time it takes a computer to complete a task. You might think you can count it, but time is often rounded up to convenient intervals, like seconds or milliseconds. Time is actually a continuum: it could take 1.3 seconds or it could take 1.333333333333333… seconds.
A person’s weight. Someone could weigh 180 pounds, they could weigh 180.10 pounds or they could weigh 180.1110 pounds. The number of possibilities for weight are limitless.
Age. So, you’re 25 years-old. Are you sure? How about 25 years, 19 days and a millisecond or two? Like time, age can take on an infinite number of possibilities and so it’s a continuous variable.
Heights and weights are both examples of quantities that are continuous variables.
Next: Discrete vs continuous variables.
← What is a Discrete Variable in Statistics?

Convert 176 Minutes to Hours (min to h) with our conversion calculator and conversion tables. To convert 176 min to h use direct conversion formula below.
176 min = 2.9333333333333 h.
You also can convert 176 Minutes to other Time (popular) units.

Elections should belong to people, not parties. Support the Open Our Democracy Act to give power back to the voters.
We're 45.83333333333333% of the way to our goal, help us get there!

Convert 356 Minutes to Hours (min to h) with our conversion calculator and conversion tables. To convert 356 min to h use direct conversion formula below.
356 min = 5.9333333333333 h.
You also can convert 356 Minutes to other Time (popular) units.

Please enter square foot (ft²) value of area unit to convert square foot to square yard.
How Many Square Yard in a Square Foot?
There are 0.1111111111 square yard in a square foot.
1 Square Foot is equal to 0.1111111111 Square Yard.
This is a very easy to use square foot to square yard converter. First of all just type the square foot (ft²) value in the text field of the conversion form to start converting ft² to yd², then select the decimals value and finally hit convert button if auto calculation didn't work. Square Yard value will be converted automatically as you type.
The decimals value is the number of digits to be calculated or rounded of the result of square foot to square yard conversion.
You can also check the square foot to square yard conversion chart below, or go back to square foot to square yard converter to top.

Convert 238.7 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 238.7 in to mile use direct conversion formula below.
238.7 in = 0.0037673611111111 mile.
You also can convert 238.7 Inches to other Length (popular) units.

With this tool you can convert inches to feet easily and free. Discover how many feet are a number of inches.
1 in is 0.0833333 feet.
To calculate how to convert inches to feet you can multiply the number 0.0833333 times. For example, 25 inches would be 25 x 0.0833333 = 2.0833325 feet.

1.133333334 as a fraction - solution and the full explanation with calculations.
What is 1.133333334 as a fraction?
To write 1.133333334 as a fraction you have to write 1.133333334 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

Convert 7.03 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 7.03 in to mile use direct conversion formula below.
7.03 in = 0.00011095328282828 mile.
You also can convert 7.03 Inches to other Length (popular) units.

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14 years & 11 months since 12/06/03.
14 years & 11 months since 12/06/03.
15.5 years since 12/06/03 in DD/MM/YY.
15.5 years since 12/06/03 in DD/MM/YY.
15.66666.. years since 12/06/03 in DD/MM/YY.
15.66666.. years since 12/06/03 in DD/MM/YY.

In this plot, we can see the lifelines of the slowest 10% of pull requests. For this project, the cutoff is 3.3333333 × 10-4 days. 46 pull requests where processed slower than that, while 413 were faster. The line represents the time between opening and closing the pull request. Pull requests whose end time aligns at the right edge of the plot are still open at the time of building this report. Generally, it is considered good practice to avoid having pull requests open for long.

Convert 331.1 Inches to Miles (in to mile) with our conversion calculator and conversion tables. To convert 331.1 in to mile use direct conversion formula below.
331.1 in = 0.0052256944444444 mile.
You also can convert 331.1 Inches to other Length (popular) units.